How do I make sure that a mongoose query has completed before returning the result?
1
I have this code to get the inventory in my game:
async function(username) {
return await User.findOne({ username: username }).lean().inventory;
}
Currently, I run this function in a socket.on that should return the data:
socket.on('give inventory', function() {
console.log(connections[socket.id])
itemmanage.getInventory(connections[socket.id]).then(function(result) {
console.log(result);
socket.emit("get inventory", result);
})
});
However, this doesn't return the data. Instead, it just returns undefined. How do I make it return the data instead of undefined? Everything I've tried still returns undefined.
node.js mongoose socket.io
edited Nov 18 '18 at 22:24
Neil Lunn
98k23174184
asked Nov 17 '18 at 2:48
William WhittWilliam Whitt
82
add a comment |
1
I have this code to get the inventory in my game:
async function(username) {
return await User.findOne({ username: username }).lean().inventory;
}
Currently, I run this function in a socket.on that should return the data:
socket.on('give inventory', function() {
console.log(connections[socket.id])
itemmanage.getInventory(connections[socket.id]).then(function(result) {
console.log(result);
socket.emit("get inventory", result);
})
});
However, this doesn't return the data. Instead, it just returns undefined. How do I make it return the data instead of undefined? Everything I've tried still returns undefined.
node.js mongoose socket.io
edited Nov 18 '18 at 22:24
Neil Lunn
98k23174184
asked Nov 17 '18 at 2:48
William WhittWilliam Whitt
82
It seems that the statement to right of await statement does not return a promise.
– sai.raj
Nov 17 '18 at 2:56
add a comment |
1
1
1
I have this code to get the inventory in my game:
async function(username) {
return await User.findOne({ username: username }).lean().inventory;
}
Currently, I run this function in a socket.on that should return the data:
socket.on('give inventory', function() {
console.log(connections[socket.id])
itemmanage.getInventory(connections[socket.id]).then(function(result) {
console.log(result);
socket.emit("get inventory", result);
})
});
However, this doesn't return the data. Instead, it just returns undefined. How do I make it return the data instead of undefined? Everything I've tried still returns undefined.
node.js mongoose socket.io
edited Nov 18 '18 at 22:24
Neil Lunn
98k23174184
asked Nov 17 '18 at 2:48
William WhittWilliam Whitt
82
I have this code to get the inventory in my game:
async function(username) {
return await User.findOne({ username: username }).lean().inventory;
}
Currently, I run this function in a socket.on that should return the data:
socket.on('give inventory', function() {
console.log(connections[socket.id])
itemmanage.getInventory(connections[socket.id]).then(function(result) {
console.log(result);
socket.emit("get inventory", result);
})
});
However, this doesn't return the data. Instead, it just returns undefined. How do I make it return the data instead of undefined? Everything I've tried still returns undefined.
node.js mongoose socket.io
node.js mongoose socket.io
edited Nov 18 '18 at 22:24
Neil Lunn
98k23174184
asked Nov 17 '18 at 2:48
William WhittWilliam Whitt
82
edited Nov 18 '18 at 22:24
Neil Lunn
98k23174184
asked Nov 17 '18 at 2:48
William WhittWilliam Whitt
82
edited Nov 18 '18 at 22:24
Neil Lunn
98k23174184
edited Nov 18 '18 at 22:24
Neil Lunn
98k23174184
edited Nov 18 '18 at 22:24
Neil Lunn
98k23174184
98k23174184
asked Nov 17 '18 at 2:48
William WhittWilliam Whitt
82
asked Nov 17 '18 at 2:48
William WhittWilliam Whitt
82
asked Nov 17 '18 at 2:48
William WhittWilliam Whitt
82
82
It seems that the statement to right of await statement does not return a promise.
– sai.raj
Nov 17 '18 at 2:56
add a comment |
It seems that the statement to right of await statement does not return a promise.
– sai.raj
Nov 17 '18 at 2:56
It seems that the statement to right of await statement does not return a promise.
– sai.raj
Nov 17 '18 at 2:56
It seems that the statement to right of await statement does not return a promise.
– sai.raj
Nov 17 '18 at 2:56
add a comment |
1 Answer
1
active
oldest
votes
0
async function(username) {
const data = await User.findOne({ username: username }).lean();
return data.inventory;
}
socket.on('give inventory', async function() {
try{
console.log(connections[socket.id])
const result = await itemmanage.getInventory(connections[socket.id]);
console.log(result);
socket.emit("get inventory", result);
}catch(err){
//code for handleing error
}
});
answered Nov 17 '18 at 3:26
Biplab MalakarBiplab Malakar
41837
that returns Promise {pending} Edit: Added await to the result const and that fixed it, thanks!
– William Whitt
Nov 17 '18 at 5:44
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
async function(username) {
const data = await User.findOne({ username: username }).lean();
return data.inventory;
}
socket.on('give inventory', async function() {
try{
console.log(connections[socket.id])
const result = await itemmanage.getInventory(connections[socket.id]);
console.log(result);
socket.emit("get inventory", result);
}catch(err){
//code for handleing error
}
});
answered Nov 17 '18 at 3:26
Biplab MalakarBiplab Malakar
41837
that returns Promise {pending} Edit: Added await to the result const and that fixed it, thanks!
– William Whitt
Nov 17 '18 at 5:44
add a comment |
0
async function(username) {
const data = await User.findOne({ username: username }).lean();
return data.inventory;
}
socket.on('give inventory', async function() {
try{
console.log(connections[socket.id])
const result = await itemmanage.getInventory(connections[socket.id]);
console.log(result);
socket.emit("get inventory", result);
}catch(err){
//code for handleing error
}
});
answered Nov 17 '18 at 3:26
Biplab MalakarBiplab Malakar
41837
that returns Promise {pending} Edit: Added await to the result const and that fixed it, thanks!
– William Whitt
Nov 17 '18 at 5:44
add a comment |
0
0
0
async function(username) {
const data = await User.findOne({ username: username }).lean();
return data.inventory;
}
socket.on('give inventory', async function() {
try{
console.log(connections[socket.id])
const result = await itemmanage.getInventory(connections[socket.id]);
console.log(result);
socket.emit("get inventory", result);
}catch(err){
//code for handleing error
}
});
answered Nov 17 '18 at 3:26
Biplab MalakarBiplab Malakar
41837
async function(username) {
const data = await User.findOne({ username: username }).lean();
return data.inventory;
}
socket.on('give inventory', async function() {
try{
console.log(connections[socket.id])
const result = await itemmanage.getInventory(connections[socket.id]);
console.log(result);
socket.emit("get inventory", result);
}catch(err){
//code for handleing error
}
});
answered Nov 17 '18 at 3:26
Biplab MalakarBiplab Malakar
41837
edited Nov 17 '18 at 6:18
answered Nov 17 '18 at 3:26
Biplab MalakarBiplab Malakar
41837
answered Nov 17 '18 at 3:26
Biplab MalakarBiplab Malakar
41837
answered Nov 17 '18 at 3:26
Biplab MalakarBiplab Malakar
41837
41837
that returns Promise {pending} Edit: Added await to the result const and that fixed it, thanks!
– William Whitt
Nov 17 '18 at 5:44
add a comment |
that returns Promise {pending} Edit: Added await to the result const and that fixed it, thanks!
– William Whitt
Nov 17 '18 at 5:44
that returns Promise {pending} Edit: Added await to the result const and that fixed it, thanks!
– William Whitt
Nov 17 '18 at 5:44
that returns Promise {pending} Edit: Added await to the result const and that fixed it, thanks!
– William Whitt
Nov 17 '18 at 5:44
add a comment |
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It seems that the statement to right of await statement does not return a promise.
– sai.raj
Nov 17 '18 at 2:56