Wsrtjtyk

Problem statement:

Loop 5 times. Each time, ask the user for an integer, check that the input received is that type, and then ask for another input until the user has given five correct inputs. The output of this program should look like this, assuming that the user gives five correct inputs of type int:

Hello! Please give me an integer: 0

Thanks! Please give me another integer: 1

Thanks! Please give me another integer: 1

Thanks! Please give me another integer: 2

Thanks! Please give me another integer: 3

Thanks! I am happy with five integers.

My attempts:

#include <stdio.h>



int invalid(x)  

{  

    printf("nThat was not an integer, please give me an integer: ");  

    scanf("%d", &x);

}



int main()

{

    int a, b, c, d, e, x;



    printf("Hello! Please give me an integer: ");

    scanf("%d", &a);

            if(scanf("%d", &a) != 1)

            {

                    invalid(x);

            }

    printf("nThanks! Please give me another integer: ");

    scanf("%d", &b);

            if(scanf("%d", &b) != 1)

            {

                    invalid(x);

            }

    printf("nThanks! Please give me another integer: ");

    scanf("%d", &c);

            if(scanf("%d", &c) != 1)

            {

                    invalid(x);

            }

    printf("nThanks! Please give me another integer: ");

    scanf("%d", &d);

            if(scanf("%d", &d) != 1)

            {

                    invalid(x);

            }

    printf("nThanks! Please give me another integer: ");

    scanf("%d", &e);

            if(scanf("%d", &e) != 1)

            {

                    invalid(x);

            }

    printf("nThanks! I am happy with five integers.n");

    return 0;

}





// Failed attempt to use a loop //

for(i = 0; i < 4; i++)

{

     printf("Thanks! Please give me another integer: ");

     scanf("%d", &y);

              if(scanf("%d", &y) != 1)

              {

                     invalid(y);

              }

 }















do

{

     printf ("Thanks! Please give me another integer: ", );

     scanf("%d", &x);

         for(scanf("%d", &x) != 1)

         {

              printf("That was not an integer, please give me an integer: ")

              scanf("%d", &x);

         }

         i++;

} while (i < 4);

Common outputs that I get from the first input being a letter or non-integer:

Hello! Please give me an integer: d  

That was not an integer, please give me an integer: Thanks! Please give me another integer:  

That was not an integer, please give me an integer: Thanks! Please give me another integer:  

That was not an integer, please give me an integer: Thanks! Please give me another integer:  

That was not an integer, please give me an integer: Thanks! Please give me another integer:  

That was not an integer, please give me an integer: Thanks! I am happy with five integers.

1. You have to use array to store 5 numbers (or 4, or any other amount greater than 1)


2. In any case you should use loop to ask 5 (or any other series of numbers) and here for loop will be good


3. You should analyse value returned by scanf to check if the input was correct, and re ask if value is wrong (this can be also loop, but do..while is prehereble) after incorrect characters removed from input buffer.

UPDATE

My version of the prog:

#include <stdio.h>



#define NUM_CNT 5



int main(void)

{

    int i, res, c;

    int num[NUM_CNT]; // array for all your numbers

    printf("Hello!n");

    for (i = 0; i < NUM_CNT; i++) {

        printf("Please give me an integer: ");

        do {

            res = scanf("%d", &num[i]);

            if ( res ) {

                printf("Thanks!n");

            } else {

                printf("That was not an integer, please give me an integer: ");

                while ((c = getchar()) != 'n' && c != EOF); // clean input buffer

            }

        } while(res != 1);

    }

    printf("I am happy with five integers.n");

    // just to see all the numbers

    for (i = 0; i < NUM_CNT; i++) {

        printf("%d ", num[i]);

    }

    return 0;

}

You are free to remake your code using my ideas.