Convert List[Map] to spark dataframe
-1
I want to convert List[Map] to a spark dataframe,the keys of
Map are sname,the keys of Map are DataFrame's columns
apache-spark apache-spark-sql
asked Nov 23 '18 at 8:59
user7687835user7687835
349
add a comment |
-1
I want to convert List[Map] to a spark dataframe,the keys of
Map are sname,the keys of Map are DataFrame's columns
apache-spark apache-spark-sql
asked Nov 23 '18 at 8:59
user7687835user7687835
349
add a comment |
-1
-1
-1
I want to convert List[Map] to a spark dataframe,the keys of
Map are sname,the keys of Map are DataFrame's columns
apache-spark apache-spark-sql
asked Nov 23 '18 at 8:59
user7687835user7687835
349
I want to convert List[Map] to a spark dataframe,the keys of
Map are sname,the keys of Map are DataFrame's columns
apache-spark apache-spark-sql
apache-spark apache-spark-sql
asked Nov 23 '18 at 8:59
user7687835user7687835
349
asked Nov 23 '18 at 8:59
user7687835user7687835
349
asked Nov 23 '18 at 8:59
user7687835user7687835
349
asked Nov 23 '18 at 8:59
user7687835user7687835
349
asked Nov 23 '18 at 8:59
user7687835user7687835
349
349
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
0
Here you can do this way
val map1 = {"a"->1}
val map2 = {"b"->2}
val lst = List(map1,map2)
val lstDF = lst.toDF
lstDF.take(2).foreach(println)
edited Nov 23 '18 at 11:32
Srce Cde
1,184612
answered Nov 23 '18 at 10:20
H RoyH Roy
16927
add a comment |
0
If you already have res which is a List[Map[String,String]] :
res: List[Map[String,String]] = List(Map(A -> a1, B -> b1, C -> c1), Map(A -> a2, B -> b2, C -> c2))
You can do this to create you dataframe:
//create your rows
val rows = res.map(m => Row(m.values.toSeq:_*))
//create the schema from the header
val header = res.head.keys.toList
val schema = StructType(header.map(fieldName => StructField(fieldName, StringType, true)))
//create your rdd
val rdd = sc.parallelize(rows)
//create your dataframe using
val df = spark.createDataFrame(rdd, schema)
You can output the result with df.show() :
+---+---+---+
| A| B| C|
+---+---+---+
| a1| b1| c1|
| a2| b2| c2|
+---+---+---+
Note that you can also create your schema in this way:
val schema = StructType(
List(
StructField("A", StringType, true),
StructField("B", StringType, true),
StructField("C", StringType, true)
)
)
answered Jan 30 at 13:37
Mohamed_RaedMohamed_Raed
11
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53443444%2fconvert-listmapstring-string-to-spark-dataframe%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
Here you can do this way
val map1 = {"a"->1}
val map2 = {"b"->2}
val lst = List(map1,map2)
val lstDF = lst.toDF
lstDF.take(2).foreach(println)
edited Nov 23 '18 at 11:32
Srce Cde
1,184612
answered Nov 23 '18 at 10:20
H RoyH Roy
16927
add a comment |
0
Here you can do this way
val map1 = {"a"->1}
val map2 = {"b"->2}
val lst = List(map1,map2)
val lstDF = lst.toDF
lstDF.take(2).foreach(println)
edited Nov 23 '18 at 11:32
Srce Cde
1,184612
answered Nov 23 '18 at 10:20
H RoyH Roy
16927
add a comment |
0
0
0
Here you can do this way
val map1 = {"a"->1}
val map2 = {"b"->2}
val lst = List(map1,map2)
val lstDF = lst.toDF
lstDF.take(2).foreach(println)
edited Nov 23 '18 at 11:32
Srce Cde
1,184612
answered Nov 23 '18 at 10:20
H RoyH Roy
16927
Here you can do this way
val map1 = {"a"->1}
val map2 = {"b"->2}
val lst = List(map1,map2)
val lstDF = lst.toDF
lstDF.take(2).foreach(println)
edited Nov 23 '18 at 11:32
Srce Cde
1,184612
answered Nov 23 '18 at 10:20
H RoyH Roy
16927
edited Nov 23 '18 at 11:32
Srce Cde
1,184612
edited Nov 23 '18 at 11:32
Srce Cde
1,184612
edited Nov 23 '18 at 11:32
Srce Cde
1,184612
1,184612
answered Nov 23 '18 at 10:20
H RoyH Roy
16927
answered Nov 23 '18 at 10:20
H RoyH Roy
16927
answered Nov 23 '18 at 10:20
H RoyH Roy
16927
16927
add a comment |
add a comment |
0
If you already have res which is a List[Map[String,String]] :
res: List[Map[String,String]] = List(Map(A -> a1, B -> b1, C -> c1), Map(A -> a2, B -> b2, C -> c2))
You can do this to create you dataframe:
//create your rows
val rows = res.map(m => Row(m.values.toSeq:_*))
//create the schema from the header
val header = res.head.keys.toList
val schema = StructType(header.map(fieldName => StructField(fieldName, StringType, true)))
//create your rdd
val rdd = sc.parallelize(rows)
//create your dataframe using
val df = spark.createDataFrame(rdd, schema)
You can output the result with df.show() :
+---+---+---+
| A| B| C|
+---+---+---+
| a1| b1| c1|
| a2| b2| c2|
+---+---+---+
Note that you can also create your schema in this way:
val schema = StructType(
List(
StructField("A", StringType, true),
StructField("B", StringType, true),
StructField("C", StringType, true)
)
)
answered Jan 30 at 13:37
Mohamed_RaedMohamed_Raed
11
add a comment |
0
If you already have res which is a List[Map[String,String]] :
res: List[Map[String,String]] = List(Map(A -> a1, B -> b1, C -> c1), Map(A -> a2, B -> b2, C -> c2))
You can do this to create you dataframe:
//create your rows
val rows = res.map(m => Row(m.values.toSeq:_*))
//create the schema from the header
val header = res.head.keys.toList
val schema = StructType(header.map(fieldName => StructField(fieldName, StringType, true)))
//create your rdd
val rdd = sc.parallelize(rows)
//create your dataframe using
val df = spark.createDataFrame(rdd, schema)
You can output the result with df.show() :
+---+---+---+
| A| B| C|
+---+---+---+
| a1| b1| c1|
| a2| b2| c2|
+---+---+---+
Note that you can also create your schema in this way:
val schema = StructType(
List(
StructField("A", StringType, true),
StructField("B", StringType, true),
StructField("C", StringType, true)
)
)
answered Jan 30 at 13:37
Mohamed_RaedMohamed_Raed
11
add a comment |
0
0
0
If you already have res which is a List[Map[String,String]] :
res: List[Map[String,String]] = List(Map(A -> a1, B -> b1, C -> c1), Map(A -> a2, B -> b2, C -> c2))
You can do this to create you dataframe:
//create your rows
val rows = res.map(m => Row(m.values.toSeq:_*))
//create the schema from the header
val header = res.head.keys.toList
val schema = StructType(header.map(fieldName => StructField(fieldName, StringType, true)))
//create your rdd
val rdd = sc.parallelize(rows)
//create your dataframe using
val df = spark.createDataFrame(rdd, schema)
You can output the result with df.show() :
+---+---+---+
| A| B| C|
+---+---+---+
| a1| b1| c1|
| a2| b2| c2|
+---+---+---+
Note that you can also create your schema in this way:
val schema = StructType(
List(
StructField("A", StringType, true),
StructField("B", StringType, true),
StructField("C", StringType, true)
)
)
answered Jan 30 at 13:37
Mohamed_RaedMohamed_Raed
11
If you already have res which is a List[Map[String,String]] :
res: List[Map[String,String]] = List(Map(A -> a1, B -> b1, C -> c1), Map(A -> a2, B -> b2, C -> c2))
You can do this to create you dataframe:
//create your rows
val rows = res.map(m => Row(m.values.toSeq:_*))
//create the schema from the header
val header = res.head.keys.toList
val schema = StructType(header.map(fieldName => StructField(fieldName, StringType, true)))
//create your rdd
val rdd = sc.parallelize(rows)
//create your dataframe using
val df = spark.createDataFrame(rdd, schema)
You can output the result with df.show() :
+---+---+---+
| A| B| C|
+---+---+---+
| a1| b1| c1|
| a2| b2| c2|
+---+---+---+
Note that you can also create your schema in this way:
val schema = StructType(
List(
StructField("A", StringType, true),
StructField("B", StringType, true),
StructField("C", StringType, true)
)
)
answered Jan 30 at 13:37
Mohamed_RaedMohamed_Raed
11
answered Jan 30 at 13:37
Mohamed_RaedMohamed_Raed
11
answered Jan 30 at 13:37
Mohamed_RaedMohamed_Raed
11
answered Jan 30 at 13:37
Mohamed_RaedMohamed_Raed
11
11
add a comment |
add a comment |
draft saved
draft discarded
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53443444%2fconvert-listmapstring-string-to-spark-dataframe%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
