How can I create a matrix , with random number on row and not replace,but in col can replace, R language
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How can I create a matrix , with random number on row and not replace.
like this
5 29 24 20 31 33
2 18 35 4 11 21
30 40 22 14 2 28
33 14 4 18 5 10
10 33 15 2 28 18
7 22 9 25 31 20
12 29 31 22 37 26
7 31 34 28 19 23
7 34 11 6 31 28
my code :
matrix(sample(1:42, 60, replace = FALSE), ncol = 6)
But I receive this error message:
Error in sample.int(length(x), size, replace, prob) : cannot take a
sample larger than the population when 'replace = FALSE'
but it's wrong because only 1~42, it can't create a 60 matrix.
r
edited Nov 23 '18 at 15:57
alepuzio
1,19722732
asked Nov 23 '18 at 14:41
破嘎獸破嘎獸
173
add a comment |
How can I create a matrix , with random number on row and not replace.
like this
5 29 24 20 31 33
2 18 35 4 11 21
30 40 22 14 2 28
33 14 4 18 5 10
10 33 15 2 28 18
7 22 9 25 31 20
12 29 31 22 37 26
7 31 34 28 19 23
7 34 11 6 31 28
my code :
matrix(sample(1:42, 60, replace = FALSE), ncol = 6)
But I receive this error message:
Error in sample.int(length(x), size, replace, prob) : cannot take a
sample larger than the population when 'replace = FALSE'
but it's wrong because only 1~42, it can't create a 60 matrix.
r
edited Nov 23 '18 at 15:57
alepuzio
1,19722732
asked Nov 23 '18 at 14:41
破嘎獸破嘎獸
173
3
Do it per row?t(sapply(1:10, function(x) sample(1:42, 6, replace = FALSE)))
– Jav
Nov 23 '18 at 14:45
can use replicate maybe:matrix(replicate(2, sample(1:42, replace = FALSE)), ncol=6, nrow=10)
– Jonny Phelps
Nov 23 '18 at 15:12
add a comment |
How can I create a matrix , with random number on row and not replace.
like this
5 29 24 20 31 33
2 18 35 4 11 21
30 40 22 14 2 28
33 14 4 18 5 10
10 33 15 2 28 18
7 22 9 25 31 20
12 29 31 22 37 26
7 31 34 28 19 23
7 34 11 6 31 28
my code :
matrix(sample(1:42, 60, replace = FALSE), ncol = 6)
But I receive this error message:
Error in sample.int(length(x), size, replace, prob) : cannot take a
sample larger than the population when 'replace = FALSE'
but it's wrong because only 1~42, it can't create a 60 matrix.
r
edited Nov 23 '18 at 15:57
alepuzio
1,19722732
asked Nov 23 '18 at 14:41
破嘎獸破嘎獸
173
How can I create a matrix , with random number on row and not replace.
like this
5 29 24 20 31 33
2 18 35 4 11 21
30 40 22 14 2 28
33 14 4 18 5 10
10 33 15 2 28 18
7 22 9 25 31 20
12 29 31 22 37 26
7 31 34 28 19 23
7 34 11 6 31 28
my code :
matrix(sample(1:42, 60, replace = FALSE), ncol = 6)
But I receive this error message:
Error in sample.int(length(x), size, replace, prob) : cannot take a
sample larger than the population when 'replace = FALSE'
but it's wrong because only 1~42, it can't create a 60 matrix.
r
r
edited Nov 23 '18 at 15:57
alepuzio
1,19722732
asked Nov 23 '18 at 14:41
破嘎獸破嘎獸
173
edited Nov 23 '18 at 15:57
alepuzio
1,19722732
asked Nov 23 '18 at 14:41
破嘎獸破嘎獸
173
edited Nov 23 '18 at 15:57
alepuzio
1,19722732
edited Nov 23 '18 at 15:57
alepuzio
1,19722732
edited Nov 23 '18 at 15:57
alepuzio
1,19722732
1,19722732
asked Nov 23 '18 at 14:41
破嘎獸破嘎獸
173
asked Nov 23 '18 at 14:41
破嘎獸破嘎獸
173
asked Nov 23 '18 at 14:41
破嘎獸破嘎獸
173
173
3
Do it per row?t(sapply(1:10, function(x) sample(1:42, 6, replace = FALSE)))
– Jav
Nov 23 '18 at 14:45
can use replicate maybe:matrix(replicate(2, sample(1:42, replace = FALSE)), ncol=6, nrow=10)
– Jonny Phelps
Nov 23 '18 at 15:12
add a comment |
3
Do it per row?t(sapply(1:10, function(x) sample(1:42, 6, replace = FALSE)))
– Jav
Nov 23 '18 at 14:45
can use replicate maybe:matrix(replicate(2, sample(1:42, replace = FALSE)), ncol=6, nrow=10)
– Jonny Phelps
Nov 23 '18 at 15:12
3
3
Do it per row?
t(sapply(1:10, function(x) sample(1:42, 6, replace = FALSE)))– Jav
Nov 23 '18 at 14:45
Do it per row?
t(sapply(1:10, function(x) sample(1:42, 6, replace = FALSE)))– Jav
Nov 23 '18 at 14:45
can use replicate maybe:
matrix(replicate(2, sample(1:42, replace = FALSE)), ncol=6, nrow=10)– Jonny Phelps
Nov 23 '18 at 15:12
can use replicate maybe:
matrix(replicate(2, sample(1:42, replace = FALSE)), ncol=6, nrow=10)– Jonny Phelps
Nov 23 '18 at 15:12
add a comment |
2 Answers
2
active
oldest
votes
You can not generate all 60 of the numbers with one sample function as you want to allow replacement of numbers in a different row. Therefore you have to do one sample per row. @Jav provided very neat code to accomplish this in the comment to the question:
t(sapply(1:10, function(x) sample(1:42, 6, replace = FALSE)))
answered Nov 23 '18 at 15:39
Aaro ViertiöAaro Viertiö
1295
add a comment |
if you want to have a different sample in each row, then replicate can help you -- but replicate (as pretty much everything else in R) works naturally columnwise, so you have to transpose the result:
t(replicate(10, sample(1:42, 6)))
replace = FALSEis the default, so I didn't include it- after transposing,
10becomes the number of rows and6becomes the number of columns
answered Nov 23 '18 at 15:53
lebatsnoklebatsnok
4,46621118
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can not generate all 60 of the numbers with one sample function as you want to allow replacement of numbers in a different row. Therefore you have to do one sample per row. @Jav provided very neat code to accomplish this in the comment to the question:
t(sapply(1:10, function(x) sample(1:42, 6, replace = FALSE)))
answered Nov 23 '18 at 15:39
Aaro ViertiöAaro Viertiö
1295
add a comment |
You can not generate all 60 of the numbers with one sample function as you want to allow replacement of numbers in a different row. Therefore you have to do one sample per row. @Jav provided very neat code to accomplish this in the comment to the question:
t(sapply(1:10, function(x) sample(1:42, 6, replace = FALSE)))
answered Nov 23 '18 at 15:39
Aaro ViertiöAaro Viertiö
1295
add a comment |
You can not generate all 60 of the numbers with one sample function as you want to allow replacement of numbers in a different row. Therefore you have to do one sample per row. @Jav provided very neat code to accomplish this in the comment to the question:
t(sapply(1:10, function(x) sample(1:42, 6, replace = FALSE)))
answered Nov 23 '18 at 15:39
Aaro ViertiöAaro Viertiö
1295
You can not generate all 60 of the numbers with one sample function as you want to allow replacement of numbers in a different row. Therefore you have to do one sample per row. @Jav provided very neat code to accomplish this in the comment to the question:
t(sapply(1:10, function(x) sample(1:42, 6, replace = FALSE)))
answered Nov 23 '18 at 15:39
Aaro ViertiöAaro Viertiö
1295
answered Nov 23 '18 at 15:39
Aaro ViertiöAaro Viertiö
1295
answered Nov 23 '18 at 15:39
Aaro ViertiöAaro Viertiö
1295
answered Nov 23 '18 at 15:39
Aaro ViertiöAaro Viertiö
1295
1295
add a comment |
add a comment |
if you want to have a different sample in each row, then replicate can help you -- but replicate (as pretty much everything else in R) works naturally columnwise, so you have to transpose the result:
t(replicate(10, sample(1:42, 6)))
replace = FALSEis the default, so I didn't include it- after transposing,
10becomes the number of rows and6becomes the number of columns
answered Nov 23 '18 at 15:53
lebatsnoklebatsnok
4,46621118
add a comment |
if you want to have a different sample in each row, then replicate can help you -- but replicate (as pretty much everything else in R) works naturally columnwise, so you have to transpose the result:
t(replicate(10, sample(1:42, 6)))
replace = FALSEis the default, so I didn't include it- after transposing,
10becomes the number of rows and6becomes the number of columns
answered Nov 23 '18 at 15:53
lebatsnoklebatsnok
4,46621118
add a comment |
if you want to have a different sample in each row, then replicate can help you -- but replicate (as pretty much everything else in R) works naturally columnwise, so you have to transpose the result:
t(replicate(10, sample(1:42, 6)))
replace = FALSEis the default, so I didn't include it- after transposing,
10becomes the number of rows and6becomes the number of columns
answered Nov 23 '18 at 15:53
lebatsnoklebatsnok
4,46621118
if you want to have a different sample in each row, then replicate can help you -- but replicate (as pretty much everything else in R) works naturally columnwise, so you have to transpose the result:
t(replicate(10, sample(1:42, 6)))
replace = FALSEis the default, so I didn't include it- after transposing,
10becomes the number of rows and6becomes the number of columns
answered Nov 23 '18 at 15:53
lebatsnoklebatsnok
4,46621118
answered Nov 23 '18 at 15:53
lebatsnoklebatsnok
4,46621118
answered Nov 23 '18 at 15:53
lebatsnoklebatsnok
4,46621118
answered Nov 23 '18 at 15:53
lebatsnoklebatsnok
4,46621118
4,46621118
add a comment |
add a comment |
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3
Do it per row?
t(sapply(1:10, function(x) sample(1:42, 6, replace = FALSE)))– Jav
Nov 23 '18 at 14:45
can use replicate maybe:
matrix(replicate(2, sample(1:42, replace = FALSE)), ncol=6, nrow=10)– Jonny Phelps
Nov 23 '18 at 15:12