How to use 8 cores while running LDA topic model in R
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I am running a Latent Dirichlet topic model in R using the follwing code:
for(k in 2:30) {
ldaOut <-LDA(dtm,k, method="Gibbs",
control=list(nstart=nstart, seed = seed, best=best,
burnin = burnin, iter = iter, thin=thin))
assign(paste("ldaOut", k, sep = "_"), ldaOut)
}
The dtm has 12 million elements, and each loop takes up to two hours on average. Meanwhile, R uses only 1 of my 8 logical processors ( i have i7-2700K CPU @ 3.50GHz wtih 4 cores). How can I make R use all the computational power available when I run one LDA topic model or when using a loop (as in this code)?
Thank you
EDIT: follwing gc_'s advice, I used the following code:
library(doParallel)
n.cores <- detectCores(all.tests = T, logical = T)
cl <- makePSOCKcluster(n.cores)
doParallel::registerDoParallel(cl)
burnin <- 4000
iter <- 2000
thin <- 500
seed <-list(2003,10,100,10005,765)
nstart <- 5
best <- TRUE
var.shared <- c("ldaOut", "dtm", "nstart", "seed", "best", "burnin", "iter", "thin", "n.cores")
library.shared <- "topicmodels" # Same for library or functions.
ldaOut <- c()
foreach (k = 2:(30 / n.cores - 1), .export = var.shared, .packages = library.shared) %dopar% {
ret <- LDA(dtm, k*n.cores , method="Gibbs",
control=list(nstart=nstart, seed = seed, best=best,
burnin = burnin, iter = iter, thin=thin))
assign(paste("ldaOut", k*n.cores, sep = "_"), ret)
}
The code ran without errors, but now there are 16 "R for Windows front-end" processes, 15 of which use 0% of the CPU and 1 is using 16-17%...And when the process was over i got this message:
A LDA_Gibbs topic model with 16 topics.
Warning messages:
1: In e$fun(obj, substitute(ex), parent.frame(), e$data) :
already exporting variable(s): dtm, nstart, seed, best, burnin, iter, thin, n.cores
2: closing unused connection 10 (<-MyPC:11888)
3: closing unused connection 9 (<-MyPC:11888)
4: closing unused connection 8 (<-MyPC:11888)
5: closing unused connection 7 (<-MyPC:11888)
6: closing unused connection 6 (<-MyPC:11888)
7: closing unused connection 5 (<-MyPC:11888)
8: closing unused connection 4 (<-MyPC:11888)
9: closing unused connection 3 (<-MyPC:11888)
r multicore lda
add a comment |
up vote
0
down vote
favorite
I am running a Latent Dirichlet topic model in R using the follwing code:
for(k in 2:30) {
ldaOut <-LDA(dtm,k, method="Gibbs",
control=list(nstart=nstart, seed = seed, best=best,
burnin = burnin, iter = iter, thin=thin))
assign(paste("ldaOut", k, sep = "_"), ldaOut)
}
The dtm has 12 million elements, and each loop takes up to two hours on average. Meanwhile, R uses only 1 of my 8 logical processors ( i have i7-2700K CPU @ 3.50GHz wtih 4 cores). How can I make R use all the computational power available when I run one LDA topic model or when using a loop (as in this code)?
Thank you
EDIT: follwing gc_'s advice, I used the following code:
library(doParallel)
n.cores <- detectCores(all.tests = T, logical = T)
cl <- makePSOCKcluster(n.cores)
doParallel::registerDoParallel(cl)
burnin <- 4000
iter <- 2000
thin <- 500
seed <-list(2003,10,100,10005,765)
nstart <- 5
best <- TRUE
var.shared <- c("ldaOut", "dtm", "nstart", "seed", "best", "burnin", "iter", "thin", "n.cores")
library.shared <- "topicmodels" # Same for library or functions.
ldaOut <- c()
foreach (k = 2:(30 / n.cores - 1), .export = var.shared, .packages = library.shared) %dopar% {
ret <- LDA(dtm, k*n.cores , method="Gibbs",
control=list(nstart=nstart, seed = seed, best=best,
burnin = burnin, iter = iter, thin=thin))
assign(paste("ldaOut", k*n.cores, sep = "_"), ret)
}
The code ran without errors, but now there are 16 "R for Windows front-end" processes, 15 of which use 0% of the CPU and 1 is using 16-17%...And when the process was over i got this message:
A LDA_Gibbs topic model with 16 topics.
Warning messages:
1: In e$fun(obj, substitute(ex), parent.frame(), e$data) :
already exporting variable(s): dtm, nstart, seed, best, burnin, iter, thin, n.cores
2: closing unused connection 10 (<-MyPC:11888)
3: closing unused connection 9 (<-MyPC:11888)
4: closing unused connection 8 (<-MyPC:11888)
5: closing unused connection 7 (<-MyPC:11888)
6: closing unused connection 6 (<-MyPC:11888)
7: closing unused connection 5 (<-MyPC:11888)
8: closing unused connection 4 (<-MyPC:11888)
9: closing unused connection 3 (<-MyPC:11888)
r multicore lda
cran.r-project.org/web/views/HighPerformanceComputing.html
– r2evans
Nov 8 at 2:30
Have you tried text2vec package for topic model? It is faster. Please see below links:text2vec.org/topic_modeling.html and stackoverflow.com/questions/52268925/…
– Sam S
Nov 13 at 23:24
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I am running a Latent Dirichlet topic model in R using the follwing code:
for(k in 2:30) {
ldaOut <-LDA(dtm,k, method="Gibbs",
control=list(nstart=nstart, seed = seed, best=best,
burnin = burnin, iter = iter, thin=thin))
assign(paste("ldaOut", k, sep = "_"), ldaOut)
}
The dtm has 12 million elements, and each loop takes up to two hours on average. Meanwhile, R uses only 1 of my 8 logical processors ( i have i7-2700K CPU @ 3.50GHz wtih 4 cores). How can I make R use all the computational power available when I run one LDA topic model or when using a loop (as in this code)?
Thank you
EDIT: follwing gc_'s advice, I used the following code:
library(doParallel)
n.cores <- detectCores(all.tests = T, logical = T)
cl <- makePSOCKcluster(n.cores)
doParallel::registerDoParallel(cl)
burnin <- 4000
iter <- 2000
thin <- 500
seed <-list(2003,10,100,10005,765)
nstart <- 5
best <- TRUE
var.shared <- c("ldaOut", "dtm", "nstart", "seed", "best", "burnin", "iter", "thin", "n.cores")
library.shared <- "topicmodels" # Same for library or functions.
ldaOut <- c()
foreach (k = 2:(30 / n.cores - 1), .export = var.shared, .packages = library.shared) %dopar% {
ret <- LDA(dtm, k*n.cores , method="Gibbs",
control=list(nstart=nstart, seed = seed, best=best,
burnin = burnin, iter = iter, thin=thin))
assign(paste("ldaOut", k*n.cores, sep = "_"), ret)
}
The code ran without errors, but now there are 16 "R for Windows front-end" processes, 15 of which use 0% of the CPU and 1 is using 16-17%...And when the process was over i got this message:
A LDA_Gibbs topic model with 16 topics.
Warning messages:
1: In e$fun(obj, substitute(ex), parent.frame(), e$data) :
already exporting variable(s): dtm, nstart, seed, best, burnin, iter, thin, n.cores
2: closing unused connection 10 (<-MyPC:11888)
3: closing unused connection 9 (<-MyPC:11888)
4: closing unused connection 8 (<-MyPC:11888)
5: closing unused connection 7 (<-MyPC:11888)
6: closing unused connection 6 (<-MyPC:11888)
7: closing unused connection 5 (<-MyPC:11888)
8: closing unused connection 4 (<-MyPC:11888)
9: closing unused connection 3 (<-MyPC:11888)
r multicore lda
I am running a Latent Dirichlet topic model in R using the follwing code:
for(k in 2:30) {
ldaOut <-LDA(dtm,k, method="Gibbs",
control=list(nstart=nstart, seed = seed, best=best,
burnin = burnin, iter = iter, thin=thin))
assign(paste("ldaOut", k, sep = "_"), ldaOut)
}
The dtm has 12 million elements, and each loop takes up to two hours on average. Meanwhile, R uses only 1 of my 8 logical processors ( i have i7-2700K CPU @ 3.50GHz wtih 4 cores). How can I make R use all the computational power available when I run one LDA topic model or when using a loop (as in this code)?
Thank you
EDIT: follwing gc_'s advice, I used the following code:
library(doParallel)
n.cores <- detectCores(all.tests = T, logical = T)
cl <- makePSOCKcluster(n.cores)
doParallel::registerDoParallel(cl)
burnin <- 4000
iter <- 2000
thin <- 500
seed <-list(2003,10,100,10005,765)
nstart <- 5
best <- TRUE
var.shared <- c("ldaOut", "dtm", "nstart", "seed", "best", "burnin", "iter", "thin", "n.cores")
library.shared <- "topicmodels" # Same for library or functions.
ldaOut <- c()
foreach (k = 2:(30 / n.cores - 1), .export = var.shared, .packages = library.shared) %dopar% {
ret <- LDA(dtm, k*n.cores , method="Gibbs",
control=list(nstart=nstart, seed = seed, best=best,
burnin = burnin, iter = iter, thin=thin))
assign(paste("ldaOut", k*n.cores, sep = "_"), ret)
}
The code ran without errors, but now there are 16 "R for Windows front-end" processes, 15 of which use 0% of the CPU and 1 is using 16-17%...And when the process was over i got this message:
A LDA_Gibbs topic model with 16 topics.
Warning messages:
1: In e$fun(obj, substitute(ex), parent.frame(), e$data) :
already exporting variable(s): dtm, nstart, seed, best, burnin, iter, thin, n.cores
2: closing unused connection 10 (<-MyPC:11888)
3: closing unused connection 9 (<-MyPC:11888)
4: closing unused connection 8 (<-MyPC:11888)
5: closing unused connection 7 (<-MyPC:11888)
6: closing unused connection 6 (<-MyPC:11888)
7: closing unused connection 5 (<-MyPC:11888)
8: closing unused connection 4 (<-MyPC:11888)
9: closing unused connection 3 (<-MyPC:11888)
r multicore lda
r multicore lda
edited Nov 8 at 18:57
asked Nov 8 at 2:19
Michael
708
708
cran.r-project.org/web/views/HighPerformanceComputing.html
– r2evans
Nov 8 at 2:30
Have you tried text2vec package for topic model? It is faster. Please see below links:text2vec.org/topic_modeling.html and stackoverflow.com/questions/52268925/…
– Sam S
Nov 13 at 23:24
add a comment |
cran.r-project.org/web/views/HighPerformanceComputing.html
– r2evans
Nov 8 at 2:30
Have you tried text2vec package for topic model? It is faster. Please see below links:text2vec.org/topic_modeling.html and stackoverflow.com/questions/52268925/…
– Sam S
Nov 13 at 23:24
cran.r-project.org/web/views/HighPerformanceComputing.html
– r2evans
Nov 8 at 2:30
cran.r-project.org/web/views/HighPerformanceComputing.html
– r2evans
Nov 8 at 2:30
Have you tried text2vec package for topic model? It is faster. Please see below links:text2vec.org/topic_modeling.html and stackoverflow.com/questions/52268925/…
– Sam S
Nov 13 at 23:24
Have you tried text2vec package for topic model? It is faster. Please see below links:text2vec.org/topic_modeling.html and stackoverflow.com/questions/52268925/…
– Sam S
Nov 13 at 23:24
add a comment |
1 Answer
1
active
oldest
votes
up vote
1
down vote
You can use the library doParallel
library(doParallel)
To get the number of cores of your computer:
n.cores <- detectCores(all.tests = T, logical = T)
You can see the distinction between logical and physical cores.
Now you need to assign the core and set up all the process:
cl <- makePSOCKcluster(n.cores)
doParallel::registerDoParallel(cl)
You can create more processes than you have cores on your computer.
As R is creating new processes you need to define the library and variables you need to share with the workers.
var.shared <- c("ldaOut", "dtm", "nstart", "seed", "best", "burnin", "iter", "thin", "n.cores")
library.shared <- c() # Same for library or functions.
Then the loop will change to:
ldaOut <- #Init the output#
foreach (k = 2:(30 / n.cores - 1), .export = var.shared, .packages = library.shared)) %dopar% {
ret <- LDA(dtm, k*n.cores , method="Gibbs",
control=list(nstart=nstart, seed = seed, best=best,
burnin = burnin, iter = iter, thin=thin))
assign(paste("ldaOut", k*n.cores, sep = "_"), ret)
}
I have never used LDA before so you might need to modify a bit the code above in order to make it works.
thank you! I've tried this code, but got an error as shown above. It seems like the loop can't find the LDA function. Am I doing something wrong?
– Michael
Nov 8 at 4:08
Have you specified the library of the LDA function in library.shared?
– gc_
Nov 8 at 4:11
ok, i think i didin,t, so now I changed from "ldaOut <- #Init the output#" to "library.shared <- LDA", did i understand you correctly? with this line I get the error "Error in foreach(k = 2:(30/n.cores - 1), .export = var.shared, .packages = library.shared) : .packages must be a character vector"
– Michael
Nov 8 at 4:35
if the package name is LDA then library.shared <- "LDA". For ldaOut you need to initialize this variable with the object (but empty) as return the function LDA.
– gc_
Nov 8 at 6:07
gc_, the package name is "topicmodels", so i did the following "library.shared <- "topicmodels", and "ldaOut <- c()". With these modifications, I've been able to run the code without any errors, but R is using only 15-17 % of my CPU. There are 15 processes "R for windows front-end" using 0% and 1 using 16%.
– Michael
Nov 8 at 17:11
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
You can use the library doParallel
library(doParallel)
To get the number of cores of your computer:
n.cores <- detectCores(all.tests = T, logical = T)
You can see the distinction between logical and physical cores.
Now you need to assign the core and set up all the process:
cl <- makePSOCKcluster(n.cores)
doParallel::registerDoParallel(cl)
You can create more processes than you have cores on your computer.
As R is creating new processes you need to define the library and variables you need to share with the workers.
var.shared <- c("ldaOut", "dtm", "nstart", "seed", "best", "burnin", "iter", "thin", "n.cores")
library.shared <- c() # Same for library or functions.
Then the loop will change to:
ldaOut <- #Init the output#
foreach (k = 2:(30 / n.cores - 1), .export = var.shared, .packages = library.shared)) %dopar% {
ret <- LDA(dtm, k*n.cores , method="Gibbs",
control=list(nstart=nstart, seed = seed, best=best,
burnin = burnin, iter = iter, thin=thin))
assign(paste("ldaOut", k*n.cores, sep = "_"), ret)
}
I have never used LDA before so you might need to modify a bit the code above in order to make it works.
thank you! I've tried this code, but got an error as shown above. It seems like the loop can't find the LDA function. Am I doing something wrong?
– Michael
Nov 8 at 4:08
Have you specified the library of the LDA function in library.shared?
– gc_
Nov 8 at 4:11
ok, i think i didin,t, so now I changed from "ldaOut <- #Init the output#" to "library.shared <- LDA", did i understand you correctly? with this line I get the error "Error in foreach(k = 2:(30/n.cores - 1), .export = var.shared, .packages = library.shared) : .packages must be a character vector"
– Michael
Nov 8 at 4:35
if the package name is LDA then library.shared <- "LDA". For ldaOut you need to initialize this variable with the object (but empty) as return the function LDA.
– gc_
Nov 8 at 6:07
gc_, the package name is "topicmodels", so i did the following "library.shared <- "topicmodels", and "ldaOut <- c()". With these modifications, I've been able to run the code without any errors, but R is using only 15-17 % of my CPU. There are 15 processes "R for windows front-end" using 0% and 1 using 16%.
– Michael
Nov 8 at 17:11
add a comment |
up vote
1
down vote
You can use the library doParallel
library(doParallel)
To get the number of cores of your computer:
n.cores <- detectCores(all.tests = T, logical = T)
You can see the distinction between logical and physical cores.
Now you need to assign the core and set up all the process:
cl <- makePSOCKcluster(n.cores)
doParallel::registerDoParallel(cl)
You can create more processes than you have cores on your computer.
As R is creating new processes you need to define the library and variables you need to share with the workers.
var.shared <- c("ldaOut", "dtm", "nstart", "seed", "best", "burnin", "iter", "thin", "n.cores")
library.shared <- c() # Same for library or functions.
Then the loop will change to:
ldaOut <- #Init the output#
foreach (k = 2:(30 / n.cores - 1), .export = var.shared, .packages = library.shared)) %dopar% {
ret <- LDA(dtm, k*n.cores , method="Gibbs",
control=list(nstart=nstart, seed = seed, best=best,
burnin = burnin, iter = iter, thin=thin))
assign(paste("ldaOut", k*n.cores, sep = "_"), ret)
}
I have never used LDA before so you might need to modify a bit the code above in order to make it works.
thank you! I've tried this code, but got an error as shown above. It seems like the loop can't find the LDA function. Am I doing something wrong?
– Michael
Nov 8 at 4:08
Have you specified the library of the LDA function in library.shared?
– gc_
Nov 8 at 4:11
ok, i think i didin,t, so now I changed from "ldaOut <- #Init the output#" to "library.shared <- LDA", did i understand you correctly? with this line I get the error "Error in foreach(k = 2:(30/n.cores - 1), .export = var.shared, .packages = library.shared) : .packages must be a character vector"
– Michael
Nov 8 at 4:35
if the package name is LDA then library.shared <- "LDA". For ldaOut you need to initialize this variable with the object (but empty) as return the function LDA.
– gc_
Nov 8 at 6:07
gc_, the package name is "topicmodels", so i did the following "library.shared <- "topicmodels", and "ldaOut <- c()". With these modifications, I've been able to run the code without any errors, but R is using only 15-17 % of my CPU. There are 15 processes "R for windows front-end" using 0% and 1 using 16%.
– Michael
Nov 8 at 17:11
add a comment |
up vote
1
down vote
up vote
1
down vote
You can use the library doParallel
library(doParallel)
To get the number of cores of your computer:
n.cores <- detectCores(all.tests = T, logical = T)
You can see the distinction between logical and physical cores.
Now you need to assign the core and set up all the process:
cl <- makePSOCKcluster(n.cores)
doParallel::registerDoParallel(cl)
You can create more processes than you have cores on your computer.
As R is creating new processes you need to define the library and variables you need to share with the workers.
var.shared <- c("ldaOut", "dtm", "nstart", "seed", "best", "burnin", "iter", "thin", "n.cores")
library.shared <- c() # Same for library or functions.
Then the loop will change to:
ldaOut <- #Init the output#
foreach (k = 2:(30 / n.cores - 1), .export = var.shared, .packages = library.shared)) %dopar% {
ret <- LDA(dtm, k*n.cores , method="Gibbs",
control=list(nstart=nstart, seed = seed, best=best,
burnin = burnin, iter = iter, thin=thin))
assign(paste("ldaOut", k*n.cores, sep = "_"), ret)
}
I have never used LDA before so you might need to modify a bit the code above in order to make it works.
You can use the library doParallel
library(doParallel)
To get the number of cores of your computer:
n.cores <- detectCores(all.tests = T, logical = T)
You can see the distinction between logical and physical cores.
Now you need to assign the core and set up all the process:
cl <- makePSOCKcluster(n.cores)
doParallel::registerDoParallel(cl)
You can create more processes than you have cores on your computer.
As R is creating new processes you need to define the library and variables you need to share with the workers.
var.shared <- c("ldaOut", "dtm", "nstart", "seed", "best", "burnin", "iter", "thin", "n.cores")
library.shared <- c() # Same for library or functions.
Then the loop will change to:
ldaOut <- #Init the output#
foreach (k = 2:(30 / n.cores - 1), .export = var.shared, .packages = library.shared)) %dopar% {
ret <- LDA(dtm, k*n.cores , method="Gibbs",
control=list(nstart=nstart, seed = seed, best=best,
burnin = burnin, iter = iter, thin=thin))
assign(paste("ldaOut", k*n.cores, sep = "_"), ret)
}
I have never used LDA before so you might need to modify a bit the code above in order to make it works.
edited Nov 8 at 2:53
answered Nov 8 at 2:47
gc_
713
713
thank you! I've tried this code, but got an error as shown above. It seems like the loop can't find the LDA function. Am I doing something wrong?
– Michael
Nov 8 at 4:08
Have you specified the library of the LDA function in library.shared?
– gc_
Nov 8 at 4:11
ok, i think i didin,t, so now I changed from "ldaOut <- #Init the output#" to "library.shared <- LDA", did i understand you correctly? with this line I get the error "Error in foreach(k = 2:(30/n.cores - 1), .export = var.shared, .packages = library.shared) : .packages must be a character vector"
– Michael
Nov 8 at 4:35
if the package name is LDA then library.shared <- "LDA". For ldaOut you need to initialize this variable with the object (but empty) as return the function LDA.
– gc_
Nov 8 at 6:07
gc_, the package name is "topicmodels", so i did the following "library.shared <- "topicmodels", and "ldaOut <- c()". With these modifications, I've been able to run the code without any errors, but R is using only 15-17 % of my CPU. There are 15 processes "R for windows front-end" using 0% and 1 using 16%.
– Michael
Nov 8 at 17:11
add a comment |
thank you! I've tried this code, but got an error as shown above. It seems like the loop can't find the LDA function. Am I doing something wrong?
– Michael
Nov 8 at 4:08
Have you specified the library of the LDA function in library.shared?
– gc_
Nov 8 at 4:11
ok, i think i didin,t, so now I changed from "ldaOut <- #Init the output#" to "library.shared <- LDA", did i understand you correctly? with this line I get the error "Error in foreach(k = 2:(30/n.cores - 1), .export = var.shared, .packages = library.shared) : .packages must be a character vector"
– Michael
Nov 8 at 4:35
if the package name is LDA then library.shared <- "LDA". For ldaOut you need to initialize this variable with the object (but empty) as return the function LDA.
– gc_
Nov 8 at 6:07
gc_, the package name is "topicmodels", so i did the following "library.shared <- "topicmodels", and "ldaOut <- c()". With these modifications, I've been able to run the code without any errors, but R is using only 15-17 % of my CPU. There are 15 processes "R for windows front-end" using 0% and 1 using 16%.
– Michael
Nov 8 at 17:11
thank you! I've tried this code, but got an error as shown above. It seems like the loop can't find the LDA function. Am I doing something wrong?
– Michael
Nov 8 at 4:08
thank you! I've tried this code, but got an error as shown above. It seems like the loop can't find the LDA function. Am I doing something wrong?
– Michael
Nov 8 at 4:08
Have you specified the library of the LDA function in library.shared?
– gc_
Nov 8 at 4:11
Have you specified the library of the LDA function in library.shared?
– gc_
Nov 8 at 4:11
ok, i think i didin,t, so now I changed from "ldaOut <- #Init the output#" to "library.shared <- LDA", did i understand you correctly? with this line I get the error "Error in foreach(k = 2:(30/n.cores - 1), .export = var.shared, .packages = library.shared) : .packages must be a character vector"
– Michael
Nov 8 at 4:35
ok, i think i didin,t, so now I changed from "ldaOut <- #Init the output#" to "library.shared <- LDA", did i understand you correctly? with this line I get the error "Error in foreach(k = 2:(30/n.cores - 1), .export = var.shared, .packages = library.shared) : .packages must be a character vector"
– Michael
Nov 8 at 4:35
if the package name is LDA then library.shared <- "LDA". For ldaOut you need to initialize this variable with the object (but empty) as return the function LDA.
– gc_
Nov 8 at 6:07
if the package name is LDA then library.shared <- "LDA". For ldaOut you need to initialize this variable with the object (but empty) as return the function LDA.
– gc_
Nov 8 at 6:07
gc_, the package name is "topicmodels", so i did the following "library.shared <- "topicmodels", and "ldaOut <- c()". With these modifications, I've been able to run the code without any errors, but R is using only 15-17 % of my CPU. There are 15 processes "R for windows front-end" using 0% and 1 using 16%.
– Michael
Nov 8 at 17:11
gc_, the package name is "topicmodels", so i did the following "library.shared <- "topicmodels", and "ldaOut <- c()". With these modifications, I've been able to run the code without any errors, but R is using only 15-17 % of my CPU. There are 15 processes "R for windows front-end" using 0% and 1 using 16%.
– Michael
Nov 8 at 17:11
add a comment |
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cran.r-project.org/web/views/HighPerformanceComputing.html
– r2evans
Nov 8 at 2:30
Have you tried text2vec package for topic model? It is faster. Please see below links:text2vec.org/topic_modeling.html and stackoverflow.com/questions/52268925/…
– Sam S
Nov 13 at 23:24