Dart indexWhere performance












1














I want to search index where fb3 is.

I have two options indexA and indexB like so.

Is there any performance differences like A is faster than B or vice versa?

Is there any better way to search fb3?



class Foo {
String id; //unique
int number;
Foo(this.id, this.number);
}

class Bar {
String id; //unique
int number;
Bar(this.id, this.number);
}

class FooBar {
Foo foo;
Bar bar;
FooBar(this.foo, this.bar);
}

void main() {
final Foo f = Foo('First Id', 18);
final Bar b = Bar('Second Id', 81);
final FooBar fb = FooBar(f, b);

final Foo f2 = Foo('Third Id', 900);
final Bar b2 = Bar('Fourth Id', 009);
final FooBar fb2 = FooBar(f2, b2);

final Foo f3 = Foo('Fifth Id', 789);
final Bar b3 = Bar('Sixth Id', 987);
final FooBar fb3 = FooBar(f3, b3);

final Foo f4 = Foo('Seventh Id', 222);
final Bar b4 = Bar('Eighth Id', 666);
final FooBar fb4 = FooBar(f4, b4);

final List<FooBar> fbs = [fb, fb2, fb3, fb4];

final int indexA = fbs.indexWhere((FooBar fb) => fb.foo.id == fb3.foo.id && fb.bar.id == fb3.bar.id);
final int indexB = fbs.indexWhere((FooBar fb) => fb == fb3);

}









share|improve this question



























    1














    I want to search index where fb3 is.

    I have two options indexA and indexB like so.

    Is there any performance differences like A is faster than B or vice versa?

    Is there any better way to search fb3?



    class Foo {
    String id; //unique
    int number;
    Foo(this.id, this.number);
    }

    class Bar {
    String id; //unique
    int number;
    Bar(this.id, this.number);
    }

    class FooBar {
    Foo foo;
    Bar bar;
    FooBar(this.foo, this.bar);
    }

    void main() {
    final Foo f = Foo('First Id', 18);
    final Bar b = Bar('Second Id', 81);
    final FooBar fb = FooBar(f, b);

    final Foo f2 = Foo('Third Id', 900);
    final Bar b2 = Bar('Fourth Id', 009);
    final FooBar fb2 = FooBar(f2, b2);

    final Foo f3 = Foo('Fifth Id', 789);
    final Bar b3 = Bar('Sixth Id', 987);
    final FooBar fb3 = FooBar(f3, b3);

    final Foo f4 = Foo('Seventh Id', 222);
    final Bar b4 = Bar('Eighth Id', 666);
    final FooBar fb4 = FooBar(f4, b4);

    final List<FooBar> fbs = [fb, fb2, fb3, fb4];

    final int indexA = fbs.indexWhere((FooBar fb) => fb.foo.id == fb3.foo.id && fb.bar.id == fb3.bar.id);
    final int indexB = fbs.indexWhere((FooBar fb) => fb == fb3);

    }









    share|improve this question

























      1












      1








      1







      I want to search index where fb3 is.

      I have two options indexA and indexB like so.

      Is there any performance differences like A is faster than B or vice versa?

      Is there any better way to search fb3?



      class Foo {
      String id; //unique
      int number;
      Foo(this.id, this.number);
      }

      class Bar {
      String id; //unique
      int number;
      Bar(this.id, this.number);
      }

      class FooBar {
      Foo foo;
      Bar bar;
      FooBar(this.foo, this.bar);
      }

      void main() {
      final Foo f = Foo('First Id', 18);
      final Bar b = Bar('Second Id', 81);
      final FooBar fb = FooBar(f, b);

      final Foo f2 = Foo('Third Id', 900);
      final Bar b2 = Bar('Fourth Id', 009);
      final FooBar fb2 = FooBar(f2, b2);

      final Foo f3 = Foo('Fifth Id', 789);
      final Bar b3 = Bar('Sixth Id', 987);
      final FooBar fb3 = FooBar(f3, b3);

      final Foo f4 = Foo('Seventh Id', 222);
      final Bar b4 = Bar('Eighth Id', 666);
      final FooBar fb4 = FooBar(f4, b4);

      final List<FooBar> fbs = [fb, fb2, fb3, fb4];

      final int indexA = fbs.indexWhere((FooBar fb) => fb.foo.id == fb3.foo.id && fb.bar.id == fb3.bar.id);
      final int indexB = fbs.indexWhere((FooBar fb) => fb == fb3);

      }









      share|improve this question













      I want to search index where fb3 is.

      I have two options indexA and indexB like so.

      Is there any performance differences like A is faster than B or vice versa?

      Is there any better way to search fb3?



      class Foo {
      String id; //unique
      int number;
      Foo(this.id, this.number);
      }

      class Bar {
      String id; //unique
      int number;
      Bar(this.id, this.number);
      }

      class FooBar {
      Foo foo;
      Bar bar;
      FooBar(this.foo, this.bar);
      }

      void main() {
      final Foo f = Foo('First Id', 18);
      final Bar b = Bar('Second Id', 81);
      final FooBar fb = FooBar(f, b);

      final Foo f2 = Foo('Third Id', 900);
      final Bar b2 = Bar('Fourth Id', 009);
      final FooBar fb2 = FooBar(f2, b2);

      final Foo f3 = Foo('Fifth Id', 789);
      final Bar b3 = Bar('Sixth Id', 987);
      final FooBar fb3 = FooBar(f3, b3);

      final Foo f4 = Foo('Seventh Id', 222);
      final Bar b4 = Bar('Eighth Id', 666);
      final FooBar fb4 = FooBar(f4, b4);

      final List<FooBar> fbs = [fb, fb2, fb3, fb4];

      final int indexA = fbs.indexWhere((FooBar fb) => fb.foo.id == fb3.foo.id && fb.bar.id == fb3.bar.id);
      final int indexB = fbs.indexWhere((FooBar fb) => fb == fb3);

      }






      dart






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      share|improve this question










      asked Nov 13 '18 at 1:22









      TwoSanTwoSan

      246111




      246111
























          1 Answer
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          oldest

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          1














          If Foo, Bar, and FooBar do not implement operator== and get hashCode then indexB will only find identical instances.



          var a = Foo('Fifth Id', 789);
          var b = Foo('Fifth Id', 789);
          var c = a;
          print(a == b); // false
          print(a == c); // true


          See also How does a set determine that two objects are equal in dart?



          There won't be any performance difference worth mentioning if operator == is implemented. If you actually only want to find identicial instances then indexB would be faster, but then it would be better to use



          (FooBar fb) => identical(fb, fb3)





          share|improve this answer





















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            1 Answer
            1






            active

            oldest

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            active

            oldest

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            active

            oldest

            votes









            1














            If Foo, Bar, and FooBar do not implement operator== and get hashCode then indexB will only find identical instances.



            var a = Foo('Fifth Id', 789);
            var b = Foo('Fifth Id', 789);
            var c = a;
            print(a == b); // false
            print(a == c); // true


            See also How does a set determine that two objects are equal in dart?



            There won't be any performance difference worth mentioning if operator == is implemented. If you actually only want to find identicial instances then indexB would be faster, but then it would be better to use



            (FooBar fb) => identical(fb, fb3)





            share|improve this answer


























              1














              If Foo, Bar, and FooBar do not implement operator== and get hashCode then indexB will only find identical instances.



              var a = Foo('Fifth Id', 789);
              var b = Foo('Fifth Id', 789);
              var c = a;
              print(a == b); // false
              print(a == c); // true


              See also How does a set determine that two objects are equal in dart?



              There won't be any performance difference worth mentioning if operator == is implemented. If you actually only want to find identicial instances then indexB would be faster, but then it would be better to use



              (FooBar fb) => identical(fb, fb3)





              share|improve this answer
























                1












                1








                1






                If Foo, Bar, and FooBar do not implement operator== and get hashCode then indexB will only find identical instances.



                var a = Foo('Fifth Id', 789);
                var b = Foo('Fifth Id', 789);
                var c = a;
                print(a == b); // false
                print(a == c); // true


                See also How does a set determine that two objects are equal in dart?



                There won't be any performance difference worth mentioning if operator == is implemented. If you actually only want to find identicial instances then indexB would be faster, but then it would be better to use



                (FooBar fb) => identical(fb, fb3)





                share|improve this answer












                If Foo, Bar, and FooBar do not implement operator== and get hashCode then indexB will only find identical instances.



                var a = Foo('Fifth Id', 789);
                var b = Foo('Fifth Id', 789);
                var c = a;
                print(a == b); // false
                print(a == c); // true


                See also How does a set determine that two objects are equal in dart?



                There won't be any performance difference worth mentioning if operator == is implemented. If you actually only want to find identicial instances then indexB would be faster, but then it would be better to use



                (FooBar fb) => identical(fb, fb3)






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 13 '18 at 6:48









                Günter ZöchbauerGünter Zöchbauer

                316k66935881




                316k66935881






























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