PHP - preg_replace - use other substitution if the current one is empty
I have this preg_replace
preg_replace('/[link=(.*?)](.*?)[/link]/', '<a href="1">2</a>', $input);
For this data
$input = "[link=xxx]xxx[/link] [link=yyy][/link]"
it produces:
<a href="xxx">xxx</a> <a href="yyy"></a>
However, I would like the result to be
<a href="xxx">xxx</a> <a href="yyy">yyy</a>
Can I somehow use 2 and if the string is empty, use 1 instead in preg_replace replacement? I dont want to use callback version of preg_replace.
php regex preg-replace
asked Nov 11 at 10:38
Martin Perry
5,07322964
add a comment |
I have this preg_replace
preg_replace('/[link=(.*?)](.*?)[/link]/', '<a href="1">2</a>', $input);
For this data
$input = "[link=xxx]xxx[/link] [link=yyy][/link]"
it produces:
<a href="xxx">xxx</a> <a href="yyy"></a>
However, I would like the result to be
<a href="xxx">xxx</a> <a href="yyy">yyy</a>
Can I somehow use 2 and if the string is empty, use 1 instead in preg_replace replacement? I dont want to use callback version of preg_replace.
php regex preg-replace
asked Nov 11 at 10:38
Martin Perry
5,07322964
1
Not to belabour the same thing over and over again, but you should avoid parsing HTML using regex.
– Tim Biegeleisen
Nov 11 at 10:49
1
You'll have to usepreg_replace_callback. The replacement does not support expressions, and the regex can't set a single capture group to either or.
– mario
Nov 11 at 10:58
add a comment |
I have this preg_replace
preg_replace('/[link=(.*?)](.*?)[/link]/', '<a href="1">2</a>', $input);
For this data
$input = "[link=xxx]xxx[/link] [link=yyy][/link]"
it produces:
<a href="xxx">xxx</a> <a href="yyy"></a>
However, I would like the result to be
<a href="xxx">xxx</a> <a href="yyy">yyy</a>
Can I somehow use 2 and if the string is empty, use 1 instead in preg_replace replacement? I dont want to use callback version of preg_replace.
php regex preg-replace
asked Nov 11 at 10:38
Martin Perry
5,07322964
I have this preg_replace
preg_replace('/[link=(.*?)](.*?)[/link]/', '<a href="1">2</a>', $input);
For this data
$input = "[link=xxx]xxx[/link] [link=yyy][/link]"
it produces:
<a href="xxx">xxx</a> <a href="yyy"></a>
However, I would like the result to be
<a href="xxx">xxx</a> <a href="yyy">yyy</a>
Can I somehow use 2 and if the string is empty, use 1 instead in preg_replace replacement? I dont want to use callback version of preg_replace.
php regex preg-replace
php regex preg-replace
asked Nov 11 at 10:38
Martin Perry
5,07322964
asked Nov 11 at 10:38
Martin Perry
5,07322964
asked Nov 11 at 10:38
Martin Perry
5,07322964
asked Nov 11 at 10:38
Martin Perry
5,07322964
asked Nov 11 at 10:38
Martin Perry
5,07322964
5,07322964
1
Not to belabour the same thing over and over again, but you should avoid parsing HTML using regex.
– Tim Biegeleisen
Nov 11 at 10:49
1
You'll have to usepreg_replace_callback. The replacement does not support expressions, and the regex can't set a single capture group to either or.
– mario
Nov 11 at 10:58
add a comment |
1
Not to belabour the same thing over and over again, but you should avoid parsing HTML using regex.
– Tim Biegeleisen
Nov 11 at 10:49
1
You'll have to usepreg_replace_callback. The replacement does not support expressions, and the regex can't set a single capture group to either or.
– mario
Nov 11 at 10:58
1
1
Not to belabour the same thing over and over again, but you should avoid parsing HTML using regex.
– Tim Biegeleisen
Nov 11 at 10:49
Not to belabour the same thing over and over again, but you should avoid parsing HTML using regex.
– Tim Biegeleisen
Nov 11 at 10:49
1
1
You'll have to use
preg_replace_callback. The replacement does not support expressions, and the regex can't set a single capture group to either or.– mario
Nov 11 at 10:58
You'll have to use
preg_replace_callback. The replacement does not support expressions, and the regex can't set a single capture group to either or.– mario
Nov 11 at 10:58
add a comment |
1 Answer
1
active
oldest
votes
As @mario pointed out, you need to use preg_replace_callback for a problem like this. Inside the callback you can check if there is a second group match, and if not, repeat the first match inside the <a> element:
$input = "[link=xxx]xxx[/link] [link=yyy][/link]";
echo preg_replace_callback('/[link=(.*?)](.*?)[/link]/',
function ($m) {
return "<a href="$m[1]">" . (strlen($m[2]) ? $m[2] : $m[1]) . '</a>';
},
$input);
Output
<a href="xxx">xxx</a> <a href="yyy">yyy</a>
Demo on 3v4l.org
answered Nov 11 at 11:16
Nick
22.9k81535
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
As @mario pointed out, you need to use preg_replace_callback for a problem like this. Inside the callback you can check if there is a second group match, and if not, repeat the first match inside the <a> element:
$input = "[link=xxx]xxx[/link] [link=yyy][/link]";
echo preg_replace_callback('/[link=(.*?)](.*?)[/link]/',
function ($m) {
return "<a href="$m[1]">" . (strlen($m[2]) ? $m[2] : $m[1]) . '</a>';
},
$input);
Output
<a href="xxx">xxx</a> <a href="yyy">yyy</a>
Demo on 3v4l.org
answered Nov 11 at 11:16
Nick
22.9k81535
add a comment |
As @mario pointed out, you need to use preg_replace_callback for a problem like this. Inside the callback you can check if there is a second group match, and if not, repeat the first match inside the <a> element:
$input = "[link=xxx]xxx[/link] [link=yyy][/link]";
echo preg_replace_callback('/[link=(.*?)](.*?)[/link]/',
function ($m) {
return "<a href="$m[1]">" . (strlen($m[2]) ? $m[2] : $m[1]) . '</a>';
},
$input);
Output
<a href="xxx">xxx</a> <a href="yyy">yyy</a>
Demo on 3v4l.org
answered Nov 11 at 11:16
Nick
22.9k81535
add a comment |
As @mario pointed out, you need to use preg_replace_callback for a problem like this. Inside the callback you can check if there is a second group match, and if not, repeat the first match inside the <a> element:
$input = "[link=xxx]xxx[/link] [link=yyy][/link]";
echo preg_replace_callback('/[link=(.*?)](.*?)[/link]/',
function ($m) {
return "<a href="$m[1]">" . (strlen($m[2]) ? $m[2] : $m[1]) . '</a>';
},
$input);
Output
<a href="xxx">xxx</a> <a href="yyy">yyy</a>
Demo on 3v4l.org
answered Nov 11 at 11:16
Nick
22.9k81535
As @mario pointed out, you need to use preg_replace_callback for a problem like this. Inside the callback you can check if there is a second group match, and if not, repeat the first match inside the <a> element:
$input = "[link=xxx]xxx[/link] [link=yyy][/link]";
echo preg_replace_callback('/[link=(.*?)](.*?)[/link]/',
function ($m) {
return "<a href="$m[1]">" . (strlen($m[2]) ? $m[2] : $m[1]) . '</a>';
},
$input);
Output
<a href="xxx">xxx</a> <a href="yyy">yyy</a>
Demo on 3v4l.org
answered Nov 11 at 11:16
Nick
22.9k81535
answered Nov 11 at 11:16
Nick
22.9k81535
answered Nov 11 at 11:16
Nick
22.9k81535
answered Nov 11 at 11:16
Nick
22.9k81535
22.9k81535
add a comment |
add a comment |
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1
Not to belabour the same thing over and over again, but you should avoid parsing HTML using regex.
– Tim Biegeleisen
Nov 11 at 10:49
1
You'll have to use
preg_replace_callback. The replacement does not support expressions, and the regex can't set a single capture group to either or.– mario
Nov 11 at 10:58