How to use re.sub
I want to modify the string test, to only have "TEXT" left. Therefor everything after "TEXT" is deleted. I figured that out. But how do I use re.sub to cut everything before "TEXT"? I only want to use " 265" and "159 " as criteria to determine when to delete.
test = "314 159 TEXT 265 357"
test = re.sub(r' 265.*$', '', test)
print(test)
The Output should be "TEXT"
python
asked Nov 14 '18 at 18:16
F.Ima F.Ima
82
|
show 2 more comments
I want to modify the string test, to only have "TEXT" left. Therefor everything after "TEXT" is deleted. I figured that out. But how do I use re.sub to cut everything before "TEXT"? I only want to use " 265" and "159 " as criteria to determine when to delete.
test = "314 159 TEXT 265 357"
test = re.sub(r' 265.*$', '', test)
print(test)
The Output should be "TEXT"
python
asked Nov 14 '18 at 18:16
F.Ima F.Ima
82
What is the expected output? Unclear: " I only want to use " 265" and "159 " as criteria...".
– Austin
Nov 14 '18 at 18:18
Possible duplicate of Stripping everything but alphanumeric chars from a string in Python
– l'L'l
Nov 14 '18 at 18:19
...test = ''.join(x for x in test if x.isalpha())...
– l'L'l
Nov 14 '18 at 18:21
the same way I used ' 265' in re.sub; The Output should be "TEXT"
– F.Ima
Nov 14 '18 at 18:23
Why do you want to do this withre.sub? It seems like the wrong tool for the job;re.searchwould be more appropriate.
– user2357112
Nov 14 '18 at 18:28
|
show 2 more comments
I want to modify the string test, to only have "TEXT" left. Therefor everything after "TEXT" is deleted. I figured that out. But how do I use re.sub to cut everything before "TEXT"? I only want to use " 265" and "159 " as criteria to determine when to delete.
test = "314 159 TEXT 265 357"
test = re.sub(r' 265.*$', '', test)
print(test)
The Output should be "TEXT"
python
asked Nov 14 '18 at 18:16
F.Ima F.Ima
82
I want to modify the string test, to only have "TEXT" left. Therefor everything after "TEXT" is deleted. I figured that out. But how do I use re.sub to cut everything before "TEXT"? I only want to use " 265" and "159 " as criteria to determine when to delete.
test = "314 159 TEXT 265 357"
test = re.sub(r' 265.*$', '', test)
print(test)
The Output should be "TEXT"
python
python
asked Nov 14 '18 at 18:16
F.Ima F.Ima
82
asked Nov 14 '18 at 18:16
F.Ima F.Ima
82
edited Nov 14 '18 at 18:25
F.Ima
asked Nov 14 '18 at 18:16
F.Ima F.Ima
82
asked Nov 14 '18 at 18:16
F.Ima F.Ima
82
asked Nov 14 '18 at 18:16
F.Ima F.Ima
82
82
What is the expected output? Unclear: " I only want to use " 265" and "159 " as criteria...".
– Austin
Nov 14 '18 at 18:18
Possible duplicate of Stripping everything but alphanumeric chars from a string in Python
– l'L'l
Nov 14 '18 at 18:19
...test = ''.join(x for x in test if x.isalpha())...
– l'L'l
Nov 14 '18 at 18:21
the same way I used ' 265' in re.sub; The Output should be "TEXT"
– F.Ima
Nov 14 '18 at 18:23
Why do you want to do this withre.sub? It seems like the wrong tool for the job;re.searchwould be more appropriate.
– user2357112
Nov 14 '18 at 18:28
|
show 2 more comments
What is the expected output? Unclear: " I only want to use " 265" and "159 " as criteria...".
– Austin
Nov 14 '18 at 18:18
Possible duplicate of Stripping everything but alphanumeric chars from a string in Python
– l'L'l
Nov 14 '18 at 18:19
...test = ''.join(x for x in test if x.isalpha())...
– l'L'l
Nov 14 '18 at 18:21
the same way I used ' 265' in re.sub; The Output should be "TEXT"
– F.Ima
Nov 14 '18 at 18:23
Why do you want to do this withre.sub? It seems like the wrong tool for the job;re.searchwould be more appropriate.
– user2357112
Nov 14 '18 at 18:28
What is the expected output? Unclear: " I only want to use " 265" and "159 " as criteria...".
– Austin
Nov 14 '18 at 18:18
What is the expected output? Unclear: " I only want to use " 265" and "159 " as criteria...".
– Austin
Nov 14 '18 at 18:18
Possible duplicate of Stripping everything but alphanumeric chars from a string in Python
– l'L'l
Nov 14 '18 at 18:19
Possible duplicate of Stripping everything but alphanumeric chars from a string in Python
– l'L'l
Nov 14 '18 at 18:19
...
test = ''.join(x for x in test if x.isalpha())...– l'L'l
Nov 14 '18 at 18:21
...
test = ''.join(x for x in test if x.isalpha())...– l'L'l
Nov 14 '18 at 18:21
the same way I used ' 265' in re.sub; The Output should be "TEXT"
– F.Ima
Nov 14 '18 at 18:23
the same way I used ' 265' in re.sub; The Output should be "TEXT"
– F.Ima
Nov 14 '18 at 18:23
Why do you want to do this with
re.sub? It seems like the wrong tool for the job; re.search would be more appropriate.– user2357112
Nov 14 '18 at 18:28
Why do you want to do this with
re.sub? It seems like the wrong tool for the job; re.search would be more appropriate.– user2357112
Nov 14 '18 at 18:28
|
show 2 more comments
1 Answer
1
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oldest
votes
Use a similar pattern as you did for subbing the end, and string them together.:
test = re.sub(r'.* 159 ', '', re.sub(r' 265.*$', '', test))
Alternatively, you could do it with a single pattern and re.findall:
test = re.findall(r'^.*159 ([A-Z]+) 265.*$', test)
answered Nov 14 '18 at 18:27
TimTim
1,759620
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Use a similar pattern as you did for subbing the end, and string them together.:
test = re.sub(r'.* 159 ', '', re.sub(r' 265.*$', '', test))
Alternatively, you could do it with a single pattern and re.findall:
test = re.findall(r'^.*159 ([A-Z]+) 265.*$', test)
answered Nov 14 '18 at 18:27
TimTim
1,759620
add a comment |
Use a similar pattern as you did for subbing the end, and string them together.:
test = re.sub(r'.* 159 ', '', re.sub(r' 265.*$', '', test))
Alternatively, you could do it with a single pattern and re.findall:
test = re.findall(r'^.*159 ([A-Z]+) 265.*$', test)
answered Nov 14 '18 at 18:27
TimTim
1,759620
add a comment |
Use a similar pattern as you did for subbing the end, and string them together.:
test = re.sub(r'.* 159 ', '', re.sub(r' 265.*$', '', test))
Alternatively, you could do it with a single pattern and re.findall:
test = re.findall(r'^.*159 ([A-Z]+) 265.*$', test)
answered Nov 14 '18 at 18:27
TimTim
1,759620
Use a similar pattern as you did for subbing the end, and string them together.:
test = re.sub(r'.* 159 ', '', re.sub(r' 265.*$', '', test))
Alternatively, you could do it with a single pattern and re.findall:
test = re.findall(r'^.*159 ([A-Z]+) 265.*$', test)
answered Nov 14 '18 at 18:27
TimTim
1,759620
answered Nov 14 '18 at 18:27
TimTim
1,759620
answered Nov 14 '18 at 18:27
TimTim
1,759620
answered Nov 14 '18 at 18:27
TimTim
1,759620
1,759620
add a comment |
add a comment |
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What is the expected output? Unclear: " I only want to use " 265" and "159 " as criteria...".
– Austin
Nov 14 '18 at 18:18
Possible duplicate of Stripping everything but alphanumeric chars from a string in Python
– l'L'l
Nov 14 '18 at 18:19
...
test = ''.join(x for x in test if x.isalpha())...– l'L'l
Nov 14 '18 at 18:21
the same way I used ' 265' in re.sub; The Output should be "TEXT"
– F.Ima
Nov 14 '18 at 18:23
Why do you want to do this with
re.sub? It seems like the wrong tool for the job;re.searchwould be more appropriate.– user2357112
Nov 14 '18 at 18:28