Increment value and save back to the file
I have a simple JSON file like this,
{
...
"version": "2.1.0",
"buildNumber": 83
}
I want to simply increment the buildNumber by one in the file. Rest of the content should remain as is.
What I have come up with so far is bellow.
jq -e '.buildNumber + 1' 'package.json' > 'package.json.tmp' && cp 'package.json.tmp' 'package.json'
But after running the script I'm only left with the updated value in the package.json file, which is just 84. The rest of the content is gone. How do I fix this?
json increment jq
add a comment |
I have a simple JSON file like this,
{
...
"version": "2.1.0",
"buildNumber": 83
}
I want to simply increment the buildNumber by one in the file. Rest of the content should remain as is.
What I have come up with so far is bellow.
jq -e '.buildNumber + 1' 'package.json' > 'package.json.tmp' && cp 'package.json.tmp' 'package.json'
But after running the script I'm only left with the updated value in the package.json file, which is just 84. The rest of the content is gone. How do I fix this?
json increment jq
add a comment |
I have a simple JSON file like this,
{
...
"version": "2.1.0",
"buildNumber": 83
}
I want to simply increment the buildNumber by one in the file. Rest of the content should remain as is.
What I have come up with so far is bellow.
jq -e '.buildNumber + 1' 'package.json' > 'package.json.tmp' && cp 'package.json.tmp' 'package.json'
But after running the script I'm only left with the updated value in the package.json file, which is just 84. The rest of the content is gone. How do I fix this?
json increment jq
I have a simple JSON file like this,
{
...
"version": "2.1.0",
"buildNumber": 83
}
I want to simply increment the buildNumber by one in the file. Rest of the content should remain as is.
What I have come up with so far is bellow.
jq -e '.buildNumber + 1' 'package.json' > 'package.json.tmp' && cp 'package.json.tmp' 'package.json'
But after running the script I'm only left with the updated value in the package.json file, which is just 84. The rest of the content is gone. How do I fix this?
json increment jq
json increment jq
edited Nov 27 '18 at 4:13
peak
33.2k94160
33.2k94160
asked Nov 21 '18 at 7:07
JanithaRJanithaR
6741918
6741918
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
First, the filter to use is:
.buildNumber += 1
Second, as you evidently realize, it would be unwise to use > to overwrite the file. One option to consider if it’s admissible would be to use coreutil’s sponge
. Another would be to rename the input file first.
I just found out about jq a couple of hours ago and I'm not quite familiar with bash every since I learned the basics of it like 8 years ago. I was under the impression that by doingjq '.buildNumber + 1' 'package.json'
the full contents of the file would be in memory including the modification. And so I was simply writing that content to a temp file and the evidently replacing the original file with the temp file contents. Am I understanding how jq works wrong?
– JanithaR
Nov 21 '18 at 7:24
uYes, that is incorrect. As you can easily check, .buildnumber + 1 adds 1 to .buildnumber, yielding an integer.
– peak
Nov 21 '18 at 7:28
So what I'm passing on to the package.json.temp file is simply that value, which in this case just 84. So if I usecurl
and read the full content of the file and then dojq '.buildNumber += 1' 'package.json'
and then carry on as is, that would give me the ouput I'm expecting yes?
– JanithaR
Nov 21 '18 at 7:38
add a comment |
I just put the two commands as bellow in two lines and it worked just as I wanted.
jq '.buildNumber += 1' 'package.json' > 'package.json.tmp'
cp 'package.json.tmp' 'package.json'
A safer variation would be along the lines of:mv package.json package.json.bak && jq ... < package.json.bak > package.json
; that way, the original file contents should not be lost under any circumstances.
– peak
Nov 27 '18 at 4:18
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
First, the filter to use is:
.buildNumber += 1
Second, as you evidently realize, it would be unwise to use > to overwrite the file. One option to consider if it’s admissible would be to use coreutil’s sponge
. Another would be to rename the input file first.
I just found out about jq a couple of hours ago and I'm not quite familiar with bash every since I learned the basics of it like 8 years ago. I was under the impression that by doingjq '.buildNumber + 1' 'package.json'
the full contents of the file would be in memory including the modification. And so I was simply writing that content to a temp file and the evidently replacing the original file with the temp file contents. Am I understanding how jq works wrong?
– JanithaR
Nov 21 '18 at 7:24
uYes, that is incorrect. As you can easily check, .buildnumber + 1 adds 1 to .buildnumber, yielding an integer.
– peak
Nov 21 '18 at 7:28
So what I'm passing on to the package.json.temp file is simply that value, which in this case just 84. So if I usecurl
and read the full content of the file and then dojq '.buildNumber += 1' 'package.json'
and then carry on as is, that would give me the ouput I'm expecting yes?
– JanithaR
Nov 21 '18 at 7:38
add a comment |
First, the filter to use is:
.buildNumber += 1
Second, as you evidently realize, it would be unwise to use > to overwrite the file. One option to consider if it’s admissible would be to use coreutil’s sponge
. Another would be to rename the input file first.
I just found out about jq a couple of hours ago and I'm not quite familiar with bash every since I learned the basics of it like 8 years ago. I was under the impression that by doingjq '.buildNumber + 1' 'package.json'
the full contents of the file would be in memory including the modification. And so I was simply writing that content to a temp file and the evidently replacing the original file with the temp file contents. Am I understanding how jq works wrong?
– JanithaR
Nov 21 '18 at 7:24
uYes, that is incorrect. As you can easily check, .buildnumber + 1 adds 1 to .buildnumber, yielding an integer.
– peak
Nov 21 '18 at 7:28
So what I'm passing on to the package.json.temp file is simply that value, which in this case just 84. So if I usecurl
and read the full content of the file and then dojq '.buildNumber += 1' 'package.json'
and then carry on as is, that would give me the ouput I'm expecting yes?
– JanithaR
Nov 21 '18 at 7:38
add a comment |
First, the filter to use is:
.buildNumber += 1
Second, as you evidently realize, it would be unwise to use > to overwrite the file. One option to consider if it’s admissible would be to use coreutil’s sponge
. Another would be to rename the input file first.
First, the filter to use is:
.buildNumber += 1
Second, as you evidently realize, it would be unwise to use > to overwrite the file. One option to consider if it’s admissible would be to use coreutil’s sponge
. Another would be to rename the input file first.
answered Nov 21 '18 at 7:14
peakpeak
33.2k94160
33.2k94160
I just found out about jq a couple of hours ago and I'm not quite familiar with bash every since I learned the basics of it like 8 years ago. I was under the impression that by doingjq '.buildNumber + 1' 'package.json'
the full contents of the file would be in memory including the modification. And so I was simply writing that content to a temp file and the evidently replacing the original file with the temp file contents. Am I understanding how jq works wrong?
– JanithaR
Nov 21 '18 at 7:24
uYes, that is incorrect. As you can easily check, .buildnumber + 1 adds 1 to .buildnumber, yielding an integer.
– peak
Nov 21 '18 at 7:28
So what I'm passing on to the package.json.temp file is simply that value, which in this case just 84. So if I usecurl
and read the full content of the file and then dojq '.buildNumber += 1' 'package.json'
and then carry on as is, that would give me the ouput I'm expecting yes?
– JanithaR
Nov 21 '18 at 7:38
add a comment |
I just found out about jq a couple of hours ago and I'm not quite familiar with bash every since I learned the basics of it like 8 years ago. I was under the impression that by doingjq '.buildNumber + 1' 'package.json'
the full contents of the file would be in memory including the modification. And so I was simply writing that content to a temp file and the evidently replacing the original file with the temp file contents. Am I understanding how jq works wrong?
– JanithaR
Nov 21 '18 at 7:24
uYes, that is incorrect. As you can easily check, .buildnumber + 1 adds 1 to .buildnumber, yielding an integer.
– peak
Nov 21 '18 at 7:28
So what I'm passing on to the package.json.temp file is simply that value, which in this case just 84. So if I usecurl
and read the full content of the file and then dojq '.buildNumber += 1' 'package.json'
and then carry on as is, that would give me the ouput I'm expecting yes?
– JanithaR
Nov 21 '18 at 7:38
I just found out about jq a couple of hours ago and I'm not quite familiar with bash every since I learned the basics of it like 8 years ago. I was under the impression that by doing
jq '.buildNumber + 1' 'package.json'
the full contents of the file would be in memory including the modification. And so I was simply writing that content to a temp file and the evidently replacing the original file with the temp file contents. Am I understanding how jq works wrong?– JanithaR
Nov 21 '18 at 7:24
I just found out about jq a couple of hours ago and I'm not quite familiar with bash every since I learned the basics of it like 8 years ago. I was under the impression that by doing
jq '.buildNumber + 1' 'package.json'
the full contents of the file would be in memory including the modification. And so I was simply writing that content to a temp file and the evidently replacing the original file with the temp file contents. Am I understanding how jq works wrong?– JanithaR
Nov 21 '18 at 7:24
uYes, that is incorrect. As you can easily check, .buildnumber + 1 adds 1 to .buildnumber, yielding an integer.
– peak
Nov 21 '18 at 7:28
uYes, that is incorrect. As you can easily check, .buildnumber + 1 adds 1 to .buildnumber, yielding an integer.
– peak
Nov 21 '18 at 7:28
So what I'm passing on to the package.json.temp file is simply that value, which in this case just 84. So if I use
curl
and read the full content of the file and then do jq '.buildNumber += 1' 'package.json'
and then carry on as is, that would give me the ouput I'm expecting yes?– JanithaR
Nov 21 '18 at 7:38
So what I'm passing on to the package.json.temp file is simply that value, which in this case just 84. So if I use
curl
and read the full content of the file and then do jq '.buildNumber += 1' 'package.json'
and then carry on as is, that would give me the ouput I'm expecting yes?– JanithaR
Nov 21 '18 at 7:38
add a comment |
I just put the two commands as bellow in two lines and it worked just as I wanted.
jq '.buildNumber += 1' 'package.json' > 'package.json.tmp'
cp 'package.json.tmp' 'package.json'
A safer variation would be along the lines of:mv package.json package.json.bak && jq ... < package.json.bak > package.json
; that way, the original file contents should not be lost under any circumstances.
– peak
Nov 27 '18 at 4:18
add a comment |
I just put the two commands as bellow in two lines and it worked just as I wanted.
jq '.buildNumber += 1' 'package.json' > 'package.json.tmp'
cp 'package.json.tmp' 'package.json'
A safer variation would be along the lines of:mv package.json package.json.bak && jq ... < package.json.bak > package.json
; that way, the original file contents should not be lost under any circumstances.
– peak
Nov 27 '18 at 4:18
add a comment |
I just put the two commands as bellow in two lines and it worked just as I wanted.
jq '.buildNumber += 1' 'package.json' > 'package.json.tmp'
cp 'package.json.tmp' 'package.json'
I just put the two commands as bellow in two lines and it worked just as I wanted.
jq '.buildNumber += 1' 'package.json' > 'package.json.tmp'
cp 'package.json.tmp' 'package.json'
answered Nov 22 '18 at 14:57
JanithaRJanithaR
6741918
6741918
A safer variation would be along the lines of:mv package.json package.json.bak && jq ... < package.json.bak > package.json
; that way, the original file contents should not be lost under any circumstances.
– peak
Nov 27 '18 at 4:18
add a comment |
A safer variation would be along the lines of:mv package.json package.json.bak && jq ... < package.json.bak > package.json
; that way, the original file contents should not be lost under any circumstances.
– peak
Nov 27 '18 at 4:18
A safer variation would be along the lines of:
mv package.json package.json.bak && jq ... < package.json.bak > package.json
; that way, the original file contents should not be lost under any circumstances.– peak
Nov 27 '18 at 4:18
A safer variation would be along the lines of:
mv package.json package.json.bak && jq ... < package.json.bak > package.json
; that way, the original file contents should not be lost under any circumstances.– peak
Nov 27 '18 at 4:18
add a comment |
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