calling function for all elements in sequence one at a time xquery
I am trying to call a function for every element in a sequence but I either get only one of the elements or all of them at the same time.
My sequence has the form $y = ("N","K")and I want to run my function with first the letter N and then the letter K.
My code is:
for $nr in 1 to count($y)
let $n := ($y)[$nr]
return local:checking($n)
But that loop never ends... which I think is because the $n that i send to the function is both "N" and "K".
Any ideas?
function for-loop xquery sequence
asked Nov 18 '18 at 9:16
SaraSara
223
add a comment |
I am trying to call a function for every element in a sequence but I either get only one of the elements or all of them at the same time.
My sequence has the form $y = ("N","K")and I want to run my function with first the letter N and then the letter K.
My code is:
for $nr in 1 to count($y)
let $n := ($y)[$nr]
return local:checking($n)
But that loop never ends... which I think is because the $n that i send to the function is both "N" and "K".
Any ideas?
function for-loop xquery sequence
asked Nov 18 '18 at 9:16
SaraSara
223
1
Your code looks fine, though it could be simplified tofor $yy in $y return local:checking($yy). Whatever is wrong, it's not the code you have shown us.
– Michael Kay
Nov 18 '18 at 19:13
With XQuery 3 you can also shorten that to$y ! local:checking(.), see the simplemapoperator w3.org/TR/xquery-31/#id-map-operator.
– Martin Honnen
Nov 19 '18 at 12:34
add a comment |
I am trying to call a function for every element in a sequence but I either get only one of the elements or all of them at the same time.
My sequence has the form $y = ("N","K")and I want to run my function with first the letter N and then the letter K.
My code is:
for $nr in 1 to count($y)
let $n := ($y)[$nr]
return local:checking($n)
But that loop never ends... which I think is because the $n that i send to the function is both "N" and "K".
Any ideas?
function for-loop xquery sequence
asked Nov 18 '18 at 9:16
SaraSara
223
I am trying to call a function for every element in a sequence but I either get only one of the elements or all of them at the same time.
My sequence has the form $y = ("N","K")and I want to run my function with first the letter N and then the letter K.
My code is:
for $nr in 1 to count($y)
let $n := ($y)[$nr]
return local:checking($n)
But that loop never ends... which I think is because the $n that i send to the function is both "N" and "K".
Any ideas?
function for-loop xquery sequence
function for-loop xquery sequence
asked Nov 18 '18 at 9:16
SaraSara
223
asked Nov 18 '18 at 9:16
SaraSara
223
edited Nov 18 '18 at 14:36
Sara
asked Nov 18 '18 at 9:16
SaraSara
223
asked Nov 18 '18 at 9:16
SaraSara
223
asked Nov 18 '18 at 9:16
SaraSara
223
223
1
Your code looks fine, though it could be simplified tofor $yy in $y return local:checking($yy). Whatever is wrong, it's not the code you have shown us.
– Michael Kay
Nov 18 '18 at 19:13
With XQuery 3 you can also shorten that to$y ! local:checking(.), see the simplemapoperator w3.org/TR/xquery-31/#id-map-operator.
– Martin Honnen
Nov 19 '18 at 12:34
add a comment |
1
Your code looks fine, though it could be simplified tofor $yy in $y return local:checking($yy). Whatever is wrong, it's not the code you have shown us.
– Michael Kay
Nov 18 '18 at 19:13
With XQuery 3 you can also shorten that to$y ! local:checking(.), see the simplemapoperator w3.org/TR/xquery-31/#id-map-operator.
– Martin Honnen
Nov 19 '18 at 12:34
1
1
Your code looks fine, though it could be simplified to
for $yy in $y return local:checking($yy). Whatever is wrong, it's not the code you have shown us.– Michael Kay
Nov 18 '18 at 19:13
Your code looks fine, though it could be simplified to
for $yy in $y return local:checking($yy). Whatever is wrong, it's not the code you have shown us.– Michael Kay
Nov 18 '18 at 19:13
With XQuery 3 you can also shorten that to
$y ! local:checking(.), see the simple map operator w3.org/TR/xquery-31/#id-map-operator.– Martin Honnen
Nov 19 '18 at 12:34
With XQuery 3 you can also shorten that to
$y ! local:checking(.), see the simple map operator w3.org/TR/xquery-31/#id-map-operator.– Martin Honnen
Nov 19 '18 at 12:34
add a comment |
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1
Your code looks fine, though it could be simplified to
for $yy in $y return local:checking($yy). Whatever is wrong, it's not the code you have shown us.– Michael Kay
Nov 18 '18 at 19:13
With XQuery 3 you can also shorten that to
$y ! local:checking(.), see the simplemapoperator w3.org/TR/xquery-31/#id-map-operator.– Martin Honnen
Nov 19 '18 at 12:34