Initialize 2d array with variable size












4















Using the following method:



myArray = [0,1] * NUM_ITEMS


Desired result (2d array):



[[0,1],[0,1],[0,1]...]


Actual result (extended 1d array):



[0,1,0,1,0,1...]


How can I achieve the desired result preferably without using numpy?






python multidimensional-array







share|improve this question


















  • 6





    Before someone suggests [[0, 1]]*NUM_ITEMS, no, that doesn't work, even if it looks like it does.

    – user2357112
    Nov 20 '18 at 22:09
















4















Using the following method:



myArray = [0,1] * NUM_ITEMS


Desired result (2d array):



[[0,1],[0,1],[0,1]...]


Actual result (extended 1d array):



[0,1,0,1,0,1...]


How can I achieve the desired result preferably without using numpy?






python multidimensional-array







share|improve this question


















  • 6





    Before someone suggests [[0, 1]]*NUM_ITEMS, no, that doesn't work, even if it looks like it does.

    – user2357112
    Nov 20 '18 at 22:09














4












4








4








Using the following method:



myArray = [0,1] * NUM_ITEMS


Desired result (2d array):



[[0,1],[0,1],[0,1]...]


Actual result (extended 1d array):



[0,1,0,1,0,1...]


How can I achieve the desired result preferably without using numpy?






python multidimensional-array







share|improve this question














Using the following method:



myArray = [0,1] * NUM_ITEMS


Desired result (2d array):



[[0,1],[0,1],[0,1]...]


Actual result (extended 1d array):



[0,1,0,1,0,1...]


How can I achieve the desired result preferably without using numpy?






python multidimensional-array




python multidimensional-array






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 20 '18 at 22:07









A__A__

4521518




4521518








  • 6





    Before someone suggests [[0, 1]]*NUM_ITEMS, no, that doesn't work, even if it looks like it does.

    – user2357112
    Nov 20 '18 at 22:09














  • 6





    Before someone suggests [[0, 1]]*NUM_ITEMS, no, that doesn't work, even if it looks like it does.

    – user2357112
    Nov 20 '18 at 22:09








6




6





Before someone suggests [[0, 1]]*NUM_ITEMS, no, that doesn't work, even if it looks like it does.

– user2357112
Nov 20 '18 at 22:09





Before someone suggests [[0, 1]]*NUM_ITEMS, no, that doesn't work, even if it looks like it does.

– user2357112
Nov 20 '18 at 22:09












2 Answers
2






active

oldest

votes


















5














A list comprehension should do the trick:



>>> NUM_ITEMS = 5

>>> my_array = [[0, 1] for _ in range(NUM_ITEMS)]

>>> my_array

[[0, 1], [0, 1], [0, 1], [0, 1], [0, 1]]





share|improve this answer
























  • Huh, interesting thanks.

    – A__
    Nov 20 '18 at 22:10



















1














Since you tagged arrays, here's an alternative numpy solution using numpy.tile.



>>> import numpy as np

>>> NUM_ITEMS = 10

>>> np.tile([0, 1], (NUM_ITEMS, 1))

array([[0, 1],

       [0, 1],

       [0, 1],

       [0, 1],

       [0, 1],

       [0, 1],

       [0, 1],

       [0, 1],

       [0, 1],

       [0, 1]])





share|improve this answer























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    2 Answers
    2






    active

    oldest

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    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    5














    A list comprehension should do the trick:



    >>> NUM_ITEMS = 5
    
>>> my_array = [[0, 1] for _ in range(NUM_ITEMS)]
    
>>> my_array
    
[[0, 1], [0, 1], [0, 1], [0, 1], [0, 1]]





    share|improve this answer
























    • Huh, interesting thanks.

      – A__
      Nov 20 '18 at 22:10
















    5














    A list comprehension should do the trick:



    >>> NUM_ITEMS = 5
    
>>> my_array = [[0, 1] for _ in range(NUM_ITEMS)]
    
>>> my_array
    
[[0, 1], [0, 1], [0, 1], [0, 1], [0, 1]]





    share|improve this answer
























    • Huh, interesting thanks.

      – A__
      Nov 20 '18 at 22:10














    5












    5








    5







    A list comprehension should do the trick:



    >>> NUM_ITEMS = 5
    
>>> my_array = [[0, 1] for _ in range(NUM_ITEMS)]
    
>>> my_array
    
[[0, 1], [0, 1], [0, 1], [0, 1], [0, 1]]





    share|improve this answer













    A list comprehension should do the trick:



    >>> NUM_ITEMS = 5
    
>>> my_array = [[0, 1] for _ in range(NUM_ITEMS)]
    
>>> my_array
    
[[0, 1], [0, 1], [0, 1], [0, 1], [0, 1]]






    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Nov 20 '18 at 22:08









    chrischris

    898814




    898814













    • Huh, interesting thanks.

      – A__
      Nov 20 '18 at 22:10



















    • Huh, interesting thanks.

      – A__
      Nov 20 '18 at 22:10

















    Huh, interesting thanks.

    – A__
    Nov 20 '18 at 22:10





    Huh, interesting thanks.

    – A__
    Nov 20 '18 at 22:10













    1














    Since you tagged arrays, here's an alternative numpy solution using numpy.tile.



    >>> import numpy as np
    
>>> NUM_ITEMS = 10
    
>>> np.tile([0, 1], (NUM_ITEMS, 1))
    
array([[0, 1],
    
       [0, 1],
    
       [0, 1],
    
       [0, 1],
    
       [0, 1],
    
       [0, 1],
    
       [0, 1],
    
       [0, 1],
    
       [0, 1],
    
       [0, 1]])





    share|improve this answer




























      1














      Since you tagged arrays, here's an alternative numpy solution using numpy.tile.



      >>> import numpy as np
      
>>> NUM_ITEMS = 10
      
>>> np.tile([0, 1], (NUM_ITEMS, 1))
      
array([[0, 1],
      
       [0, 1],
      
       [0, 1],
      
       [0, 1],
      
       [0, 1],
      
       [0, 1],
      
       [0, 1],
      
       [0, 1],
      
       [0, 1],
      
       [0, 1]])





      share|improve this answer


























        1












        1








        1







        Since you tagged arrays, here's an alternative numpy solution using numpy.tile.



        >>> import numpy as np
        
>>> NUM_ITEMS = 10
        
>>> np.tile([0, 1], (NUM_ITEMS, 1))
        
array([[0, 1],
        
       [0, 1],
        
       [0, 1],
        
       [0, 1],
        
       [0, 1],
        
       [0, 1],
        
       [0, 1],
        
       [0, 1],
        
       [0, 1],
        
       [0, 1]])





        share|improve this answer













        Since you tagged arrays, here's an alternative numpy solution using numpy.tile.



        >>> import numpy as np
        
>>> NUM_ITEMS = 10
        
>>> np.tile([0, 1], (NUM_ITEMS, 1))
        
array([[0, 1],
        
       [0, 1],
        
       [0, 1],
        
       [0, 1],
        
       [0, 1],
        
       [0, 1],
        
       [0, 1],
        
       [0, 1],
        
       [0, 1],
        
       [0, 1]])






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 20 '18 at 22:19









        timgebtimgeb

        51k116693




        51k116693






























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