Python: Not able to split the dates from csv file
I am trying to plot the dates and prices from a csv. However the dates.append()
function is throwing me an error. What can I do to solve this issue?
dates=
prices=
def getdata(filename):
with open(filename,'r') as csvfile:
csvFilereader=csv.reader(csvfile)
next(csvFilereader)
for row in csvFilereader:
dates.append(int(row[4].split('-')))
prices.append(float(row[2]))
return
def predicted_price(dates, prices, x):
dates=np.reshape(dates,len(dates),1)
svr_linear= SVR(kernel='linear', C=1e3)
svr_poly= SVR(kernel='poly', C=1e3, degree=2)
svr_rbf= SVR(kernel='rbf', C=1e3, gamma=0.1)
svr_linear.fir(dates,prices)
svr_ploy(dates,prices)
svr_rbf(dates,prices)
plt.scatter(dates,prices, color='black', label='Data')
plt.plot(dates, svr.rbf.predict(dates), color='red', label='RBF Model')
plt.plot(dates, svr.poly.predict(dates), color='blue', label='Poly Model')
plt.plot(dates, svr.linear.predict(dates), color='green', label='Linera Model')
plt.xlabel('Dates')
plt.ylabel('Prices')
plt.title('Regression')
plt.legend()
plt.show()
return svr_rbf.predict(x[4]), svr_linerar(x[4]), svr_poly(x[4])
getdata('D:\android\trans1.csv')
predicted_prices=predicted_price(dates,price,30)
print(predicted_prices)
Here is the error message.
TypeError Traceback (most recent call last)
<ipython-input-4-63df0e521768> in <module>()
35 return svr_rbf.predict(x[4]), svr_linerar(x[4]), svr_poly(x[4])
36
---> 37 getdata('D:\android\trans1.csv')
38
39 predicted_prices=predicted_price(dates,price,30)
<ipython-input-4-63df0e521768> in getdata(filename)
7 next(csvFilereader)
8 for row in csvFilereader:
----> 9 dates.append(int(row[4].split('-')))
10 prices.append(float(row[2]))
11 return
TypeError: int() argument must be a string, a bytes-like object or a number, not 'list
python
add a comment |
I am trying to plot the dates and prices from a csv. However the dates.append()
function is throwing me an error. What can I do to solve this issue?
dates=
prices=
def getdata(filename):
with open(filename,'r') as csvfile:
csvFilereader=csv.reader(csvfile)
next(csvFilereader)
for row in csvFilereader:
dates.append(int(row[4].split('-')))
prices.append(float(row[2]))
return
def predicted_price(dates, prices, x):
dates=np.reshape(dates,len(dates),1)
svr_linear= SVR(kernel='linear', C=1e3)
svr_poly= SVR(kernel='poly', C=1e3, degree=2)
svr_rbf= SVR(kernel='rbf', C=1e3, gamma=0.1)
svr_linear.fir(dates,prices)
svr_ploy(dates,prices)
svr_rbf(dates,prices)
plt.scatter(dates,prices, color='black', label='Data')
plt.plot(dates, svr.rbf.predict(dates), color='red', label='RBF Model')
plt.plot(dates, svr.poly.predict(dates), color='blue', label='Poly Model')
plt.plot(dates, svr.linear.predict(dates), color='green', label='Linera Model')
plt.xlabel('Dates')
plt.ylabel('Prices')
plt.title('Regression')
plt.legend()
plt.show()
return svr_rbf.predict(x[4]), svr_linerar(x[4]), svr_poly(x[4])
getdata('D:\android\trans1.csv')
predicted_prices=predicted_price(dates,price,30)
print(predicted_prices)
Here is the error message.
TypeError Traceback (most recent call last)
<ipython-input-4-63df0e521768> in <module>()
35 return svr_rbf.predict(x[4]), svr_linerar(x[4]), svr_poly(x[4])
36
---> 37 getdata('D:\android\trans1.csv')
38
39 predicted_prices=predicted_price(dates,price,30)
<ipython-input-4-63df0e521768> in getdata(filename)
7 next(csvFilereader)
8 for row in csvFilereader:
----> 9 dates.append(int(row[4].split('-')))
10 prices.append(float(row[2]))
11 return
TypeError: int() argument must be a string, a bytes-like object or a number, not 'list
python
Are you sure the data coming from your csv file is what you expect?
– Red Cricket
Nov 22 '18 at 6:28
add a comment |
I am trying to plot the dates and prices from a csv. However the dates.append()
function is throwing me an error. What can I do to solve this issue?
dates=
prices=
def getdata(filename):
with open(filename,'r') as csvfile:
csvFilereader=csv.reader(csvfile)
next(csvFilereader)
for row in csvFilereader:
dates.append(int(row[4].split('-')))
prices.append(float(row[2]))
return
def predicted_price(dates, prices, x):
dates=np.reshape(dates,len(dates),1)
svr_linear= SVR(kernel='linear', C=1e3)
svr_poly= SVR(kernel='poly', C=1e3, degree=2)
svr_rbf= SVR(kernel='rbf', C=1e3, gamma=0.1)
svr_linear.fir(dates,prices)
svr_ploy(dates,prices)
svr_rbf(dates,prices)
plt.scatter(dates,prices, color='black', label='Data')
plt.plot(dates, svr.rbf.predict(dates), color='red', label='RBF Model')
plt.plot(dates, svr.poly.predict(dates), color='blue', label='Poly Model')
plt.plot(dates, svr.linear.predict(dates), color='green', label='Linera Model')
plt.xlabel('Dates')
plt.ylabel('Prices')
plt.title('Regression')
plt.legend()
plt.show()
return svr_rbf.predict(x[4]), svr_linerar(x[4]), svr_poly(x[4])
getdata('D:\android\trans1.csv')
predicted_prices=predicted_price(dates,price,30)
print(predicted_prices)
Here is the error message.
TypeError Traceback (most recent call last)
<ipython-input-4-63df0e521768> in <module>()
35 return svr_rbf.predict(x[4]), svr_linerar(x[4]), svr_poly(x[4])
36
---> 37 getdata('D:\android\trans1.csv')
38
39 predicted_prices=predicted_price(dates,price,30)
<ipython-input-4-63df0e521768> in getdata(filename)
7 next(csvFilereader)
8 for row in csvFilereader:
----> 9 dates.append(int(row[4].split('-')))
10 prices.append(float(row[2]))
11 return
TypeError: int() argument must be a string, a bytes-like object or a number, not 'list
python
I am trying to plot the dates and prices from a csv. However the dates.append()
function is throwing me an error. What can I do to solve this issue?
dates=
prices=
def getdata(filename):
with open(filename,'r') as csvfile:
csvFilereader=csv.reader(csvfile)
next(csvFilereader)
for row in csvFilereader:
dates.append(int(row[4].split('-')))
prices.append(float(row[2]))
return
def predicted_price(dates, prices, x):
dates=np.reshape(dates,len(dates),1)
svr_linear= SVR(kernel='linear', C=1e3)
svr_poly= SVR(kernel='poly', C=1e3, degree=2)
svr_rbf= SVR(kernel='rbf', C=1e3, gamma=0.1)
svr_linear.fir(dates,prices)
svr_ploy(dates,prices)
svr_rbf(dates,prices)
plt.scatter(dates,prices, color='black', label='Data')
plt.plot(dates, svr.rbf.predict(dates), color='red', label='RBF Model')
plt.plot(dates, svr.poly.predict(dates), color='blue', label='Poly Model')
plt.plot(dates, svr.linear.predict(dates), color='green', label='Linera Model')
plt.xlabel('Dates')
plt.ylabel('Prices')
plt.title('Regression')
plt.legend()
plt.show()
return svr_rbf.predict(x[4]), svr_linerar(x[4]), svr_poly(x[4])
getdata('D:\android\trans1.csv')
predicted_prices=predicted_price(dates,price,30)
print(predicted_prices)
Here is the error message.
TypeError Traceback (most recent call last)
<ipython-input-4-63df0e521768> in <module>()
35 return svr_rbf.predict(x[4]), svr_linerar(x[4]), svr_poly(x[4])
36
---> 37 getdata('D:\android\trans1.csv')
38
39 predicted_prices=predicted_price(dates,price,30)
<ipython-input-4-63df0e521768> in getdata(filename)
7 next(csvFilereader)
8 for row in csvFilereader:
----> 9 dates.append(int(row[4].split('-')))
10 prices.append(float(row[2]))
11 return
TypeError: int() argument must be a string, a bytes-like object or a number, not 'list
python
python
edited Nov 22 '18 at 7:12
Milo Lu
1,65711628
1,65711628
asked Nov 22 '18 at 6:24
varun chauhanvarun chauhan
3910
3910
Are you sure the data coming from your csv file is what you expect?
– Red Cricket
Nov 22 '18 at 6:28
add a comment |
Are you sure the data coming from your csv file is what you expect?
– Red Cricket
Nov 22 '18 at 6:28
Are you sure the data coming from your csv file is what you expect?
– Red Cricket
Nov 22 '18 at 6:28
Are you sure the data coming from your csv file is what you expect?
– Red Cricket
Nov 22 '18 at 6:28
add a comment |
1 Answer
1
active
oldest
votes
Once you split
a string, you are returned a list, the error happens here:
def getdata(filename):
with open(filename,'r') as csvfile:
csvFilereader=csv.reader(csvfile)
next(csvFilereader)
for row in csvFilereader:
dates.append(int(row[4].split('-'))) <------------ here
prices.append(float(row[2]))
So instead of converting a string item to int
you are converting the results of your .split()
, which is a list to int
, which is not possible.
If you want to select a target result from your list, you can try with selecting a particular index from the results to test it out:
dates.append(int(row[4].split('-')[0]))
No problem and welcome to SO. If any of the answers here solved your question, kindly accept them as an answer by ticking the checkmark below the vote buttons on the left.
– BernardL
Nov 22 '18 at 7:01
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Once you split
a string, you are returned a list, the error happens here:
def getdata(filename):
with open(filename,'r') as csvfile:
csvFilereader=csv.reader(csvfile)
next(csvFilereader)
for row in csvFilereader:
dates.append(int(row[4].split('-'))) <------------ here
prices.append(float(row[2]))
So instead of converting a string item to int
you are converting the results of your .split()
, which is a list to int
, which is not possible.
If you want to select a target result from your list, you can try with selecting a particular index from the results to test it out:
dates.append(int(row[4].split('-')[0]))
No problem and welcome to SO. If any of the answers here solved your question, kindly accept them as an answer by ticking the checkmark below the vote buttons on the left.
– BernardL
Nov 22 '18 at 7:01
add a comment |
Once you split
a string, you are returned a list, the error happens here:
def getdata(filename):
with open(filename,'r') as csvfile:
csvFilereader=csv.reader(csvfile)
next(csvFilereader)
for row in csvFilereader:
dates.append(int(row[4].split('-'))) <------------ here
prices.append(float(row[2]))
So instead of converting a string item to int
you are converting the results of your .split()
, which is a list to int
, which is not possible.
If you want to select a target result from your list, you can try with selecting a particular index from the results to test it out:
dates.append(int(row[4].split('-')[0]))
No problem and welcome to SO. If any of the answers here solved your question, kindly accept them as an answer by ticking the checkmark below the vote buttons on the left.
– BernardL
Nov 22 '18 at 7:01
add a comment |
Once you split
a string, you are returned a list, the error happens here:
def getdata(filename):
with open(filename,'r') as csvfile:
csvFilereader=csv.reader(csvfile)
next(csvFilereader)
for row in csvFilereader:
dates.append(int(row[4].split('-'))) <------------ here
prices.append(float(row[2]))
So instead of converting a string item to int
you are converting the results of your .split()
, which is a list to int
, which is not possible.
If you want to select a target result from your list, you can try with selecting a particular index from the results to test it out:
dates.append(int(row[4].split('-')[0]))
Once you split
a string, you are returned a list, the error happens here:
def getdata(filename):
with open(filename,'r') as csvfile:
csvFilereader=csv.reader(csvfile)
next(csvFilereader)
for row in csvFilereader:
dates.append(int(row[4].split('-'))) <------------ here
prices.append(float(row[2]))
So instead of converting a string item to int
you are converting the results of your .split()
, which is a list to int
, which is not possible.
If you want to select a target result from your list, you can try with selecting a particular index from the results to test it out:
dates.append(int(row[4].split('-')[0]))
answered Nov 22 '18 at 6:32
BernardLBernardL
2,39611130
2,39611130
No problem and welcome to SO. If any of the answers here solved your question, kindly accept them as an answer by ticking the checkmark below the vote buttons on the left.
– BernardL
Nov 22 '18 at 7:01
add a comment |
No problem and welcome to SO. If any of the answers here solved your question, kindly accept them as an answer by ticking the checkmark below the vote buttons on the left.
– BernardL
Nov 22 '18 at 7:01
No problem and welcome to SO. If any of the answers here solved your question, kindly accept them as an answer by ticking the checkmark below the vote buttons on the left.
– BernardL
Nov 22 '18 at 7:01
No problem and welcome to SO. If any of the answers here solved your question, kindly accept them as an answer by ticking the checkmark below the vote buttons on the left.
– BernardL
Nov 22 '18 at 7:01
add a comment |
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Are you sure the data coming from your csv file is what you expect?
– Red Cricket
Nov 22 '18 at 6:28