Extract rows from dataframe that have keywords in them (Twitter data in RStudio)
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1
down vote
favorite
I have a large dataframe (~500,000 observations) consisting of structured Twitter data (i.e. username, rewtweet counts, text) in RStudio. I want to run a text analysis on the tweets so I can extract observations that have one or more keywords in the tweet text.
I have uploaded my keywords as keywords_C <- c("climate change","climate","climatechange","global warming","globalwarming")
. Tweet text is stored in my dataframe in a column labelled text
.
How do I make a new dataframe containing only observations where one or more of the keywords are present in the text
column? Alternatively, can I delete observations where the keywords are not present?
Added info:
My dataframe looks something like this...
id_num, follower_count, text ;
123 , 135 , Climate change is not science, it’s religion;
456 , 73 , Interesting article here from Reuters ;
789 , 1367 , Our warming climate is danger #1! ;
345 , 489 , New episode of blue planet! ;
Using the keywords_C
value, I'm hoping to write a code that will extract rows that contain the keywords and create a new dataframe. So in this example, the new dataframe would be...
id_num, follower_count, text ;
123 , 135 , Climate change is not science, it’s religion;
789 , 1367 , Our warming climate is danger #1! ;
My dataframe is called NewCData
dput(droplevels(head(NewCData, 10)))
structure(list(timestamp = structure(c(1L, 3L, 2L, 6L, 4L, 4L,
5L, 8L, 7L, 9L), .Label = c("2015-10-30 21:37:58", "2015-10-30 21:38:02",
"2015-10-30 21:38:03", "2015-10-30 21:38:06", "2015-10-30 21:38:07",
"2015-10-30 21:38:10", "2015-10-30 21:38:14", "2015-10-30 21:38:32",
"2015-10-30 21:39:04"), class = "factor"), id_str = structure(c(1L,
3L, 2L, 7L, 4L, 5L, 6L, 9L, 8L, 10L), .Label = c("660209050429186048",
"660209067584016384", "660209072768212992", "660209083505504256",
"660209086143688704", "660209087628578816", "660209102790914048",
"660209119152893952", "660209195162206208", "660209325986549760"
), class = "factor"), user.id_str = structure(c(1L, 3L, 8L, 5L,
5L, 2L, 4L, 6L, 9L, 7L), .Label = c("277335277", "32380087",
"325105950", "33398863", "68956490", "808114195", "87712431",
"90280824", "949996219"), class = "factor"), user.followers_count = structure(c(7L,
2L, 8L, 4L, 4L, 3L, 6L, 9L, 5L, 1L), .Label = c("10212", "1062",
"1389", "15227", "2214", "2851", "38", "4137", "55"), class = "factor"),
ideology = structure(c(2L, 4L, 3L, 9L, 9L, 5L, 8L, 6L, 1L,
7L), .Label = c("-0.309303177803536", "-0.393703659798908",
"-0.795976086971656", "-0.811321629152632", "-0.946143178314071",
"-1.16317298915931", "0.353843466445817", "1.09919837237897",
"2.29286233202781"), class = "factor"), text = structure(c(2L,
9L, 4L, 1L, 3L, 10L, 5L, 7L, 6L, 8L), .Label = c("Better Dead than Red! Bill Gates says that only socialism can save us ",
"Expert briefing on #disarmament #SDGs @NMUN ",
"I see red people Bill Gates says that only socialism can save us from climate change ",
"RT: Oddly enough, some Republicans think climate change is real: Oddly enough,… #UniteBlue ",
"Ted Cruz: ‘Climate change is not science, it’s religion’ via @glennbeck",
"This is an amusing headline: "Bill Gates says that only socialism can save us from climate change"",
"Unusual Weather Kills Gulf of Maine Cod : Discovery News #globalwarming ",
"What do the remaining Republican candidates have to say about climate change? #FixGov",
"Who Uses #NASA Earth Science Data? He looks at impact of #aerosols on #climate #weather!",
"Why go for ecosystem basses conservation! #ClimateChange #Raajje #Maldives"
), class = "factor")), .Names = c("timestamp", "id_str",
"user.id_str", "user.followers_count", "ideology", "text"), row.names = c(NA,
10L), class = "data.frame")
twitter rstudio extract keyword text-mining
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show 3 more comments
up vote
1
down vote
favorite
I have a large dataframe (~500,000 observations) consisting of structured Twitter data (i.e. username, rewtweet counts, text) in RStudio. I want to run a text analysis on the tweets so I can extract observations that have one or more keywords in the tweet text.
I have uploaded my keywords as keywords_C <- c("climate change","climate","climatechange","global warming","globalwarming")
. Tweet text is stored in my dataframe in a column labelled text
.
How do I make a new dataframe containing only observations where one or more of the keywords are present in the text
column? Alternatively, can I delete observations where the keywords are not present?
Added info:
My dataframe looks something like this...
id_num, follower_count, text ;
123 , 135 , Climate change is not science, it’s religion;
456 , 73 , Interesting article here from Reuters ;
789 , 1367 , Our warming climate is danger #1! ;
345 , 489 , New episode of blue planet! ;
Using the keywords_C
value, I'm hoping to write a code that will extract rows that contain the keywords and create a new dataframe. So in this example, the new dataframe would be...
id_num, follower_count, text ;
123 , 135 , Climate change is not science, it’s religion;
789 , 1367 , Our warming climate is danger #1! ;
My dataframe is called NewCData
dput(droplevels(head(NewCData, 10)))
structure(list(timestamp = structure(c(1L, 3L, 2L, 6L, 4L, 4L,
5L, 8L, 7L, 9L), .Label = c("2015-10-30 21:37:58", "2015-10-30 21:38:02",
"2015-10-30 21:38:03", "2015-10-30 21:38:06", "2015-10-30 21:38:07",
"2015-10-30 21:38:10", "2015-10-30 21:38:14", "2015-10-30 21:38:32",
"2015-10-30 21:39:04"), class = "factor"), id_str = structure(c(1L,
3L, 2L, 7L, 4L, 5L, 6L, 9L, 8L, 10L), .Label = c("660209050429186048",
"660209067584016384", "660209072768212992", "660209083505504256",
"660209086143688704", "660209087628578816", "660209102790914048",
"660209119152893952", "660209195162206208", "660209325986549760"
), class = "factor"), user.id_str = structure(c(1L, 3L, 8L, 5L,
5L, 2L, 4L, 6L, 9L, 7L), .Label = c("277335277", "32380087",
"325105950", "33398863", "68956490", "808114195", "87712431",
"90280824", "949996219"), class = "factor"), user.followers_count = structure(c(7L,
2L, 8L, 4L, 4L, 3L, 6L, 9L, 5L, 1L), .Label = c("10212", "1062",
"1389", "15227", "2214", "2851", "38", "4137", "55"), class = "factor"),
ideology = structure(c(2L, 4L, 3L, 9L, 9L, 5L, 8L, 6L, 1L,
7L), .Label = c("-0.309303177803536", "-0.393703659798908",
"-0.795976086971656", "-0.811321629152632", "-0.946143178314071",
"-1.16317298915931", "0.353843466445817", "1.09919837237897",
"2.29286233202781"), class = "factor"), text = structure(c(2L,
9L, 4L, 1L, 3L, 10L, 5L, 7L, 6L, 8L), .Label = c("Better Dead than Red! Bill Gates says that only socialism can save us ",
"Expert briefing on #disarmament #SDGs @NMUN ",
"I see red people Bill Gates says that only socialism can save us from climate change ",
"RT: Oddly enough, some Republicans think climate change is real: Oddly enough,… #UniteBlue ",
"Ted Cruz: ‘Climate change is not science, it’s religion’ via @glennbeck",
"This is an amusing headline: "Bill Gates says that only socialism can save us from climate change"",
"Unusual Weather Kills Gulf of Maine Cod : Discovery News #globalwarming ",
"What do the remaining Republican candidates have to say about climate change? #FixGov",
"Who Uses #NASA Earth Science Data? He looks at impact of #aerosols on #climate #weather!",
"Why go for ecosystem basses conservation! #ClimateChange #Raajje #Maldives"
), class = "factor")), .Names = c("timestamp", "id_str",
"user.id_str", "user.followers_count", "ideology", "text"), row.names = c(NA,
10L), class = "data.frame")
twitter rstudio extract keyword text-mining
Can you please share a reproducible example? Usedput(head(twitterData,10))
and add the result to the question. Ordput(droplevels(head(twitterData, 10)))
if your data frame has a factor with many levels. See How to make a great R reproducible example
– Wiktor Stribiżew
Nov 8 at 7:47
My apologies, but I'm not sure I understand your request. Perhaps you could elaborate on what information you need from me?
– Jason B
Nov 8 at 9:48
See stackoverflow.com/questions/5963269/…. In order to help you a portion of your input data is necessary together with the expected result.
– Wiktor Stribiżew
Nov 8 at 9:48
I couldn't get an understandable output from thedput
function you suggested (sorry, I'm quite inexperienced), but I added more info in my question. Please let me know if this makes sense.
– Jason B
Nov 8 at 11:13
It is not usable. Add the output you got fromdput
as is. You do not need to understand it.
– Wiktor Stribiżew
Nov 8 at 11:14
|
show 3 more comments
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I have a large dataframe (~500,000 observations) consisting of structured Twitter data (i.e. username, rewtweet counts, text) in RStudio. I want to run a text analysis on the tweets so I can extract observations that have one or more keywords in the tweet text.
I have uploaded my keywords as keywords_C <- c("climate change","climate","climatechange","global warming","globalwarming")
. Tweet text is stored in my dataframe in a column labelled text
.
How do I make a new dataframe containing only observations where one or more of the keywords are present in the text
column? Alternatively, can I delete observations where the keywords are not present?
Added info:
My dataframe looks something like this...
id_num, follower_count, text ;
123 , 135 , Climate change is not science, it’s religion;
456 , 73 , Interesting article here from Reuters ;
789 , 1367 , Our warming climate is danger #1! ;
345 , 489 , New episode of blue planet! ;
Using the keywords_C
value, I'm hoping to write a code that will extract rows that contain the keywords and create a new dataframe. So in this example, the new dataframe would be...
id_num, follower_count, text ;
123 , 135 , Climate change is not science, it’s religion;
789 , 1367 , Our warming climate is danger #1! ;
My dataframe is called NewCData
dput(droplevels(head(NewCData, 10)))
structure(list(timestamp = structure(c(1L, 3L, 2L, 6L, 4L, 4L,
5L, 8L, 7L, 9L), .Label = c("2015-10-30 21:37:58", "2015-10-30 21:38:02",
"2015-10-30 21:38:03", "2015-10-30 21:38:06", "2015-10-30 21:38:07",
"2015-10-30 21:38:10", "2015-10-30 21:38:14", "2015-10-30 21:38:32",
"2015-10-30 21:39:04"), class = "factor"), id_str = structure(c(1L,
3L, 2L, 7L, 4L, 5L, 6L, 9L, 8L, 10L), .Label = c("660209050429186048",
"660209067584016384", "660209072768212992", "660209083505504256",
"660209086143688704", "660209087628578816", "660209102790914048",
"660209119152893952", "660209195162206208", "660209325986549760"
), class = "factor"), user.id_str = structure(c(1L, 3L, 8L, 5L,
5L, 2L, 4L, 6L, 9L, 7L), .Label = c("277335277", "32380087",
"325105950", "33398863", "68956490", "808114195", "87712431",
"90280824", "949996219"), class = "factor"), user.followers_count = structure(c(7L,
2L, 8L, 4L, 4L, 3L, 6L, 9L, 5L, 1L), .Label = c("10212", "1062",
"1389", "15227", "2214", "2851", "38", "4137", "55"), class = "factor"),
ideology = structure(c(2L, 4L, 3L, 9L, 9L, 5L, 8L, 6L, 1L,
7L), .Label = c("-0.309303177803536", "-0.393703659798908",
"-0.795976086971656", "-0.811321629152632", "-0.946143178314071",
"-1.16317298915931", "0.353843466445817", "1.09919837237897",
"2.29286233202781"), class = "factor"), text = structure(c(2L,
9L, 4L, 1L, 3L, 10L, 5L, 7L, 6L, 8L), .Label = c("Better Dead than Red! Bill Gates says that only socialism can save us ",
"Expert briefing on #disarmament #SDGs @NMUN ",
"I see red people Bill Gates says that only socialism can save us from climate change ",
"RT: Oddly enough, some Republicans think climate change is real: Oddly enough,… #UniteBlue ",
"Ted Cruz: ‘Climate change is not science, it’s religion’ via @glennbeck",
"This is an amusing headline: "Bill Gates says that only socialism can save us from climate change"",
"Unusual Weather Kills Gulf of Maine Cod : Discovery News #globalwarming ",
"What do the remaining Republican candidates have to say about climate change? #FixGov",
"Who Uses #NASA Earth Science Data? He looks at impact of #aerosols on #climate #weather!",
"Why go for ecosystem basses conservation! #ClimateChange #Raajje #Maldives"
), class = "factor")), .Names = c("timestamp", "id_str",
"user.id_str", "user.followers_count", "ideology", "text"), row.names = c(NA,
10L), class = "data.frame")
twitter rstudio extract keyword text-mining
I have a large dataframe (~500,000 observations) consisting of structured Twitter data (i.e. username, rewtweet counts, text) in RStudio. I want to run a text analysis on the tweets so I can extract observations that have one or more keywords in the tweet text.
I have uploaded my keywords as keywords_C <- c("climate change","climate","climatechange","global warming","globalwarming")
. Tweet text is stored in my dataframe in a column labelled text
.
How do I make a new dataframe containing only observations where one or more of the keywords are present in the text
column? Alternatively, can I delete observations where the keywords are not present?
Added info:
My dataframe looks something like this...
id_num, follower_count, text ;
123 , 135 , Climate change is not science, it’s religion;
456 , 73 , Interesting article here from Reuters ;
789 , 1367 , Our warming climate is danger #1! ;
345 , 489 , New episode of blue planet! ;
Using the keywords_C
value, I'm hoping to write a code that will extract rows that contain the keywords and create a new dataframe. So in this example, the new dataframe would be...
id_num, follower_count, text ;
123 , 135 , Climate change is not science, it’s religion;
789 , 1367 , Our warming climate is danger #1! ;
My dataframe is called NewCData
dput(droplevels(head(NewCData, 10)))
structure(list(timestamp = structure(c(1L, 3L, 2L, 6L, 4L, 4L,
5L, 8L, 7L, 9L), .Label = c("2015-10-30 21:37:58", "2015-10-30 21:38:02",
"2015-10-30 21:38:03", "2015-10-30 21:38:06", "2015-10-30 21:38:07",
"2015-10-30 21:38:10", "2015-10-30 21:38:14", "2015-10-30 21:38:32",
"2015-10-30 21:39:04"), class = "factor"), id_str = structure(c(1L,
3L, 2L, 7L, 4L, 5L, 6L, 9L, 8L, 10L), .Label = c("660209050429186048",
"660209067584016384", "660209072768212992", "660209083505504256",
"660209086143688704", "660209087628578816", "660209102790914048",
"660209119152893952", "660209195162206208", "660209325986549760"
), class = "factor"), user.id_str = structure(c(1L, 3L, 8L, 5L,
5L, 2L, 4L, 6L, 9L, 7L), .Label = c("277335277", "32380087",
"325105950", "33398863", "68956490", "808114195", "87712431",
"90280824", "949996219"), class = "factor"), user.followers_count = structure(c(7L,
2L, 8L, 4L, 4L, 3L, 6L, 9L, 5L, 1L), .Label = c("10212", "1062",
"1389", "15227", "2214", "2851", "38", "4137", "55"), class = "factor"),
ideology = structure(c(2L, 4L, 3L, 9L, 9L, 5L, 8L, 6L, 1L,
7L), .Label = c("-0.309303177803536", "-0.393703659798908",
"-0.795976086971656", "-0.811321629152632", "-0.946143178314071",
"-1.16317298915931", "0.353843466445817", "1.09919837237897",
"2.29286233202781"), class = "factor"), text = structure(c(2L,
9L, 4L, 1L, 3L, 10L, 5L, 7L, 6L, 8L), .Label = c("Better Dead than Red! Bill Gates says that only socialism can save us ",
"Expert briefing on #disarmament #SDGs @NMUN ",
"I see red people Bill Gates says that only socialism can save us from climate change ",
"RT: Oddly enough, some Republicans think climate change is real: Oddly enough,… #UniteBlue ",
"Ted Cruz: ‘Climate change is not science, it’s religion’ via @glennbeck",
"This is an amusing headline: "Bill Gates says that only socialism can save us from climate change"",
"Unusual Weather Kills Gulf of Maine Cod : Discovery News #globalwarming ",
"What do the remaining Republican candidates have to say about climate change? #FixGov",
"Who Uses #NASA Earth Science Data? He looks at impact of #aerosols on #climate #weather!",
"Why go for ecosystem basses conservation! #ClimateChange #Raajje #Maldives"
), class = "factor")), .Names = c("timestamp", "id_str",
"user.id_str", "user.followers_count", "ideology", "text"), row.names = c(NA,
10L), class = "data.frame")
twitter rstudio extract keyword text-mining
twitter rstudio extract keyword text-mining
edited Nov 8 at 11:33
asked Nov 7 at 11:27
Jason B
245
245
Can you please share a reproducible example? Usedput(head(twitterData,10))
and add the result to the question. Ordput(droplevels(head(twitterData, 10)))
if your data frame has a factor with many levels. See How to make a great R reproducible example
– Wiktor Stribiżew
Nov 8 at 7:47
My apologies, but I'm not sure I understand your request. Perhaps you could elaborate on what information you need from me?
– Jason B
Nov 8 at 9:48
See stackoverflow.com/questions/5963269/…. In order to help you a portion of your input data is necessary together with the expected result.
– Wiktor Stribiżew
Nov 8 at 9:48
I couldn't get an understandable output from thedput
function you suggested (sorry, I'm quite inexperienced), but I added more info in my question. Please let me know if this makes sense.
– Jason B
Nov 8 at 11:13
It is not usable. Add the output you got fromdput
as is. You do not need to understand it.
– Wiktor Stribiżew
Nov 8 at 11:14
|
show 3 more comments
Can you please share a reproducible example? Usedput(head(twitterData,10))
and add the result to the question. Ordput(droplevels(head(twitterData, 10)))
if your data frame has a factor with many levels. See How to make a great R reproducible example
– Wiktor Stribiżew
Nov 8 at 7:47
My apologies, but I'm not sure I understand your request. Perhaps you could elaborate on what information you need from me?
– Jason B
Nov 8 at 9:48
See stackoverflow.com/questions/5963269/…. In order to help you a portion of your input data is necessary together with the expected result.
– Wiktor Stribiżew
Nov 8 at 9:48
I couldn't get an understandable output from thedput
function you suggested (sorry, I'm quite inexperienced), but I added more info in my question. Please let me know if this makes sense.
– Jason B
Nov 8 at 11:13
It is not usable. Add the output you got fromdput
as is. You do not need to understand it.
– Wiktor Stribiżew
Nov 8 at 11:14
Can you please share a reproducible example? Use
dput(head(twitterData,10))
and add the result to the question. Or dput(droplevels(head(twitterData, 10)))
if your data frame has a factor with many levels. See How to make a great R reproducible example– Wiktor Stribiżew
Nov 8 at 7:47
Can you please share a reproducible example? Use
dput(head(twitterData,10))
and add the result to the question. Or dput(droplevels(head(twitterData, 10)))
if your data frame has a factor with many levels. See How to make a great R reproducible example– Wiktor Stribiżew
Nov 8 at 7:47
My apologies, but I'm not sure I understand your request. Perhaps you could elaborate on what information you need from me?
– Jason B
Nov 8 at 9:48
My apologies, but I'm not sure I understand your request. Perhaps you could elaborate on what information you need from me?
– Jason B
Nov 8 at 9:48
See stackoverflow.com/questions/5963269/…. In order to help you a portion of your input data is necessary together with the expected result.
– Wiktor Stribiżew
Nov 8 at 9:48
See stackoverflow.com/questions/5963269/…. In order to help you a portion of your input data is necessary together with the expected result.
– Wiktor Stribiżew
Nov 8 at 9:48
I couldn't get an understandable output from the
dput
function you suggested (sorry, I'm quite inexperienced), but I added more info in my question. Please let me know if this makes sense.– Jason B
Nov 8 at 11:13
I couldn't get an understandable output from the
dput
function you suggested (sorry, I'm quite inexperienced), but I added more info in my question. Please let me know if this makes sense.– Jason B
Nov 8 at 11:13
It is not usable. Add the output you got from
dput
as is. You do not need to understand it.– Wiktor Stribiżew
Nov 8 at 11:14
It is not usable. Add the output you got from
dput
as is. You do not need to understand it.– Wiktor Stribiżew
Nov 8 at 11:14
|
show 3 more comments
1 Answer
1
active
oldest
votes
up vote
1
down vote
accepted
You may use
new_df <- NewCData[with(NewCData, grepl(paste0("\b(?:",paste(keywords_C, collapse="|"),")\b"), text)),]
See the R demo online
The point here is to combine the keywords into a pattern like
b(?:climate change|climate|climatechange|global warming|globalwarming)b
It will match the words as whole words and if there is a match in the text
column, the row will be returned, else, the row will get discarded.
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
You may use
new_df <- NewCData[with(NewCData, grepl(paste0("\b(?:",paste(keywords_C, collapse="|"),")\b"), text)),]
See the R demo online
The point here is to combine the keywords into a pattern like
b(?:climate change|climate|climatechange|global warming|globalwarming)b
It will match the words as whole words and if there is a match in the text
column, the row will be returned, else, the row will get discarded.
add a comment |
up vote
1
down vote
accepted
You may use
new_df <- NewCData[with(NewCData, grepl(paste0("\b(?:",paste(keywords_C, collapse="|"),")\b"), text)),]
See the R demo online
The point here is to combine the keywords into a pattern like
b(?:climate change|climate|climatechange|global warming|globalwarming)b
It will match the words as whole words and if there is a match in the text
column, the row will be returned, else, the row will get discarded.
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
You may use
new_df <- NewCData[with(NewCData, grepl(paste0("\b(?:",paste(keywords_C, collapse="|"),")\b"), text)),]
See the R demo online
The point here is to combine the keywords into a pattern like
b(?:climate change|climate|climatechange|global warming|globalwarming)b
It will match the words as whole words and if there is a match in the text
column, the row will be returned, else, the row will get discarded.
You may use
new_df <- NewCData[with(NewCData, grepl(paste0("\b(?:",paste(keywords_C, collapse="|"),")\b"), text)),]
See the R demo online
The point here is to combine the keywords into a pattern like
b(?:climate change|climate|climatechange|global warming|globalwarming)b
It will match the words as whole words and if there is a match in the text
column, the row will be returned, else, the row will get discarded.
answered Nov 8 at 11:52
Wiktor Stribiżew
301k16122197
301k16122197
add a comment |
add a comment |
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Can you please share a reproducible example? Use
dput(head(twitterData,10))
and add the result to the question. Ordput(droplevels(head(twitterData, 10)))
if your data frame has a factor with many levels. See How to make a great R reproducible example– Wiktor Stribiżew
Nov 8 at 7:47
My apologies, but I'm not sure I understand your request. Perhaps you could elaborate on what information you need from me?
– Jason B
Nov 8 at 9:48
See stackoverflow.com/questions/5963269/…. In order to help you a portion of your input data is necessary together with the expected result.
– Wiktor Stribiżew
Nov 8 at 9:48
I couldn't get an understandable output from the
dput
function you suggested (sorry, I'm quite inexperienced), but I added more info in my question. Please let me know if this makes sense.– Jason B
Nov 8 at 11:13
It is not usable. Add the output you got from
dput
as is. You do not need to understand it.– Wiktor Stribiżew
Nov 8 at 11:14