How to grep out the first file path in python

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I am always headache with regex but guess it might be the way to do it. Here is the string I have:



-rw-rw----+  3 userabc clouderausersdev   12267543 2018-02-05 16:41 hdfs://nameservice1/client/abc/scenarios/warehouse/product/tdb_histscen_2/part-00000-6fa2e019-96e5-4280-b2fc-994917013a6a-c000.snappy.parquet


All I want to grep out is the file's full path:




hdfs://nameservice1/client/abc/scenarios/warehouse/product/tdb_histscen_2/part-00000-6fa2e019-96e5-4280-b2fc-994917013a6a-c000.snappy.parquet




Thank you very much.






python regex grep







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  • Will the file always begin with hdfs ?
    – Rodolfo Donã Hosp
    Nov 5 at 17:01















up vote
0
down vote

favorite












I am always headache with regex but guess it might be the way to do it. Here is the string I have:



-rw-rw----+  3 userabc clouderausersdev   12267543 2018-02-05 16:41 hdfs://nameservice1/client/abc/scenarios/warehouse/product/tdb_histscen_2/part-00000-6fa2e019-96e5-4280-b2fc-994917013a6a-c000.snappy.parquet


All I want to grep out is the file's full path:




hdfs://nameservice1/client/abc/scenarios/warehouse/product/tdb_histscen_2/part-00000-6fa2e019-96e5-4280-b2fc-994917013a6a-c000.snappy.parquet




Thank you very much.






python regex grep







share|improve this question






















  • Will the file always begin with hdfs ?
    – Rodolfo Donã Hosp
    Nov 5 at 17:01













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I am always headache with regex but guess it might be the way to do it. Here is the string I have:



-rw-rw----+  3 userabc clouderausersdev   12267543 2018-02-05 16:41 hdfs://nameservice1/client/abc/scenarios/warehouse/product/tdb_histscen_2/part-00000-6fa2e019-96e5-4280-b2fc-994917013a6a-c000.snappy.parquet


All I want to grep out is the file's full path:




hdfs://nameservice1/client/abc/scenarios/warehouse/product/tdb_histscen_2/part-00000-6fa2e019-96e5-4280-b2fc-994917013a6a-c000.snappy.parquet




Thank you very much.






python regex grep







share|improve this question













I am always headache with regex but guess it might be the way to do it. Here is the string I have:



-rw-rw----+  3 userabc clouderausersdev   12267543 2018-02-05 16:41 hdfs://nameservice1/client/abc/scenarios/warehouse/product/tdb_histscen_2/part-00000-6fa2e019-96e5-4280-b2fc-994917013a6a-c000.snappy.parquet


All I want to grep out is the file's full path:




hdfs://nameservice1/client/abc/scenarios/warehouse/product/tdb_histscen_2/part-00000-6fa2e019-96e5-4280-b2fc-994917013a6a-c000.snappy.parquet




Thank you very much.






python regex grep




python regex grep






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asked Nov 5 at 16:59









mdivk

53821024




53821024












  • Will the file always begin with hdfs ?
    – Rodolfo Donã Hosp
    Nov 5 at 17:01


















  • Will the file always begin with hdfs ?
    – Rodolfo Donã Hosp
    Nov 5 at 17:01
















Will the file always begin with hdfs ?
– Rodolfo Donã Hosp
Nov 5 at 17:01




Will the file always begin with hdfs ?
– Rodolfo Donã Hosp
Nov 5 at 17:01












1 Answer
1






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Why not just take the last value of the space-separated string?



x = "-rw-rw----+  3 userabc clouderausersdev   12267543 2018-02-05 16:41 hdfs://nameservice1/client/abc/scenarios/warehouse/product/tdb_histscen_2/part-00000-6fa2e019-96e5-4280-b2fc-994917013a6a-c000.snappy.parquet"

parts = [y for y in x.split(' ') if y]  # removes empty strings

fname = parts[-1]





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  • Thank you, yes I just realized that :)
    – mdivk
    Nov 5 at 17:04










  • If your format is really fixed, as in an auto generated log file, this answer is probably easiest than using a length regex to fish out the path +1.
    – Tim Biegeleisen
    Nov 5 at 17:06











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
1
down vote



accepted










Why not just take the last value of the space-separated string?



x = "-rw-rw----+  3 userabc clouderausersdev   12267543 2018-02-05 16:41 hdfs://nameservice1/client/abc/scenarios/warehouse/product/tdb_histscen_2/part-00000-6fa2e019-96e5-4280-b2fc-994917013a6a-c000.snappy.parquet"

parts = [y for y in x.split(' ') if y]  # removes empty strings

fname = parts[-1]





share|improve this answer





















  • Thank you, yes I just realized that :)
    – mdivk
    Nov 5 at 17:04










  • If your format is really fixed, as in an auto generated log file, this answer is probably easiest than using a length regex to fish out the path +1.
    – Tim Biegeleisen
    Nov 5 at 17:06















up vote
1
down vote



accepted










Why not just take the last value of the space-separated string?



x = "-rw-rw----+  3 userabc clouderausersdev   12267543 2018-02-05 16:41 hdfs://nameservice1/client/abc/scenarios/warehouse/product/tdb_histscen_2/part-00000-6fa2e019-96e5-4280-b2fc-994917013a6a-c000.snappy.parquet"

parts = [y for y in x.split(' ') if y]  # removes empty strings

fname = parts[-1]





share|improve this answer





















  • Thank you, yes I just realized that :)
    – mdivk
    Nov 5 at 17:04










  • If your format is really fixed, as in an auto generated log file, this answer is probably easiest than using a length regex to fish out the path +1.
    – Tim Biegeleisen
    Nov 5 at 17:06













up vote
1
down vote



accepted







up vote
1
down vote



accepted






Why not just take the last value of the space-separated string?



x = "-rw-rw----+  3 userabc clouderausersdev   12267543 2018-02-05 16:41 hdfs://nameservice1/client/abc/scenarios/warehouse/product/tdb_histscen_2/part-00000-6fa2e019-96e5-4280-b2fc-994917013a6a-c000.snappy.parquet"

parts = [y for y in x.split(' ') if y]  # removes empty strings

fname = parts[-1]





share|improve this answer












Why not just take the last value of the space-separated string?



x = "-rw-rw----+  3 userabc clouderausersdev   12267543 2018-02-05 16:41 hdfs://nameservice1/client/abc/scenarios/warehouse/product/tdb_histscen_2/part-00000-6fa2e019-96e5-4280-b2fc-994917013a6a-c000.snappy.parquet"

parts = [y for y in x.split(' ') if y]  # removes empty strings

fname = parts[-1]






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 5 at 17:03









wpercy

6,04841933




6,04841933












  • Thank you, yes I just realized that :)
    – mdivk
    Nov 5 at 17:04










  • If your format is really fixed, as in an auto generated log file, this answer is probably easiest than using a length regex to fish out the path +1.
    – Tim Biegeleisen
    Nov 5 at 17:06


















  • Thank you, yes I just realized that :)
    – mdivk
    Nov 5 at 17:04










  • If your format is really fixed, as in an auto generated log file, this answer is probably easiest than using a length regex to fish out the path +1.
    – Tim Biegeleisen
    Nov 5 at 17:06
















Thank you, yes I just realized that :)
– mdivk
Nov 5 at 17:04




Thank you, yes I just realized that :)
– mdivk
Nov 5 at 17:04












If your format is really fixed, as in an auto generated log file, this answer is probably easiest than using a length regex to fish out the path +1.
– Tim Biegeleisen
Nov 5 at 17:06




If your format is really fixed, as in an auto generated log file, this answer is probably easiest than using a length regex to fish out the path +1.
– Tim Biegeleisen
Nov 5 at 17:06


















 

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