How to get # of distinct characters in a string? (Swift 4.2 + )
This algorithm or code should work for any # of unique character in a string, by the condition we use to check after.
For instance (If I have a string that I want to know if we have at least 7 unique characters we can do):
let number_of_distinct = Set(some_string.characters).count
if(number_of_distinct >= 7)
{
// yes we have at least 7 unique chars.
}
else
{
// no we don't have at least 7 unique chars.
}
However, this technique seems to be deprecated in Swift 4.2 +, due to the way Strings were updated in Swift 4.0 +.
What would be the new correct approach for this technique mentioned above?
swift4 swift4.2
asked Nov 11 at 23:30
Omid CompSCI
3181619
add a comment |
This algorithm or code should work for any # of unique character in a string, by the condition we use to check after.
For instance (If I have a string that I want to know if we have at least 7 unique characters we can do):
let number_of_distinct = Set(some_string.characters).count
if(number_of_distinct >= 7)
{
// yes we have at least 7 unique chars.
}
else
{
// no we don't have at least 7 unique chars.
}
However, this technique seems to be deprecated in Swift 4.2 +, due to the way Strings were updated in Swift 4.0 +.
What would be the new correct approach for this technique mentioned above?
swift4 swift4.2
asked Nov 11 at 23:30
Omid CompSCI
3181619
add a comment |
This algorithm or code should work for any # of unique character in a string, by the condition we use to check after.
For instance (If I have a string that I want to know if we have at least 7 unique characters we can do):
let number_of_distinct = Set(some_string.characters).count
if(number_of_distinct >= 7)
{
// yes we have at least 7 unique chars.
}
else
{
// no we don't have at least 7 unique chars.
}
However, this technique seems to be deprecated in Swift 4.2 +, due to the way Strings were updated in Swift 4.0 +.
What would be the new correct approach for this technique mentioned above?
swift4 swift4.2
asked Nov 11 at 23:30
Omid CompSCI
3181619
This algorithm or code should work for any # of unique character in a string, by the condition we use to check after.
For instance (If I have a string that I want to know if we have at least 7 unique characters we can do):
let number_of_distinct = Set(some_string.characters).count
if(number_of_distinct >= 7)
{
// yes we have at least 7 unique chars.
}
else
{
// no we don't have at least 7 unique chars.
}
However, this technique seems to be deprecated in Swift 4.2 +, due to the way Strings were updated in Swift 4.0 +.
What would be the new correct approach for this technique mentioned above?
swift4 swift4.2
swift4 swift4.2
asked Nov 11 at 23:30
Omid CompSCI
3181619
asked Nov 11 at 23:30
Omid CompSCI
3181619
asked Nov 11 at 23:30
Omid CompSCI
3181619
asked Nov 11 at 23:30
Omid CompSCI
3181619
asked Nov 11 at 23:30
Omid CompSCI
3181619
3181619
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Just remove the .characters
let number_of_distinct = Set(some_string).count
if(number_of_distinct >= 7)
{
print("yes")
// yes we have at least 7 unique chars.
}
else
{
print("no")
// no we don't have at least 7 unique chars.
}
answered Nov 12 at 0:42
Daniel T.
12.8k22534
Thank you, what an easy solution and way :)
– Omid CompSCI
Nov 12 at 1:05
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Just remove the .characters
let number_of_distinct = Set(some_string).count
if(number_of_distinct >= 7)
{
print("yes")
// yes we have at least 7 unique chars.
}
else
{
print("no")
// no we don't have at least 7 unique chars.
}
answered Nov 12 at 0:42
Daniel T.
12.8k22534
Thank you, what an easy solution and way :)
– Omid CompSCI
Nov 12 at 1:05
add a comment |
Just remove the .characters
let number_of_distinct = Set(some_string).count
if(number_of_distinct >= 7)
{
print("yes")
// yes we have at least 7 unique chars.
}
else
{
print("no")
// no we don't have at least 7 unique chars.
}
answered Nov 12 at 0:42
Daniel T.
12.8k22534
Thank you, what an easy solution and way :)
– Omid CompSCI
Nov 12 at 1:05
add a comment |
Just remove the .characters
let number_of_distinct = Set(some_string).count
if(number_of_distinct >= 7)
{
print("yes")
// yes we have at least 7 unique chars.
}
else
{
print("no")
// no we don't have at least 7 unique chars.
}
answered Nov 12 at 0:42
Daniel T.
12.8k22534
Just remove the .characters
let number_of_distinct = Set(some_string).count
if(number_of_distinct >= 7)
{
print("yes")
// yes we have at least 7 unique chars.
}
else
{
print("no")
// no we don't have at least 7 unique chars.
}
answered Nov 12 at 0:42
Daniel T.
12.8k22534
answered Nov 12 at 0:42
Daniel T.
12.8k22534
answered Nov 12 at 0:42
Daniel T.
12.8k22534
answered Nov 12 at 0:42
Daniel T.
12.8k22534
12.8k22534
Thank you, what an easy solution and way :)
– Omid CompSCI
Nov 12 at 1:05
add a comment |
Thank you, what an easy solution and way :)
– Omid CompSCI
Nov 12 at 1:05
Thank you, what an easy solution and way :)
– Omid CompSCI
Nov 12 at 1:05
Thank you, what an easy solution and way :)
– Omid CompSCI
Nov 12 at 1:05
add a comment |
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