dump of lists into csv export












-2














I need to add column headers and then export the following to csv.
But when I export the list, I get the last line with each of the characters in columns.



This is the output:



Current output of list



If I implement df=pd.DataFrame([d])
I get the following :



enter image description here



Code that creates this list is as follows



soup=BeautifulSoup(s,'lxml')
soup.prettify()
for anchor in soup.findAll('a', href=True):
s=anchor['href']
if 'bus' in s:
urlparse(s)
path = urlparse(s).path[1:]
parts = path.split('/')
d= parts[2:4]
df=pd.DataFrame(d)
print(df)









share|improve this question




















  • 2




    Please replace the screenshots with the actual data. Screenshots of data, code, and errors do not belong on SO.
    – DYZ
    Nov 11 at 23:35










  • @DYZ but I am unable to get the data to csv hence why I am asking the question. I cannot copy paste the results for some reason from the command prompt. Its a lot of data by the way and its just a small fraction of it.
    – tabarneck
    Nov 11 at 23:47










  • What type of object is d? Why are you passing it to pd.DataFrame as a list (e.g. in ). Have you tried pd.DataFrame(d)?
    – dmitriys
    Nov 11 at 23:50










  • I get something like this if I do without the alon-De-Coiffure-Pour-Hommes-Laurier 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 Kings-Barbershop 0 0 Longueuil 1 Kings-Barbershop
    – tabarneck
    Nov 11 at 23:52








  • 1




    I will add the code to the post
    – tabarneck
    Nov 11 at 23:54
















-2














I need to add column headers and then export the following to csv.
But when I export the list, I get the last line with each of the characters in columns.



This is the output:



Current output of list



If I implement df=pd.DataFrame([d])
I get the following :



enter image description here



Code that creates this list is as follows



soup=BeautifulSoup(s,'lxml')
soup.prettify()
for anchor in soup.findAll('a', href=True):
s=anchor['href']
if 'bus' in s:
urlparse(s)
path = urlparse(s).path[1:]
parts = path.split('/')
d= parts[2:4]
df=pd.DataFrame(d)
print(df)









share|improve this question




















  • 2




    Please replace the screenshots with the actual data. Screenshots of data, code, and errors do not belong on SO.
    – DYZ
    Nov 11 at 23:35










  • @DYZ but I am unable to get the data to csv hence why I am asking the question. I cannot copy paste the results for some reason from the command prompt. Its a lot of data by the way and its just a small fraction of it.
    – tabarneck
    Nov 11 at 23:47










  • What type of object is d? Why are you passing it to pd.DataFrame as a list (e.g. in ). Have you tried pd.DataFrame(d)?
    – dmitriys
    Nov 11 at 23:50










  • I get something like this if I do without the alon-De-Coiffure-Pour-Hommes-Laurier 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 Kings-Barbershop 0 0 Longueuil 1 Kings-Barbershop
    – tabarneck
    Nov 11 at 23:52








  • 1




    I will add the code to the post
    – tabarneck
    Nov 11 at 23:54














-2












-2








-2







I need to add column headers and then export the following to csv.
But when I export the list, I get the last line with each of the characters in columns.



This is the output:



Current output of list



If I implement df=pd.DataFrame([d])
I get the following :



enter image description here



Code that creates this list is as follows



soup=BeautifulSoup(s,'lxml')
soup.prettify()
for anchor in soup.findAll('a', href=True):
s=anchor['href']
if 'bus' in s:
urlparse(s)
path = urlparse(s).path[1:]
parts = path.split('/')
d= parts[2:4]
df=pd.DataFrame(d)
print(df)









share|improve this question















I need to add column headers and then export the following to csv.
But when I export the list, I get the last line with each of the characters in columns.



This is the output:



Current output of list



If I implement df=pd.DataFrame([d])
I get the following :



enter image description here



Code that creates this list is as follows



soup=BeautifulSoup(s,'lxml')
soup.prettify()
for anchor in soup.findAll('a', href=True):
s=anchor['href']
if 'bus' in s:
urlparse(s)
path = urlparse(s).path[1:]
parts = path.split('/')
d= parts[2:4]
df=pd.DataFrame(d)
print(df)






python pandas






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 12 at 0:23









eyllanesc

73.4k103056




73.4k103056










asked Nov 11 at 23:29









tabarneck

226




226








  • 2




    Please replace the screenshots with the actual data. Screenshots of data, code, and errors do not belong on SO.
    – DYZ
    Nov 11 at 23:35










  • @DYZ but I am unable to get the data to csv hence why I am asking the question. I cannot copy paste the results for some reason from the command prompt. Its a lot of data by the way and its just a small fraction of it.
    – tabarneck
    Nov 11 at 23:47










  • What type of object is d? Why are you passing it to pd.DataFrame as a list (e.g. in ). Have you tried pd.DataFrame(d)?
    – dmitriys
    Nov 11 at 23:50










  • I get something like this if I do without the alon-De-Coiffure-Pour-Hommes-Laurier 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 Kings-Barbershop 0 0 Longueuil 1 Kings-Barbershop
    – tabarneck
    Nov 11 at 23:52








  • 1




    I will add the code to the post
    – tabarneck
    Nov 11 at 23:54














  • 2




    Please replace the screenshots with the actual data. Screenshots of data, code, and errors do not belong on SO.
    – DYZ
    Nov 11 at 23:35










  • @DYZ but I am unable to get the data to csv hence why I am asking the question. I cannot copy paste the results for some reason from the command prompt. Its a lot of data by the way and its just a small fraction of it.
    – tabarneck
    Nov 11 at 23:47










  • What type of object is d? Why are you passing it to pd.DataFrame as a list (e.g. in ). Have you tried pd.DataFrame(d)?
    – dmitriys
    Nov 11 at 23:50










  • I get something like this if I do without the alon-De-Coiffure-Pour-Hommes-Laurier 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 Kings-Barbershop 0 0 Longueuil 1 Kings-Barbershop
    – tabarneck
    Nov 11 at 23:52








  • 1




    I will add the code to the post
    – tabarneck
    Nov 11 at 23:54








2




2




Please replace the screenshots with the actual data. Screenshots of data, code, and errors do not belong on SO.
– DYZ
Nov 11 at 23:35




Please replace the screenshots with the actual data. Screenshots of data, code, and errors do not belong on SO.
– DYZ
Nov 11 at 23:35












@DYZ but I am unable to get the data to csv hence why I am asking the question. I cannot copy paste the results for some reason from the command prompt. Its a lot of data by the way and its just a small fraction of it.
– tabarneck
Nov 11 at 23:47




@DYZ but I am unable to get the data to csv hence why I am asking the question. I cannot copy paste the results for some reason from the command prompt. Its a lot of data by the way and its just a small fraction of it.
– tabarneck
Nov 11 at 23:47












What type of object is d? Why are you passing it to pd.DataFrame as a list (e.g. in ). Have you tried pd.DataFrame(d)?
– dmitriys
Nov 11 at 23:50




What type of object is d? Why are you passing it to pd.DataFrame as a list (e.g. in ). Have you tried pd.DataFrame(d)?
– dmitriys
Nov 11 at 23:50












I get something like this if I do without the alon-De-Coiffure-Pour-Hommes-Laurier 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 Kings-Barbershop 0 0 Longueuil 1 Kings-Barbershop
– tabarneck
Nov 11 at 23:52






I get something like this if I do without the alon-De-Coiffure-Pour-Hommes-Laurier 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 King-s-Barbershop 0 0 Longueuil 1 Kings-Barbershop 0 0 Longueuil 1 Kings-Barbershop
– tabarneck
Nov 11 at 23:52






1




1




I will add the code to the post
– tabarneck
Nov 11 at 23:54




I will add the code to the post
– tabarneck
Nov 11 at 23:54












1 Answer
1






active

oldest

votes


















1














I think the issue is that for each iteration of the loop you're creating a new DataFrame; whereas what I imagine you probably want is a single DataFrame with all of the values for d. Try the below:



# Instantiate an empty list to collect values of `d` for each iteration
d_values =

soup=BeautifulSoup(s,'lxml')
soup.prettify()
for anchor in soup.findAll('a', href=True):
s=anchor['href']

if 'bus' in s:
urlparse(s)
path = urlparse(s).path[1:]
parts = path.split('/')
d = parts[2:4]

# Append `d` to your list, creating a list of lists
d_values.append(d)

# Once your loop is done, create a DataFrame from your list of lists
df = pd.DataFrame(d_values, columns=['col1name','col2name'])





share|improve this answer





















  • Thank you so much! really appreciate your help!
    – tabarneck
    Nov 12 at 4:08











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














I think the issue is that for each iteration of the loop you're creating a new DataFrame; whereas what I imagine you probably want is a single DataFrame with all of the values for d. Try the below:



# Instantiate an empty list to collect values of `d` for each iteration
d_values =

soup=BeautifulSoup(s,'lxml')
soup.prettify()
for anchor in soup.findAll('a', href=True):
s=anchor['href']

if 'bus' in s:
urlparse(s)
path = urlparse(s).path[1:]
parts = path.split('/')
d = parts[2:4]

# Append `d` to your list, creating a list of lists
d_values.append(d)

# Once your loop is done, create a DataFrame from your list of lists
df = pd.DataFrame(d_values, columns=['col1name','col2name'])





share|improve this answer





















  • Thank you so much! really appreciate your help!
    – tabarneck
    Nov 12 at 4:08
















1














I think the issue is that for each iteration of the loop you're creating a new DataFrame; whereas what I imagine you probably want is a single DataFrame with all of the values for d. Try the below:



# Instantiate an empty list to collect values of `d` for each iteration
d_values =

soup=BeautifulSoup(s,'lxml')
soup.prettify()
for anchor in soup.findAll('a', href=True):
s=anchor['href']

if 'bus' in s:
urlparse(s)
path = urlparse(s).path[1:]
parts = path.split('/')
d = parts[2:4]

# Append `d` to your list, creating a list of lists
d_values.append(d)

# Once your loop is done, create a DataFrame from your list of lists
df = pd.DataFrame(d_values, columns=['col1name','col2name'])





share|improve this answer





















  • Thank you so much! really appreciate your help!
    – tabarneck
    Nov 12 at 4:08














1












1








1






I think the issue is that for each iteration of the loop you're creating a new DataFrame; whereas what I imagine you probably want is a single DataFrame with all of the values for d. Try the below:



# Instantiate an empty list to collect values of `d` for each iteration
d_values =

soup=BeautifulSoup(s,'lxml')
soup.prettify()
for anchor in soup.findAll('a', href=True):
s=anchor['href']

if 'bus' in s:
urlparse(s)
path = urlparse(s).path[1:]
parts = path.split('/')
d = parts[2:4]

# Append `d` to your list, creating a list of lists
d_values.append(d)

# Once your loop is done, create a DataFrame from your list of lists
df = pd.DataFrame(d_values, columns=['col1name','col2name'])





share|improve this answer












I think the issue is that for each iteration of the loop you're creating a new DataFrame; whereas what I imagine you probably want is a single DataFrame with all of the values for d. Try the below:



# Instantiate an empty list to collect values of `d` for each iteration
d_values =

soup=BeautifulSoup(s,'lxml')
soup.prettify()
for anchor in soup.findAll('a', href=True):
s=anchor['href']

if 'bus' in s:
urlparse(s)
path = urlparse(s).path[1:]
parts = path.split('/')
d = parts[2:4]

# Append `d` to your list, creating a list of lists
d_values.append(d)

# Once your loop is done, create a DataFrame from your list of lists
df = pd.DataFrame(d_values, columns=['col1name','col2name'])






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 12 at 1:30









dmitriys

15119




15119












  • Thank you so much! really appreciate your help!
    – tabarneck
    Nov 12 at 4:08


















  • Thank you so much! really appreciate your help!
    – tabarneck
    Nov 12 at 4:08
















Thank you so much! really appreciate your help!
– tabarneck
Nov 12 at 4:08




Thank you so much! really appreciate your help!
– tabarneck
Nov 12 at 4:08


















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