SQL: Why is column avg_spent getting an error that it does not exist?












0














SELECT
city,
usd_spent / count(city) AS avg_spent
FROM travel_spending
GROUP BY city HAVING avg_spent > 90;






group-by having







share|improve this question


















  • 1




    What version of SQL are you using?
    – Tim Biegeleisen
    Nov 12 at 1:44
















0














SELECT
city,
usd_spent / count(city) AS avg_spent
FROM travel_spending
GROUP BY city HAVING avg_spent > 90;






group-by having







share|improve this question


















  • 1




    What version of SQL are you using?
    – Tim Biegeleisen
    Nov 12 at 1:44














0












0








0







SELECT
city,
usd_spent / count(city) AS avg_spent
FROM travel_spending
GROUP BY city HAVING avg_spent > 90;






group-by having







share|improve this question













SELECT
city,
usd_spent / count(city) AS avg_spent
FROM travel_spending
GROUP BY city HAVING avg_spent > 90;






group-by having




group-by having






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 12 at 1:40









user10638261

1




1








  • 1




    What version of SQL are you using?
    – Tim Biegeleisen
    Nov 12 at 1:44














  • 1




    What version of SQL are you using?
    – Tim Biegeleisen
    Nov 12 at 1:44








1




1




What version of SQL are you using?
– Tim Biegeleisen
Nov 12 at 1:44




What version of SQL are you using?
– Tim Biegeleisen
Nov 12 at 1:44












1 Answer
1






active

oldest

votes


















0














Certain versions of SQL (e.g. MySQL) allow the use of aliases in the HAVING clause, while other versions (e.g. SQL Server) do not. In any case, just repeating the aggregate expression in the HAVING clause should work:



SELECT city, AVG(usd_spent) AS avg_spent

FROM travel_spending

GROUP BY city

HAVING AVG(usd_spent) > 90;





share|improve this answer























  • Thank you - However I got this error. ERROR: column "travel_spending.usd_spent" must appear in the GROUP BY clause or be used in an aggregate function Line: 1 Position in the line: 14
    – user10638261
    Nov 12 at 1:54












  • @user10638261 I think you just want the average USD spend here.
    – Tim Biegeleisen
    Nov 12 at 1:55











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1 Answer
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active

oldest

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1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














Certain versions of SQL (e.g. MySQL) allow the use of aliases in the HAVING clause, while other versions (e.g. SQL Server) do not. In any case, just repeating the aggregate expression in the HAVING clause should work:



SELECT city, AVG(usd_spent) AS avg_spent

FROM travel_spending

GROUP BY city

HAVING AVG(usd_spent) > 90;





share|improve this answer























  • Thank you - However I got this error. ERROR: column "travel_spending.usd_spent" must appear in the GROUP BY clause or be used in an aggregate function Line: 1 Position in the line: 14
    – user10638261
    Nov 12 at 1:54












  • @user10638261 I think you just want the average USD spend here.
    – Tim Biegeleisen
    Nov 12 at 1:55
















0














Certain versions of SQL (e.g. MySQL) allow the use of aliases in the HAVING clause, while other versions (e.g. SQL Server) do not. In any case, just repeating the aggregate expression in the HAVING clause should work:



SELECT city, AVG(usd_spent) AS avg_spent

FROM travel_spending

GROUP BY city

HAVING AVG(usd_spent) > 90;





share|improve this answer























  • Thank you - However I got this error. ERROR: column "travel_spending.usd_spent" must appear in the GROUP BY clause or be used in an aggregate function Line: 1 Position in the line: 14
    – user10638261
    Nov 12 at 1:54












  • @user10638261 I think you just want the average USD spend here.
    – Tim Biegeleisen
    Nov 12 at 1:55














0












0








0






Certain versions of SQL (e.g. MySQL) allow the use of aliases in the HAVING clause, while other versions (e.g. SQL Server) do not. In any case, just repeating the aggregate expression in the HAVING clause should work:



SELECT city, AVG(usd_spent) AS avg_spent

FROM travel_spending

GROUP BY city

HAVING AVG(usd_spent) > 90;





share|improve this answer














Certain versions of SQL (e.g. MySQL) allow the use of aliases in the HAVING clause, while other versions (e.g. SQL Server) do not. In any case, just repeating the aggregate expression in the HAVING clause should work:



SELECT city, AVG(usd_spent) AS avg_spent

FROM travel_spending

GROUP BY city

HAVING AVG(usd_spent) > 90;






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 12 at 1:55

























answered Nov 12 at 1:51









Tim Biegeleisen

217k1386139




217k1386139












  • Thank you - However I got this error. ERROR: column "travel_spending.usd_spent" must appear in the GROUP BY clause or be used in an aggregate function Line: 1 Position in the line: 14
    – user10638261
    Nov 12 at 1:54












  • @user10638261 I think you just want the average USD spend here.
    – Tim Biegeleisen
    Nov 12 at 1:55


















  • Thank you - However I got this error. ERROR: column "travel_spending.usd_spent" must appear in the GROUP BY clause or be used in an aggregate function Line: 1 Position in the line: 14
    – user10638261
    Nov 12 at 1:54












  • @user10638261 I think you just want the average USD spend here.
    – Tim Biegeleisen
    Nov 12 at 1:55
















Thank you - However I got this error. ERROR: column "travel_spending.usd_spent" must appear in the GROUP BY clause or be used in an aggregate function Line: 1 Position in the line: 14
– user10638261
Nov 12 at 1:54






Thank you - However I got this error. ERROR: column "travel_spending.usd_spent" must appear in the GROUP BY clause or be used in an aggregate function Line: 1 Position in the line: 14
– user10638261
Nov 12 at 1:54














@user10638261 I think you just want the average USD spend here.
– Tim Biegeleisen
Nov 12 at 1:55




@user10638261 I think you just want the average USD spend here.
– Tim Biegeleisen
Nov 12 at 1:55


















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