How can I create a json file for API calls?












-1















I want to parse all of the returned values from a MySQL database into a JSON file. So I wrote my php side like this:



foreach ($Posts->Show() as $Key => $Post) {
$Data ['POST'][$Post['Post_Id']]["Id"]=$Post['Post_Id'];
$Data ['POST'][$Post['Post_Id']]["Url"] = "https://eastcloud.ir/Blog?=" . $Post['Post_Url'];
$Data ['POST'][$Post['Post_Id']]["Name"] = $Post['Post_Name'];
$Data ['POST'][$Post['Post_Id']]["Date"] = $Post['Post_Date'];
$Data ['POST'][$Post['Post_Id']]["Author"] = $Post['Post_Author'];
$Data ['POST'][$Post['Post_Id']]["Image"] = "https://eastcloud.ir/" . $Post['Post_Image'];
$Data ['POST'][$Post['Post_Id']]["Tags"] = "https://eastcloud.ir/" . $Post['Post_Image'];
$ID++;
}


The given json is something like this:



POST
17
{
Id "17"
Url "https://eastcloud.ir/Blog?=Simplist-Documentations"
Name "Simplist Documentations"
Date "23 May, 2018"
Author "Milad"
Image "https://eastcloud.ir/Content/Shared/Posts/SimplistV2.png"
Tags "https://eastcloud.ir/Content/Shared/Posts/SimplistV2.png"
}


The loop will continue getting value and parsing them into JSON (The JSON file is available here) but if I want to use the given JSON here on Json2Sharp it tells invalid JSON file given.
What is the solution? How can I create a JSON from my database values with PHP?










share|improve this question




















  • 1





    You showed just loop of gathering data, not how you make json. And it's invalid. Keys must be enclosed with double-quote, then : and key-value pairs except last must end with , : {"Id": "17", "Url": "https://eastcloud.ir/Blog?=Simplist-Documentations"}. Best way is to use json_encode($Data)

    – Justinas
    Nov 13 '18 at 8:48













  • Something like this: $fp = fopen('Blog.json', 'w'); fwrite($fp, json_encode($Data)); fclose($fp);

    – Milad Xandi
    Nov 13 '18 at 8:50













  • The generated JSON is valid. What is your precise question? Is it about __invalid_type__…? Then why not mention it?!)

    – mario
    Nov 13 '18 at 8:51













  • The problem is here when I give this JSON to make its related C# classess.

    – Milad Xandi
    Nov 13 '18 at 8:56


















-1















I want to parse all of the returned values from a MySQL database into a JSON file. So I wrote my php side like this:



foreach ($Posts->Show() as $Key => $Post) {
$Data ['POST'][$Post['Post_Id']]["Id"]=$Post['Post_Id'];
$Data ['POST'][$Post['Post_Id']]["Url"] = "https://eastcloud.ir/Blog?=" . $Post['Post_Url'];
$Data ['POST'][$Post['Post_Id']]["Name"] = $Post['Post_Name'];
$Data ['POST'][$Post['Post_Id']]["Date"] = $Post['Post_Date'];
$Data ['POST'][$Post['Post_Id']]["Author"] = $Post['Post_Author'];
$Data ['POST'][$Post['Post_Id']]["Image"] = "https://eastcloud.ir/" . $Post['Post_Image'];
$Data ['POST'][$Post['Post_Id']]["Tags"] = "https://eastcloud.ir/" . $Post['Post_Image'];
$ID++;
}


The given json is something like this:



POST
17
{
Id "17"
Url "https://eastcloud.ir/Blog?=Simplist-Documentations"
Name "Simplist Documentations"
Date "23 May, 2018"
Author "Milad"
Image "https://eastcloud.ir/Content/Shared/Posts/SimplistV2.png"
Tags "https://eastcloud.ir/Content/Shared/Posts/SimplistV2.png"
}


The loop will continue getting value and parsing them into JSON (The JSON file is available here) but if I want to use the given JSON here on Json2Sharp it tells invalid JSON file given.
What is the solution? How can I create a JSON from my database values with PHP?










share|improve this question




















  • 1





    You showed just loop of gathering data, not how you make json. And it's invalid. Keys must be enclosed with double-quote, then : and key-value pairs except last must end with , : {"Id": "17", "Url": "https://eastcloud.ir/Blog?=Simplist-Documentations"}. Best way is to use json_encode($Data)

    – Justinas
    Nov 13 '18 at 8:48













  • Something like this: $fp = fopen('Blog.json', 'w'); fwrite($fp, json_encode($Data)); fclose($fp);

    – Milad Xandi
    Nov 13 '18 at 8:50













  • The generated JSON is valid. What is your precise question? Is it about __invalid_type__…? Then why not mention it?!)

    – mario
    Nov 13 '18 at 8:51













  • The problem is here when I give this JSON to make its related C# classess.

    – Milad Xandi
    Nov 13 '18 at 8:56
















-1












-1








-1








I want to parse all of the returned values from a MySQL database into a JSON file. So I wrote my php side like this:



foreach ($Posts->Show() as $Key => $Post) {
$Data ['POST'][$Post['Post_Id']]["Id"]=$Post['Post_Id'];
$Data ['POST'][$Post['Post_Id']]["Url"] = "https://eastcloud.ir/Blog?=" . $Post['Post_Url'];
$Data ['POST'][$Post['Post_Id']]["Name"] = $Post['Post_Name'];
$Data ['POST'][$Post['Post_Id']]["Date"] = $Post['Post_Date'];
$Data ['POST'][$Post['Post_Id']]["Author"] = $Post['Post_Author'];
$Data ['POST'][$Post['Post_Id']]["Image"] = "https://eastcloud.ir/" . $Post['Post_Image'];
$Data ['POST'][$Post['Post_Id']]["Tags"] = "https://eastcloud.ir/" . $Post['Post_Image'];
$ID++;
}


The given json is something like this:



POST
17
{
Id "17"
Url "https://eastcloud.ir/Blog?=Simplist-Documentations"
Name "Simplist Documentations"
Date "23 May, 2018"
Author "Milad"
Image "https://eastcloud.ir/Content/Shared/Posts/SimplistV2.png"
Tags "https://eastcloud.ir/Content/Shared/Posts/SimplistV2.png"
}


The loop will continue getting value and parsing them into JSON (The JSON file is available here) but if I want to use the given JSON here on Json2Sharp it tells invalid JSON file given.
What is the solution? How can I create a JSON from my database values with PHP?










share|improve this question
















I want to parse all of the returned values from a MySQL database into a JSON file. So I wrote my php side like this:



foreach ($Posts->Show() as $Key => $Post) {
$Data ['POST'][$Post['Post_Id']]["Id"]=$Post['Post_Id'];
$Data ['POST'][$Post['Post_Id']]["Url"] = "https://eastcloud.ir/Blog?=" . $Post['Post_Url'];
$Data ['POST'][$Post['Post_Id']]["Name"] = $Post['Post_Name'];
$Data ['POST'][$Post['Post_Id']]["Date"] = $Post['Post_Date'];
$Data ['POST'][$Post['Post_Id']]["Author"] = $Post['Post_Author'];
$Data ['POST'][$Post['Post_Id']]["Image"] = "https://eastcloud.ir/" . $Post['Post_Image'];
$Data ['POST'][$Post['Post_Id']]["Tags"] = "https://eastcloud.ir/" . $Post['Post_Image'];
$ID++;
}


The given json is something like this:



POST
17
{
Id "17"
Url "https://eastcloud.ir/Blog?=Simplist-Documentations"
Name "Simplist Documentations"
Date "23 May, 2018"
Author "Milad"
Image "https://eastcloud.ir/Content/Shared/Posts/SimplistV2.png"
Tags "https://eastcloud.ir/Content/Shared/Posts/SimplistV2.png"
}


The loop will continue getting value and parsing them into JSON (The JSON file is available here) but if I want to use the given JSON here on Json2Sharp it tells invalid JSON file given.
What is the solution? How can I create a JSON from my database values with PHP?







php json






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 13 '18 at 8:45









Justinas

27.1k33559




27.1k33559










asked Nov 13 '18 at 8:43









Milad XandiMilad Xandi

428




428








  • 1





    You showed just loop of gathering data, not how you make json. And it's invalid. Keys must be enclosed with double-quote, then : and key-value pairs except last must end with , : {"Id": "17", "Url": "https://eastcloud.ir/Blog?=Simplist-Documentations"}. Best way is to use json_encode($Data)

    – Justinas
    Nov 13 '18 at 8:48













  • Something like this: $fp = fopen('Blog.json', 'w'); fwrite($fp, json_encode($Data)); fclose($fp);

    – Milad Xandi
    Nov 13 '18 at 8:50













  • The generated JSON is valid. What is your precise question? Is it about __invalid_type__…? Then why not mention it?!)

    – mario
    Nov 13 '18 at 8:51













  • The problem is here when I give this JSON to make its related C# classess.

    – Milad Xandi
    Nov 13 '18 at 8:56
















  • 1





    You showed just loop of gathering data, not how you make json. And it's invalid. Keys must be enclosed with double-quote, then : and key-value pairs except last must end with , : {"Id": "17", "Url": "https://eastcloud.ir/Blog?=Simplist-Documentations"}. Best way is to use json_encode($Data)

    – Justinas
    Nov 13 '18 at 8:48













  • Something like this: $fp = fopen('Blog.json', 'w'); fwrite($fp, json_encode($Data)); fclose($fp);

    – Milad Xandi
    Nov 13 '18 at 8:50













  • The generated JSON is valid. What is your precise question? Is it about __invalid_type__…? Then why not mention it?!)

    – mario
    Nov 13 '18 at 8:51













  • The problem is here when I give this JSON to make its related C# classess.

    – Milad Xandi
    Nov 13 '18 at 8:56










1




1





You showed just loop of gathering data, not how you make json. And it's invalid. Keys must be enclosed with double-quote, then : and key-value pairs except last must end with , : {"Id": "17", "Url": "https://eastcloud.ir/Blog?=Simplist-Documentations"}. Best way is to use json_encode($Data)

– Justinas
Nov 13 '18 at 8:48







You showed just loop of gathering data, not how you make json. And it's invalid. Keys must be enclosed with double-quote, then : and key-value pairs except last must end with , : {"Id": "17", "Url": "https://eastcloud.ir/Blog?=Simplist-Documentations"}. Best way is to use json_encode($Data)

– Justinas
Nov 13 '18 at 8:48















Something like this: $fp = fopen('Blog.json', 'w'); fwrite($fp, json_encode($Data)); fclose($fp);

– Milad Xandi
Nov 13 '18 at 8:50







Something like this: $fp = fopen('Blog.json', 'w'); fwrite($fp, json_encode($Data)); fclose($fp);

– Milad Xandi
Nov 13 '18 at 8:50















The generated JSON is valid. What is your precise question? Is it about __invalid_type__…? Then why not mention it?!)

– mario
Nov 13 '18 at 8:51







The generated JSON is valid. What is your precise question? Is it about __invalid_type__…? Then why not mention it?!)

– mario
Nov 13 '18 at 8:51















The problem is here when I give this JSON to make its related C# classess.

– Milad Xandi
Nov 13 '18 at 8:56







The problem is here when I give this JSON to make its related C# classess.

– Milad Xandi
Nov 13 '18 at 8:56














3 Answers
3






active

oldest

votes


















0














Did you tried to use json_encode() method?



foreach ($Posts->Show() as $Key => $Post) {
$Data['POST'] = [
$Post['Post_Id'] = [
"Id" => $Post['Post_Id'],
"Url" => "https://eastcloud.ir/Blog?=" . $Post['Post_Url'],
"Name" => $Post['Post_Name'],
"Date" => $Post['Post_Date'],
"Author" => $Post['Post_Author'],
"Image" => "https://eastcloud.ir/" . $Post['Post_Image'],
"Tags" => "https://eastcloud.ir/" . $Post['Post_Image'],
],
];
$ID++;
}

// here is your json from db fetching loop
$json = json_encode($Data);


upd 1.0



Please check this JSON, which I generated based on your



{
"POST" : [
{
"Id": "17",
"Url": "https://eastcloud.ir/Blog?=Simplist-Documentations",
"Name": "Simplist Documentations",
"Date": "23 May, 2018",
"Author": "Milad",
"Image": "https://eastcloud.ir/Content/Shared/Posts/SimplistV2.png",
"Tags": "https://eastcloud.ir/Content/Shared/Posts/SimplistV2.png"
},
{
"Id": "18",
"Url": "https://eastcloud.ir/Blog?=angular-2-vs-react",
"Name": "انگیولار ۲ در مقابل ری‌اکت",
"Date": "23 May, 2018",
"Author": "Milad",
"Image": "https://eastcloud.ir/Content/Shared/Posts/432644.png",
"Tags": "https://eastcloud.ir/Content/Shared/Posts/432644.png"
}
]
}


Reponse from json2csharp



public class POST
{
public string Id { get; set; }
public string Url { get; set; }
public string Name { get; set; }
public string Date { get; set; }
public string Author { get; set; }
public string Image { get; set; }
public string Tags { get; set; }
}

public class RootObject
{
public List<POST> POST { get; set; }
}





share|improve this answer


























  • Sure. Also, I generated a JSON file here but the JSON is not valid to use on json2sharp

    – Milad Xandi
    Nov 13 '18 at 9:09











  • @MiladXandi Please check my upd 1.0. I've generated some similar array using Laravel and then used it for your tool and seems get a correct response from the json2shart service. Structure is a bit different, there are not lead Post_ID and all objects are wrapped in

    – alexey-novikov
    Nov 13 '18 at 9:38





















0














Use the json_encode for creating json. It is not the best way to create it
manually.



To understand what is wrong with your output, the correct JSON format of your data should look like this:



{
"Id":"17",
"Url":"https://eastcloud.ir/Blog?=Simplist-Documentations",
"Name":"Simplist Documentations",
"Date":"23 May, 2018",
"Author":"Milad",
"Image":"https://eastcloud.ir/Content/Shared/Posts/SimplistV2.png",
"Tags":"https://eastcloud.ir/Content/Shared/Posts/SimplistV2.png"
}


Take a closer look at the quotation marks and the double dots and comma after each not the last line.






share|improve this answer


























  • Even if I send those values directly for encoding, the result is not valid for json2sharp. here is the given result

    – Milad Xandi
    Nov 13 '18 at 8:54








  • 1





    @MiladXandi Actually it's valid JSON and your json2csharp works fine

    – Justinas
    Nov 13 '18 at 8:55











  • The output you have given is an array, not a JSON.

    – Diceros
    Nov 13 '18 at 8:56













  • @MiladXandi yep I just used the result from your link on json2csharp and it generates code, no errors. Perhaps it's not the code you wanted, but that's not the same thing as saying it isn't valid. If you're wondering, it creates classes called "invalid type" because you're using numbers as property names in your JSON...you can't make a C# class whose name starts with a number. Perhaps you should tell us what C# you were hoping to generate.

    – ADyson
    Nov 13 '18 at 9:25













  • @Diceros now I am editing this page to get a valid result

    – Milad Xandi
    Nov 13 '18 at 10:21



















-1














You can use json_encode() data from database






share|improve this answer























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    3 Answers
    3






    active

    oldest

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    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    Did you tried to use json_encode() method?



    foreach ($Posts->Show() as $Key => $Post) {
    $Data['POST'] = [
    $Post['Post_Id'] = [
    "Id" => $Post['Post_Id'],
    "Url" => "https://eastcloud.ir/Blog?=" . $Post['Post_Url'],
    "Name" => $Post['Post_Name'],
    "Date" => $Post['Post_Date'],
    "Author" => $Post['Post_Author'],
    "Image" => "https://eastcloud.ir/" . $Post['Post_Image'],
    "Tags" => "https://eastcloud.ir/" . $Post['Post_Image'],
    ],
    ];
    $ID++;
    }

    // here is your json from db fetching loop
    $json = json_encode($Data);


    upd 1.0



    Please check this JSON, which I generated based on your



    {
    "POST" : [
    {
    "Id": "17",
    "Url": "https://eastcloud.ir/Blog?=Simplist-Documentations",
    "Name": "Simplist Documentations",
    "Date": "23 May, 2018",
    "Author": "Milad",
    "Image": "https://eastcloud.ir/Content/Shared/Posts/SimplistV2.png",
    "Tags": "https://eastcloud.ir/Content/Shared/Posts/SimplistV2.png"
    },
    {
    "Id": "18",
    "Url": "https://eastcloud.ir/Blog?=angular-2-vs-react",
    "Name": "انگیولار ۲ در مقابل ری‌اکت",
    "Date": "23 May, 2018",
    "Author": "Milad",
    "Image": "https://eastcloud.ir/Content/Shared/Posts/432644.png",
    "Tags": "https://eastcloud.ir/Content/Shared/Posts/432644.png"
    }
    ]
    }


    Reponse from json2csharp



    public class POST
    {
    public string Id { get; set; }
    public string Url { get; set; }
    public string Name { get; set; }
    public string Date { get; set; }
    public string Author { get; set; }
    public string Image { get; set; }
    public string Tags { get; set; }
    }

    public class RootObject
    {
    public List<POST> POST { get; set; }
    }





    share|improve this answer


























    • Sure. Also, I generated a JSON file here but the JSON is not valid to use on json2sharp

      – Milad Xandi
      Nov 13 '18 at 9:09











    • @MiladXandi Please check my upd 1.0. I've generated some similar array using Laravel and then used it for your tool and seems get a correct response from the json2shart service. Structure is a bit different, there are not lead Post_ID and all objects are wrapped in

      – alexey-novikov
      Nov 13 '18 at 9:38


















    0














    Did you tried to use json_encode() method?



    foreach ($Posts->Show() as $Key => $Post) {
    $Data['POST'] = [
    $Post['Post_Id'] = [
    "Id" => $Post['Post_Id'],
    "Url" => "https://eastcloud.ir/Blog?=" . $Post['Post_Url'],
    "Name" => $Post['Post_Name'],
    "Date" => $Post['Post_Date'],
    "Author" => $Post['Post_Author'],
    "Image" => "https://eastcloud.ir/" . $Post['Post_Image'],
    "Tags" => "https://eastcloud.ir/" . $Post['Post_Image'],
    ],
    ];
    $ID++;
    }

    // here is your json from db fetching loop
    $json = json_encode($Data);


    upd 1.0



    Please check this JSON, which I generated based on your



    {
    "POST" : [
    {
    "Id": "17",
    "Url": "https://eastcloud.ir/Blog?=Simplist-Documentations",
    "Name": "Simplist Documentations",
    "Date": "23 May, 2018",
    "Author": "Milad",
    "Image": "https://eastcloud.ir/Content/Shared/Posts/SimplistV2.png",
    "Tags": "https://eastcloud.ir/Content/Shared/Posts/SimplistV2.png"
    },
    {
    "Id": "18",
    "Url": "https://eastcloud.ir/Blog?=angular-2-vs-react",
    "Name": "انگیولار ۲ در مقابل ری‌اکت",
    "Date": "23 May, 2018",
    "Author": "Milad",
    "Image": "https://eastcloud.ir/Content/Shared/Posts/432644.png",
    "Tags": "https://eastcloud.ir/Content/Shared/Posts/432644.png"
    }
    ]
    }


    Reponse from json2csharp



    public class POST
    {
    public string Id { get; set; }
    public string Url { get; set; }
    public string Name { get; set; }
    public string Date { get; set; }
    public string Author { get; set; }
    public string Image { get; set; }
    public string Tags { get; set; }
    }

    public class RootObject
    {
    public List<POST> POST { get; set; }
    }





    share|improve this answer


























    • Sure. Also, I generated a JSON file here but the JSON is not valid to use on json2sharp

      – Milad Xandi
      Nov 13 '18 at 9:09











    • @MiladXandi Please check my upd 1.0. I've generated some similar array using Laravel and then used it for your tool and seems get a correct response from the json2shart service. Structure is a bit different, there are not lead Post_ID and all objects are wrapped in

      – alexey-novikov
      Nov 13 '18 at 9:38
















    0












    0








    0







    Did you tried to use json_encode() method?



    foreach ($Posts->Show() as $Key => $Post) {
    $Data['POST'] = [
    $Post['Post_Id'] = [
    "Id" => $Post['Post_Id'],
    "Url" => "https://eastcloud.ir/Blog?=" . $Post['Post_Url'],
    "Name" => $Post['Post_Name'],
    "Date" => $Post['Post_Date'],
    "Author" => $Post['Post_Author'],
    "Image" => "https://eastcloud.ir/" . $Post['Post_Image'],
    "Tags" => "https://eastcloud.ir/" . $Post['Post_Image'],
    ],
    ];
    $ID++;
    }

    // here is your json from db fetching loop
    $json = json_encode($Data);


    upd 1.0



    Please check this JSON, which I generated based on your



    {
    "POST" : [
    {
    "Id": "17",
    "Url": "https://eastcloud.ir/Blog?=Simplist-Documentations",
    "Name": "Simplist Documentations",
    "Date": "23 May, 2018",
    "Author": "Milad",
    "Image": "https://eastcloud.ir/Content/Shared/Posts/SimplistV2.png",
    "Tags": "https://eastcloud.ir/Content/Shared/Posts/SimplistV2.png"
    },
    {
    "Id": "18",
    "Url": "https://eastcloud.ir/Blog?=angular-2-vs-react",
    "Name": "انگیولار ۲ در مقابل ری‌اکت",
    "Date": "23 May, 2018",
    "Author": "Milad",
    "Image": "https://eastcloud.ir/Content/Shared/Posts/432644.png",
    "Tags": "https://eastcloud.ir/Content/Shared/Posts/432644.png"
    }
    ]
    }


    Reponse from json2csharp



    public class POST
    {
    public string Id { get; set; }
    public string Url { get; set; }
    public string Name { get; set; }
    public string Date { get; set; }
    public string Author { get; set; }
    public string Image { get; set; }
    public string Tags { get; set; }
    }

    public class RootObject
    {
    public List<POST> POST { get; set; }
    }





    share|improve this answer















    Did you tried to use json_encode() method?



    foreach ($Posts->Show() as $Key => $Post) {
    $Data['POST'] = [
    $Post['Post_Id'] = [
    "Id" => $Post['Post_Id'],
    "Url" => "https://eastcloud.ir/Blog?=" . $Post['Post_Url'],
    "Name" => $Post['Post_Name'],
    "Date" => $Post['Post_Date'],
    "Author" => $Post['Post_Author'],
    "Image" => "https://eastcloud.ir/" . $Post['Post_Image'],
    "Tags" => "https://eastcloud.ir/" . $Post['Post_Image'],
    ],
    ];
    $ID++;
    }

    // here is your json from db fetching loop
    $json = json_encode($Data);


    upd 1.0



    Please check this JSON, which I generated based on your



    {
    "POST" : [
    {
    "Id": "17",
    "Url": "https://eastcloud.ir/Blog?=Simplist-Documentations",
    "Name": "Simplist Documentations",
    "Date": "23 May, 2018",
    "Author": "Milad",
    "Image": "https://eastcloud.ir/Content/Shared/Posts/SimplistV2.png",
    "Tags": "https://eastcloud.ir/Content/Shared/Posts/SimplistV2.png"
    },
    {
    "Id": "18",
    "Url": "https://eastcloud.ir/Blog?=angular-2-vs-react",
    "Name": "انگیولار ۲ در مقابل ری‌اکت",
    "Date": "23 May, 2018",
    "Author": "Milad",
    "Image": "https://eastcloud.ir/Content/Shared/Posts/432644.png",
    "Tags": "https://eastcloud.ir/Content/Shared/Posts/432644.png"
    }
    ]
    }


    Reponse from json2csharp



    public class POST
    {
    public string Id { get; set; }
    public string Url { get; set; }
    public string Name { get; set; }
    public string Date { get; set; }
    public string Author { get; set; }
    public string Image { get; set; }
    public string Tags { get; set; }
    }

    public class RootObject
    {
    public List<POST> POST { get; set; }
    }






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Nov 13 '18 at 9:36

























    answered Nov 13 '18 at 8:57









    alexey-novikovalexey-novikov

    898




    898













    • Sure. Also, I generated a JSON file here but the JSON is not valid to use on json2sharp

      – Milad Xandi
      Nov 13 '18 at 9:09











    • @MiladXandi Please check my upd 1.0. I've generated some similar array using Laravel and then used it for your tool and seems get a correct response from the json2shart service. Structure is a bit different, there are not lead Post_ID and all objects are wrapped in

      – alexey-novikov
      Nov 13 '18 at 9:38





















    • Sure. Also, I generated a JSON file here but the JSON is not valid to use on json2sharp

      – Milad Xandi
      Nov 13 '18 at 9:09











    • @MiladXandi Please check my upd 1.0. I've generated some similar array using Laravel and then used it for your tool and seems get a correct response from the json2shart service. Structure is a bit different, there are not lead Post_ID and all objects are wrapped in

      – alexey-novikov
      Nov 13 '18 at 9:38



















    Sure. Also, I generated a JSON file here but the JSON is not valid to use on json2sharp

    – Milad Xandi
    Nov 13 '18 at 9:09





    Sure. Also, I generated a JSON file here but the JSON is not valid to use on json2sharp

    – Milad Xandi
    Nov 13 '18 at 9:09













    @MiladXandi Please check my upd 1.0. I've generated some similar array using Laravel and then used it for your tool and seems get a correct response from the json2shart service. Structure is a bit different, there are not lead Post_ID and all objects are wrapped in

    – alexey-novikov
    Nov 13 '18 at 9:38







    @MiladXandi Please check my upd 1.0. I've generated some similar array using Laravel and then used it for your tool and seems get a correct response from the json2shart service. Structure is a bit different, there are not lead Post_ID and all objects are wrapped in

    – alexey-novikov
    Nov 13 '18 at 9:38















    0














    Use the json_encode for creating json. It is not the best way to create it
    manually.



    To understand what is wrong with your output, the correct JSON format of your data should look like this:



    {
    "Id":"17",
    "Url":"https://eastcloud.ir/Blog?=Simplist-Documentations",
    "Name":"Simplist Documentations",
    "Date":"23 May, 2018",
    "Author":"Milad",
    "Image":"https://eastcloud.ir/Content/Shared/Posts/SimplistV2.png",
    "Tags":"https://eastcloud.ir/Content/Shared/Posts/SimplistV2.png"
    }


    Take a closer look at the quotation marks and the double dots and comma after each not the last line.






    share|improve this answer


























    • Even if I send those values directly for encoding, the result is not valid for json2sharp. here is the given result

      – Milad Xandi
      Nov 13 '18 at 8:54








    • 1





      @MiladXandi Actually it's valid JSON and your json2csharp works fine

      – Justinas
      Nov 13 '18 at 8:55











    • The output you have given is an array, not a JSON.

      – Diceros
      Nov 13 '18 at 8:56













    • @MiladXandi yep I just used the result from your link on json2csharp and it generates code, no errors. Perhaps it's not the code you wanted, but that's not the same thing as saying it isn't valid. If you're wondering, it creates classes called "invalid type" because you're using numbers as property names in your JSON...you can't make a C# class whose name starts with a number. Perhaps you should tell us what C# you were hoping to generate.

      – ADyson
      Nov 13 '18 at 9:25













    • @Diceros now I am editing this page to get a valid result

      – Milad Xandi
      Nov 13 '18 at 10:21
















    0














    Use the json_encode for creating json. It is not the best way to create it
    manually.



    To understand what is wrong with your output, the correct JSON format of your data should look like this:



    {
    "Id":"17",
    "Url":"https://eastcloud.ir/Blog?=Simplist-Documentations",
    "Name":"Simplist Documentations",
    "Date":"23 May, 2018",
    "Author":"Milad",
    "Image":"https://eastcloud.ir/Content/Shared/Posts/SimplistV2.png",
    "Tags":"https://eastcloud.ir/Content/Shared/Posts/SimplistV2.png"
    }


    Take a closer look at the quotation marks and the double dots and comma after each not the last line.






    share|improve this answer


























    • Even if I send those values directly for encoding, the result is not valid for json2sharp. here is the given result

      – Milad Xandi
      Nov 13 '18 at 8:54








    • 1





      @MiladXandi Actually it's valid JSON and your json2csharp works fine

      – Justinas
      Nov 13 '18 at 8:55











    • The output you have given is an array, not a JSON.

      – Diceros
      Nov 13 '18 at 8:56













    • @MiladXandi yep I just used the result from your link on json2csharp and it generates code, no errors. Perhaps it's not the code you wanted, but that's not the same thing as saying it isn't valid. If you're wondering, it creates classes called "invalid type" because you're using numbers as property names in your JSON...you can't make a C# class whose name starts with a number. Perhaps you should tell us what C# you were hoping to generate.

      – ADyson
      Nov 13 '18 at 9:25













    • @Diceros now I am editing this page to get a valid result

      – Milad Xandi
      Nov 13 '18 at 10:21














    0












    0








    0







    Use the json_encode for creating json. It is not the best way to create it
    manually.



    To understand what is wrong with your output, the correct JSON format of your data should look like this:



    {
    "Id":"17",
    "Url":"https://eastcloud.ir/Blog?=Simplist-Documentations",
    "Name":"Simplist Documentations",
    "Date":"23 May, 2018",
    "Author":"Milad",
    "Image":"https://eastcloud.ir/Content/Shared/Posts/SimplistV2.png",
    "Tags":"https://eastcloud.ir/Content/Shared/Posts/SimplistV2.png"
    }


    Take a closer look at the quotation marks and the double dots and comma after each not the last line.






    share|improve this answer















    Use the json_encode for creating json. It is not the best way to create it
    manually.



    To understand what is wrong with your output, the correct JSON format of your data should look like this:



    {
    "Id":"17",
    "Url":"https://eastcloud.ir/Blog?=Simplist-Documentations",
    "Name":"Simplist Documentations",
    "Date":"23 May, 2018",
    "Author":"Milad",
    "Image":"https://eastcloud.ir/Content/Shared/Posts/SimplistV2.png",
    "Tags":"https://eastcloud.ir/Content/Shared/Posts/SimplistV2.png"
    }


    Take a closer look at the quotation marks and the double dots and comma after each not the last line.







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Nov 13 '18 at 8:53

























    answered Nov 13 '18 at 8:47









    DicerosDiceros

    13




    13













    • Even if I send those values directly for encoding, the result is not valid for json2sharp. here is the given result

      – Milad Xandi
      Nov 13 '18 at 8:54








    • 1





      @MiladXandi Actually it's valid JSON and your json2csharp works fine

      – Justinas
      Nov 13 '18 at 8:55











    • The output you have given is an array, not a JSON.

      – Diceros
      Nov 13 '18 at 8:56













    • @MiladXandi yep I just used the result from your link on json2csharp and it generates code, no errors. Perhaps it's not the code you wanted, but that's not the same thing as saying it isn't valid. If you're wondering, it creates classes called "invalid type" because you're using numbers as property names in your JSON...you can't make a C# class whose name starts with a number. Perhaps you should tell us what C# you were hoping to generate.

      – ADyson
      Nov 13 '18 at 9:25













    • @Diceros now I am editing this page to get a valid result

      – Milad Xandi
      Nov 13 '18 at 10:21



















    • Even if I send those values directly for encoding, the result is not valid for json2sharp. here is the given result

      – Milad Xandi
      Nov 13 '18 at 8:54








    • 1





      @MiladXandi Actually it's valid JSON and your json2csharp works fine

      – Justinas
      Nov 13 '18 at 8:55











    • The output you have given is an array, not a JSON.

      – Diceros
      Nov 13 '18 at 8:56













    • @MiladXandi yep I just used the result from your link on json2csharp and it generates code, no errors. Perhaps it's not the code you wanted, but that's not the same thing as saying it isn't valid. If you're wondering, it creates classes called "invalid type" because you're using numbers as property names in your JSON...you can't make a C# class whose name starts with a number. Perhaps you should tell us what C# you were hoping to generate.

      – ADyson
      Nov 13 '18 at 9:25













    • @Diceros now I am editing this page to get a valid result

      – Milad Xandi
      Nov 13 '18 at 10:21

















    Even if I send those values directly for encoding, the result is not valid for json2sharp. here is the given result

    – Milad Xandi
    Nov 13 '18 at 8:54







    Even if I send those values directly for encoding, the result is not valid for json2sharp. here is the given result

    – Milad Xandi
    Nov 13 '18 at 8:54






    1




    1





    @MiladXandi Actually it's valid JSON and your json2csharp works fine

    – Justinas
    Nov 13 '18 at 8:55





    @MiladXandi Actually it's valid JSON and your json2csharp works fine

    – Justinas
    Nov 13 '18 at 8:55













    The output you have given is an array, not a JSON.

    – Diceros
    Nov 13 '18 at 8:56







    The output you have given is an array, not a JSON.

    – Diceros
    Nov 13 '18 at 8:56















    @MiladXandi yep I just used the result from your link on json2csharp and it generates code, no errors. Perhaps it's not the code you wanted, but that's not the same thing as saying it isn't valid. If you're wondering, it creates classes called "invalid type" because you're using numbers as property names in your JSON...you can't make a C# class whose name starts with a number. Perhaps you should tell us what C# you were hoping to generate.

    – ADyson
    Nov 13 '18 at 9:25







    @MiladXandi yep I just used the result from your link on json2csharp and it generates code, no errors. Perhaps it's not the code you wanted, but that's not the same thing as saying it isn't valid. If you're wondering, it creates classes called "invalid type" because you're using numbers as property names in your JSON...you can't make a C# class whose name starts with a number. Perhaps you should tell us what C# you were hoping to generate.

    – ADyson
    Nov 13 '18 at 9:25















    @Diceros now I am editing this page to get a valid result

    – Milad Xandi
    Nov 13 '18 at 10:21





    @Diceros now I am editing this page to get a valid result

    – Milad Xandi
    Nov 13 '18 at 10:21











    -1














    You can use json_encode() data from database






    share|improve this answer




























      -1














      You can use json_encode() data from database






      share|improve this answer


























        -1












        -1








        -1







        You can use json_encode() data from database






        share|improve this answer













        You can use json_encode() data from database







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 13 '18 at 9:09









        TP.ARMTP.ARM

        41




        41






























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