How to select a specific value from a table












1















I'm trying to make an code for each file I have. My problem is that I cannot use:



for(int i =0 .... i++)


I do not want to check every line in the table, I want to check a specific file, and I need the code for that specific file.



#include <iostream>

using namespace std;

int main ()
{

static struct CHECKFILE
{
const char *s_File;
const char *s_SpecialCode;
} s_check_code = {
"file_1" , "code_1"
"file_2" , "code_2"
"file_3" , "code_3"
"file_4" , "code_4"
"file_5" , "code_5"
};


std::string str;
str.append(s_check_code[file_1].s_SpecialCode);

std::cout << str << 'n';

return 0;
}









share|improve this question




















  • 3





    What you need is to study C++'s basics, before moving on...

    – gsamaras
    Nov 19 '18 at 8:20











  • Maybe, but i know if i do something like this prntscr.com/lk4b6x will work but i wander if is posibile to do it without checking every line.

    – Denis
    Nov 19 '18 at 8:26













  • Ofcourse you can do that. With "file_1" instead of file_1 and you need the right associative container. You can checkout std::map or std::unordered_map . Which one is right might depend on you application.

    – hetepeperfan
    Nov 19 '18 at 8:33











  • Yep, i didn't know about <map>. Thank you.

    – Denis
    Nov 19 '18 at 8:39











  • Or use s_check_code[0]. C++ arrays are zero indexed. If you want mapping from string to content use std::(unordered_)map.

    – gast128
    Nov 19 '18 at 8:57
















1















I'm trying to make an code for each file I have. My problem is that I cannot use:



for(int i =0 .... i++)


I do not want to check every line in the table, I want to check a specific file, and I need the code for that specific file.



#include <iostream>

using namespace std;

int main ()
{

static struct CHECKFILE
{
const char *s_File;
const char *s_SpecialCode;
} s_check_code = {
"file_1" , "code_1"
"file_2" , "code_2"
"file_3" , "code_3"
"file_4" , "code_4"
"file_5" , "code_5"
};


std::string str;
str.append(s_check_code[file_1].s_SpecialCode);

std::cout << str << 'n';

return 0;
}









share|improve this question




















  • 3





    What you need is to study C++'s basics, before moving on...

    – gsamaras
    Nov 19 '18 at 8:20











  • Maybe, but i know if i do something like this prntscr.com/lk4b6x will work but i wander if is posibile to do it without checking every line.

    – Denis
    Nov 19 '18 at 8:26













  • Ofcourse you can do that. With "file_1" instead of file_1 and you need the right associative container. You can checkout std::map or std::unordered_map . Which one is right might depend on you application.

    – hetepeperfan
    Nov 19 '18 at 8:33











  • Yep, i didn't know about <map>. Thank you.

    – Denis
    Nov 19 '18 at 8:39











  • Or use s_check_code[0]. C++ arrays are zero indexed. If you want mapping from string to content use std::(unordered_)map.

    – gast128
    Nov 19 '18 at 8:57














1












1








1








I'm trying to make an code for each file I have. My problem is that I cannot use:



for(int i =0 .... i++)


I do not want to check every line in the table, I want to check a specific file, and I need the code for that specific file.



#include <iostream>

using namespace std;

int main ()
{

static struct CHECKFILE
{
const char *s_File;
const char *s_SpecialCode;
} s_check_code = {
"file_1" , "code_1"
"file_2" , "code_2"
"file_3" , "code_3"
"file_4" , "code_4"
"file_5" , "code_5"
};


std::string str;
str.append(s_check_code[file_1].s_SpecialCode);

std::cout << str << 'n';

return 0;
}









share|improve this question
















I'm trying to make an code for each file I have. My problem is that I cannot use:



for(int i =0 .... i++)


I do not want to check every line in the table, I want to check a specific file, and I need the code for that specific file.



#include <iostream>

using namespace std;

int main ()
{

static struct CHECKFILE
{
const char *s_File;
const char *s_SpecialCode;
} s_check_code = {
"file_1" , "code_1"
"file_2" , "code_2"
"file_3" , "code_3"
"file_4" , "code_4"
"file_5" , "code_5"
};


std::string str;
str.append(s_check_code[file_1].s_SpecialCode);

std::cout << str << 'n';

return 0;
}






c++






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share|improve this question













share|improve this question




share|improve this question








edited Nov 19 '18 at 8:47









Cœur

18.1k9108148




18.1k9108148










asked Nov 19 '18 at 8:17









DenisDenis

253




253








  • 3





    What you need is to study C++'s basics, before moving on...

    – gsamaras
    Nov 19 '18 at 8:20











  • Maybe, but i know if i do something like this prntscr.com/lk4b6x will work but i wander if is posibile to do it without checking every line.

    – Denis
    Nov 19 '18 at 8:26













  • Ofcourse you can do that. With "file_1" instead of file_1 and you need the right associative container. You can checkout std::map or std::unordered_map . Which one is right might depend on you application.

    – hetepeperfan
    Nov 19 '18 at 8:33











  • Yep, i didn't know about <map>. Thank you.

    – Denis
    Nov 19 '18 at 8:39











  • Or use s_check_code[0]. C++ arrays are zero indexed. If you want mapping from string to content use std::(unordered_)map.

    – gast128
    Nov 19 '18 at 8:57














  • 3





    What you need is to study C++'s basics, before moving on...

    – gsamaras
    Nov 19 '18 at 8:20











  • Maybe, but i know if i do something like this prntscr.com/lk4b6x will work but i wander if is posibile to do it without checking every line.

    – Denis
    Nov 19 '18 at 8:26













  • Ofcourse you can do that. With "file_1" instead of file_1 and you need the right associative container. You can checkout std::map or std::unordered_map . Which one is right might depend on you application.

    – hetepeperfan
    Nov 19 '18 at 8:33











  • Yep, i didn't know about <map>. Thank you.

    – Denis
    Nov 19 '18 at 8:39











  • Or use s_check_code[0]. C++ arrays are zero indexed. If you want mapping from string to content use std::(unordered_)map.

    – gast128
    Nov 19 '18 at 8:57








3




3





What you need is to study C++'s basics, before moving on...

– gsamaras
Nov 19 '18 at 8:20





What you need is to study C++'s basics, before moving on...

– gsamaras
Nov 19 '18 at 8:20













Maybe, but i know if i do something like this prntscr.com/lk4b6x will work but i wander if is posibile to do it without checking every line.

– Denis
Nov 19 '18 at 8:26







Maybe, but i know if i do something like this prntscr.com/lk4b6x will work but i wander if is posibile to do it without checking every line.

– Denis
Nov 19 '18 at 8:26















Ofcourse you can do that. With "file_1" instead of file_1 and you need the right associative container. You can checkout std::map or std::unordered_map . Which one is right might depend on you application.

– hetepeperfan
Nov 19 '18 at 8:33





Ofcourse you can do that. With "file_1" instead of file_1 and you need the right associative container. You can checkout std::map or std::unordered_map . Which one is right might depend on you application.

– hetepeperfan
Nov 19 '18 at 8:33













Yep, i didn't know about <map>. Thank you.

– Denis
Nov 19 '18 at 8:39





Yep, i didn't know about <map>. Thank you.

– Denis
Nov 19 '18 at 8:39













Or use s_check_code[0]. C++ arrays are zero indexed. If you want mapping from string to content use std::(unordered_)map.

– gast128
Nov 19 '18 at 8:57





Or use s_check_code[0]. C++ arrays are zero indexed. If you want mapping from string to content use std::(unordered_)map.

– gast128
Nov 19 '18 at 8:57












1 Answer
1






active

oldest

votes


















3














Use a std::map of std::string to do this.



#include <iostream>
#include <map>

int main ()
{

std::map<std::string, std::string> myMap = {
{"file_1" , "code_1"},
{"file_2" , "code_2"},
{"file_3" , "code_3"},
{"file_4" , "code_4"},
{"file_5" , "code_5"}
};

std::string str;
str.append(myMap["file_1"]);

std::cout << str << 'n';

return 0;
}


See it live here.






share|improve this answer
























  • Ohh I see, thank you very much.

    – Denis
    Nov 19 '18 at 8:33











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









3














Use a std::map of std::string to do this.



#include <iostream>
#include <map>

int main ()
{

std::map<std::string, std::string> myMap = {
{"file_1" , "code_1"},
{"file_2" , "code_2"},
{"file_3" , "code_3"},
{"file_4" , "code_4"},
{"file_5" , "code_5"}
};

std::string str;
str.append(myMap["file_1"]);

std::cout << str << 'n';

return 0;
}


See it live here.






share|improve this answer
























  • Ohh I see, thank you very much.

    – Denis
    Nov 19 '18 at 8:33
















3














Use a std::map of std::string to do this.



#include <iostream>
#include <map>

int main ()
{

std::map<std::string, std::string> myMap = {
{"file_1" , "code_1"},
{"file_2" , "code_2"},
{"file_3" , "code_3"},
{"file_4" , "code_4"},
{"file_5" , "code_5"}
};

std::string str;
str.append(myMap["file_1"]);

std::cout << str << 'n';

return 0;
}


See it live here.






share|improve this answer
























  • Ohh I see, thank you very much.

    – Denis
    Nov 19 '18 at 8:33














3












3








3







Use a std::map of std::string to do this.



#include <iostream>
#include <map>

int main ()
{

std::map<std::string, std::string> myMap = {
{"file_1" , "code_1"},
{"file_2" , "code_2"},
{"file_3" , "code_3"},
{"file_4" , "code_4"},
{"file_5" , "code_5"}
};

std::string str;
str.append(myMap["file_1"]);

std::cout << str << 'n';

return 0;
}


See it live here.






share|improve this answer













Use a std::map of std::string to do this.



#include <iostream>
#include <map>

int main ()
{

std::map<std::string, std::string> myMap = {
{"file_1" , "code_1"},
{"file_2" , "code_2"},
{"file_3" , "code_3"},
{"file_4" , "code_4"},
{"file_5" , "code_5"}
};

std::string str;
str.append(myMap["file_1"]);

std::cout << str << 'n';

return 0;
}


See it live here.







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 19 '18 at 8:26









P.WP.W

13.8k31247




13.8k31247













  • Ohh I see, thank you very much.

    – Denis
    Nov 19 '18 at 8:33



















  • Ohh I see, thank you very much.

    – Denis
    Nov 19 '18 at 8:33

















Ohh I see, thank you very much.

– Denis
Nov 19 '18 at 8:33





Ohh I see, thank you very much.

– Denis
Nov 19 '18 at 8:33




















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