JavaScript Function Skipping

I have a script that should run a function every 5 seconds depending on what one was previously run however it seems to be skipping every second one.

let i = 0;

function testOne()

{

    $("#two").fadeOut().css("display","none");

    $("#three").fadeOut().css("display","none");

    $("#four").fadeOut().css("display","none");

    $("#five").fadeOut().css("display","none");

    $("#one").fadeIn().css("display","block");

    $("#iOne").addClass("btn-active");

    $("#iTwo").removeClass("btn-active");

    $("#iThree").removeClass("btn-active");

    $("#iFour").removeClass("btn-active");

    $("#iFive").removeClass("btn-active");

    i++;

}

function testTwo() {

    $("#one").fadeOut().css("display","none");

    $("#three").fadeOut().css("display","none");

    $("#four").fadeOut().css("display","none");

    $("#five").fadeOut().css("display","none");

    $("#two").fadeIn().css("display","block");

    $("#iTwo").addClass("btn-active");

    $("#iOne").removeClass("btn-active");

    $("#iThree").removeClass("btn-active");

    $("#iFour").removeClass("btn-active");

    $("#iFive").removeClass("btn-active");

    i++;

}

function testThree() {

    $("#one").fadeOut().css("display","none");

    $("#two").fadeOut().css("display","none");

    $("#four").fadeOut().css("display","none");

    $("#five").fadeOut().css("display","none");

    $("#three").fadeIn().css("display","block");

    $("#iThree").addClass("btn-active");

    $("#iTwo").removeClass("btn-active");

    $("#iOne").removeClass("btn-active");

    $("#iFour").removeClass("btn-active");

    $("#iFive").removeClass("btn-active");

    i++;

}

function testFour() {

    $("#one").fadeOut().css("display","none");

    $("#two").fadeOut().css("display","none");

    $("#three").fadeOut().css("display","none");

    $("#five").fadeOut().css("display","none");

    $("#four").fadeIn().css("display","block");

    $("#iFour").addClass("btn-active");

    $("#iTwo").removeClass("btn-active");

    $("#iThree").removeClass("btn-active");

    $("#iOne").removeClass("btn-active");

    $("#iFive").removeClass("btn-active");

    i++;

}

function testFive() {

    $("#one").fadeOut().css("display","none");

    $("#two").fadeOut().css("display","none");

    $("#three").fadeOut().css("display","none");

    $("#four").fadeOut().css("display","none");

    $("#five").fadeIn().css("display","block");

    $("#iFive").addClass("btn-active");

    $("#iTwo").removeClass("btn-active");

    $("#iThree").removeClass("btn-active");

    $("#iFour").removeClass("btn-active");

    $("#iOne").removeClass("btn-active");

    i = 0;

}

window.setInterval(function()

    {



        if(i === 0) {

            testOne();

            i++;

        } else if (i === 1) {

            testTwo();

            i++;

        } else if (i === 2) {

            testThree();

            i++;

        } else if (i === 3) {

            testFour();

            i++;

        } else if (i === 4) {

            testFive();

            let i = 0;

        }



    }, 5000);

The functions are displayed after "let i = 0" however I chose not to put them in as they are too long. All they do is run some jQuery code before i++; or let i = 0; on the fifth function.

Do you know why this could be the issue?

Full JS Code - https://hastebin.com/icalefafoy.js

Ben J

edited Nov 20 '18 at 19:08

zfrisch

4,57511024

asked Nov 20 '18 at 18:54

Ben J

let i = 0; -> i = 0;, otherwise looks good, maybe you call the whole code more than once?

– Jonas Wilms
Nov 20 '18 at 18:57

I tried that but still the same error.

– Ben J
Nov 20 '18 at 18:59

1

It works just fine aside from what Jonas pointed out. I'm unable to duplicate jsfiddle.net/pzejvrfc/1

– zfrisch
Nov 20 '18 at 18:59

Forgot to mention. It takes double the time the setInterval should take before skipping the code.

– Ben J
Nov 20 '18 at 19:00

@BenJ Okay, but the function isn't or is skipping for you? You have to be more specific with what the problem is - and since we can't duplicate, please show us more of your code.

– zfrisch
Nov 20 '18 at 19:03

|
show 1 more comment

I have a script that should run a function every 5 seconds depending on what one was previously run however it seems to be skipping every second one.

let i = 0;

function testOne()

{

    $("#two").fadeOut().css("display","none");

    $("#three").fadeOut().css("display","none");

    $("#four").fadeOut().css("display","none");

    $("#five").fadeOut().css("display","none");

    $("#one").fadeIn().css("display","block");

    $("#iOne").addClass("btn-active");

    $("#iTwo").removeClass("btn-active");

    $("#iThree").removeClass("btn-active");

    $("#iFour").removeClass("btn-active");

    $("#iFive").removeClass("btn-active");

    i++;

}

function testTwo() {

    $("#one").fadeOut().css("display","none");

    $("#three").fadeOut().css("display","none");

    $("#four").fadeOut().css("display","none");

    $("#five").fadeOut().css("display","none");

    $("#two").fadeIn().css("display","block");

    $("#iTwo").addClass("btn-active");

    $("#iOne").removeClass("btn-active");

    $("#iThree").removeClass("btn-active");

    $("#iFour").removeClass("btn-active");

    $("#iFive").removeClass("btn-active");

    i++;

}

function testThree() {

    $("#one").fadeOut().css("display","none");

    $("#two").fadeOut().css("display","none");

    $("#four").fadeOut().css("display","none");

    $("#five").fadeOut().css("display","none");

    $("#three").fadeIn().css("display","block");

    $("#iThree").addClass("btn-active");

    $("#iTwo").removeClass("btn-active");

    $("#iOne").removeClass("btn-active");

    $("#iFour").removeClass("btn-active");

    $("#iFive").removeClass("btn-active");

    i++;

}

function testFour() {

    $("#one").fadeOut().css("display","none");

    $("#two").fadeOut().css("display","none");

    $("#three").fadeOut().css("display","none");

    $("#five").fadeOut().css("display","none");

    $("#four").fadeIn().css("display","block");

    $("#iFour").addClass("btn-active");

    $("#iTwo").removeClass("btn-active");

    $("#iThree").removeClass("btn-active");

    $("#iOne").removeClass("btn-active");

    $("#iFive").removeClass("btn-active");

    i++;

}

function testFive() {

    $("#one").fadeOut().css("display","none");

    $("#two").fadeOut().css("display","none");

    $("#three").fadeOut().css("display","none");

    $("#four").fadeOut().css("display","none");

    $("#five").fadeIn().css("display","block");

    $("#iFive").addClass("btn-active");

    $("#iTwo").removeClass("btn-active");

    $("#iThree").removeClass("btn-active");

    $("#iFour").removeClass("btn-active");

    $("#iOne").removeClass("btn-active");

    i = 0;

}

window.setInterval(function()

    {



        if(i === 0) {

            testOne();

            i++;

        } else if (i === 1) {

            testTwo();

            i++;

        } else if (i === 2) {

            testThree();

            i++;

        } else if (i === 3) {

            testFour();

            i++;

        } else if (i === 4) {

            testFive();

            let i = 0;

        }



    }, 5000);

The functions are displayed after "let i = 0" however I chose not to put them in as they are too long. All they do is run some jQuery code before i++; or let i = 0; on the fifth function.

Do you know why this could be the issue?

Full JS Code - https://hastebin.com/icalefafoy.js

Ben J

edited Nov 20 '18 at 19:08

zfrisch

4,57511024

asked Nov 20 '18 at 18:54

Ben J

let i = 0; -> i = 0;, otherwise looks good, maybe you call the whole code more than once?

– Jonas Wilms
Nov 20 '18 at 18:57

I tried that but still the same error.

– Ben J
Nov 20 '18 at 18:59

1

It works just fine aside from what Jonas pointed out. I'm unable to duplicate jsfiddle.net/pzejvrfc/1

– zfrisch
Nov 20 '18 at 18:59

Forgot to mention. It takes double the time the setInterval should take before skipping the code.

– Ben J
Nov 20 '18 at 19:00

@BenJ Okay, but the function isn't or is skipping for you? You have to be more specific with what the problem is - and since we can't duplicate, please show us more of your code.

– zfrisch
Nov 20 '18 at 19:03

|
show 1 more comment

I have a script that should run a function every 5 seconds depending on what one was previously run however it seems to be skipping every second one.

let i = 0;

function testOne()

{

    $("#two").fadeOut().css("display","none");

    $("#three").fadeOut().css("display","none");

    $("#four").fadeOut().css("display","none");

    $("#five").fadeOut().css("display","none");

    $("#one").fadeIn().css("display","block");

    $("#iOne").addClass("btn-active");

    $("#iTwo").removeClass("btn-active");

    $("#iThree").removeClass("btn-active");

    $("#iFour").removeClass("btn-active");

    $("#iFive").removeClass("btn-active");

    i++;

}

function testTwo() {

    $("#one").fadeOut().css("display","none");

    $("#three").fadeOut().css("display","none");

    $("#four").fadeOut().css("display","none");

    $("#five").fadeOut().css("display","none");

    $("#two").fadeIn().css("display","block");

    $("#iTwo").addClass("btn-active");

    $("#iOne").removeClass("btn-active");

    $("#iThree").removeClass("btn-active");

    $("#iFour").removeClass("btn-active");

    $("#iFive").removeClass("btn-active");

    i++;

}

function testThree() {

    $("#one").fadeOut().css("display","none");

    $("#two").fadeOut().css("display","none");

    $("#four").fadeOut().css("display","none");

    $("#five").fadeOut().css("display","none");

    $("#three").fadeIn().css("display","block");

    $("#iThree").addClass("btn-active");

    $("#iTwo").removeClass("btn-active");

    $("#iOne").removeClass("btn-active");

    $("#iFour").removeClass("btn-active");

    $("#iFive").removeClass("btn-active");

    i++;

}

function testFour() {

    $("#one").fadeOut().css("display","none");

    $("#two").fadeOut().css("display","none");

    $("#three").fadeOut().css("display","none");

    $("#five").fadeOut().css("display","none");

    $("#four").fadeIn().css("display","block");

    $("#iFour").addClass("btn-active");

    $("#iTwo").removeClass("btn-active");

    $("#iThree").removeClass("btn-active");

    $("#iOne").removeClass("btn-active");

    $("#iFive").removeClass("btn-active");

    i++;

}

function testFive() {

    $("#one").fadeOut().css("display","none");

    $("#two").fadeOut().css("display","none");

    $("#three").fadeOut().css("display","none");

    $("#four").fadeOut().css("display","none");

    $("#five").fadeIn().css("display","block");

    $("#iFive").addClass("btn-active");

    $("#iTwo").removeClass("btn-active");

    $("#iThree").removeClass("btn-active");

    $("#iFour").removeClass("btn-active");

    $("#iOne").removeClass("btn-active");

    i = 0;

}

window.setInterval(function()

    {



        if(i === 0) {

            testOne();

            i++;

        } else if (i === 1) {

            testTwo();

            i++;

        } else if (i === 2) {

            testThree();

            i++;

        } else if (i === 3) {

            testFour();

            i++;

        } else if (i === 4) {

            testFive();

            let i = 0;

        }



    }, 5000);

The functions are displayed after "let i = 0" however I chose not to put them in as they are too long. All they do is run some jQuery code before i++; or let i = 0; on the fifth function.

Do you know why this could be the issue?

Full JS Code - https://hastebin.com/icalefafoy.js

Ben J

edited Nov 20 '18 at 19:08

zfrisch

4,57511024

asked Nov 20 '18 at 18:54

Ben J

I have a script that should run a function every 5 seconds depending on what one was previously run however it seems to be skipping every second one.

let i = 0;

function testOne()

{

    $("#two").fadeOut().css("display","none");

    $("#three").fadeOut().css("display","none");

    $("#four").fadeOut().css("display","none");

    $("#five").fadeOut().css("display","none");

    $("#one").fadeIn().css("display","block");

    $("#iOne").addClass("btn-active");

    $("#iTwo").removeClass("btn-active");

    $("#iThree").removeClass("btn-active");

    $("#iFour").removeClass("btn-active");

    $("#iFive").removeClass("btn-active");

    i++;

}

function testTwo() {

    $("#one").fadeOut().css("display","none");

    $("#three").fadeOut().css("display","none");

    $("#four").fadeOut().css("display","none");

    $("#five").fadeOut().css("display","none");

    $("#two").fadeIn().css("display","block");

    $("#iTwo").addClass("btn-active");

    $("#iOne").removeClass("btn-active");

    $("#iThree").removeClass("btn-active");

    $("#iFour").removeClass("btn-active");

    $("#iFive").removeClass("btn-active");

    i++;

}

function testThree() {

    $("#one").fadeOut().css("display","none");

    $("#two").fadeOut().css("display","none");

    $("#four").fadeOut().css("display","none");

    $("#five").fadeOut().css("display","none");

    $("#three").fadeIn().css("display","block");

    $("#iThree").addClass("btn-active");

    $("#iTwo").removeClass("btn-active");

    $("#iOne").removeClass("btn-active");

    $("#iFour").removeClass("btn-active");

    $("#iFive").removeClass("btn-active");

    i++;

}

function testFour() {

    $("#one").fadeOut().css("display","none");

    $("#two").fadeOut().css("display","none");

    $("#three").fadeOut().css("display","none");

    $("#five").fadeOut().css("display","none");

    $("#four").fadeIn().css("display","block");

    $("#iFour").addClass("btn-active");

    $("#iTwo").removeClass("btn-active");

    $("#iThree").removeClass("btn-active");

    $("#iOne").removeClass("btn-active");

    $("#iFive").removeClass("btn-active");

    i++;

}

function testFive() {

    $("#one").fadeOut().css("display","none");

    $("#two").fadeOut().css("display","none");

    $("#three").fadeOut().css("display","none");

    $("#four").fadeOut().css("display","none");

    $("#five").fadeIn().css("display","block");

    $("#iFive").addClass("btn-active");

    $("#iTwo").removeClass("btn-active");

    $("#iThree").removeClass("btn-active");

    $("#iFour").removeClass("btn-active");

    $("#iOne").removeClass("btn-active");

    i = 0;

}

window.setInterval(function()

    {



        if(i === 0) {

            testOne();

            i++;

        } else if (i === 1) {

            testTwo();

            i++;

        } else if (i === 2) {

            testThree();

            i++;

        } else if (i === 3) {

            testFour();

            i++;

        } else if (i === 4) {

            testFive();

            let i = 0;

        }



    }, 5000);

The functions are displayed after "let i = 0" however I chose not to put them in as they are too long. All they do is run some jQuery code before i++; or let i = 0; on the fifth function.

Do you know why this could be the issue?

Full JS Code - https://hastebin.com/icalefafoy.js

Ben J

javascript jquery

edited Nov 20 '18 at 19:08

zfrisch

4,57511024

asked Nov 20 '18 at 18:54

Ben J

edited Nov 20 '18 at 19:08

zfrisch

4,57511024

asked Nov 20 '18 at 18:54

Ben J

edited Nov 20 '18 at 19:08

zfrisch

4,57511024

edited Nov 20 '18 at 19:08

zfrisch

4,57511024

edited Nov 20 '18 at 19:08

zfrisch

4,57511024

asked Nov 20 '18 at 18:54

Ben J

asked Nov 20 '18 at 18:54

Ben J

asked Nov 20 '18 at 18:54

Ben J

let i = 0; -> i = 0;, otherwise looks good, maybe you call the whole code more than once?

– Jonas Wilms
Nov 20 '18 at 18:57

I tried that but still the same error.

– Ben J
Nov 20 '18 at 18:59

1

It works just fine aside from what Jonas pointed out. I'm unable to duplicate jsfiddle.net/pzejvrfc/1

– zfrisch
Nov 20 '18 at 18:59

Forgot to mention. It takes double the time the setInterval should take before skipping the code.

– Ben J
Nov 20 '18 at 19:00

@BenJ Okay, but the function isn't or is skipping for you? You have to be more specific with what the problem is - and since we can't duplicate, please show us more of your code.

– zfrisch
Nov 20 '18 at 19:03

|
show 1 more comment

let i = 0; -> i = 0;, otherwise looks good, maybe you call the whole code more than once?

– Jonas Wilms
Nov 20 '18 at 18:57

I tried that but still the same error.

– Ben J
Nov 20 '18 at 18:59

1

It works just fine aside from what Jonas pointed out. I'm unable to duplicate jsfiddle.net/pzejvrfc/1

– zfrisch
Nov 20 '18 at 18:59

Forgot to mention. It takes double the time the setInterval should take before skipping the code.

– Ben J
Nov 20 '18 at 19:00

@BenJ Okay, but the function isn't or is skipping for you? You have to be more specific with what the problem is - and since we can't duplicate, please show us more of your code.

– zfrisch
Nov 20 '18 at 19:03

let i = 0; -> i = 0;, otherwise looks good, maybe you call the whole code more than once?

– Jonas Wilms
Nov 20 '18 at 18:57

I tried that but still the same error.

– Ben J
Nov 20 '18 at 18:59

It works just fine aside from what Jonas pointed out. I'm unable to duplicate jsfiddle.net/pzejvrfc/1

– zfrisch
Nov 20 '18 at 18:59

Forgot to mention. It takes double the time the setInterval should take before skipping the code.

– Ben J
Nov 20 '18 at 19:00

@BenJ Okay, but the function isn't or is skipping for you? You have to be more specific with what the problem is - and since we can't duplicate, please show us more of your code.

– zfrisch
Nov 20 '18 at 19:03

|
show 1 more comment

2 Answers
2

active

oldest

votes

You increment i twice, once in the interval code and once in the function itself:

 function testOne() {

   //...

   i++

 }



 //...

 testOne();

 i++

just don't do that.

answered Nov 20 '18 at 19:07

community wiki

Jonas Wilms

Ah I see now. Thank you. ISSUE FIXED

– Ben J
Nov 20 '18 at 19:14

add a comment |

You're incrementing the variable i twice on each iteration of your interval, once in the function you call and once in the interval function itself, which is why it's skipping. Remove the i++ from your other functions.

let i = 0;

function testOne()

{

 console.log("one");



}

function testTwo() {

 console.log("two");



}

function testThree() {

 console.log("three");



}

function testFour() {

 console.log("four");

}

function testFive() {

 console.log("five");

}

window.setInterval(function()

    {



        if(i === 0) {

            testOne();

            i++;

        } else if (i === 1) {

            testTwo();

            i++;

        } else if (i === 2) {

            testThree();

            i++;

        } else if (i === 3) {

            testFour();

            i++;

        } else if (i === 4) {

            testFive();

            let i = 0;

        }



    }, 5000);

answered Nov 20 '18 at 19:10

zfrisch

4,57511024

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

You increment i twice, once in the interval code and once in the function itself:

 function testOne() {

   //...

   i++

 }



 //...

 testOne();

 i++

just don't do that.

answered Nov 20 '18 at 19:07

community wiki

Jonas Wilms

Ah I see now. Thank you. ISSUE FIXED

– Ben J
Nov 20 '18 at 19:14

add a comment |

You increment i twice, once in the interval code and once in the function itself:

 function testOne() {

   //...

   i++

 }



 //...

 testOne();

 i++

just don't do that.

answered Nov 20 '18 at 19:07

community wiki

Jonas Wilms

Ah I see now. Thank you. ISSUE FIXED

– Ben J
Nov 20 '18 at 19:14

add a comment |

You increment i twice, once in the interval code and once in the function itself:

 function testOne() {

   //...

   i++

 }



 //...

 testOne();

 i++

just don't do that.

answered Nov 20 '18 at 19:07

community wiki

Jonas Wilms

You increment i twice, once in the interval code and once in the function itself:

 function testOne() {

   //...

   i++

 }



 //...

 testOne();

 i++

just don't do that.

answered Nov 20 '18 at 19:07

community wiki

Jonas Wilms

answered Nov 20 '18 at 19:07

community wiki

Jonas Wilms

community wiki

Jonas Wilms

community wiki

Jonas Wilms

Ah I see now. Thank you. ISSUE FIXED

– Ben J
Nov 20 '18 at 19:14

add a comment |

Ah I see now. Thank you. ISSUE FIXED

– Ben J
Nov 20 '18 at 19:14

Ah I see now. Thank you. ISSUE FIXED

– Ben J
Nov 20 '18 at 19:14

add a comment |

let i = 0;

function testOne()

{

 console.log("one");



}

function testTwo() {

 console.log("two");



}

function testThree() {

 console.log("three");



}

function testFour() {

 console.log("four");

}

function testFive() {

 console.log("five");

}

window.setInterval(function()

    {



        if(i === 0) {

            testOne();

            i++;

        } else if (i === 1) {

            testTwo();

            i++;

        } else if (i === 2) {

            testThree();

            i++;

        } else if (i === 3) {

            testFour();

            i++;

        } else if (i === 4) {

            testFive();

            let i = 0;

        }



    }, 5000);

answered Nov 20 '18 at 19:10

zfrisch

4,57511024

add a comment |

let i = 0;

function testOne()

{

 console.log("one");



}

function testTwo() {

 console.log("two");



}

function testThree() {

 console.log("three");



}

function testFour() {

 console.log("four");

}

function testFive() {

 console.log("five");

}

window.setInterval(function()

    {



        if(i === 0) {

            testOne();

            i++;

        } else if (i === 1) {

            testTwo();

            i++;

        } else if (i === 2) {

            testThree();

            i++;

        } else if (i === 3) {

            testFour();

            i++;

        } else if (i === 4) {

            testFive();

            let i = 0;

        }



    }, 5000);

answered Nov 20 '18 at 19:10

zfrisch

4,57511024

add a comment |

let i = 0;

function testOne()

{

 console.log("one");



}

function testTwo() {

 console.log("two");



}

function testThree() {

 console.log("three");



}

function testFour() {

 console.log("four");

}

function testFive() {

 console.log("five");

}

window.setInterval(function()

    {



        if(i === 0) {

            testOne();

            i++;

        } else if (i === 1) {

            testTwo();

            i++;

        } else if (i === 2) {

            testThree();

            i++;

        } else if (i === 3) {

            testFour();

            i++;

        } else if (i === 4) {

            testFive();

            let i = 0;

        }



    }, 5000);

answered Nov 20 '18 at 19:10

zfrisch

4,57511024

let i = 0;

function testOne()

{

 console.log("one");



}

function testTwo() {

 console.log("two");



}

function testThree() {

 console.log("three");



}

function testFour() {

 console.log("four");

}

function testFive() {

 console.log("five");

}

window.setInterval(function()

    {



        if(i === 0) {

            testOne();

            i++;

        } else if (i === 1) {

            testTwo();

            i++;

        } else if (i === 2) {

            testThree();

            i++;

        } else if (i === 3) {

            testFour();

            i++;

        } else if (i === 4) {

            testFive();

            let i = 0;

        }



    }, 5000);

let i = 0;

function testOne()

{

 console.log("one");



}

function testTwo() {

 console.log("two");



}

function testThree() {

 console.log("three");



}

function testFour() {

 console.log("four");

}

function testFive() {

 console.log("five");

}

window.setInterval(function()

    {



        if(i === 0) {

            testOne();

            i++;

        } else if (i === 1) {

            testTwo();

            i++;

        } else if (i === 2) {

            testThree();

            i++;

        } else if (i === 3) {

            testFour();

            i++;

        } else if (i === 4) {

            testFive();

            let i = 0;

        }



    }, 5000);

let i = 0;

function testOne()

{

 console.log("one");



}

function testTwo() {

 console.log("two");



}

function testThree() {

 console.log("three");



}

function testFour() {

 console.log("four");

}

function testFive() {

 console.log("five");

}

window.setInterval(function()

    {



        if(i === 0) {

            testOne();

            i++;

        } else if (i === 1) {

            testTwo();

            i++;

        } else if (i === 2) {

            testThree();

            i++;

        } else if (i === 3) {

            testFour();

            i++;

        } else if (i === 4) {

            testFive();

            let i = 0;

        }



    }, 5000);

answered Nov 20 '18 at 19:10

zfrisch

4,57511024

answered Nov 20 '18 at 19:10

zfrisch

4,57511024

answered Nov 20 '18 at 19:10

zfrisch

4,57511024

answered Nov 20 '18 at 19:10

zfrisch

4,57511024

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