“Call to std::pair is ambiguous” by Clion but code can be compiled
I have a function that compiles in this state but gives "Call to pair is ambiguous" but only in Clion IDE, compiles without problem and the warning dissapears if i add whatever random thing, even if it ends up causing compiler error.
std::pair<Status, std::set<std::string>> Config::foo(const std::string &sec, const std::string &key) const {
return std::pair<Status, std::set<std::string>>(
hasSection(sec) ? (hasKey(sec, key) ? Status::Success
: Status::MissingKey)
: Status::MissingSec ,
hasKey(sec, key) ? config_map.find(sec)->second.find(key)->second
: std::set<std::string>()
);
}
I have no idea how to fix it, or even what the problem actually is.
c++ windows clion
add a comment |
I have a function that compiles in this state but gives "Call to pair is ambiguous" but only in Clion IDE, compiles without problem and the warning dissapears if i add whatever random thing, even if it ends up causing compiler error.
std::pair<Status, std::set<std::string>> Config::foo(const std::string &sec, const std::string &key) const {
return std::pair<Status, std::set<std::string>>(
hasSection(sec) ? (hasKey(sec, key) ? Status::Success
: Status::MissingKey)
: Status::MissingSec ,
hasKey(sec, key) ? config_map.find(sec)->second.find(key)->second
: std::set<std::string>()
);
}
I have no idea how to fix it, or even what the problem actually is.
c++ windows clion
add a comment |
I have a function that compiles in this state but gives "Call to pair is ambiguous" but only in Clion IDE, compiles without problem and the warning dissapears if i add whatever random thing, even if it ends up causing compiler error.
std::pair<Status, std::set<std::string>> Config::foo(const std::string &sec, const std::string &key) const {
return std::pair<Status, std::set<std::string>>(
hasSection(sec) ? (hasKey(sec, key) ? Status::Success
: Status::MissingKey)
: Status::MissingSec ,
hasKey(sec, key) ? config_map.find(sec)->second.find(key)->second
: std::set<std::string>()
);
}
I have no idea how to fix it, or even what the problem actually is.
c++ windows clion
I have a function that compiles in this state but gives "Call to pair is ambiguous" but only in Clion IDE, compiles without problem and the warning dissapears if i add whatever random thing, even if it ends up causing compiler error.
std::pair<Status, std::set<std::string>> Config::foo(const std::string &sec, const std::string &key) const {
return std::pair<Status, std::set<std::string>>(
hasSection(sec) ? (hasKey(sec, key) ? Status::Success
: Status::MissingKey)
: Status::MissingSec ,
hasKey(sec, key) ? config_map.find(sec)->second.find(key)->second
: std::set<std::string>()
);
}
I have no idea how to fix it, or even what the problem actually is.
c++ windows clion
c++ windows clion
edited Nov 22 '18 at 8:44
jww
53.9k40232508
53.9k40232508
asked Nov 2 '17 at 1:00
Zerg OvermindZerg Overmind
1376
1376
add a comment |
add a comment |
1 Answer
1
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oldest
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If you want constructs a pair object, you have to use std::make_pair function template.
template <class T1, class T2>
pair<V1,V2> make_pair (T1&& x, T2&& y);
The template types can be implicitly deduced from the arguments passed to make_pair.
return std::make_pair(
hasSection(sec) ? (hasKey(sec, key) ? Status::Success
: Status::MissingKey)
: Status::MissingSec ,
hasKey(sec, key) ? config_map.find(sec)->second.find(key)->second :
std::set<std::string>()
);
This code compile without "Call to pair is ambiguous".
If you specify the make_pair template type, you encounter an error of the type "Expression must be rvalue".
Please be clear about what the problem actually is
– Welton122
Nov 8 '17 at 20:15
Zerg's code is correct, "Call to pair is ambiguous" is essentially a CLion bug. std::pair has an initialization constructor that you use it so "std::pair <std::string,int> example("example",2);
". std::make_pair, instead, build std::pair object using r-value and move constructor (and implicit conversion).
– S. Martelli
Nov 10 '17 at 10:56
I'd ratherreturn { a, b };
.
– Marc Glisse
Nov 22 '18 at 8:47
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
If you want constructs a pair object, you have to use std::make_pair function template.
template <class T1, class T2>
pair<V1,V2> make_pair (T1&& x, T2&& y);
The template types can be implicitly deduced from the arguments passed to make_pair.
return std::make_pair(
hasSection(sec) ? (hasKey(sec, key) ? Status::Success
: Status::MissingKey)
: Status::MissingSec ,
hasKey(sec, key) ? config_map.find(sec)->second.find(key)->second :
std::set<std::string>()
);
This code compile without "Call to pair is ambiguous".
If you specify the make_pair template type, you encounter an error of the type "Expression must be rvalue".
Please be clear about what the problem actually is
– Welton122
Nov 8 '17 at 20:15
Zerg's code is correct, "Call to pair is ambiguous" is essentially a CLion bug. std::pair has an initialization constructor that you use it so "std::pair <std::string,int> example("example",2);
". std::make_pair, instead, build std::pair object using r-value and move constructor (and implicit conversion).
– S. Martelli
Nov 10 '17 at 10:56
I'd ratherreturn { a, b };
.
– Marc Glisse
Nov 22 '18 at 8:47
add a comment |
If you want constructs a pair object, you have to use std::make_pair function template.
template <class T1, class T2>
pair<V1,V2> make_pair (T1&& x, T2&& y);
The template types can be implicitly deduced from the arguments passed to make_pair.
return std::make_pair(
hasSection(sec) ? (hasKey(sec, key) ? Status::Success
: Status::MissingKey)
: Status::MissingSec ,
hasKey(sec, key) ? config_map.find(sec)->second.find(key)->second :
std::set<std::string>()
);
This code compile without "Call to pair is ambiguous".
If you specify the make_pair template type, you encounter an error of the type "Expression must be rvalue".
Please be clear about what the problem actually is
– Welton122
Nov 8 '17 at 20:15
Zerg's code is correct, "Call to pair is ambiguous" is essentially a CLion bug. std::pair has an initialization constructor that you use it so "std::pair <std::string,int> example("example",2);
". std::make_pair, instead, build std::pair object using r-value and move constructor (and implicit conversion).
– S. Martelli
Nov 10 '17 at 10:56
I'd ratherreturn { a, b };
.
– Marc Glisse
Nov 22 '18 at 8:47
add a comment |
If you want constructs a pair object, you have to use std::make_pair function template.
template <class T1, class T2>
pair<V1,V2> make_pair (T1&& x, T2&& y);
The template types can be implicitly deduced from the arguments passed to make_pair.
return std::make_pair(
hasSection(sec) ? (hasKey(sec, key) ? Status::Success
: Status::MissingKey)
: Status::MissingSec ,
hasKey(sec, key) ? config_map.find(sec)->second.find(key)->second :
std::set<std::string>()
);
This code compile without "Call to pair is ambiguous".
If you specify the make_pair template type, you encounter an error of the type "Expression must be rvalue".
If you want constructs a pair object, you have to use std::make_pair function template.
template <class T1, class T2>
pair<V1,V2> make_pair (T1&& x, T2&& y);
The template types can be implicitly deduced from the arguments passed to make_pair.
return std::make_pair(
hasSection(sec) ? (hasKey(sec, key) ? Status::Success
: Status::MissingKey)
: Status::MissingSec ,
hasKey(sec, key) ? config_map.find(sec)->second.find(key)->second :
std::set<std::string>()
);
This code compile without "Call to pair is ambiguous".
If you specify the make_pair template type, you encounter an error of the type "Expression must be rvalue".
answered Nov 8 '17 at 20:13
S. MartelliS. Martelli
1921
1921
Please be clear about what the problem actually is
– Welton122
Nov 8 '17 at 20:15
Zerg's code is correct, "Call to pair is ambiguous" is essentially a CLion bug. std::pair has an initialization constructor that you use it so "std::pair <std::string,int> example("example",2);
". std::make_pair, instead, build std::pair object using r-value and move constructor (and implicit conversion).
– S. Martelli
Nov 10 '17 at 10:56
I'd ratherreturn { a, b };
.
– Marc Glisse
Nov 22 '18 at 8:47
add a comment |
Please be clear about what the problem actually is
– Welton122
Nov 8 '17 at 20:15
Zerg's code is correct, "Call to pair is ambiguous" is essentially a CLion bug. std::pair has an initialization constructor that you use it so "std::pair <std::string,int> example("example",2);
". std::make_pair, instead, build std::pair object using r-value and move constructor (and implicit conversion).
– S. Martelli
Nov 10 '17 at 10:56
I'd ratherreturn { a, b };
.
– Marc Glisse
Nov 22 '18 at 8:47
Please be clear about what the problem actually is
– Welton122
Nov 8 '17 at 20:15
Please be clear about what the problem actually is
– Welton122
Nov 8 '17 at 20:15
Zerg's code is correct, "Call to pair is ambiguous" is essentially a CLion bug. std::pair has an initialization constructor that you use it so "
std::pair <std::string,int> example("example",2);
". std::make_pair, instead, build std::pair object using r-value and move constructor (and implicit conversion).– S. Martelli
Nov 10 '17 at 10:56
Zerg's code is correct, "Call to pair is ambiguous" is essentially a CLion bug. std::pair has an initialization constructor that you use it so "
std::pair <std::string,int> example("example",2);
". std::make_pair, instead, build std::pair object using r-value and move constructor (and implicit conversion).– S. Martelli
Nov 10 '17 at 10:56
I'd rather
return { a, b };
.– Marc Glisse
Nov 22 '18 at 8:47
I'd rather
return { a, b };
.– Marc Glisse
Nov 22 '18 at 8:47
add a comment |
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