How to enforce a date value input in a REST API?
The user needs to make a POST to /api/date with something like March 13, 2019 or 08/19/2020. As long as it's a date, it should be accepted.
I have something like this (Using Dropwizard framework)
@POST
public void post(String date)
{
validateDate(date);
//continue
}
private void validateDate(String date)
{
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd");
try
{
LocalDateTime.parse(date, formatter);
}
catch (DateTimeParseException e)
{
//not a date
}
}
I'm not sure if I'm in the right approach, there must be a better way to validate strings as dates.
java rest
asked Nov 21 '18 at 14:58
RonApple1996RonApple1996
897
|
show 4 more comments
The user needs to make a POST to /api/date with something like March 13, 2019 or 08/19/2020. As long as it's a date, it should be accepted.
I have something like this (Using Dropwizard framework)
@POST
public void post(String date)
{
validateDate(date);
//continue
}
private void validateDate(String date)
{
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd");
try
{
LocalDateTime.parse(date, formatter);
}
catch (DateTimeParseException e)
{
//not a date
}
}
I'm not sure if I'm in the right approach, there must be a better way to validate strings as dates.
java rest
asked Nov 21 '18 at 14:58
RonApple1996RonApple1996
897
1
you are guessing the format (yyyy-MM-dd") while first you need to figure out what the format is
– Andrew Tobilko
Nov 21 '18 at 15:03
Is it better to only accept one date format? I was hoping to keep it flexible so different formats can be used.
– RonApple1996
Nov 21 '18 at 15:04
1
@RonApple1996 Just use one date format. APIs should be well-defined contracts.
– Michael
Nov 21 '18 at 15:08
1
@RonApple1996 If you need a date, ask for a date. Given you have the control, I would use an ISO-8601 standard date format e.g. 2011-12-21
– Michael
Nov 21 '18 at 15:17
1
Yea @Hulk, I was just thinking about that. Ahhh dates have so much involved.. I'm returning UTC time zone, so I think logically it makes sense to accept only UTC time as well
– RonApple1996
Nov 21 '18 at 15:23
|
show 4 more comments
The user needs to make a POST to /api/date with something like March 13, 2019 or 08/19/2020. As long as it's a date, it should be accepted.
I have something like this (Using Dropwizard framework)
@POST
public void post(String date)
{
validateDate(date);
//continue
}
private void validateDate(String date)
{
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd");
try
{
LocalDateTime.parse(date, formatter);
}
catch (DateTimeParseException e)
{
//not a date
}
}
I'm not sure if I'm in the right approach, there must be a better way to validate strings as dates.
java rest
asked Nov 21 '18 at 14:58
RonApple1996RonApple1996
897
The user needs to make a POST to /api/date with something like March 13, 2019 or 08/19/2020. As long as it's a date, it should be accepted.
I have something like this (Using Dropwizard framework)
@POST
public void post(String date)
{
validateDate(date);
//continue
}
private void validateDate(String date)
{
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd");
try
{
LocalDateTime.parse(date, formatter);
}
catch (DateTimeParseException e)
{
//not a date
}
}
I'm not sure if I'm in the right approach, there must be a better way to validate strings as dates.
java rest
java rest
asked Nov 21 '18 at 14:58
RonApple1996RonApple1996
897
asked Nov 21 '18 at 14:58
RonApple1996RonApple1996
897
asked Nov 21 '18 at 14:58
RonApple1996RonApple1996
897
asked Nov 21 '18 at 14:58
RonApple1996RonApple1996
897
asked Nov 21 '18 at 14:58
RonApple1996RonApple1996
897
897
1
you are guessing the format (yyyy-MM-dd") while first you need to figure out what the format is
– Andrew Tobilko
Nov 21 '18 at 15:03
Is it better to only accept one date format? I was hoping to keep it flexible so different formats can be used.
– RonApple1996
Nov 21 '18 at 15:04
1
@RonApple1996 Just use one date format. APIs should be well-defined contracts.
– Michael
Nov 21 '18 at 15:08
1
@RonApple1996 If you need a date, ask for a date. Given you have the control, I would use an ISO-8601 standard date format e.g. 2011-12-21
– Michael
Nov 21 '18 at 15:17
1
Yea @Hulk, I was just thinking about that. Ahhh dates have so much involved.. I'm returning UTC time zone, so I think logically it makes sense to accept only UTC time as well
– RonApple1996
Nov 21 '18 at 15:23
|
show 4 more comments
1
you are guessing the format (yyyy-MM-dd") while first you need to figure out what the format is
– Andrew Tobilko
Nov 21 '18 at 15:03
Is it better to only accept one date format? I was hoping to keep it flexible so different formats can be used.
– RonApple1996
Nov 21 '18 at 15:04
1
@RonApple1996 Just use one date format. APIs should be well-defined contracts.
– Michael
Nov 21 '18 at 15:08
1
@RonApple1996 If you need a date, ask for a date. Given you have the control, I would use an ISO-8601 standard date format e.g. 2011-12-21
– Michael
Nov 21 '18 at 15:17
1
Yea @Hulk, I was just thinking about that. Ahhh dates have so much involved.. I'm returning UTC time zone, so I think logically it makes sense to accept only UTC time as well
– RonApple1996
Nov 21 '18 at 15:23
1
1
you are guessing the format (
yyyy-MM-dd") while first you need to figure out what the format is– Andrew Tobilko
Nov 21 '18 at 15:03
you are guessing the format (
yyyy-MM-dd") while first you need to figure out what the format is– Andrew Tobilko
Nov 21 '18 at 15:03
Is it better to only accept one date format? I was hoping to keep it flexible so different formats can be used.
– RonApple1996
Nov 21 '18 at 15:04
Is it better to only accept one date format? I was hoping to keep it flexible so different formats can be used.
– RonApple1996
Nov 21 '18 at 15:04
1
1
@RonApple1996 Just use one date format. APIs should be well-defined contracts.
– Michael
Nov 21 '18 at 15:08
@RonApple1996 Just use one date format. APIs should be well-defined contracts.
– Michael
Nov 21 '18 at 15:08
1
1
@RonApple1996 If you need a date, ask for a date. Given you have the control, I would use an ISO-8601 standard date format e.g. 2011-12-21
– Michael
Nov 21 '18 at 15:17
@RonApple1996 If you need a date, ask for a date. Given you have the control, I would use an ISO-8601 standard date format e.g. 2011-12-21
– Michael
Nov 21 '18 at 15:17
1
1
Yea @Hulk, I was just thinking about that. Ahhh dates have so much involved.. I'm returning UTC time zone, so I think logically it makes sense to accept only UTC time as well
– RonApple1996
Nov 21 '18 at 15:23
Yea @Hulk, I was just thinking about that. Ahhh dates have so much involved.. I'm returning UTC time zone, so I think logically it makes sense to accept only UTC time as well
– RonApple1996
Nov 21 '18 at 15:23
|
show 4 more comments
2 Answers
2
active
oldest
votes
You can accept multiple formats for a date time using the optional syntax ([<your format>])*. eg
DateTimeFormatter formatter = DateTimeFormatter.ofPattern(
"[yyyy-MM-dd][dd-MM-yyyy][MMMM dd, yyyy]");
answered Nov 21 '18 at 15:13
flakesflakes
6,89012053
add a comment |
EDIT: It is not really clear if you want to know how to validate dates correctly or how to handle invalid inputs to your REST API. My answer shows the latter.
You should use a return value for your post method. You can return javax.ws.rs.core.Response, with that you can control the HTTP code and response object you want to return.
On success, you would normally return the created object with a 200 success code.
On failure, you would return an error code (like 400 Bad request) with a detailed error message ("Date must be in the format yyyy-MM-dd").
To create the response, you can use the ResponseBuilder.
Example:
Response.ok( yourObject ).build(); //success
Response.status( Status.BAD_REQUEST ).entity( yourErrorMessageObject ).build(); // failure
So I would change the code to this:
@POST
public Response post(String date)
{
if(!isDateValid(date)){
return Response.status( Status.BAD_REQUEST ).entity( buildErrorMessage()).build();
}
//continue
Response.ok().build(); // returns nothing on success (like void)
}
private boolean isDateValid(String date)
{
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd");
try
{
LocalDateTime.parse(date, formatter);
return true;
}
catch (DateTimeParseException e)
{
//not a date
return false;
}
}
answered Nov 21 '18 at 15:08
Michael KleimannMichael Kleimann
37217
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can accept multiple formats for a date time using the optional syntax ([<your format>])*. eg
DateTimeFormatter formatter = DateTimeFormatter.ofPattern(
"[yyyy-MM-dd][dd-MM-yyyy][MMMM dd, yyyy]");
answered Nov 21 '18 at 15:13
flakesflakes
6,89012053
add a comment |
You can accept multiple formats for a date time using the optional syntax ([<your format>])*. eg
DateTimeFormatter formatter = DateTimeFormatter.ofPattern(
"[yyyy-MM-dd][dd-MM-yyyy][MMMM dd, yyyy]");
answered Nov 21 '18 at 15:13
flakesflakes
6,89012053
add a comment |
You can accept multiple formats for a date time using the optional syntax ([<your format>])*. eg
DateTimeFormatter formatter = DateTimeFormatter.ofPattern(
"[yyyy-MM-dd][dd-MM-yyyy][MMMM dd, yyyy]");
answered Nov 21 '18 at 15:13
flakesflakes
6,89012053
You can accept multiple formats for a date time using the optional syntax ([<your format>])*. eg
DateTimeFormatter formatter = DateTimeFormatter.ofPattern(
"[yyyy-MM-dd][dd-MM-yyyy][MMMM dd, yyyy]");
answered Nov 21 '18 at 15:13
flakesflakes
6,89012053
answered Nov 21 '18 at 15:13
flakesflakes
6,89012053
answered Nov 21 '18 at 15:13
flakesflakes
6,89012053
answered Nov 21 '18 at 15:13
flakesflakes
6,89012053
6,89012053
add a comment |
add a comment |
EDIT: It is not really clear if you want to know how to validate dates correctly or how to handle invalid inputs to your REST API. My answer shows the latter.
You should use a return value for your post method. You can return javax.ws.rs.core.Response, with that you can control the HTTP code and response object you want to return.
On success, you would normally return the created object with a 200 success code.
On failure, you would return an error code (like 400 Bad request) with a detailed error message ("Date must be in the format yyyy-MM-dd").
To create the response, you can use the ResponseBuilder.
Example:
Response.ok( yourObject ).build(); //success
Response.status( Status.BAD_REQUEST ).entity( yourErrorMessageObject ).build(); // failure
So I would change the code to this:
@POST
public Response post(String date)
{
if(!isDateValid(date)){
return Response.status( Status.BAD_REQUEST ).entity( buildErrorMessage()).build();
}
//continue
Response.ok().build(); // returns nothing on success (like void)
}
private boolean isDateValid(String date)
{
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd");
try
{
LocalDateTime.parse(date, formatter);
return true;
}
catch (DateTimeParseException e)
{
//not a date
return false;
}
}
answered Nov 21 '18 at 15:08
Michael KleimannMichael Kleimann
37217
add a comment |
EDIT: It is not really clear if you want to know how to validate dates correctly or how to handle invalid inputs to your REST API. My answer shows the latter.
You should use a return value for your post method. You can return javax.ws.rs.core.Response, with that you can control the HTTP code and response object you want to return.
On success, you would normally return the created object with a 200 success code.
On failure, you would return an error code (like 400 Bad request) with a detailed error message ("Date must be in the format yyyy-MM-dd").
To create the response, you can use the ResponseBuilder.
Example:
Response.ok( yourObject ).build(); //success
Response.status( Status.BAD_REQUEST ).entity( yourErrorMessageObject ).build(); // failure
So I would change the code to this:
@POST
public Response post(String date)
{
if(!isDateValid(date)){
return Response.status( Status.BAD_REQUEST ).entity( buildErrorMessage()).build();
}
//continue
Response.ok().build(); // returns nothing on success (like void)
}
private boolean isDateValid(String date)
{
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd");
try
{
LocalDateTime.parse(date, formatter);
return true;
}
catch (DateTimeParseException e)
{
//not a date
return false;
}
}
answered Nov 21 '18 at 15:08
Michael KleimannMichael Kleimann
37217
add a comment |
EDIT: It is not really clear if you want to know how to validate dates correctly or how to handle invalid inputs to your REST API. My answer shows the latter.
You should use a return value for your post method. You can return javax.ws.rs.core.Response, with that you can control the HTTP code and response object you want to return.
On success, you would normally return the created object with a 200 success code.
On failure, you would return an error code (like 400 Bad request) with a detailed error message ("Date must be in the format yyyy-MM-dd").
To create the response, you can use the ResponseBuilder.
Example:
Response.ok( yourObject ).build(); //success
Response.status( Status.BAD_REQUEST ).entity( yourErrorMessageObject ).build(); // failure
So I would change the code to this:
@POST
public Response post(String date)
{
if(!isDateValid(date)){
return Response.status( Status.BAD_REQUEST ).entity( buildErrorMessage()).build();
}
//continue
Response.ok().build(); // returns nothing on success (like void)
}
private boolean isDateValid(String date)
{
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd");
try
{
LocalDateTime.parse(date, formatter);
return true;
}
catch (DateTimeParseException e)
{
//not a date
return false;
}
}
answered Nov 21 '18 at 15:08
Michael KleimannMichael Kleimann
37217
EDIT: It is not really clear if you want to know how to validate dates correctly or how to handle invalid inputs to your REST API. My answer shows the latter.
You should use a return value for your post method. You can return javax.ws.rs.core.Response, with that you can control the HTTP code and response object you want to return.
On success, you would normally return the created object with a 200 success code.
On failure, you would return an error code (like 400 Bad request) with a detailed error message ("Date must be in the format yyyy-MM-dd").
To create the response, you can use the ResponseBuilder.
Example:
Response.ok( yourObject ).build(); //success
Response.status( Status.BAD_REQUEST ).entity( yourErrorMessageObject ).build(); // failure
So I would change the code to this:
@POST
public Response post(String date)
{
if(!isDateValid(date)){
return Response.status( Status.BAD_REQUEST ).entity( buildErrorMessage()).build();
}
//continue
Response.ok().build(); // returns nothing on success (like void)
}
private boolean isDateValid(String date)
{
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd");
try
{
LocalDateTime.parse(date, formatter);
return true;
}
catch (DateTimeParseException e)
{
//not a date
return false;
}
}
answered Nov 21 '18 at 15:08
Michael KleimannMichael Kleimann
37217
edited Nov 21 '18 at 15:19
answered Nov 21 '18 at 15:08
Michael KleimannMichael Kleimann
37217
answered Nov 21 '18 at 15:08
Michael KleimannMichael Kleimann
37217
answered Nov 21 '18 at 15:08
Michael KleimannMichael Kleimann
37217
37217
add a comment |
add a comment |
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1
you are guessing the format (
yyyy-MM-dd") while first you need to figure out what the format is– Andrew Tobilko
Nov 21 '18 at 15:03
Is it better to only accept one date format? I was hoping to keep it flexible so different formats can be used.
– RonApple1996
Nov 21 '18 at 15:04
1
@RonApple1996 Just use one date format. APIs should be well-defined contracts.
– Michael
Nov 21 '18 at 15:08
1
@RonApple1996 If you need a date, ask for a date. Given you have the control, I would use an ISO-8601 standard date format e.g. 2011-12-21
– Michael
Nov 21 '18 at 15:17
1
Yea @Hulk, I was just thinking about that. Ahhh dates have so much involved.. I'm returning UTC time zone, so I think logically it makes sense to accept only UTC time as well
– RonApple1996
Nov 21 '18 at 15:23