Wsrtjtyk

I'm trying to find a code that transforms a list of lists into a dictionary. Lets say I have a list that is

list_one = [['id1', 'id2', id3', 'id4', 'id5'],

            ['1', 'Cat', '400', 'Fur', '50'],

            ['2', 'Dog', '500', 'Smelly', '60']]

The dictionary should have keys to number each list in dictionaries in this format

new_dict = {1.0: {'id1': 1,

                 'id2': 'Cat',

                 'id3': 400,

                 'id4': 'Fur',

                 'id5': 50},

            2.0: {'id1': 2,

                  'id2': 'Dog',

                  'id3': 500,

                  'id4': 'Smelly'

                  'id5': 60}

Can such a conversion be done in list comprehension or through a for loop?

a simple dict-comprehension using enumerate:

list_one = [['id1', 'id2', 'id3', 'id4', 'id5'],

            ['1', 'Cat', '400', 'Fur', '50'],

            ['2', 'Dog', '500', 'Smelly', '60']]



new_dict = {float(i): dict(zip(list_one[0], items)) 

            for i, items in enumerate(list_one[1:], start=1)}



print(new_dict)

results in

{1.0: {'id1': '1', 'id2': 'Cat', 'id3': '400', 'id4': 'Fur', 'id5': '50'}, 

 2.0: {'id1': '2', 'id2': 'Dog', 'id3': '500', 'id4': 'Smelly', 'id5': '60'}}

In your use case, the keys are the first list in your list, and the objects are the rest. You can zip them together and create that dictionary like so:

ks, objs = list_one[0], list_one[1:]



myobjects = {i: dict(zip(ks, l)) for i,l in enumerate(objs)}

zip will take the element-by-element pairs and create tuples like (x, y) and dict will make {x: y} from that tuple. The docs can be found here

If you are okay with third party library pandas

import pandas as pd

{float(k):v for k,v in enumerate(pd.DataFrame(list_one[1:],columns=list_one[0]).to_dict('records'),1)}

The following should do the trick:

>>> new_dict = {float(i): {list_one[0][j]:val for j,val in enumerate(list_one[i])} for i in range(1,len(list_one))}

>>> new_dict

 {1.0: {'id1': '1', 'id2': 'Cat', 'id3': '400', 'id4': 'Fur', 'id5': '50'},

 2.0: {'id1': '2', 'id2': 'Dog', 'id3': '500', 'id4': 'Smelly', 'id5': '60'}}