clear everything but one variable rm(list = ls()) [duplicate]

up vote
0
down vote

favorite

This question already has an answer here:

How can I remove all objects but one from the workspace in R?

13 answers

I'm aware that rm(list = ls()) will clear my workspace.

I have a data frame x that I would like to preserve while removing everything else from memory. How can I do that?

rm(list = ls(!x)) #???

asked Nov 9 at 18:04

Doug Fir

5,2722780148

marked as duplicate by Ronak Shah r
Users with the r badge can single-handedly close r questions as duplicates and reopen them as needed.

StackExchange.ready(function() {
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function() {
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function() {
$hover.showInfoMessage('', {
messageElement: $msg.clone().show(),
transient: false,
position: { my: 'bottom left', at: 'top center', offsetTop: -7 },
dismissable: false,
relativeToBody: true
});
},
function() {
StackExchange.helpers.removeMessages();
}
);
});
});
Nov 9 at 18:18

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

add a comment |

up vote
0
down vote

favorite

This question already has an answer here:

How can I remove all objects but one from the workspace in R?

13 answers

I'm aware that rm(list = ls()) will clear my workspace.

I have a data frame x that I would like to preserve while removing everything else from memory. How can I do that?

rm(list = ls(!x)) #???

asked Nov 9 at 18:04

Doug Fir

5,2722780148

marked as duplicate by Ronak Shah r
Users with the r badge can single-handedly close r questions as duplicates and reopen them as needed.

StackExchange.ready(function() {
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function() {
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function() {
$hover.showInfoMessage('', {
messageElement: $msg.clone().show(),
transient: false,
position: { my: 'bottom left', at: 'top center', offsetTop: -7 },
dismissable: false,
relativeToBody: true
});
},
function() {
StackExchange.helpers.removeMessages();
}
);
});
});
Nov 9 at 18:18

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

add a comment |

up vote
0
down vote

favorite

This question already has an answer here:

How can I remove all objects but one from the workspace in R?

13 answers

I'm aware that rm(list = ls()) will clear my workspace.

I have a data frame x that I would like to preserve while removing everything else from memory. How can I do that?

rm(list = ls(!x)) #???

asked Nov 9 at 18:04

Doug Fir

5,2722780148

This question already has an answer here:

How can I remove all objects but one from the workspace in R?

13 answers

I'm aware that rm(list = ls()) will clear my workspace.

I have a data frame x that I would like to preserve while removing everything else from memory. How can I do that?

rm(list = ls(!x)) #???

This question already has an answer here:

How can I remove all objects but one from the workspace in R?

13 answers

asked Nov 9 at 18:04

Doug Fir

5,2722780148

asked Nov 9 at 18:04

Doug Fir

5,2722780148

asked Nov 9 at 18:04

Doug Fir

5,2722780148

asked Nov 9 at 18:04

Doug Fir

5,2722780148

asked Nov 9 at 18:04

Doug Fir

5,2722780148

marked as duplicate by Ronak Shah r
Users with the r badge can single-handedly close r questions as duplicates and reopen them as needed.

StackExchange.ready(function() {
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function() {
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function() {
$hover.showInfoMessage('', {
messageElement: $msg.clone().show(),
transient: false,
position: { my: 'bottom left', at: 'top center', offsetTop: -7 },
dismissable: false,
relativeToBody: true
});
},
function() {
StackExchange.helpers.removeMessages();
}
);
});
});
Nov 9 at 18:18

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

marked as duplicate by Ronak Shah r
Users with the r badge can single-handedly close r questions as duplicates and reopen them as needed.

StackExchange.ready(function() {
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function() {
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function() {
$hover.showInfoMessage('', {
messageElement: $msg.clone().show(),
transient: false,
position: { my: 'bottom left', at: 'top center', offsetTop: -7 },
dismissable: false,
relativeToBody: true
});
},
function() {
StackExchange.helpers.removeMessages();
}
);
});
});
Nov 9 at 18:18

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

add a comment |

1 Answer
1

active

oldest

votes

up vote
6
down vote

accepted

Try: rm(list = setdiff(ls(), x))

Edit based on mickey's comment:

Three objects in environment:

ls()

[1] "data_df" "list_ls" "vector_v"

Remove data_df:

rm(list = setdiff(ls(), "data_df"))

ls()

[1] "data_df"

Vector of things to keep:

toKeep_v <- c("list_ls", "vector_v")

rm(list = setdiff(ls(), toKeep_v)

ls()

[1] "list_ls" "vector_v"

edited Nov 9 at 18:14

answered Nov 9 at 18:06

Qwfqwf

1488

5

If x is the name of the data frame, it should be in quotes.
– mickey
Nov 9 at 18:08

1

While rm has NSE, setdiff doesn't so this will have unexpected results unless x is "x"
– James
Nov 9 at 18:10

add a comment |

1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

up vote
6
down vote

accepted

Try: rm(list = setdiff(ls(), x))

Edit based on mickey's comment:

Three objects in environment:

ls()

[1] "data_df" "list_ls" "vector_v"

Remove data_df:

rm(list = setdiff(ls(), "data_df"))

ls()

[1] "data_df"

Vector of things to keep:

toKeep_v <- c("list_ls", "vector_v")

rm(list = setdiff(ls(), toKeep_v)

ls()

[1] "list_ls" "vector_v"

edited Nov 9 at 18:14

answered Nov 9 at 18:06

Qwfqwf

1488

5

If x is the name of the data frame, it should be in quotes.
– mickey
Nov 9 at 18:08

1

While rm has NSE, setdiff doesn't so this will have unexpected results unless x is "x"
– James
Nov 9 at 18:10

add a comment |

up vote
6
down vote

accepted

Try: rm(list = setdiff(ls(), x))

Edit based on mickey's comment:

Three objects in environment:

ls()

[1] "data_df" "list_ls" "vector_v"

Remove data_df:

rm(list = setdiff(ls(), "data_df"))

ls()

[1] "data_df"

Vector of things to keep:

toKeep_v <- c("list_ls", "vector_v")

rm(list = setdiff(ls(), toKeep_v)

ls()

[1] "list_ls" "vector_v"

edited Nov 9 at 18:14

answered Nov 9 at 18:06

Qwfqwf

1488

5

If x is the name of the data frame, it should be in quotes.
– mickey
Nov 9 at 18:08

1

While rm has NSE, setdiff doesn't so this will have unexpected results unless x is "x"
– James
Nov 9 at 18:10

add a comment |

up vote
6
down vote

accepted

Try: rm(list = setdiff(ls(), x))

Edit based on mickey's comment:

Three objects in environment:

ls()

[1] "data_df" "list_ls" "vector_v"

Remove data_df:

rm(list = setdiff(ls(), "data_df"))

ls()

[1] "data_df"

Vector of things to keep:

toKeep_v <- c("list_ls", "vector_v")

rm(list = setdiff(ls(), toKeep_v)

ls()

[1] "list_ls" "vector_v"

edited Nov 9 at 18:14

answered Nov 9 at 18:06

Qwfqwf

1488

Try: rm(list = setdiff(ls(), x))

Edit based on mickey's comment:

Three objects in environment:

ls()

[1] "data_df" "list_ls" "vector_v"

Remove data_df:

rm(list = setdiff(ls(), "data_df"))

ls()

[1] "data_df"

Vector of things to keep:

toKeep_v <- c("list_ls", "vector_v")

rm(list = setdiff(ls(), toKeep_v)

ls()

[1] "list_ls" "vector_v"

edited Nov 9 at 18:14

answered Nov 9 at 18:06

Qwfqwf

1488

edited Nov 9 at 18:14

answered Nov 9 at 18:06

Qwfqwf

1488

answered Nov 9 at 18:06

Qwfqwf

1488

answered Nov 9 at 18:06

Qwfqwf

1488

5

If x is the name of the data frame, it should be in quotes.
– mickey
Nov 9 at 18:08

1

While rm has NSE, setdiff doesn't so this will have unexpected results unless x is "x"
– James
Nov 9 at 18:10

add a comment |

5

If x is the name of the data frame, it should be in quotes.
– mickey
Nov 9 at 18:08

1

While rm has NSE, setdiff doesn't so this will have unexpected results unless x is "x"
– James
Nov 9 at 18:10

If x is the name of the data frame, it should be in quotes.
– mickey
Nov 9 at 18:08

While rm has NSE, setdiff doesn't so this will have unexpected results unless x is "x"
– James
Nov 9 at 18:10

add a comment |

This page is only for reference, If you need detailed information, please check here

搜尋此網誌

Wsrtjtyk