clear everything but one variable rm(list = ls()) [duplicate]
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How can I remove all objects but one from the workspace in R?
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I'm aware that rm(list = ls()) will clear my workspace.
I have a data frame x that I would like to preserve while removing everything else from memory. How can I do that?
rm(list = ls(!x)) #???
r
asked Nov 9 at 18:04
Doug Fir
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marked as duplicate by Ronak Shah r
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Nov 9 at 18:18
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This question already has an answer here:
How can I remove all objects but one from the workspace in R?
13 answers
I'm aware that rm(list = ls()) will clear my workspace.
I have a data frame x that I would like to preserve while removing everything else from memory. How can I do that?
rm(list = ls(!x)) #???
r
asked Nov 9 at 18:04
Doug Fir
5,2722780148
marked as duplicate by Ronak Shah r
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up vote
0
down vote
favorite
This question already has an answer here:
How can I remove all objects but one from the workspace in R?
13 answers
I'm aware that rm(list = ls()) will clear my workspace.
I have a data frame x that I would like to preserve while removing everything else from memory. How can I do that?
rm(list = ls(!x)) #???
r
asked Nov 9 at 18:04
Doug Fir
5,2722780148
This question already has an answer here:
How can I remove all objects but one from the workspace in R?
13 answers
I'm aware that rm(list = ls()) will clear my workspace.
I have a data frame x that I would like to preserve while removing everything else from memory. How can I do that?
rm(list = ls(!x)) #???
This question already has an answer here:
How can I remove all objects but one from the workspace in R?
13 answers
r
r
asked Nov 9 at 18:04
Doug Fir
5,2722780148
asked Nov 9 at 18:04
Doug Fir
5,2722780148
asked Nov 9 at 18:04
Doug Fir
5,2722780148
asked Nov 9 at 18:04
Doug Fir
5,2722780148
asked Nov 9 at 18:04
Doug Fir
5,2722780148
5,2722780148
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Nov 9 at 18:18
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1 Answer
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Try: rm(list = setdiff(ls(), x))
Edit based on mickey's comment:
Three objects in environment:
ls()
[1] "data_df" "list_ls" "vector_v"
Remove data_df:
rm(list = setdiff(ls(), "data_df"))
ls()
[1] "data_df"
Vector of things to keep:
toKeep_v <- c("list_ls", "vector_v")
rm(list = setdiff(ls(), toKeep_v)
ls()
[1] "list_ls" "vector_v"
answered Nov 9 at 18:06
Qwfqwf
1488
5
If x is the name of the data frame, it should be in quotes.
– mickey
Nov 9 at 18:08
1
Whilermhas NSE,setdiffdoesn't so this will have unexpected results unlessxis"x"
– James
Nov 9 at 18:10
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
6
down vote
accepted
Try: rm(list = setdiff(ls(), x))
Edit based on mickey's comment:
Three objects in environment:
ls()
[1] "data_df" "list_ls" "vector_v"
Remove data_df:
rm(list = setdiff(ls(), "data_df"))
ls()
[1] "data_df"
Vector of things to keep:
toKeep_v <- c("list_ls", "vector_v")
rm(list = setdiff(ls(), toKeep_v)
ls()
[1] "list_ls" "vector_v"
answered Nov 9 at 18:06
Qwfqwf
1488
5
If x is the name of the data frame, it should be in quotes.
– mickey
Nov 9 at 18:08
1
Whilermhas NSE,setdiffdoesn't so this will have unexpected results unlessxis"x"
– James
Nov 9 at 18:10
add a comment |
up vote
6
down vote
accepted
Try: rm(list = setdiff(ls(), x))
Edit based on mickey's comment:
Three objects in environment:
ls()
[1] "data_df" "list_ls" "vector_v"
Remove data_df:
rm(list = setdiff(ls(), "data_df"))
ls()
[1] "data_df"
Vector of things to keep:
toKeep_v <- c("list_ls", "vector_v")
rm(list = setdiff(ls(), toKeep_v)
ls()
[1] "list_ls" "vector_v"
answered Nov 9 at 18:06
Qwfqwf
1488
5
If x is the name of the data frame, it should be in quotes.
– mickey
Nov 9 at 18:08
1
Whilermhas NSE,setdiffdoesn't so this will have unexpected results unlessxis"x"
– James
Nov 9 at 18:10
add a comment |
up vote
6
down vote
accepted
up vote
6
down vote
accepted
Try: rm(list = setdiff(ls(), x))
Edit based on mickey's comment:
Three objects in environment:
ls()
[1] "data_df" "list_ls" "vector_v"
Remove data_df:
rm(list = setdiff(ls(), "data_df"))
ls()
[1] "data_df"
Vector of things to keep:
toKeep_v <- c("list_ls", "vector_v")
rm(list = setdiff(ls(), toKeep_v)
ls()
[1] "list_ls" "vector_v"
answered Nov 9 at 18:06
Qwfqwf
1488
Try: rm(list = setdiff(ls(), x))
Edit based on mickey's comment:
Three objects in environment:
ls()
[1] "data_df" "list_ls" "vector_v"
Remove data_df:
rm(list = setdiff(ls(), "data_df"))
ls()
[1] "data_df"
Vector of things to keep:
toKeep_v <- c("list_ls", "vector_v")
rm(list = setdiff(ls(), toKeep_v)
ls()
[1] "list_ls" "vector_v"
answered Nov 9 at 18:06
Qwfqwf
1488
edited Nov 9 at 18:14
answered Nov 9 at 18:06
Qwfqwf
1488
answered Nov 9 at 18:06
Qwfqwf
1488
answered Nov 9 at 18:06
Qwfqwf
1488
1488
5
If x is the name of the data frame, it should be in quotes.
– mickey
Nov 9 at 18:08
1
Whilermhas NSE,setdiffdoesn't so this will have unexpected results unlessxis"x"
– James
Nov 9 at 18:10
add a comment |
5
If x is the name of the data frame, it should be in quotes.
– mickey
Nov 9 at 18:08
1
Whilermhas NSE,setdiffdoesn't so this will have unexpected results unlessxis"x"
– James
Nov 9 at 18:10
5
5
If x is the name of the data frame, it should be in quotes.
– mickey
Nov 9 at 18:08
If x is the name of the data frame, it should be in quotes.
– mickey
Nov 9 at 18:08
1
1
While
rm has NSE, setdiff doesn't so this will have unexpected results unless x is "x"– James
Nov 9 at 18:10
While
rm has NSE, setdiff doesn't so this will have unexpected results unless x is "x"– James
Nov 9 at 18:10
add a comment |
