Removing square brackets from hash array for value











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2
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I am having a following hash array



A = [{"name" => ["xx"], "status" => ["true"]}, {"name" => ["yy"], "status" => ["true"]}


I tried following code to remove the square brackets



A.to_s.gsub("\[|\]", "")


also tried with code



p A.map { |hash| hash.each_with_object({}) { |(k, v), hash| hash[k] = v.first } }


but its not working.



How I remove the square brackets to get following output



A = [{"name" => "xx", "status" => "true"}, {"name" => "yy", "status" => "true"}


Kindly assist










share|improve this question




























    up vote
    2
    down vote

    favorite












    I am having a following hash array



    A = [{"name" => ["xx"], "status" => ["true"]}, {"name" => ["yy"], "status" => ["true"]}


    I tried following code to remove the square brackets



    A.to_s.gsub("\[|\]", "")


    also tried with code



    p A.map { |hash| hash.each_with_object({}) { |(k, v), hash| hash[k] = v.first } }


    but its not working.



    How I remove the square brackets to get following output



    A = [{"name" => "xx", "status" => "true"}, {"name" => "yy", "status" => "true"}


    Kindly assist










    share|improve this question


























      up vote
      2
      down vote

      favorite









      up vote
      2
      down vote

      favorite











      I am having a following hash array



      A = [{"name" => ["xx"], "status" => ["true"]}, {"name" => ["yy"], "status" => ["true"]}


      I tried following code to remove the square brackets



      A.to_s.gsub("\[|\]", "")


      also tried with code



      p A.map { |hash| hash.each_with_object({}) { |(k, v), hash| hash[k] = v.first } }


      but its not working.



      How I remove the square brackets to get following output



      A = [{"name" => "xx", "status" => "true"}, {"name" => "yy", "status" => "true"}


      Kindly assist










      share|improve this question















      I am having a following hash array



      A = [{"name" => ["xx"], "status" => ["true"]}, {"name" => ["yy"], "status" => ["true"]}


      I tried following code to remove the square brackets



      A.to_s.gsub("\[|\]", "")


      also tried with code



      p A.map { |hash| hash.each_with_object({}) { |(k, v), hash| hash[k] = v.first } }


      but its not working.



      How I remove the square brackets to get following output



      A = [{"name" => "xx", "status" => "true"}, {"name" => "yy", "status" => "true"}


      Kindly assist







      ruby hash






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 8 at 19:32

























      asked Nov 8 at 18:48









      Jinx

      236




      236
























          1 Answer
          1






          active

          oldest

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          up vote
          3
          down vote



          accepted










          Since they're strings inside arrays, the is the representation Ruby does of it. Try accessing the first element for each key's value in those hashes:



          a = [{"name" => ["xx"], "status" => ["true"]}, {"name" => ["yy"], "status" => ["true"]}]
          p a.map { |hash| hash.transform_values(&:first) }
          # [{"name"=>"xx", "status"=>"true"}, {"name"=>"yy", "status"=>"true"}]


          Depending on your Ruby version, you might not have transform_values available. A simple each_with_object would work similarly in that case:



          p a.map { |hash| hash.each_with_object({}) { |(k, v), hash| hash[k] = v.first } }
          # [{"name"=>"xx", "status"=>"true"}, {"name"=>"yy", "status"=>"true"}]





          share|improve this answer























          • Its throwing me undefined method `transform_values' for {"name"=>["xx"], "status"=>["true"]}:Hash (NoMethodError)
            – Jinx
            Nov 8 at 18:59










          • Sorry, it depends in your Ruby version. See the updated answer.
            – Sebastian Palma
            Nov 8 at 19:03










          • I am not sure what I did wrong but its still giving me response as A = [{"name" => ["xx"], "status" => ["true"]}, {"name" => ["yy"], "status" => ["true"]}
            – Jinx
            Nov 8 at 19:29










          • Can you add your attempt to the question?
            – Sebastian Palma
            Nov 8 at 19:30










          • updated the question.
            – Jinx
            Nov 8 at 19:33











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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          3
          down vote



          accepted










          Since they're strings inside arrays, the is the representation Ruby does of it. Try accessing the first element for each key's value in those hashes:



          a = [{"name" => ["xx"], "status" => ["true"]}, {"name" => ["yy"], "status" => ["true"]}]
          p a.map { |hash| hash.transform_values(&:first) }
          # [{"name"=>"xx", "status"=>"true"}, {"name"=>"yy", "status"=>"true"}]


          Depending on your Ruby version, you might not have transform_values available. A simple each_with_object would work similarly in that case:



          p a.map { |hash| hash.each_with_object({}) { |(k, v), hash| hash[k] = v.first } }
          # [{"name"=>"xx", "status"=>"true"}, {"name"=>"yy", "status"=>"true"}]





          share|improve this answer























          • Its throwing me undefined method `transform_values' for {"name"=>["xx"], "status"=>["true"]}:Hash (NoMethodError)
            – Jinx
            Nov 8 at 18:59










          • Sorry, it depends in your Ruby version. See the updated answer.
            – Sebastian Palma
            Nov 8 at 19:03










          • I am not sure what I did wrong but its still giving me response as A = [{"name" => ["xx"], "status" => ["true"]}, {"name" => ["yy"], "status" => ["true"]}
            – Jinx
            Nov 8 at 19:29










          • Can you add your attempt to the question?
            – Sebastian Palma
            Nov 8 at 19:30










          • updated the question.
            – Jinx
            Nov 8 at 19:33















          up vote
          3
          down vote



          accepted










          Since they're strings inside arrays, the is the representation Ruby does of it. Try accessing the first element for each key's value in those hashes:



          a = [{"name" => ["xx"], "status" => ["true"]}, {"name" => ["yy"], "status" => ["true"]}]
          p a.map { |hash| hash.transform_values(&:first) }
          # [{"name"=>"xx", "status"=>"true"}, {"name"=>"yy", "status"=>"true"}]


          Depending on your Ruby version, you might not have transform_values available. A simple each_with_object would work similarly in that case:



          p a.map { |hash| hash.each_with_object({}) { |(k, v), hash| hash[k] = v.first } }
          # [{"name"=>"xx", "status"=>"true"}, {"name"=>"yy", "status"=>"true"}]





          share|improve this answer























          • Its throwing me undefined method `transform_values' for {"name"=>["xx"], "status"=>["true"]}:Hash (NoMethodError)
            – Jinx
            Nov 8 at 18:59










          • Sorry, it depends in your Ruby version. See the updated answer.
            – Sebastian Palma
            Nov 8 at 19:03










          • I am not sure what I did wrong but its still giving me response as A = [{"name" => ["xx"], "status" => ["true"]}, {"name" => ["yy"], "status" => ["true"]}
            – Jinx
            Nov 8 at 19:29










          • Can you add your attempt to the question?
            – Sebastian Palma
            Nov 8 at 19:30










          • updated the question.
            – Jinx
            Nov 8 at 19:33













          up vote
          3
          down vote



          accepted







          up vote
          3
          down vote



          accepted






          Since they're strings inside arrays, the is the representation Ruby does of it. Try accessing the first element for each key's value in those hashes:



          a = [{"name" => ["xx"], "status" => ["true"]}, {"name" => ["yy"], "status" => ["true"]}]
          p a.map { |hash| hash.transform_values(&:first) }
          # [{"name"=>"xx", "status"=>"true"}, {"name"=>"yy", "status"=>"true"}]


          Depending on your Ruby version, you might not have transform_values available. A simple each_with_object would work similarly in that case:



          p a.map { |hash| hash.each_with_object({}) { |(k, v), hash| hash[k] = v.first } }
          # [{"name"=>"xx", "status"=>"true"}, {"name"=>"yy", "status"=>"true"}]





          share|improve this answer














          Since they're strings inside arrays, the is the representation Ruby does of it. Try accessing the first element for each key's value in those hashes:



          a = [{"name" => ["xx"], "status" => ["true"]}, {"name" => ["yy"], "status" => ["true"]}]
          p a.map { |hash| hash.transform_values(&:first) }
          # [{"name"=>"xx", "status"=>"true"}, {"name"=>"yy", "status"=>"true"}]


          Depending on your Ruby version, you might not have transform_values available. A simple each_with_object would work similarly in that case:



          p a.map { |hash| hash.each_with_object({}) { |(k, v), hash| hash[k] = v.first } }
          # [{"name"=>"xx", "status"=>"true"}, {"name"=>"yy", "status"=>"true"}]






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 8 at 19:05

























          answered Nov 8 at 18:53









          Sebastian Palma

          15.2k41933




          15.2k41933












          • Its throwing me undefined method `transform_values' for {"name"=>["xx"], "status"=>["true"]}:Hash (NoMethodError)
            – Jinx
            Nov 8 at 18:59










          • Sorry, it depends in your Ruby version. See the updated answer.
            – Sebastian Palma
            Nov 8 at 19:03










          • I am not sure what I did wrong but its still giving me response as A = [{"name" => ["xx"], "status" => ["true"]}, {"name" => ["yy"], "status" => ["true"]}
            – Jinx
            Nov 8 at 19:29










          • Can you add your attempt to the question?
            – Sebastian Palma
            Nov 8 at 19:30










          • updated the question.
            – Jinx
            Nov 8 at 19:33


















          • Its throwing me undefined method `transform_values' for {"name"=>["xx"], "status"=>["true"]}:Hash (NoMethodError)
            – Jinx
            Nov 8 at 18:59










          • Sorry, it depends in your Ruby version. See the updated answer.
            – Sebastian Palma
            Nov 8 at 19:03










          • I am not sure what I did wrong but its still giving me response as A = [{"name" => ["xx"], "status" => ["true"]}, {"name" => ["yy"], "status" => ["true"]}
            – Jinx
            Nov 8 at 19:29










          • Can you add your attempt to the question?
            – Sebastian Palma
            Nov 8 at 19:30










          • updated the question.
            – Jinx
            Nov 8 at 19:33
















          Its throwing me undefined method `transform_values' for {"name"=>["xx"], "status"=>["true"]}:Hash (NoMethodError)
          – Jinx
          Nov 8 at 18:59




          Its throwing me undefined method `transform_values' for {"name"=>["xx"], "status"=>["true"]}:Hash (NoMethodError)
          – Jinx
          Nov 8 at 18:59












          Sorry, it depends in your Ruby version. See the updated answer.
          – Sebastian Palma
          Nov 8 at 19:03




          Sorry, it depends in your Ruby version. See the updated answer.
          – Sebastian Palma
          Nov 8 at 19:03












          I am not sure what I did wrong but its still giving me response as A = [{"name" => ["xx"], "status" => ["true"]}, {"name" => ["yy"], "status" => ["true"]}
          – Jinx
          Nov 8 at 19:29




          I am not sure what I did wrong but its still giving me response as A = [{"name" => ["xx"], "status" => ["true"]}, {"name" => ["yy"], "status" => ["true"]}
          – Jinx
          Nov 8 at 19:29












          Can you add your attempt to the question?
          – Sebastian Palma
          Nov 8 at 19:30




          Can you add your attempt to the question?
          – Sebastian Palma
          Nov 8 at 19:30












          updated the question.
          – Jinx
          Nov 8 at 19:33




          updated the question.
          – Jinx
          Nov 8 at 19:33


















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