How to check if string has letter in second character with regex
Say I wanted to create an ID number such as 1A45 or 4F01.
What would the regex be to make sure that the string had exactly one letter as the second character?
I am unsure how to check for specific combinations of characters.
What I have so far is:
if(!Regex.IsMatch(txtTrainID.Text, @"^[w,d,w,w]+$"))
Which is obviously completely wrong, I've had trouble trying to find a decent simple answer to this anywhere.
c# regex
edited Dec 2 '18 at 11:40
Jan
24.4k52348
asked Nov 14 '18 at 7:33
ESuthESuth
676
add a comment |
Say I wanted to create an ID number such as 1A45 or 4F01.
What would the regex be to make sure that the string had exactly one letter as the second character?
I am unsure how to check for specific combinations of characters.
What I have so far is:
if(!Regex.IsMatch(txtTrainID.Text, @"^[w,d,w,w]+$"))
Which is obviously completely wrong, I've had trouble trying to find a decent simple answer to this anywhere.
c# regex
edited Dec 2 '18 at 11:40
Jan
24.4k52348
asked Nov 14 '18 at 7:33
ESuthESuth
676
What about other three characters? I guess you have X/Y problem.
– JohnyL
Dec 2 '18 at 11:50
add a comment |
Say I wanted to create an ID number such as 1A45 or 4F01.
What would the regex be to make sure that the string had exactly one letter as the second character?
I am unsure how to check for specific combinations of characters.
What I have so far is:
if(!Regex.IsMatch(txtTrainID.Text, @"^[w,d,w,w]+$"))
Which is obviously completely wrong, I've had trouble trying to find a decent simple answer to this anywhere.
c# regex
edited Dec 2 '18 at 11:40
Jan
24.4k52348
asked Nov 14 '18 at 7:33
ESuthESuth
676
Say I wanted to create an ID number such as 1A45 or 4F01.
What would the regex be to make sure that the string had exactly one letter as the second character?
I am unsure how to check for specific combinations of characters.
What I have so far is:
if(!Regex.IsMatch(txtTrainID.Text, @"^[w,d,w,w]+$"))
Which is obviously completely wrong, I've had trouble trying to find a decent simple answer to this anywhere.
c# regex
c# regex
edited Dec 2 '18 at 11:40
Jan
24.4k52348
asked Nov 14 '18 at 7:33
ESuthESuth
676
edited Dec 2 '18 at 11:40
Jan
24.4k52348
asked Nov 14 '18 at 7:33
ESuthESuth
676
edited Dec 2 '18 at 11:40
Jan
24.4k52348
edited Dec 2 '18 at 11:40
Jan
24.4k52348
edited Dec 2 '18 at 11:40
Jan
24.4k52348
24.4k52348
asked Nov 14 '18 at 7:33
ESuthESuth
676
asked Nov 14 '18 at 7:33
ESuthESuth
676
asked Nov 14 '18 at 7:33
ESuthESuth
676
676
What about other three characters? I guess you have X/Y problem.
– JohnyL
Dec 2 '18 at 11:50
add a comment |
What about other three characters? I guess you have X/Y problem.
– JohnyL
Dec 2 '18 at 11:50
What about other three characters? I guess you have X/Y problem.
– JohnyL
Dec 2 '18 at 11:50
What about other three characters? I guess you have X/Y problem.
– JohnyL
Dec 2 '18 at 11:50
add a comment |
1 Answer
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oldest
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If that's the only requirement (and I am sure it's not), use anchors and a character class in the second position as in
^.[A-Za-z]
See a demo on regex101.com.
What you probably mean, comes down to:
^d[a-zA-Z]d{2}$
The latter means one digit, one of a-zA-Z, followed by two other digits and the end of the string. See another demo on the same site.
answered Nov 14 '18 at 7:35
JanJan
24.4k52348
add a comment |
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1 Answer
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1 Answer
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active
oldest
votes
active
oldest
votes
active
oldest
votes
If that's the only requirement (and I am sure it's not), use anchors and a character class in the second position as in
^.[A-Za-z]
See a demo on regex101.com.
What you probably mean, comes down to:
^d[a-zA-Z]d{2}$
The latter means one digit, one of a-zA-Z, followed by two other digits and the end of the string. See another demo on the same site.
answered Nov 14 '18 at 7:35
JanJan
24.4k52348
add a comment |
If that's the only requirement (and I am sure it's not), use anchors and a character class in the second position as in
^.[A-Za-z]
See a demo on regex101.com.
What you probably mean, comes down to:
^d[a-zA-Z]d{2}$
The latter means one digit, one of a-zA-Z, followed by two other digits and the end of the string. See another demo on the same site.
answered Nov 14 '18 at 7:35
JanJan
24.4k52348
add a comment |
If that's the only requirement (and I am sure it's not), use anchors and a character class in the second position as in
^.[A-Za-z]
See a demo on regex101.com.
What you probably mean, comes down to:
^d[a-zA-Z]d{2}$
The latter means one digit, one of a-zA-Z, followed by two other digits and the end of the string. See another demo on the same site.
answered Nov 14 '18 at 7:35
JanJan
24.4k52348
If that's the only requirement (and I am sure it's not), use anchors and a character class in the second position as in
^.[A-Za-z]
See a demo on regex101.com.
What you probably mean, comes down to:
^d[a-zA-Z]d{2}$
The latter means one digit, one of a-zA-Z, followed by two other digits and the end of the string. See another demo on the same site.
answered Nov 14 '18 at 7:35
JanJan
24.4k52348
answered Nov 14 '18 at 7:35
JanJan
24.4k52348
answered Nov 14 '18 at 7:35
JanJan
24.4k52348
answered Nov 14 '18 at 7:35
JanJan
24.4k52348
24.4k52348
add a comment |
add a comment |
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What about other three characters? I guess you have X/Y problem.
– JohnyL
Dec 2 '18 at 11:50