How to use Julia to compute the pearson correlation coefficient with p-value?












1















I am looking for help to calculate the Pearson correlation coefficient with p-value by using Julia language. The analogous function in Python is scipy.stats.pearson.



The Julia function below only gives me the correlation. Appreciate your help/hint about the p-value part.



using RDatasets, Statistics
iris = dataset("datasets", "iris");
Statistics.cor(iris.SepalLength, iris.SepalWidth)









share|improve this question





























    1















    I am looking for help to calculate the Pearson correlation coefficient with p-value by using Julia language. The analogous function in Python is scipy.stats.pearson.



    The Julia function below only gives me the correlation. Appreciate your help/hint about the p-value part.



    using RDatasets, Statistics
    iris = dataset("datasets", "iris");
    Statistics.cor(iris.SepalLength, iris.SepalWidth)









    share|improve this question



























      1












      1








      1








      I am looking for help to calculate the Pearson correlation coefficient with p-value by using Julia language. The analogous function in Python is scipy.stats.pearson.



      The Julia function below only gives me the correlation. Appreciate your help/hint about the p-value part.



      using RDatasets, Statistics
      iris = dataset("datasets", "iris");
      Statistics.cor(iris.SepalLength, iris.SepalWidth)









      share|improve this question
















      I am looking for help to calculate the Pearson correlation coefficient with p-value by using Julia language. The analogous function in Python is scipy.stats.pearson.



      The Julia function below only gives me the correlation. Appreciate your help/hint about the p-value part.



      using RDatasets, Statistics
      iris = dataset("datasets", "iris");
      Statistics.cor(iris.SepalLength, iris.SepalWidth)






      julia-lang






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      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 16 '18 at 21:39







      Puriney

















      asked Nov 16 '18 at 21:34









      PurineyPuriney

      90821022




      90821022
























          1 Answer
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          I do not know about an existing implementation but here is a two-sided test with H0 equal to 0 using Fisher transformation:



          using Distributions

          cortest(x,y) =
          if length(x) == length(y)
          2 * ccdf(Normal(), atanh(abs(cor(x, y))) * sqrt(length(x) - 3))
          else
          error("x and y have different lengths")
          end


          or use the HypothesisTests.jl package, e.g.:



          using HypothesisTests

          OneSampleZTest(atanh(cor(iris.SepalLength, iris.SepalWidth)),
          1, nrow(iris)-3)





          share|improve this answer

























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            1 Answer
            1






            active

            oldest

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            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            2














            I do not know about an existing implementation but here is a two-sided test with H0 equal to 0 using Fisher transformation:



            using Distributions

            cortest(x,y) =
            if length(x) == length(y)
            2 * ccdf(Normal(), atanh(abs(cor(x, y))) * sqrt(length(x) - 3))
            else
            error("x and y have different lengths")
            end


            or use the HypothesisTests.jl package, e.g.:



            using HypothesisTests

            OneSampleZTest(atanh(cor(iris.SepalLength, iris.SepalWidth)),
            1, nrow(iris)-3)





            share|improve this answer






























              2














              I do not know about an existing implementation but here is a two-sided test with H0 equal to 0 using Fisher transformation:



              using Distributions

              cortest(x,y) =
              if length(x) == length(y)
              2 * ccdf(Normal(), atanh(abs(cor(x, y))) * sqrt(length(x) - 3))
              else
              error("x and y have different lengths")
              end


              or use the HypothesisTests.jl package, e.g.:



              using HypothesisTests

              OneSampleZTest(atanh(cor(iris.SepalLength, iris.SepalWidth)),
              1, nrow(iris)-3)





              share|improve this answer




























                2












                2








                2







                I do not know about an existing implementation but here is a two-sided test with H0 equal to 0 using Fisher transformation:



                using Distributions

                cortest(x,y) =
                if length(x) == length(y)
                2 * ccdf(Normal(), atanh(abs(cor(x, y))) * sqrt(length(x) - 3))
                else
                error("x and y have different lengths")
                end


                or use the HypothesisTests.jl package, e.g.:



                using HypothesisTests

                OneSampleZTest(atanh(cor(iris.SepalLength, iris.SepalWidth)),
                1, nrow(iris)-3)





                share|improve this answer















                I do not know about an existing implementation but here is a two-sided test with H0 equal to 0 using Fisher transformation:



                using Distributions

                cortest(x,y) =
                if length(x) == length(y)
                2 * ccdf(Normal(), atanh(abs(cor(x, y))) * sqrt(length(x) - 3))
                else
                error("x and y have different lengths")
                end


                or use the HypothesisTests.jl package, e.g.:



                using HypothesisTests

                OneSampleZTest(atanh(cor(iris.SepalLength, iris.SepalWidth)),
                1, nrow(iris)-3)






                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Nov 17 '18 at 8:50

























                answered Nov 16 '18 at 22:02









                Bogumił KamińskiBogumił Kamiński

                12.8k11220




                12.8k11220






























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