How to use sqrt on Double in Spark Scala












1














I am trying to calculate Root Mean Square Error (RMSE) manually on Spark (Scala 2.11)



se



As screenshot above, I calculate Square Error (SE) for each row



val predicted_with_sqr_err = predicted.withColumn("se", pow(($"medianHouseValue" - $"prediction"), lit(2)))


Then I calculate Mean Square Error (MSE)



val sum_se = predicted_with_sqr_err.agg(sum("se")).first.get(0)
val sum_se_double = sum_se.toString.toDouble
val mean_sqr_err = (1.0/predicted_with_sqr_err.count)*sum_se_double


It worked fine. But when I trying to square root to calculate Root Mean Square Error (RMSE).



val root_mean_sqr_err = sqrt(mean_sqr_err)


It give error:



<console>:83: error: overloaded method value sqrt with alternatives:
(colName: String)org.apache.spark.sql.Column <and>
(e: org.apache.spark.sql.Column)org.apache.spark.sql.Column
cannot be applied to (Double)
val root_mean_sqr_err = sqrt(mean_sqr_err)


sqrt error



How should I fix ?










share|improve this question



























    1














    I am trying to calculate Root Mean Square Error (RMSE) manually on Spark (Scala 2.11)



    se



    As screenshot above, I calculate Square Error (SE) for each row



    val predicted_with_sqr_err = predicted.withColumn("se", pow(($"medianHouseValue" - $"prediction"), lit(2)))


    Then I calculate Mean Square Error (MSE)



    val sum_se = predicted_with_sqr_err.agg(sum("se")).first.get(0)
    val sum_se_double = sum_se.toString.toDouble
    val mean_sqr_err = (1.0/predicted_with_sqr_err.count)*sum_se_double


    It worked fine. But when I trying to square root to calculate Root Mean Square Error (RMSE).



    val root_mean_sqr_err = sqrt(mean_sqr_err)


    It give error:



    <console>:83: error: overloaded method value sqrt with alternatives:
    (colName: String)org.apache.spark.sql.Column <and>
    (e: org.apache.spark.sql.Column)org.apache.spark.sql.Column
    cannot be applied to (Double)
    val root_mean_sqr_err = sqrt(mean_sqr_err)


    sqrt error



    How should I fix ?










    share|improve this question

























      1












      1








      1







      I am trying to calculate Root Mean Square Error (RMSE) manually on Spark (Scala 2.11)



      se



      As screenshot above, I calculate Square Error (SE) for each row



      val predicted_with_sqr_err = predicted.withColumn("se", pow(($"medianHouseValue" - $"prediction"), lit(2)))


      Then I calculate Mean Square Error (MSE)



      val sum_se = predicted_with_sqr_err.agg(sum("se")).first.get(0)
      val sum_se_double = sum_se.toString.toDouble
      val mean_sqr_err = (1.0/predicted_with_sqr_err.count)*sum_se_double


      It worked fine. But when I trying to square root to calculate Root Mean Square Error (RMSE).



      val root_mean_sqr_err = sqrt(mean_sqr_err)


      It give error:



      <console>:83: error: overloaded method value sqrt with alternatives:
      (colName: String)org.apache.spark.sql.Column <and>
      (e: org.apache.spark.sql.Column)org.apache.spark.sql.Column
      cannot be applied to (Double)
      val root_mean_sqr_err = sqrt(mean_sqr_err)


      sqrt error



      How should I fix ?










      share|improve this question













      I am trying to calculate Root Mean Square Error (RMSE) manually on Spark (Scala 2.11)



      se



      As screenshot above, I calculate Square Error (SE) for each row



      val predicted_with_sqr_err = predicted.withColumn("se", pow(($"medianHouseValue" - $"prediction"), lit(2)))


      Then I calculate Mean Square Error (MSE)



      val sum_se = predicted_with_sqr_err.agg(sum("se")).first.get(0)
      val sum_se_double = sum_se.toString.toDouble
      val mean_sqr_err = (1.0/predicted_with_sqr_err.count)*sum_se_double


      It worked fine. But when I trying to square root to calculate Root Mean Square Error (RMSE).



      val root_mean_sqr_err = sqrt(mean_sqr_err)


      It give error:



      <console>:83: error: overloaded method value sqrt with alternatives:
      (colName: String)org.apache.spark.sql.Column <and>
      (e: org.apache.spark.sql.Column)org.apache.spark.sql.Column
      cannot be applied to (Double)
      val root_mean_sqr_err = sqrt(mean_sqr_err)


      sqrt error



      How should I fix ?







      scala apache-spark apache-zeppelin






      share|improve this question













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      asked Nov 12 '18 at 12:26









      Haha TTpro

      1,42031031




      1,42031031
























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          The problem is that you are using sqrt function which is defined in Spark SQL. This function should be used only as a part of Spark SQL DSL (in selections, aggregations, etc.).
          It takes Column or String as a parameter but you are trying to pass Double.
          Instead use sqrt function which is defined in scala.math package:



          val root_mean_sqr_err = math.sqrt(mean_sqr_err)





          share|improve this answer





















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            1 Answer
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            active

            oldest

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            active

            oldest

            votes






            active

            oldest

            votes









            2














            The problem is that you are using sqrt function which is defined in Spark SQL. This function should be used only as a part of Spark SQL DSL (in selections, aggregations, etc.).
            It takes Column or String as a parameter but you are trying to pass Double.
            Instead use sqrt function which is defined in scala.math package:



            val root_mean_sqr_err = math.sqrt(mean_sqr_err)





            share|improve this answer


























              2














              The problem is that you are using sqrt function which is defined in Spark SQL. This function should be used only as a part of Spark SQL DSL (in selections, aggregations, etc.).
              It takes Column or String as a parameter but you are trying to pass Double.
              Instead use sqrt function which is defined in scala.math package:



              val root_mean_sqr_err = math.sqrt(mean_sqr_err)





              share|improve this answer
























                2












                2








                2






                The problem is that you are using sqrt function which is defined in Spark SQL. This function should be used only as a part of Spark SQL DSL (in selections, aggregations, etc.).
                It takes Column or String as a parameter but you are trying to pass Double.
                Instead use sqrt function which is defined in scala.math package:



                val root_mean_sqr_err = math.sqrt(mean_sqr_err)





                share|improve this answer












                The problem is that you are using sqrt function which is defined in Spark SQL. This function should be used only as a part of Spark SQL DSL (in selections, aggregations, etc.).
                It takes Column or String as a parameter but you are trying to pass Double.
                Instead use sqrt function which is defined in scala.math package:



                val root_mean_sqr_err = math.sqrt(mean_sqr_err)






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 12 '18 at 12:44









                Vitalii Honta

                1878




                1878






























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