Getting nested group members via Get-ADObject
I have Universal group with distribution scope and there are contacts and groups and users which are members of this DL. I am trying to below command but not getting details of groups or users with powershell. Those groups have groups nested within them that contain users.
How can i export nested group members and users from distribution group from AD Powershell cmdlet?
Example:
Group A
Members = asmith(Contact), jbloggs,Group B (member = kbrown)
Here is my code :
$memberof=get-adgroup -Filter "Name -like 'IT*'" |select -expandproperty distinguishedname
#$distinguishedName = $memberof -replace "(CN=)(.*?),.*",'$2'
foreach ($memberof1 in $memberof) {
$distinguishedName = $memberof1 -replace "(CN=)(.*?),.*",'$2'
Get-ADObject -Filter 'memberof -eq $memberof1 -and (objectClass -eq "user" -or ObjectClass -eq "contact" -or objectclass -eq "group")' -properties *|select name | Export-csv -Path "C:temp$distinguishedName.csv" -NoTypeInformation -Encoding UTF8
}
powershell
asked Nov 20 '18 at 10:28
ArbelacArbelac
45011129
add a comment |
I have Universal group with distribution scope and there are contacts and groups and users which are members of this DL. I am trying to below command but not getting details of groups or users with powershell. Those groups have groups nested within them that contain users.
How can i export nested group members and users from distribution group from AD Powershell cmdlet?
Example:
Group A
Members = asmith(Contact), jbloggs,Group B (member = kbrown)
Here is my code :
$memberof=get-adgroup -Filter "Name -like 'IT*'" |select -expandproperty distinguishedname
#$distinguishedName = $memberof -replace "(CN=)(.*?),.*",'$2'
foreach ($memberof1 in $memberof) {
$distinguishedName = $memberof1 -replace "(CN=)(.*?),.*",'$2'
Get-ADObject -Filter 'memberof -eq $memberof1 -and (objectClass -eq "user" -or ObjectClass -eq "contact" -or objectclass -eq "group")' -properties *|select name | Export-csv -Path "C:temp$distinguishedName.csv" -NoTypeInformation -Encoding UTF8
}
powershell
asked Nov 20 '18 at 10:28
ArbelacArbelac
45011129
add a comment |
I have Universal group with distribution scope and there are contacts and groups and users which are members of this DL. I am trying to below command but not getting details of groups or users with powershell. Those groups have groups nested within them that contain users.
How can i export nested group members and users from distribution group from AD Powershell cmdlet?
Example:
Group A
Members = asmith(Contact), jbloggs,Group B (member = kbrown)
Here is my code :
$memberof=get-adgroup -Filter "Name -like 'IT*'" |select -expandproperty distinguishedname
#$distinguishedName = $memberof -replace "(CN=)(.*?),.*",'$2'
foreach ($memberof1 in $memberof) {
$distinguishedName = $memberof1 -replace "(CN=)(.*?),.*",'$2'
Get-ADObject -Filter 'memberof -eq $memberof1 -and (objectClass -eq "user" -or ObjectClass -eq "contact" -or objectclass -eq "group")' -properties *|select name | Export-csv -Path "C:temp$distinguishedName.csv" -NoTypeInformation -Encoding UTF8
}
powershell
asked Nov 20 '18 at 10:28
ArbelacArbelac
45011129
I have Universal group with distribution scope and there are contacts and groups and users which are members of this DL. I am trying to below command but not getting details of groups or users with powershell. Those groups have groups nested within them that contain users.
How can i export nested group members and users from distribution group from AD Powershell cmdlet?
Example:
Group A
Members = asmith(Contact), jbloggs,Group B (member = kbrown)
Here is my code :
$memberof=get-adgroup -Filter "Name -like 'IT*'" |select -expandproperty distinguishedname
#$distinguishedName = $memberof -replace "(CN=)(.*?),.*",'$2'
foreach ($memberof1 in $memberof) {
$distinguishedName = $memberof1 -replace "(CN=)(.*?),.*",'$2'
Get-ADObject -Filter 'memberof -eq $memberof1 -and (objectClass -eq "user" -or ObjectClass -eq "contact" -or objectclass -eq "group")' -properties *|select name | Export-csv -Path "C:temp$distinguishedName.csv" -NoTypeInformation -Encoding UTF8
}
powershell
powershell
asked Nov 20 '18 at 10:28
ArbelacArbelac
45011129
asked Nov 20 '18 at 10:28
ArbelacArbelac
45011129
asked Nov 20 '18 at 10:28
ArbelacArbelac
45011129
asked Nov 20 '18 at 10:28
ArbelacArbelac
45011129
asked Nov 20 '18 at 10:28
ArbelacArbelac
45011129
45011129
add a comment |
add a comment |
1 Answer
1
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votes
Either use Get-ADGroupMember with the -Recursive parameter switch:
$AllMembers = Get-ADGroup -Filter "Name -like 'IT*'" |Get-ADGroupMember -Recursive
or use the special in-chain operator in an LDAP query filter for the memberOf attribute:
$GroupDN = Get-ADGroup -Filter "Name -like 'IT*'" |Select -Expand DistinguishedName
$AllMembers = Get-ADUser -LDAPFilter "(memberof:1.2.840.113556.1.4.1941:=$GroupDN)"
answered Nov 20 '18 at 11:04
Mathias R. JessenMathias R. Jessen
57.8k460106
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Either use Get-ADGroupMember with the -Recursive parameter switch:
$AllMembers = Get-ADGroup -Filter "Name -like 'IT*'" |Get-ADGroupMember -Recursive
or use the special in-chain operator in an LDAP query filter for the memberOf attribute:
$GroupDN = Get-ADGroup -Filter "Name -like 'IT*'" |Select -Expand DistinguishedName
$AllMembers = Get-ADUser -LDAPFilter "(memberof:1.2.840.113556.1.4.1941:=$GroupDN)"
answered Nov 20 '18 at 11:04
Mathias R. JessenMathias R. Jessen
57.8k460106
add a comment |
Either use Get-ADGroupMember with the -Recursive parameter switch:
$AllMembers = Get-ADGroup -Filter "Name -like 'IT*'" |Get-ADGroupMember -Recursive
or use the special in-chain operator in an LDAP query filter for the memberOf attribute:
$GroupDN = Get-ADGroup -Filter "Name -like 'IT*'" |Select -Expand DistinguishedName
$AllMembers = Get-ADUser -LDAPFilter "(memberof:1.2.840.113556.1.4.1941:=$GroupDN)"
answered Nov 20 '18 at 11:04
Mathias R. JessenMathias R. Jessen
57.8k460106
add a comment |
Either use Get-ADGroupMember with the -Recursive parameter switch:
$AllMembers = Get-ADGroup -Filter "Name -like 'IT*'" |Get-ADGroupMember -Recursive
or use the special in-chain operator in an LDAP query filter for the memberOf attribute:
$GroupDN = Get-ADGroup -Filter "Name -like 'IT*'" |Select -Expand DistinguishedName
$AllMembers = Get-ADUser -LDAPFilter "(memberof:1.2.840.113556.1.4.1941:=$GroupDN)"
answered Nov 20 '18 at 11:04
Mathias R. JessenMathias R. Jessen
57.8k460106
Either use Get-ADGroupMember with the -Recursive parameter switch:
$AllMembers = Get-ADGroup -Filter "Name -like 'IT*'" |Get-ADGroupMember -Recursive
or use the special in-chain operator in an LDAP query filter for the memberOf attribute:
$GroupDN = Get-ADGroup -Filter "Name -like 'IT*'" |Select -Expand DistinguishedName
$AllMembers = Get-ADUser -LDAPFilter "(memberof:1.2.840.113556.1.4.1941:=$GroupDN)"
answered Nov 20 '18 at 11:04
Mathias R. JessenMathias R. Jessen
57.8k460106
answered Nov 20 '18 at 11:04
Mathias R. JessenMathias R. Jessen
57.8k460106
answered Nov 20 '18 at 11:04
Mathias R. JessenMathias R. Jessen
57.8k460106
answered Nov 20 '18 at 11:04
Mathias R. JessenMathias R. Jessen
57.8k460106
57.8k460106
add a comment |
add a comment |
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