split character at deliminator conditionally negative lookahead assertion












1















I want to split a string at . or : unless the next character is )



Following this question: R strsplit: Split based on character except when a specific character follows why isn't 



strsplit("Glenelg (Vic.)",'\.|:(?!\))', perl = TRUE)


returning 



[[1]]

[1] "Glenelg (Vic)"


instead it splits at the ., like so: 



[1] "Glenelg (Vic" ")"





r regex pcre







share|improve this question



























    1















    I want to split a string at . or : unless the next character is )



    Following this question: R strsplit: Split based on character except when a specific character follows why isn't 



    strsplit("Glenelg (Vic.)",'\.|:(?!\))', perl = TRUE)


    returning 



    [[1]]
    
[1] "Glenelg (Vic)"


    instead it splits at the ., like so: 



    [1] "Glenelg (Vic" ")"





    r regex pcre







    share|improve this question

























      1












      1








      1








      I want to split a string at . or : unless the next character is )



      Following this question: R strsplit: Split based on character except when a specific character follows why isn't 



      strsplit("Glenelg (Vic.)",'\.|:(?!\))', perl = TRUE)


      returning 



      [[1]]
      
[1] "Glenelg (Vic)"


      instead it splits at the ., like so: 



      [1] "Glenelg (Vic" ")"





      r regex pcre







      share|improve this question














      I want to split a string at . or : unless the next character is )



      Following this question: R strsplit: Split based on character except when a specific character follows why isn't 



      strsplit("Glenelg (Vic.)",'\.|:(?!\))', perl = TRUE)


      returning 



      [[1]]
      
[1] "Glenelg (Vic)"


      instead it splits at the ., like so: 



      [1] "Glenelg (Vic" ")"





      r regex pcre




      r regex pcre






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 19 '18 at 23:15









      R.M.R.M.

      1,0531924




      1,0531924
























          2 Answers
          2






          active

          oldest

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          1














          It is not grouped correctly. .|:(?!)) matches a . anywhere in a string or a : not followed with ). If you group . and : patterns, '(?:\.|:)(?!\))', it will work.



          However, you may use a better regex version based on a character class:



          strsplit("Glenelg (Vic.)",'[.:](?!\))', perl = TRUE)
          
[[1]]
          
[1] "Glenelg (Vic.)"


          Here, [.:](?!)) matches either . or : that are both not immediately followed with ).



          See the regex demo.






          share|improve this answer































            0














            You can also use stringr: 



            stringr::str_split("Glenelg (Vic.)","[\.:](?!\))")
            
[[1]]
            
[1] "Glenelg (Vic.)"





            share|improve this answer























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              2 Answers
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              active

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              active

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              active

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              1














              It is not grouped correctly. .|:(?!)) matches a . anywhere in a string or a : not followed with ). If you group . and : patterns, '(?:\.|:)(?!\))', it will work.



              However, you may use a better regex version based on a character class:



              strsplit("Glenelg (Vic.)",'[.:](?!\))', perl = TRUE)
              
[[1]]
              
[1] "Glenelg (Vic.)"


              Here, [.:](?!)) matches either . or : that are both not immediately followed with ).



              See the regex demo.






              share|improve this answer




























                1














                It is not grouped correctly. .|:(?!)) matches a . anywhere in a string or a : not followed with ). If you group . and : patterns, '(?:\.|:)(?!\))', it will work.



                However, you may use a better regex version based on a character class:



                strsplit("Glenelg (Vic.)",'[.:](?!\))', perl = TRUE)
                
[[1]]
                
[1] "Glenelg (Vic.)"


                Here, [.:](?!)) matches either . or : that are both not immediately followed with ).



                See the regex demo.






                share|improve this answer


























                  1












                  1








                  1







                  It is not grouped correctly. .|:(?!)) matches a . anywhere in a string or a : not followed with ). If you group . and : patterns, '(?:\.|:)(?!\))', it will work.



                  However, you may use a better regex version based on a character class:



                  strsplit("Glenelg (Vic.)",'[.:](?!\))', perl = TRUE)
                  
[[1]]
                  
[1] "Glenelg (Vic.)"


                  Here, [.:](?!)) matches either . or : that are both not immediately followed with ).



                  See the regex demo.






                  share|improve this answer













                  It is not grouped correctly. .|:(?!)) matches a . anywhere in a string or a : not followed with ). If you group . and : patterns, '(?:\.|:)(?!\))', it will work.



                  However, you may use a better regex version based on a character class:



                  strsplit("Glenelg (Vic.)",'[.:](?!\))', perl = TRUE)
                  
[[1]]
                  
[1] "Glenelg (Vic.)"


                  Here, [.:](?!)) matches either . or : that are both not immediately followed with ).



                  See the regex demo.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 19 '18 at 23:17









                  Wiktor StribiżewWiktor Stribiżew

                  317k16138220




                  317k16138220

























                      0














                      You can also use stringr: 



                      stringr::str_split("Glenelg (Vic.)","[\.:](?!\))")
                      
[[1]]
                      
[1] "Glenelg (Vic.)"





                      share|improve this answer




























                        0














                        You can also use stringr: 



                        stringr::str_split("Glenelg (Vic.)","[\.:](?!\))")
                        
[[1]]
                        
[1] "Glenelg (Vic.)"





                        share|improve this answer


























                          0












                          0








                          0







                          You can also use stringr: 



                          stringr::str_split("Glenelg (Vic.)","[\.:](?!\))")
                          
[[1]]
                          
[1] "Glenelg (Vic.)"





                          share|improve this answer













                          You can also use stringr: 



                          stringr::str_split("Glenelg (Vic.)","[\.:](?!\))")
                          
[[1]]
                          
[1] "Glenelg (Vic.)"






                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Nov 20 '18 at 0:00









                          JoséJosé

                          516815




                          516815






























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