Convert atan2 value to standard 360-degree-system value












6















Lets say I'm using atan2 to get the angle between two vectors.



atan2 gives a value in radians. I convert it to degrees using a built in function in Java. This gives me a value between 0 and 180 degrees or between 0 and -180 (the nature of atan2).



Is there a way to convert the value received with this function (after it's been converted to degrees), to the standard 360-degree-system, without changing the angle - only the way it's written? It would make it easier for me to work with.



Thanks






math vector geometry trigonometry atan2







share|improve this question

























  • Can you provide an example of what you mean because your question doesn't make sense to me as written?

    – jmcilhinney
    Feb 1 '14 at 2:02











  • @jmcilhinney Please see my edit.

    – user3150201
    Feb 1 '14 at 2:09











  • The angle between two vectors is always between 0 and 180. The only way for it to be between -180 and 180 is if you've measured the second vector in relation to the first (because swapping the vectors will negate the angle you have). So, what do you mean by "the standard 360-degree-system"? Could you give some sample vectors?

    – Teepeemm
    Feb 1 '14 at 3:36











  • Are you saying that you want the angles less that zero to be represented in the range between 180 and 360? If so then just use a bit of simple arithmetic.

    – jmcilhinney
    Feb 1 '14 at 3:52











  • @jmcilhinney Yes, but without changing the actual angle, only how it's written. -90 degrees, the output of atan2, is actually 270 in the normal 360-system. Is the way to do that simply add 360 to any angle below zero?

    – user3150201
    Feb 1 '14 at 11:29
















6















Lets say I'm using atan2 to get the angle between two vectors.



atan2 gives a value in radians. I convert it to degrees using a built in function in Java. This gives me a value between 0 and 180 degrees or between 0 and -180 (the nature of atan2).



Is there a way to convert the value received with this function (after it's been converted to degrees), to the standard 360-degree-system, without changing the angle - only the way it's written? It would make it easier for me to work with.



Thanks






math vector geometry trigonometry atan2







share|improve this question

























  • Can you provide an example of what you mean because your question doesn't make sense to me as written?

    – jmcilhinney
    Feb 1 '14 at 2:02











  • @jmcilhinney Please see my edit.

    – user3150201
    Feb 1 '14 at 2:09











  • The angle between two vectors is always between 0 and 180. The only way for it to be between -180 and 180 is if you've measured the second vector in relation to the first (because swapping the vectors will negate the angle you have). So, what do you mean by "the standard 360-degree-system"? Could you give some sample vectors?

    – Teepeemm
    Feb 1 '14 at 3:36











  • Are you saying that you want the angles less that zero to be represented in the range between 180 and 360? If so then just use a bit of simple arithmetic.

    – jmcilhinney
    Feb 1 '14 at 3:52











  • @jmcilhinney Yes, but without changing the actual angle, only how it's written. -90 degrees, the output of atan2, is actually 270 in the normal 360-system. Is the way to do that simply add 360 to any angle below zero?

    – user3150201
    Feb 1 '14 at 11:29














6












6








6


2






Lets say I'm using atan2 to get the angle between two vectors.



atan2 gives a value in radians. I convert it to degrees using a built in function in Java. This gives me a value between 0 and 180 degrees or between 0 and -180 (the nature of atan2).



Is there a way to convert the value received with this function (after it's been converted to degrees), to the standard 360-degree-system, without changing the angle - only the way it's written? It would make it easier for me to work with.



Thanks






math vector geometry trigonometry atan2







share|improve this question
















Lets say I'm using atan2 to get the angle between two vectors.



atan2 gives a value in radians. I convert it to degrees using a built in function in Java. This gives me a value between 0 and 180 degrees or between 0 and -180 (the nature of atan2).



Is there a way to convert the value received with this function (after it's been converted to degrees), to the standard 360-degree-system, without changing the angle - only the way it's written? It would make it easier for me to work with.



Thanks






math vector geometry trigonometry atan2




math vector geometry trigonometry atan2






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Apr 2 '15 at 15:09









patientia

52




52










asked Feb 1 '14 at 1:59









user3150201user3150201

67331525




67331525













  • Can you provide an example of what you mean because your question doesn't make sense to me as written?

    – jmcilhinney
    Feb 1 '14 at 2:02











  • @jmcilhinney Please see my edit.

    – user3150201
    Feb 1 '14 at 2:09











  • The angle between two vectors is always between 0 and 180. The only way for it to be between -180 and 180 is if you've measured the second vector in relation to the first (because swapping the vectors will negate the angle you have). So, what do you mean by "the standard 360-degree-system"? Could you give some sample vectors?

    – Teepeemm
    Feb 1 '14 at 3:36











  • Are you saying that you want the angles less that zero to be represented in the range between 180 and 360? If so then just use a bit of simple arithmetic.

    – jmcilhinney
    Feb 1 '14 at 3:52











  • @jmcilhinney Yes, but without changing the actual angle, only how it's written. -90 degrees, the output of atan2, is actually 270 in the normal 360-system. Is the way to do that simply add 360 to any angle below zero?

    – user3150201
    Feb 1 '14 at 11:29



















  • Can you provide an example of what you mean because your question doesn't make sense to me as written?

    – jmcilhinney
    Feb 1 '14 at 2:02











  • @jmcilhinney Please see my edit.

    – user3150201
    Feb 1 '14 at 2:09











  • The angle between two vectors is always between 0 and 180. The only way for it to be between -180 and 180 is if you've measured the second vector in relation to the first (because swapping the vectors will negate the angle you have). So, what do you mean by "the standard 360-degree-system"? Could you give some sample vectors?

    – Teepeemm
    Feb 1 '14 at 3:36











  • Are you saying that you want the angles less that zero to be represented in the range between 180 and 360? If so then just use a bit of simple arithmetic.

    – jmcilhinney
    Feb 1 '14 at 3:52











  • @jmcilhinney Yes, but without changing the actual angle, only how it's written. -90 degrees, the output of atan2, is actually 270 in the normal 360-system. Is the way to do that simply add 360 to any angle below zero?

    – user3150201
    Feb 1 '14 at 11:29

















Can you provide an example of what you mean because your question doesn't make sense to me as written?

– jmcilhinney
Feb 1 '14 at 2:02





Can you provide an example of what you mean because your question doesn't make sense to me as written?

– jmcilhinney
Feb 1 '14 at 2:02













@jmcilhinney Please see my edit.

– user3150201
Feb 1 '14 at 2:09





@jmcilhinney Please see my edit.

– user3150201
Feb 1 '14 at 2:09













The angle between two vectors is always between 0 and 180. The only way for it to be between -180 and 180 is if you've measured the second vector in relation to the first (because swapping the vectors will negate the angle you have). So, what do you mean by "the standard 360-degree-system"? Could you give some sample vectors?

– Teepeemm
Feb 1 '14 at 3:36





The angle between two vectors is always between 0 and 180. The only way for it to be between -180 and 180 is if you've measured the second vector in relation to the first (because swapping the vectors will negate the angle you have). So, what do you mean by "the standard 360-degree-system"? Could you give some sample vectors?

– Teepeemm
Feb 1 '14 at 3:36













Are you saying that you want the angles less that zero to be represented in the range between 180 and 360? If so then just use a bit of simple arithmetic.

– jmcilhinney
Feb 1 '14 at 3:52





Are you saying that you want the angles less that zero to be represented in the range between 180 and 360? If so then just use a bit of simple arithmetic.

– jmcilhinney
Feb 1 '14 at 3:52













@jmcilhinney Yes, but without changing the actual angle, only how it's written. -90 degrees, the output of atan2, is actually 270 in the normal 360-system. Is the way to do that simply add 360 to any angle below zero?

– user3150201
Feb 1 '14 at 11:29





@jmcilhinney Yes, but without changing the actual angle, only how it's written. -90 degrees, the output of atan2, is actually 270 in the normal 360-system. Is the way to do that simply add 360 to any angle below zero?

– user3150201
Feb 1 '14 at 11:29












4 Answers
4






active

oldest

votes


















7














Try this:



double theta = Math.toDegrees(atan2(y, x));



if (theta < 0.0) {

    theta += 360.0;

}





share|improve this answer
























  • Incredibly simple solution. Thank you.

    – J.M. Janzen
    Oct 1 '16 at 19:00



















2














To convert it to a North referenced 0 - 360 degree value:



double degrees = 90.0d - Math.toDegrees( Math.atan2( y, x ) );



if( degrees < 0.0d )

{

   degrees += 360.0;

}





share|improve this answer































    0














    According to what I learned in my trig class, the above answers are incorrect. For example, if you have a vector intersecting point (-1,-1) at an angle of 225 degrees (standard position), the tangent will be positive 1, which yields an arc tangent of 45 degrees. This will not be noticed by the above solutions, and the angle of the vector will be wrong. That is why arc tangent's formula is different depending on the situation. You have to have an idea of what the angle is going to be first.




    Recall that we can apply trig functions to any angle, including large and negative angles. But when we consider the inverse function we run into a problem, because there are an infinite number of angles that have the same tangent. For example 45° and 360+45° would have the same tangent. For more on this see Inverse trigonometric functions.



    To solve this problem, the range of inverse trig functions are limited in such a way that the inverse functions are one-to-one, that is, there is only one result for each input value.




    From http://www.mathopenref.com/arctan.html






    share|improve this answer


























    • Still working on the CORRECT solution for myself.

      – zephos2014
      Sep 19 '14 at 7:47











    • You should look into how atan2(y, x) works in the various programming languages in which it is implemented. It takes into account the quadrant of the point (x, y) and returns values in the range (-pi, pi] not [-pi/2, pi/2]. When doing so, please note the coordinate order. In many cases (C and C++ for example) the y coordinate is the first argument since the common pattern for it is to use it in place of atan(y/x). Other programming languages may use a different convention.

      – andand
      Jun 11 '15 at 19:45



















    0














    A formula that gives an angle from 0 to 360 degrees.



    f(x,y)=180-90*(1+sign(x))* (1-sign(y^2))-45*(2+sign(x))*sign(y)
    




    -(180/pi())*sign(x*y)*atan((abs(x)-abs(y))/(abs(x)+abs(y)))





    share|improve this answer

























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      4 Answers
      4






      active

      oldest

      votes








      4 Answers
      4






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      7














      Try this:



      double theta = Math.toDegrees(atan2(y, x));
      

      
if (theta < 0.0) {
      
    theta += 360.0;
      
}





      share|improve this answer
























      • Incredibly simple solution. Thank you.

        – J.M. Janzen
        Oct 1 '16 at 19:00
















      7














      Try this:



      double theta = Math.toDegrees(atan2(y, x));
      

      
if (theta < 0.0) {
      
    theta += 360.0;
      
}





      share|improve this answer
























      • Incredibly simple solution. Thank you.

        – J.M. Janzen
        Oct 1 '16 at 19:00














      7












      7








      7







      Try this:



      double theta = Math.toDegrees(atan2(y, x));
      

      
if (theta < 0.0) {
      
    theta += 360.0;
      
}





      share|improve this answer













      Try this:



      double theta = Math.toDegrees(atan2(y, x));
      

      
if (theta < 0.0) {
      
    theta += 360.0;
      
}






      share|improve this answer












      share|improve this answer



      share|improve this answer










      answered Feb 1 '14 at 4:21









      andandandand

      11.4k94070




      11.4k94070













      • Incredibly simple solution. Thank you.

        – J.M. Janzen
        Oct 1 '16 at 19:00



















      • Incredibly simple solution. Thank you.

        – J.M. Janzen
        Oct 1 '16 at 19:00

















      Incredibly simple solution. Thank you.

      – J.M. Janzen
      Oct 1 '16 at 19:00





      Incredibly simple solution. Thank you.

      – J.M. Janzen
      Oct 1 '16 at 19:00













      2














      To convert it to a North referenced 0 - 360 degree value:



      double degrees = 90.0d - Math.toDegrees( Math.atan2( y, x ) );
      

      
if( degrees < 0.0d )
      
{
      
   degrees += 360.0;
      
}





      share|improve this answer




























        2














        To convert it to a North referenced 0 - 360 degree value:



        double degrees = 90.0d - Math.toDegrees( Math.atan2( y, x ) );
        

        
if( degrees < 0.0d )
        
{
        
   degrees += 360.0;
        
}





        share|improve this answer


























          2












          2








          2







          To convert it to a North referenced 0 - 360 degree value:



          double degrees = 90.0d - Math.toDegrees( Math.atan2( y, x ) );
          

          
if( degrees < 0.0d )
          
{
          
   degrees += 360.0;
          
}





          share|improve this answer













          To convert it to a North referenced 0 - 360 degree value:



          double degrees = 90.0d - Math.toDegrees( Math.atan2( y, x ) );
          

          
if( degrees < 0.0d )
          
{
          
   degrees += 360.0;
          
}






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Jul 11 '14 at 16:44









          DennyDenny

          211




          211























              0














              According to what I learned in my trig class, the above answers are incorrect. For example, if you have a vector intersecting point (-1,-1) at an angle of 225 degrees (standard position), the tangent will be positive 1, which yields an arc tangent of 45 degrees. This will not be noticed by the above solutions, and the angle of the vector will be wrong. That is why arc tangent's formula is different depending on the situation. You have to have an idea of what the angle is going to be first.




              Recall that we can apply trig functions to any angle, including large and negative angles. But when we consider the inverse function we run into a problem, because there are an infinite number of angles that have the same tangent. For example 45° and 360+45° would have the same tangent. For more on this see Inverse trigonometric functions.



              To solve this problem, the range of inverse trig functions are limited in such a way that the inverse functions are one-to-one, that is, there is only one result for each input value.




              From http://www.mathopenref.com/arctan.html






              share|improve this answer


























              • Still working on the CORRECT solution for myself.

                – zephos2014
                Sep 19 '14 at 7:47











              • You should look into how atan2(y, x) works in the various programming languages in which it is implemented. It takes into account the quadrant of the point (x, y) and returns values in the range (-pi, pi] not [-pi/2, pi/2]. When doing so, please note the coordinate order. In many cases (C and C++ for example) the y coordinate is the first argument since the common pattern for it is to use it in place of atan(y/x). Other programming languages may use a different convention.

                – andand
                Jun 11 '15 at 19:45
















              0














              According to what I learned in my trig class, the above answers are incorrect. For example, if you have a vector intersecting point (-1,-1) at an angle of 225 degrees (standard position), the tangent will be positive 1, which yields an arc tangent of 45 degrees. This will not be noticed by the above solutions, and the angle of the vector will be wrong. That is why arc tangent's formula is different depending on the situation. You have to have an idea of what the angle is going to be first.




              Recall that we can apply trig functions to any angle, including large and negative angles. But when we consider the inverse function we run into a problem, because there are an infinite number of angles that have the same tangent. For example 45° and 360+45° would have the same tangent. For more on this see Inverse trigonometric functions.



              To solve this problem, the range of inverse trig functions are limited in such a way that the inverse functions are one-to-one, that is, there is only one result for each input value.




              From http://www.mathopenref.com/arctan.html






              share|improve this answer


























              • Still working on the CORRECT solution for myself.

                – zephos2014
                Sep 19 '14 at 7:47











              • You should look into how atan2(y, x) works in the various programming languages in which it is implemented. It takes into account the quadrant of the point (x, y) and returns values in the range (-pi, pi] not [-pi/2, pi/2]. When doing so, please note the coordinate order. In many cases (C and C++ for example) the y coordinate is the first argument since the common pattern for it is to use it in place of atan(y/x). Other programming languages may use a different convention.

                – andand
                Jun 11 '15 at 19:45














              0












              0








              0







              According to what I learned in my trig class, the above answers are incorrect. For example, if you have a vector intersecting point (-1,-1) at an angle of 225 degrees (standard position), the tangent will be positive 1, which yields an arc tangent of 45 degrees. This will not be noticed by the above solutions, and the angle of the vector will be wrong. That is why arc tangent's formula is different depending on the situation. You have to have an idea of what the angle is going to be first.




              Recall that we can apply trig functions to any angle, including large and negative angles. But when we consider the inverse function we run into a problem, because there are an infinite number of angles that have the same tangent. For example 45° and 360+45° would have the same tangent. For more on this see Inverse trigonometric functions.



              To solve this problem, the range of inverse trig functions are limited in such a way that the inverse functions are one-to-one, that is, there is only one result for each input value.




              From http://www.mathopenref.com/arctan.html






              share|improve this answer















              According to what I learned in my trig class, the above answers are incorrect. For example, if you have a vector intersecting point (-1,-1) at an angle of 225 degrees (standard position), the tangent will be positive 1, which yields an arc tangent of 45 degrees. This will not be noticed by the above solutions, and the angle of the vector will be wrong. That is why arc tangent's formula is different depending on the situation. You have to have an idea of what the angle is going to be first.




              Recall that we can apply trig functions to any angle, including large and negative angles. But when we consider the inverse function we run into a problem, because there are an infinite number of angles that have the same tangent. For example 45° and 360+45° would have the same tangent. For more on this see Inverse trigonometric functions.



              To solve this problem, the range of inverse trig functions are limited in such a way that the inverse functions are one-to-one, that is, there is only one result for each input value.




              From http://www.mathopenref.com/arctan.html







              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited Sep 19 '14 at 7:55

























              answered Sep 19 '14 at 7:46









              zephos2014zephos2014

              13418




              13418













              • Still working on the CORRECT solution for myself.

                – zephos2014
                Sep 19 '14 at 7:47











              • You should look into how atan2(y, x) works in the various programming languages in which it is implemented. It takes into account the quadrant of the point (x, y) and returns values in the range (-pi, pi] not [-pi/2, pi/2]. When doing so, please note the coordinate order. In many cases (C and C++ for example) the y coordinate is the first argument since the common pattern for it is to use it in place of atan(y/x). Other programming languages may use a different convention.

                – andand
                Jun 11 '15 at 19:45



















              • Still working on the CORRECT solution for myself.

                – zephos2014
                Sep 19 '14 at 7:47











              • You should look into how atan2(y, x) works in the various programming languages in which it is implemented. It takes into account the quadrant of the point (x, y) and returns values in the range (-pi, pi] not [-pi/2, pi/2]. When doing so, please note the coordinate order. In many cases (C and C++ for example) the y coordinate is the first argument since the common pattern for it is to use it in place of atan(y/x). Other programming languages may use a different convention.

                – andand
                Jun 11 '15 at 19:45

















              Still working on the CORRECT solution for myself.

              – zephos2014
              Sep 19 '14 at 7:47





              Still working on the CORRECT solution for myself.

              – zephos2014
              Sep 19 '14 at 7:47













              You should look into how atan2(y, x) works in the various programming languages in which it is implemented. It takes into account the quadrant of the point (x, y) and returns values in the range (-pi, pi] not [-pi/2, pi/2]. When doing so, please note the coordinate order. In many cases (C and C++ for example) the y coordinate is the first argument since the common pattern for it is to use it in place of atan(y/x). Other programming languages may use a different convention.

              – andand
              Jun 11 '15 at 19:45





              You should look into how atan2(y, x) works in the various programming languages in which it is implemented. It takes into account the quadrant of the point (x, y) and returns values in the range (-pi, pi] not [-pi/2, pi/2]. When doing so, please note the coordinate order. In many cases (C and C++ for example) the y coordinate is the first argument since the common pattern for it is to use it in place of atan(y/x). Other programming languages may use a different convention.

              – andand
              Jun 11 '15 at 19:45











              0














              A formula that gives an angle from 0 to 360 degrees.



              f(x,y)=180-90*(1+sign(x))* (1-sign(y^2))-45*(2+sign(x))*sign(y)
              




              -(180/pi())*sign(x*y)*atan((abs(x)-abs(y))/(abs(x)+abs(y)))





              share|improve this answer






























                0














                A formula that gives an angle from 0 to 360 degrees.



                f(x,y)=180-90*(1+sign(x))* (1-sign(y^2))-45*(2+sign(x))*sign(y)
                




                -(180/pi())*sign(x*y)*atan((abs(x)-abs(y))/(abs(x)+abs(y)))





                share|improve this answer




























                  0












                  0








                  0







                  A formula that gives an angle from 0 to 360 degrees.



                  f(x,y)=180-90*(1+sign(x))* (1-sign(y^2))-45*(2+sign(x))*sign(y)
                  




                  -(180/pi())*sign(x*y)*atan((abs(x)-abs(y))/(abs(x)+abs(y)))





                  share|improve this answer















                  A formula that gives an angle from 0 to 360 degrees.



                  f(x,y)=180-90*(1+sign(x))* (1-sign(y^2))-45*(2+sign(x))*sign(y)
                  




                  -(180/pi())*sign(x*y)*atan((abs(x)-abs(y))/(abs(x)+abs(y)))






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Nov 22 '18 at 8:44









                  Unheilig

                  12.1k165387




                  12.1k165387










                  answered Nov 22 '18 at 8:25









                  theodore panagostheodore panagos

                  1




                  1






























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                      Academy of Television Arts & Sciences

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                      American television organization Academy of Television Arts & Sciences Founded 1946 ; 73 years ago  ( 1946 ) Location North Hollywood, California, United States Area served Television industry Product Emmy Awards Key people Frank Scherma ( Chairman and CEO ) Website televisionacademy.com [redirects to emmys.com , official website of the Emmys and the Television Academy The Academy of Television Arts & Sciences ( ATAS ), also colloquially known as the Television Academy , is a professional honorary organization dedicated to the advancement of the television industry in the United States. Founded in 1946, the organization presents the Primetime Emmy Awards, an annual ceremony honoring achievement in U.S. primetime television. Contents 1 History 2 Emmy Award 3 Publications and programs 4 Current governance 4.1 Board of Governors 5 Television Academy honors 5.1 1st Annual (2008) 5.2 2nd Annual (2009)...
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                      L'Équipe

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                      For other uses, see Équipe (disambiguation). L'Équipe The front page of L'Équipe on 4 July 2011 Type Daily newspaper Format Tabloid Owner(s) Éditions Philippe Amaury Editor François Morinière Editor-in-chief Fabrice Jouhaud Founded 1946 Language French Headquarters Boulogne-Billancourt ISSN 0153-1069 Website www.lequipe.fr L'Équipe ( pronounced  [lekip] , French for "the team") is a French nationwide daily newspaper devoted to sport, owned by Éditions Philippe Amaury. The paper is noted for coverage of association football , rugby, motorsport and cycling. Its predecessor was L'Auto , a general sports paper whose name reflected not any narrow interest but the excitement of the time in car racing. L'Auto originated the Tour de France cycling stage race in 1903 as a circulation booster. The race leader's yellow jersey (French: maillot jaune ) was instituted in 1919, probably to reflect the dist...
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                      1995 France bombings

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                      This article is a rough translation from French . It may have been generated by a computer or by a translator without dual proficiency. Please help to enhance the translation. The original article is under "français" in the "languages" sidebar. See this article's entry on Pages needing translation into English for discussion. 1995 France bombings Part of Algerian Civil War (spillover) Plaque commemorating the victims of the Saint-Michel station bombing on 25 July 1995 Location Paris and Lyon, France Date 25 July 1995  ( 1995-07-25 ) – 17 October 1995  ( 1995-10-17 ) Weapons Improvised explosive devices, school bombing Deaths 8 Non-fatal injuries 157 Perpetrator Armed Islamic Group Motive To induce the French government to withdraw support from the Algerian government during the Algerian Civil War The 1995 bombings in France were carried out by the Armed Islamic Group (GIA), who were broadening the Alger...
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