Count number of true and false condition in spark data frame





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I am coming from a MATLAB background, and I can simply do this



age_sum_error = sum(age > prediction - 4 & age < prediction + 4);


This will count the number of age values for which the prediction (+4/-4) is true, I want to do something similar in spark data frame.



Say that below is my spark data frame



+--------------------------+
|age | gender | prediction |
+----+--------+------------+
|35 | M | 30 |
|40 | F | 42 |
|45 | F | 38 |
|26 | F | 29 |
+----+--------+------------+


I want my result to look something like this



+------+----------+
|false | positive |
+------+----------+
|2 | 2 |
+------+----------+









share|improve this question





























    0















    I am coming from a MATLAB background, and I can simply do this



    age_sum_error = sum(age > prediction - 4 & age < prediction + 4);


    This will count the number of age values for which the prediction (+4/-4) is true, I want to do something similar in spark data frame.



    Say that below is my spark data frame



    +--------------------------+
    |age | gender | prediction |
    +----+--------+------------+
    |35 | M | 30 |
    |40 | F | 42 |
    |45 | F | 38 |
    |26 | F | 29 |
    +----+--------+------------+


    I want my result to look something like this



    +------+----------+
    |false | positive |
    +------+----------+
    |2 | 2 |
    +------+----------+









    share|improve this question

























      0












      0








      0








      I am coming from a MATLAB background, and I can simply do this



      age_sum_error = sum(age > prediction - 4 & age < prediction + 4);


      This will count the number of age values for which the prediction (+4/-4) is true, I want to do something similar in spark data frame.



      Say that below is my spark data frame



      +--------------------------+
      |age | gender | prediction |
      +----+--------+------------+
      |35 | M | 30 |
      |40 | F | 42 |
      |45 | F | 38 |
      |26 | F | 29 |
      +----+--------+------------+


      I want my result to look something like this



      +------+----------+
      |false | positive |
      +------+----------+
      |2 | 2 |
      +------+----------+









      share|improve this question














      I am coming from a MATLAB background, and I can simply do this



      age_sum_error = sum(age > prediction - 4 & age < prediction + 4);


      This will count the number of age values for which the prediction (+4/-4) is true, I want to do something similar in spark data frame.



      Say that below is my spark data frame



      +--------------------------+
      |age | gender | prediction |
      +----+--------+------------+
      |35 | M | 30 |
      |40 | F | 42 |
      |45 | F | 38 |
      |26 | F | 29 |
      +----+--------+------------+


      I want my result to look something like this



      +------+----------+
      |false | positive |
      +------+----------+
      |2 | 2 |
      +------+----------+






      python apache-spark pyspark apache-spark-sql






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 24 '18 at 21:13









      Jam1Jam1

      306315




      306315
























          2 Answers
          2






          active

          oldest

          votes


















          1














          First calculate the condition, and then aggregate the result by summing up the 1s and 0s:



          df.selectExpr(
          'cast(abs(age - prediction) < 4 as int) as condition'
          ).selectExpr(
          'sum(condition) as positive',
          'sum(1-condition) as negative'
          ).show()
          +--------+--------+
          |positive|negative|
          +--------+--------+
          | 2| 2|
          +--------+--------+





          share|improve this answer































            0














            Its a lot more code than matlab, but here's how I would do it.



            import numpy as np

            ages = [35, 40, 45, 26]
            pred = [30, 42, 38, 29]
            tolerance = 4

            # get boolean array of people older and younger than limits
            is_older = np.greater(ages, pred-tolerance) # a boolean array
            is_younger = np.less(ages, pred+tolerance) # a boolean array

            # convert these boolean arrays to ints then multiply. True = 1, False = 0.
            in_range = is_older.astype(int)*is_younger.astype(int) # 0's cancel 1's

            # add upp the indixes that are still 1
            senior_count = np.sum(in_range)


            Hope this helps.






            share|improve this answer
























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              2 Answers
              2






              active

              oldest

              votes








              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              1














              First calculate the condition, and then aggregate the result by summing up the 1s and 0s:



              df.selectExpr(
              'cast(abs(age - prediction) < 4 as int) as condition'
              ).selectExpr(
              'sum(condition) as positive',
              'sum(1-condition) as negative'
              ).show()
              +--------+--------+
              |positive|negative|
              +--------+--------+
              | 2| 2|
              +--------+--------+





              share|improve this answer




























                1














                First calculate the condition, and then aggregate the result by summing up the 1s and 0s:



                df.selectExpr(
                'cast(abs(age - prediction) < 4 as int) as condition'
                ).selectExpr(
                'sum(condition) as positive',
                'sum(1-condition) as negative'
                ).show()
                +--------+--------+
                |positive|negative|
                +--------+--------+
                | 2| 2|
                +--------+--------+





                share|improve this answer


























                  1












                  1








                  1







                  First calculate the condition, and then aggregate the result by summing up the 1s and 0s:



                  df.selectExpr(
                  'cast(abs(age - prediction) < 4 as int) as condition'
                  ).selectExpr(
                  'sum(condition) as positive',
                  'sum(1-condition) as negative'
                  ).show()
                  +--------+--------+
                  |positive|negative|
                  +--------+--------+
                  | 2| 2|
                  +--------+--------+





                  share|improve this answer













                  First calculate the condition, and then aggregate the result by summing up the 1s and 0s:



                  df.selectExpr(
                  'cast(abs(age - prediction) < 4 as int) as condition'
                  ).selectExpr(
                  'sum(condition) as positive',
                  'sum(1-condition) as negative'
                  ).show()
                  +--------+--------+
                  |positive|negative|
                  +--------+--------+
                  | 2| 2|
                  +--------+--------+






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 24 '18 at 21:57









                  PsidomPsidom

                  129k1295142




                  129k1295142

























                      0














                      Its a lot more code than matlab, but here's how I would do it.



                      import numpy as np

                      ages = [35, 40, 45, 26]
                      pred = [30, 42, 38, 29]
                      tolerance = 4

                      # get boolean array of people older and younger than limits
                      is_older = np.greater(ages, pred-tolerance) # a boolean array
                      is_younger = np.less(ages, pred+tolerance) # a boolean array

                      # convert these boolean arrays to ints then multiply. True = 1, False = 0.
                      in_range = is_older.astype(int)*is_younger.astype(int) # 0's cancel 1's

                      # add upp the indixes that are still 1
                      senior_count = np.sum(in_range)


                      Hope this helps.






                      share|improve this answer




























                        0














                        Its a lot more code than matlab, but here's how I would do it.



                        import numpy as np

                        ages = [35, 40, 45, 26]
                        pred = [30, 42, 38, 29]
                        tolerance = 4

                        # get boolean array of people older and younger than limits
                        is_older = np.greater(ages, pred-tolerance) # a boolean array
                        is_younger = np.less(ages, pred+tolerance) # a boolean array

                        # convert these boolean arrays to ints then multiply. True = 1, False = 0.
                        in_range = is_older.astype(int)*is_younger.astype(int) # 0's cancel 1's

                        # add upp the indixes that are still 1
                        senior_count = np.sum(in_range)


                        Hope this helps.






                        share|improve this answer


























                          0












                          0








                          0







                          Its a lot more code than matlab, but here's how I would do it.



                          import numpy as np

                          ages = [35, 40, 45, 26]
                          pred = [30, 42, 38, 29]
                          tolerance = 4

                          # get boolean array of people older and younger than limits
                          is_older = np.greater(ages, pred-tolerance) # a boolean array
                          is_younger = np.less(ages, pred+tolerance) # a boolean array

                          # convert these boolean arrays to ints then multiply. True = 1, False = 0.
                          in_range = is_older.astype(int)*is_younger.astype(int) # 0's cancel 1's

                          # add upp the indixes that are still 1
                          senior_count = np.sum(in_range)


                          Hope this helps.






                          share|improve this answer













                          Its a lot more code than matlab, but here's how I would do it.



                          import numpy as np

                          ages = [35, 40, 45, 26]
                          pred = [30, 42, 38, 29]
                          tolerance = 4

                          # get boolean array of people older and younger than limits
                          is_older = np.greater(ages, pred-tolerance) # a boolean array
                          is_younger = np.less(ages, pred+tolerance) # a boolean array

                          # convert these boolean arrays to ints then multiply. True = 1, False = 0.
                          in_range = is_older.astype(int)*is_younger.astype(int) # 0's cancel 1's

                          # add upp the indixes that are still 1
                          senior_count = np.sum(in_range)


                          Hope this helps.







                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Nov 24 '18 at 21:54









                          Charles StraussCharles Strauss

                          912




                          912






























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