Iterating over the last dimensions of a numpy array





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Consider the following snippet:



a = np.ones((2,2,2,2,2))

for example in a:

    for row in example:

        for col in row:

            for box in col:

                print (box.shape)


Having so many nested fors makes for some very ugly code.



How can I get the same effect with only one explicit iteration?






python arrays python-3.x numpy iteration







share|improve this question





























    0















    Consider the following snippet:



    a = np.ones((2,2,2,2,2))
    
for example in a:
    
    for row in example:
    
        for col in row:
    
            for box in col:
    
                print (box.shape)


    Having so many nested fors makes for some very ugly code.



    How can I get the same effect with only one explicit iteration?






    python arrays python-3.x numpy iteration







    share|improve this question

























      0












      0








      0








      Consider the following snippet:



      a = np.ones((2,2,2,2,2))
      
for example in a:
      
    for row in example:
      
        for col in row:
      
            for box in col:
      
                print (box.shape)


      Having so many nested fors makes for some very ugly code.



      How can I get the same effect with only one explicit iteration?






      python arrays python-3.x numpy iteration







      share|improve this question














      Consider the following snippet:



      a = np.ones((2,2,2,2,2))
      
for example in a:
      
    for row in example:
      
        for col in row:
      
            for box in col:
      
                print (box.shape)


      Having so many nested fors makes for some very ugly code.



      How can I get the same effect with only one explicit iteration?






      python arrays python-3.x numpy iteration




      python arrays python-3.x numpy iteration






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 24 '18 at 21:16









      JsevillamolJsevillamol

      719819




      719819
























          1 Answer
          1






          active

          oldest

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          1














          Reshape your array:



          for box in a.reshape(16,2):
          
    print(box.shape)



          A general solution:



          for box in a.reshape(np.prod(a.shape[:-1]), a.shape[-1]):
          
     print(box.shape)


          which will always iterate over one-before-the-last dimension of a.






          share|improve this answer


























          • Any way of doing this without referencing the shape of a, only the axis we want to iterate over?

            – Jsevillamol
            Nov 24 '18 at 21:34






          • 1





            @Jsevillamol See my update for a general solution :)

            – Joe Iddon
            Nov 24 '18 at 21:38












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          active

          oldest

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          1 Answer
          1






          active

          oldest

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          active

          oldest

          votes






          active

          oldest

          votes









          1














          Reshape your array:



          for box in a.reshape(16,2):
          
    print(box.shape)



          A general solution:



          for box in a.reshape(np.prod(a.shape[:-1]), a.shape[-1]):
          
     print(box.shape)


          which will always iterate over one-before-the-last dimension of a.






          share|improve this answer


























          • Any way of doing this without referencing the shape of a, only the axis we want to iterate over?

            – Jsevillamol
            Nov 24 '18 at 21:34






          • 1





            @Jsevillamol See my update for a general solution :)

            – Joe Iddon
            Nov 24 '18 at 21:38
















          1














          Reshape your array:



          for box in a.reshape(16,2):
          
    print(box.shape)



          A general solution:



          for box in a.reshape(np.prod(a.shape[:-1]), a.shape[-1]):
          
     print(box.shape)


          which will always iterate over one-before-the-last dimension of a.






          share|improve this answer


























          • Any way of doing this without referencing the shape of a, only the axis we want to iterate over?

            – Jsevillamol
            Nov 24 '18 at 21:34






          • 1





            @Jsevillamol See my update for a general solution :)

            – Joe Iddon
            Nov 24 '18 at 21:38














          1












          1








          1







          Reshape your array:



          for box in a.reshape(16,2):
          
    print(box.shape)



          A general solution:



          for box in a.reshape(np.prod(a.shape[:-1]), a.shape[-1]):
          
     print(box.shape)


          which will always iterate over one-before-the-last dimension of a.






          share|improve this answer















          Reshape your array:



          for box in a.reshape(16,2):
          
    print(box.shape)



          A general solution:



          for box in a.reshape(np.prod(a.shape[:-1]), a.shape[-1]):
          
     print(box.shape)


          which will always iterate over one-before-the-last dimension of a.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 24 '18 at 21:38

























          answered Nov 24 '18 at 21:20









          Joe IddonJoe Iddon

          15.6k31741




          15.6k31741













          • Any way of doing this without referencing the shape of a, only the axis we want to iterate over?

            – Jsevillamol
            Nov 24 '18 at 21:34






          • 1





            @Jsevillamol See my update for a general solution :)

            – Joe Iddon
            Nov 24 '18 at 21:38



















          • Any way of doing this without referencing the shape of a, only the axis we want to iterate over?

            – Jsevillamol
            Nov 24 '18 at 21:34






          • 1





            @Jsevillamol See my update for a general solution :)

            – Joe Iddon
            Nov 24 '18 at 21:38

















          Any way of doing this without referencing the shape of a, only the axis we want to iterate over?

          – Jsevillamol
          Nov 24 '18 at 21:34





          Any way of doing this without referencing the shape of a, only the axis we want to iterate over?

          – Jsevillamol
          Nov 24 '18 at 21:34




          1




          1





          @Jsevillamol See my update for a general solution :)

          – Joe Iddon
          Nov 24 '18 at 21:38





          @Jsevillamol See my update for a general solution :)

          – Joe Iddon
          Nov 24 '18 at 21:38




















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