left and right not working on parentheses within the same line when internal fractions are changed












12















I'm trying to show the product of two Legendre symbols. When I compile the following



documentclass{article}
begin{document}
$$left(frac{x}{p}right) left(frac{x}{p}right)$$
end{document}


it yields





as expected. However, when I switch the variables, i.e.



documentclass{article}
begin{document}
$$left(frac{x}{p}right)left(frac{p}{x}right)$$
end{document}


it yields



enter image description here



How do I resolve this? Why do the values within the fractions matter?










share|improve this question


















  • 1





    The double signs of $$ it is a old syntax. You should must [...].

    – Sebastiano
    Nov 24 '18 at 19:30
















12















I'm trying to show the product of two Legendre symbols. When I compile the following



documentclass{article}
begin{document}
$$left(frac{x}{p}right) left(frac{x}{p}right)$$
end{document}


it yields





as expected. However, when I switch the variables, i.e.



documentclass{article}
begin{document}
$$left(frac{x}{p}right)left(frac{p}{x}right)$$
end{document}


it yields



enter image description here



How do I resolve this? Why do the values within the fractions matter?










share|improve this question


















  • 1





    The double signs of $$ it is a old syntax. You should must [...].

    – Sebastiano
    Nov 24 '18 at 19:30














12












12








12








I'm trying to show the product of two Legendre symbols. When I compile the following



documentclass{article}
begin{document}
$$left(frac{x}{p}right) left(frac{x}{p}right)$$
end{document}


it yields





as expected. However, when I switch the variables, i.e.



documentclass{article}
begin{document}
$$left(frac{x}{p}right)left(frac{p}{x}right)$$
end{document}


it yields



enter image description here



How do I resolve this? Why do the values within the fractions matter?










share|improve this question














I'm trying to show the product of two Legendre symbols. When I compile the following



documentclass{article}
begin{document}
$$left(frac{x}{p}right) left(frac{x}{p}right)$$
end{document}


it yields





as expected. However, when I switch the variables, i.e.



documentclass{article}
begin{document}
$$left(frac{x}{p}right)left(frac{p}{x}right)$$
end{document}


it yields



enter image description here



How do I resolve this? Why do the values within the fractions matter?







math-mode






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 24 '18 at 16:55









Antoine EgoAntoine Ego

1037




1037








  • 1





    The double signs of $$ it is a old syntax. You should must [...].

    – Sebastiano
    Nov 24 '18 at 19:30














  • 1





    The double signs of $$ it is a old syntax. You should must [...].

    – Sebastiano
    Nov 24 '18 at 19:30








1




1





The double signs of $$ it is a old syntax. You should must [...].

– Sebastiano
Nov 24 '18 at 19:30





The double signs of $$ it is a old syntax. You should must [...].

– Sebastiano
Nov 24 '18 at 19:30










3 Answers
3






active

oldest

votes


















13














This is somewhat similar to this question.



The values in the fractions matter because the boxes of the characters have different sizes. The p has a descender below the baseline which the x doesn't, thus when you swap them, the box of the denominator get a little bigger and TeX uses a larger delimiter to make that fit.



You have a few possibilities to work around that (basically the same ones I listed in the linked question):





  • You can use a fixed delimiter size (bigg or Big, for instance):



    $$Bigl(frac{x}{p}Bigr)Bigl(frac{p}{x}Bigr)$$
    $$biggl(frac{x}{p}biggr)biggl(frac{p}{x}biggr)$$



  • You can raise the p so that TeX won't try to use a larger box:



    $$left(frac{x}{raise0.35exhbox{$p$}}right)left(frac{p}{x}right)$$



  • or you can add an invisible p next to the x so that the delimiter used will be the larger one:



    $$left(frac{x}{p}right)left(frac{p}{vphantom{p}x}right)$$



  • Or you can change change TeX's delimiterfactor (and delimitershortfall, which I didn't show here) and let TeX adjust the delimiters accordingly:



    $$delimiterfactor=790
    left(frac{x}{p}right)left(frac{p}{x}right)$$

    $$delimiterfactor=970
    left(frac{x}{p}right)left(frac{p}{x}right)$$



Full code:



documentclass{article}
begin{document}
% delimitershortfall=5pt % Default
% delimiterfactor=901 % Default

$$left(frac{x}{p}right)left(frac{p}{x}right)$$

$$Bigl(frac{x}{p}Bigr)Bigl(frac{p}{x}Bigr)$$
$$biggl(frac{x}{p}biggr)biggl(frac{p}{x}biggr)$$

$$left(frac{x}{raise0.35exhbox{$p$}}right)left(frac{p}{x}right)$$

$$left(frac{x}{p}right)left(frac{p}{vphantom{p}x}right)$$

$$delimiterfactor=790
left(frac{x}{p}right)left(frac{p}{x}right)$$

$$delimiterfactor=970
left(frac{x}{p}right)left(frac{p}{x}right)$$
end{document}


Output:




enter image description here







share|improve this answer































    13














    Use genfrac for this:



    documentclass{article}
    usepackage{amsmath}

    newcommand{genlegendre}[3]{genfrac{(}{)}{}{#1}{#2}{#3}}
    newcommand{legendre}[2]{genlegendre{}{#1}{#2}}
    newcommand{dlegendre}[2]{genlegendre{0}{#1}{#2}}
    newcommand{tlegendre}[2]{genlegendre{1}{#1}{#2}}

    begin{document}

    [
    legendre{x}{p}quadlegendre{p}{x}quad
    legendre{x}{x}quadlegendre{d}{b}
    ]

    end{document}


    enter image description here



    The variants dlegendre and tlegendre are analogous to dfrac and tfrac.






    share|improve this answer
























    • I've never heard of tfrac, what's the package that defines it?

      – AndréC
      Nov 24 '18 at 22:14






    • 1





      @AndréC amsmath, along with dfrac; also binom, dbinom and tbinom. In some cases, in displays tfrac is needed not to give prominence to fractional factors.

      – egreg
      Nov 24 '18 at 22:24





















    0














    I like the unified syntax for this kind of stuff in the mathtools package.



    documentclass{article}

    usepackage{mathtools}
    DeclarePairedDelimiter{paren}{lparen}{rparen}

    begin{document}

    begin{equation*}
    paren*{frac{x}{p} }quad paren*{frac{p}{x}}
    qquad
    paren[bigg]{frac{x}{p}} quad paren[bigg]{frac{p}{x}}
    end{equation*}

    end{document}


    enter image description here






    share|improve this answer
























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      3 Answers
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      3 Answers
      3






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      active

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      active

      oldest

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      13














      This is somewhat similar to this question.



      The values in the fractions matter because the boxes of the characters have different sizes. The p has a descender below the baseline which the x doesn't, thus when you swap them, the box of the denominator get a little bigger and TeX uses a larger delimiter to make that fit.



      You have a few possibilities to work around that (basically the same ones I listed in the linked question):





      • You can use a fixed delimiter size (bigg or Big, for instance):



        $$Bigl(frac{x}{p}Bigr)Bigl(frac{p}{x}Bigr)$$
        $$biggl(frac{x}{p}biggr)biggl(frac{p}{x}biggr)$$



      • You can raise the p so that TeX won't try to use a larger box:



        $$left(frac{x}{raise0.35exhbox{$p$}}right)left(frac{p}{x}right)$$



      • or you can add an invisible p next to the x so that the delimiter used will be the larger one:



        $$left(frac{x}{p}right)left(frac{p}{vphantom{p}x}right)$$



      • Or you can change change TeX's delimiterfactor (and delimitershortfall, which I didn't show here) and let TeX adjust the delimiters accordingly:



        $$delimiterfactor=790
        left(frac{x}{p}right)left(frac{p}{x}right)$$

        $$delimiterfactor=970
        left(frac{x}{p}right)left(frac{p}{x}right)$$



      Full code:



      documentclass{article}
      begin{document}
      % delimitershortfall=5pt % Default
      % delimiterfactor=901 % Default

      $$left(frac{x}{p}right)left(frac{p}{x}right)$$

      $$Bigl(frac{x}{p}Bigr)Bigl(frac{p}{x}Bigr)$$
      $$biggl(frac{x}{p}biggr)biggl(frac{p}{x}biggr)$$

      $$left(frac{x}{raise0.35exhbox{$p$}}right)left(frac{p}{x}right)$$

      $$left(frac{x}{p}right)left(frac{p}{vphantom{p}x}right)$$

      $$delimiterfactor=790
      left(frac{x}{p}right)left(frac{p}{x}right)$$

      $$delimiterfactor=970
      left(frac{x}{p}right)left(frac{p}{x}right)$$
      end{document}


      Output:




      enter image description here







      share|improve this answer




























        13














        This is somewhat similar to this question.



        The values in the fractions matter because the boxes of the characters have different sizes. The p has a descender below the baseline which the x doesn't, thus when you swap them, the box of the denominator get a little bigger and TeX uses a larger delimiter to make that fit.



        You have a few possibilities to work around that (basically the same ones I listed in the linked question):





        • You can use a fixed delimiter size (bigg or Big, for instance):



          $$Bigl(frac{x}{p}Bigr)Bigl(frac{p}{x}Bigr)$$
          $$biggl(frac{x}{p}biggr)biggl(frac{p}{x}biggr)$$



        • You can raise the p so that TeX won't try to use a larger box:



          $$left(frac{x}{raise0.35exhbox{$p$}}right)left(frac{p}{x}right)$$



        • or you can add an invisible p next to the x so that the delimiter used will be the larger one:



          $$left(frac{x}{p}right)left(frac{p}{vphantom{p}x}right)$$



        • Or you can change change TeX's delimiterfactor (and delimitershortfall, which I didn't show here) and let TeX adjust the delimiters accordingly:



          $$delimiterfactor=790
          left(frac{x}{p}right)left(frac{p}{x}right)$$

          $$delimiterfactor=970
          left(frac{x}{p}right)left(frac{p}{x}right)$$



        Full code:



        documentclass{article}
        begin{document}
        % delimitershortfall=5pt % Default
        % delimiterfactor=901 % Default

        $$left(frac{x}{p}right)left(frac{p}{x}right)$$

        $$Bigl(frac{x}{p}Bigr)Bigl(frac{p}{x}Bigr)$$
        $$biggl(frac{x}{p}biggr)biggl(frac{p}{x}biggr)$$

        $$left(frac{x}{raise0.35exhbox{$p$}}right)left(frac{p}{x}right)$$

        $$left(frac{x}{p}right)left(frac{p}{vphantom{p}x}right)$$

        $$delimiterfactor=790
        left(frac{x}{p}right)left(frac{p}{x}right)$$

        $$delimiterfactor=970
        left(frac{x}{p}right)left(frac{p}{x}right)$$
        end{document}


        Output:




        enter image description here







        share|improve this answer


























          13












          13








          13







          This is somewhat similar to this question.



          The values in the fractions matter because the boxes of the characters have different sizes. The p has a descender below the baseline which the x doesn't, thus when you swap them, the box of the denominator get a little bigger and TeX uses a larger delimiter to make that fit.



          You have a few possibilities to work around that (basically the same ones I listed in the linked question):





          • You can use a fixed delimiter size (bigg or Big, for instance):



            $$Bigl(frac{x}{p}Bigr)Bigl(frac{p}{x}Bigr)$$
            $$biggl(frac{x}{p}biggr)biggl(frac{p}{x}biggr)$$



          • You can raise the p so that TeX won't try to use a larger box:



            $$left(frac{x}{raise0.35exhbox{$p$}}right)left(frac{p}{x}right)$$



          • or you can add an invisible p next to the x so that the delimiter used will be the larger one:



            $$left(frac{x}{p}right)left(frac{p}{vphantom{p}x}right)$$



          • Or you can change change TeX's delimiterfactor (and delimitershortfall, which I didn't show here) and let TeX adjust the delimiters accordingly:



            $$delimiterfactor=790
            left(frac{x}{p}right)left(frac{p}{x}right)$$

            $$delimiterfactor=970
            left(frac{x}{p}right)left(frac{p}{x}right)$$



          Full code:



          documentclass{article}
          begin{document}
          % delimitershortfall=5pt % Default
          % delimiterfactor=901 % Default

          $$left(frac{x}{p}right)left(frac{p}{x}right)$$

          $$Bigl(frac{x}{p}Bigr)Bigl(frac{p}{x}Bigr)$$
          $$biggl(frac{x}{p}biggr)biggl(frac{p}{x}biggr)$$

          $$left(frac{x}{raise0.35exhbox{$p$}}right)left(frac{p}{x}right)$$

          $$left(frac{x}{p}right)left(frac{p}{vphantom{p}x}right)$$

          $$delimiterfactor=790
          left(frac{x}{p}right)left(frac{p}{x}right)$$

          $$delimiterfactor=970
          left(frac{x}{p}right)left(frac{p}{x}right)$$
          end{document}


          Output:




          enter image description here







          share|improve this answer













          This is somewhat similar to this question.



          The values in the fractions matter because the boxes of the characters have different sizes. The p has a descender below the baseline which the x doesn't, thus when you swap them, the box of the denominator get a little bigger and TeX uses a larger delimiter to make that fit.



          You have a few possibilities to work around that (basically the same ones I listed in the linked question):





          • You can use a fixed delimiter size (bigg or Big, for instance):



            $$Bigl(frac{x}{p}Bigr)Bigl(frac{p}{x}Bigr)$$
            $$biggl(frac{x}{p}biggr)biggl(frac{p}{x}biggr)$$



          • You can raise the p so that TeX won't try to use a larger box:



            $$left(frac{x}{raise0.35exhbox{$p$}}right)left(frac{p}{x}right)$$



          • or you can add an invisible p next to the x so that the delimiter used will be the larger one:



            $$left(frac{x}{p}right)left(frac{p}{vphantom{p}x}right)$$



          • Or you can change change TeX's delimiterfactor (and delimitershortfall, which I didn't show here) and let TeX adjust the delimiters accordingly:



            $$delimiterfactor=790
            left(frac{x}{p}right)left(frac{p}{x}right)$$

            $$delimiterfactor=970
            left(frac{x}{p}right)left(frac{p}{x}right)$$



          Full code:



          documentclass{article}
          begin{document}
          % delimitershortfall=5pt % Default
          % delimiterfactor=901 % Default

          $$left(frac{x}{p}right)left(frac{p}{x}right)$$

          $$Bigl(frac{x}{p}Bigr)Bigl(frac{p}{x}Bigr)$$
          $$biggl(frac{x}{p}biggr)biggl(frac{p}{x}biggr)$$

          $$left(frac{x}{raise0.35exhbox{$p$}}right)left(frac{p}{x}right)$$

          $$left(frac{x}{p}right)left(frac{p}{vphantom{p}x}right)$$

          $$delimiterfactor=790
          left(frac{x}{p}right)left(frac{p}{x}right)$$

          $$delimiterfactor=970
          left(frac{x}{p}right)left(frac{p}{x}right)$$
          end{document}


          Output:




          enter image description here








          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 24 '18 at 17:16









          Phelype OleinikPhelype Oleinik

          25.8k54691




          25.8k54691























              13














              Use genfrac for this:



              documentclass{article}
              usepackage{amsmath}

              newcommand{genlegendre}[3]{genfrac{(}{)}{}{#1}{#2}{#3}}
              newcommand{legendre}[2]{genlegendre{}{#1}{#2}}
              newcommand{dlegendre}[2]{genlegendre{0}{#1}{#2}}
              newcommand{tlegendre}[2]{genlegendre{1}{#1}{#2}}

              begin{document}

              [
              legendre{x}{p}quadlegendre{p}{x}quad
              legendre{x}{x}quadlegendre{d}{b}
              ]

              end{document}


              enter image description here



              The variants dlegendre and tlegendre are analogous to dfrac and tfrac.






              share|improve this answer
























              • I've never heard of tfrac, what's the package that defines it?

                – AndréC
                Nov 24 '18 at 22:14






              • 1





                @AndréC amsmath, along with dfrac; also binom, dbinom and tbinom. In some cases, in displays tfrac is needed not to give prominence to fractional factors.

                – egreg
                Nov 24 '18 at 22:24


















              13














              Use genfrac for this:



              documentclass{article}
              usepackage{amsmath}

              newcommand{genlegendre}[3]{genfrac{(}{)}{}{#1}{#2}{#3}}
              newcommand{legendre}[2]{genlegendre{}{#1}{#2}}
              newcommand{dlegendre}[2]{genlegendre{0}{#1}{#2}}
              newcommand{tlegendre}[2]{genlegendre{1}{#1}{#2}}

              begin{document}

              [
              legendre{x}{p}quadlegendre{p}{x}quad
              legendre{x}{x}quadlegendre{d}{b}
              ]

              end{document}


              enter image description here



              The variants dlegendre and tlegendre are analogous to dfrac and tfrac.






              share|improve this answer
























              • I've never heard of tfrac, what's the package that defines it?

                – AndréC
                Nov 24 '18 at 22:14






              • 1





                @AndréC amsmath, along with dfrac; also binom, dbinom and tbinom. In some cases, in displays tfrac is needed not to give prominence to fractional factors.

                – egreg
                Nov 24 '18 at 22:24
















              13












              13








              13







              Use genfrac for this:



              documentclass{article}
              usepackage{amsmath}

              newcommand{genlegendre}[3]{genfrac{(}{)}{}{#1}{#2}{#3}}
              newcommand{legendre}[2]{genlegendre{}{#1}{#2}}
              newcommand{dlegendre}[2]{genlegendre{0}{#1}{#2}}
              newcommand{tlegendre}[2]{genlegendre{1}{#1}{#2}}

              begin{document}

              [
              legendre{x}{p}quadlegendre{p}{x}quad
              legendre{x}{x}quadlegendre{d}{b}
              ]

              end{document}


              enter image description here



              The variants dlegendre and tlegendre are analogous to dfrac and tfrac.






              share|improve this answer













              Use genfrac for this:



              documentclass{article}
              usepackage{amsmath}

              newcommand{genlegendre}[3]{genfrac{(}{)}{}{#1}{#2}{#3}}
              newcommand{legendre}[2]{genlegendre{}{#1}{#2}}
              newcommand{dlegendre}[2]{genlegendre{0}{#1}{#2}}
              newcommand{tlegendre}[2]{genlegendre{1}{#1}{#2}}

              begin{document}

              [
              legendre{x}{p}quadlegendre{p}{x}quad
              legendre{x}{x}quadlegendre{d}{b}
              ]

              end{document}


              enter image description here



              The variants dlegendre and tlegendre are analogous to dfrac and tfrac.







              share|improve this answer












              share|improve this answer



              share|improve this answer










              answered Nov 24 '18 at 22:09









              egregegreg

              735k8919343260




              735k8919343260













              • I've never heard of tfrac, what's the package that defines it?

                – AndréC
                Nov 24 '18 at 22:14






              • 1





                @AndréC amsmath, along with dfrac; also binom, dbinom and tbinom. In some cases, in displays tfrac is needed not to give prominence to fractional factors.

                – egreg
                Nov 24 '18 at 22:24





















              • I've never heard of tfrac, what's the package that defines it?

                – AndréC
                Nov 24 '18 at 22:14






              • 1





                @AndréC amsmath, along with dfrac; also binom, dbinom and tbinom. In some cases, in displays tfrac is needed not to give prominence to fractional factors.

                – egreg
                Nov 24 '18 at 22:24



















              I've never heard of tfrac, what's the package that defines it?

              – AndréC
              Nov 24 '18 at 22:14





              I've never heard of tfrac, what's the package that defines it?

              – AndréC
              Nov 24 '18 at 22:14




              1




              1





              @AndréC amsmath, along with dfrac; also binom, dbinom and tbinom. In some cases, in displays tfrac is needed not to give prominence to fractional factors.

              – egreg
              Nov 24 '18 at 22:24







              @AndréC amsmath, along with dfrac; also binom, dbinom and tbinom. In some cases, in displays tfrac is needed not to give prominence to fractional factors.

              – egreg
              Nov 24 '18 at 22:24













              0














              I like the unified syntax for this kind of stuff in the mathtools package.



              documentclass{article}

              usepackage{mathtools}
              DeclarePairedDelimiter{paren}{lparen}{rparen}

              begin{document}

              begin{equation*}
              paren*{frac{x}{p} }quad paren*{frac{p}{x}}
              qquad
              paren[bigg]{frac{x}{p}} quad paren[bigg]{frac{p}{x}}
              end{equation*}

              end{document}


              enter image description here






              share|improve this answer




























                0














                I like the unified syntax for this kind of stuff in the mathtools package.



                documentclass{article}

                usepackage{mathtools}
                DeclarePairedDelimiter{paren}{lparen}{rparen}

                begin{document}

                begin{equation*}
                paren*{frac{x}{p} }quad paren*{frac{p}{x}}
                qquad
                paren[bigg]{frac{x}{p}} quad paren[bigg]{frac{p}{x}}
                end{equation*}

                end{document}


                enter image description here






                share|improve this answer


























                  0












                  0








                  0







                  I like the unified syntax for this kind of stuff in the mathtools package.



                  documentclass{article}

                  usepackage{mathtools}
                  DeclarePairedDelimiter{paren}{lparen}{rparen}

                  begin{document}

                  begin{equation*}
                  paren*{frac{x}{p} }quad paren*{frac{p}{x}}
                  qquad
                  paren[bigg]{frac{x}{p}} quad paren[bigg]{frac{p}{x}}
                  end{equation*}

                  end{document}


                  enter image description here






                  share|improve this answer













                  I like the unified syntax for this kind of stuff in the mathtools package.



                  documentclass{article}

                  usepackage{mathtools}
                  DeclarePairedDelimiter{paren}{lparen}{rparen}

                  begin{document}

                  begin{equation*}
                  paren*{frac{x}{p} }quad paren*{frac{p}{x}}
                  qquad
                  paren[bigg]{frac{x}{p}} quad paren[bigg]{frac{p}{x}}
                  end{equation*}

                  end{document}


                  enter image description here







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 27 '18 at 21:29









                  Máté WierdlMáté Wierdl

                  53729




                  53729






























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