compare specific string to a word python
say I have a certain string and a list of strings.
I would like to append to a new list all the words from the list (of strings)
that are exactly like the pattern
for example:
list of strings = ['string1','string2'...]
pattern =__letter__letter_ ('_c__ye_' for instance)
I need to add all strings that are made up of the same letters in the same places as the pattern, and has the same length.
so for instance:
new_list = ['aczxyep','zcisyef'...]
I have tried this:
def pattern_word_equality(words,pattern):
list1 =
for word in words:
for letter in word:
if letter in pattern:
list1.append(word)
return list1
help will be much appreciated :)
python string list word
|
show 3 more comments
say I have a certain string and a list of strings.
I would like to append to a new list all the words from the list (of strings)
that are exactly like the pattern
for example:
list of strings = ['string1','string2'...]
pattern =__letter__letter_ ('_c__ye_' for instance)
I need to add all strings that are made up of the same letters in the same places as the pattern, and has the same length.
so for instance:
new_list = ['aczxyep','zcisyef'...]
I have tried this:
def pattern_word_equality(words,pattern):
list1 =
for word in words:
for letter in word:
if letter in pattern:
list1.append(word)
return list1
help will be much appreciated :)
python string list word
2
more hangman homework? :) Someone asked this yesterday too funnily enough.
– Paritosh Singh
Nov 11 at 17:01
haha it was me but the question wasnt specific enough anyway..
– user10596917
Nov 11 at 17:01
oh! did the solution not work for you?
– Paritosh Singh
Nov 11 at 17:02
Noo.. I mean the nice people tried to help but I gave an example that made it seem like the situation isnt exactly what it was. (I gave an example for a pattern that STARTS with letters, though it is actually a random pattern)
– user10596917
Nov 11 at 17:04
stackoverflow.com/a/53242554/10618540 posted there will work the same, doesnt matter if the string didnt start with it.
– Paritosh Singh
Nov 11 at 17:05
|
show 3 more comments
say I have a certain string and a list of strings.
I would like to append to a new list all the words from the list (of strings)
that are exactly like the pattern
for example:
list of strings = ['string1','string2'...]
pattern =__letter__letter_ ('_c__ye_' for instance)
I need to add all strings that are made up of the same letters in the same places as the pattern, and has the same length.
so for instance:
new_list = ['aczxyep','zcisyef'...]
I have tried this:
def pattern_word_equality(words,pattern):
list1 =
for word in words:
for letter in word:
if letter in pattern:
list1.append(word)
return list1
help will be much appreciated :)
python string list word
say I have a certain string and a list of strings.
I would like to append to a new list all the words from the list (of strings)
that are exactly like the pattern
for example:
list of strings = ['string1','string2'...]
pattern =__letter__letter_ ('_c__ye_' for instance)
I need to add all strings that are made up of the same letters in the same places as the pattern, and has the same length.
so for instance:
new_list = ['aczxyep','zcisyef'...]
I have tried this:
def pattern_word_equality(words,pattern):
list1 =
for word in words:
for letter in word:
if letter in pattern:
list1.append(word)
return list1
help will be much appreciated :)
python string list word
python string list word
asked Nov 11 at 16:53
user10596917
2
more hangman homework? :) Someone asked this yesterday too funnily enough.
– Paritosh Singh
Nov 11 at 17:01
haha it was me but the question wasnt specific enough anyway..
– user10596917
Nov 11 at 17:01
oh! did the solution not work for you?
– Paritosh Singh
Nov 11 at 17:02
Noo.. I mean the nice people tried to help but I gave an example that made it seem like the situation isnt exactly what it was. (I gave an example for a pattern that STARTS with letters, though it is actually a random pattern)
– user10596917
Nov 11 at 17:04
stackoverflow.com/a/53242554/10618540 posted there will work the same, doesnt matter if the string didnt start with it.
– Paritosh Singh
Nov 11 at 17:05
|
show 3 more comments
2
more hangman homework? :) Someone asked this yesterday too funnily enough.
– Paritosh Singh
Nov 11 at 17:01
haha it was me but the question wasnt specific enough anyway..
– user10596917
Nov 11 at 17:01
oh! did the solution not work for you?
– Paritosh Singh
Nov 11 at 17:02
Noo.. I mean the nice people tried to help but I gave an example that made it seem like the situation isnt exactly what it was. (I gave an example for a pattern that STARTS with letters, though it is actually a random pattern)
– user10596917
Nov 11 at 17:04
stackoverflow.com/a/53242554/10618540 posted there will work the same, doesnt matter if the string didnt start with it.
– Paritosh Singh
Nov 11 at 17:05
2
2
more hangman homework? :) Someone asked this yesterday too funnily enough.
– Paritosh Singh
Nov 11 at 17:01
more hangman homework? :) Someone asked this yesterday too funnily enough.
– Paritosh Singh
Nov 11 at 17:01
haha it was me but the question wasnt specific enough anyway..
– user10596917
Nov 11 at 17:01
haha it was me but the question wasnt specific enough anyway..
– user10596917
Nov 11 at 17:01
oh! did the solution not work for you?
– Paritosh Singh
Nov 11 at 17:02
oh! did the solution not work for you?
– Paritosh Singh
Nov 11 at 17:02
Noo.. I mean the nice people tried to help but I gave an example that made it seem like the situation isnt exactly what it was. (I gave an example for a pattern that STARTS with letters, though it is actually a random pattern)
– user10596917
Nov 11 at 17:04
Noo.. I mean the nice people tried to help but I gave an example that made it seem like the situation isnt exactly what it was. (I gave an example for a pattern that STARTS with letters, though it is actually a random pattern)
– user10596917
Nov 11 at 17:04
stackoverflow.com/a/53242554/10618540 posted there will work the same, doesnt matter if the string didnt start with it.
– Paritosh Singh
Nov 11 at 17:05
stackoverflow.com/a/53242554/10618540 posted there will work the same, doesnt matter if the string didnt start with it.
– Paritosh Singh
Nov 11 at 17:05
|
show 3 more comments
1 Answer
1
active
oldest
votes
If your pattern is as simple as _c__ye_, then you can look for the characters in the specific positions:
words = ['aczxyep', 'cxxye', 'zcisyef', 'abcdefg']
result1 = list(filter(lambda w: w[1] == 'c' and w[4:6] == 'ye', words))
If your pattern is getting more complex, then you can start using regular expressions:
pat = re.compile("^.c..ye.$")
result2 = list(filter(lambda w: pat.match(w), words))
Output:
print(result1) # ['aczxyep', 'zcisyef']
print(result2) # ['aczxyep', 'zcisyef']
answered Nov 12 at 7:25
Edgar R. Mondragón
1,4341619
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
If your pattern is as simple as _c__ye_, then you can look for the characters in the specific positions:
words = ['aczxyep', 'cxxye', 'zcisyef', 'abcdefg']
result1 = list(filter(lambda w: w[1] == 'c' and w[4:6] == 'ye', words))
If your pattern is getting more complex, then you can start using regular expressions:
pat = re.compile("^.c..ye.$")
result2 = list(filter(lambda w: pat.match(w), words))
Output:
print(result1) # ['aczxyep', 'zcisyef']
print(result2) # ['aczxyep', 'zcisyef']
answered Nov 12 at 7:25
Edgar R. Mondragón
1,4341619
add a comment |
If your pattern is as simple as _c__ye_, then you can look for the characters in the specific positions:
words = ['aczxyep', 'cxxye', 'zcisyef', 'abcdefg']
result1 = list(filter(lambda w: w[1] == 'c' and w[4:6] == 'ye', words))
If your pattern is getting more complex, then you can start using regular expressions:
pat = re.compile("^.c..ye.$")
result2 = list(filter(lambda w: pat.match(w), words))
Output:
print(result1) # ['aczxyep', 'zcisyef']
print(result2) # ['aczxyep', 'zcisyef']
answered Nov 12 at 7:25
Edgar R. Mondragón
1,4341619
add a comment |
If your pattern is as simple as _c__ye_, then you can look for the characters in the specific positions:
words = ['aczxyep', 'cxxye', 'zcisyef', 'abcdefg']
result1 = list(filter(lambda w: w[1] == 'c' and w[4:6] == 'ye', words))
If your pattern is getting more complex, then you can start using regular expressions:
pat = re.compile("^.c..ye.$")
result2 = list(filter(lambda w: pat.match(w), words))
Output:
print(result1) # ['aczxyep', 'zcisyef']
print(result2) # ['aczxyep', 'zcisyef']
answered Nov 12 at 7:25
Edgar R. Mondragón
1,4341619
If your pattern is as simple as _c__ye_, then you can look for the characters in the specific positions:
words = ['aczxyep', 'cxxye', 'zcisyef', 'abcdefg']
result1 = list(filter(lambda w: w[1] == 'c' and w[4:6] == 'ye', words))
If your pattern is getting more complex, then you can start using regular expressions:
pat = re.compile("^.c..ye.$")
result2 = list(filter(lambda w: pat.match(w), words))
Output:
print(result1) # ['aczxyep', 'zcisyef']
print(result2) # ['aczxyep', 'zcisyef']
answered Nov 12 at 7:25
Edgar R. Mondragón
1,4341619
answered Nov 12 at 7:25
Edgar R. Mondragón
1,4341619
answered Nov 12 at 7:25
Edgar R. Mondragón
1,4341619
answered Nov 12 at 7:25
Edgar R. Mondragón
1,4341619
1,4341619
add a comment |
add a comment |
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2
more hangman homework? :) Someone asked this yesterday too funnily enough.
– Paritosh Singh
Nov 11 at 17:01
haha it was me but the question wasnt specific enough anyway..
– user10596917
Nov 11 at 17:01
oh! did the solution not work for you?
– Paritosh Singh
Nov 11 at 17:02
Noo.. I mean the nice people tried to help but I gave an example that made it seem like the situation isnt exactly what it was. (I gave an example for a pattern that STARTS with letters, though it is actually a random pattern)
– user10596917
Nov 11 at 17:04
stackoverflow.com/a/53242554/10618540 posted there will work the same, doesnt matter if the string didnt start with it.
– Paritosh Singh
Nov 11 at 17:05