count an element in a list with list inside in python [duplicate]
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Nested List and count()
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I have a list with one list inside and I would like to count how many times is one element repeat. for example:
list = ['a','b','c',['a','d']]
find = 'a'
list.count(find)
The ouptput is 1, but I'm looking for 2.
There is any easy way to do it?
thanks
python list count
asked Nov 9 at 11:14
Alberto Aguilera
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Nov 9 at 11:16
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This question already has an answer here:
Nested List and count()
7 answers
I have a list with one list inside and I would like to count how many times is one element repeat. for example:
list = ['a','b','c',['a','d']]
find = 'a'
list.count(find)
The ouptput is 1, but I'm looking for 2.
There is any easy way to do it?
thanks
python list count
asked Nov 9 at 11:14
Alberto Aguilera
354
marked as duplicate by jpp list
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Nov 9 at 11:16
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up vote
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up vote
0
down vote
favorite
This question already has an answer here:
Nested List and count()
7 answers
I have a list with one list inside and I would like to count how many times is one element repeat. for example:
list = ['a','b','c',['a','d']]
find = 'a'
list.count(find)
The ouptput is 1, but I'm looking for 2.
There is any easy way to do it?
thanks
python list count
asked Nov 9 at 11:14
Alberto Aguilera
354
This question already has an answer here:
Nested List and count()
7 answers
I have a list with one list inside and I would like to count how many times is one element repeat. for example:
list = ['a','b','c',['a','d']]
find = 'a'
list.count(find)
The ouptput is 1, but I'm looking for 2.
There is any easy way to do it?
thanks
This question already has an answer here:
Nested List and count()
7 answers
python list count
python list count
asked Nov 9 at 11:14
Alberto Aguilera
354
asked Nov 9 at 11:14
Alberto Aguilera
354
asked Nov 9 at 11:14
Alberto Aguilera
354
asked Nov 9 at 11:14
Alberto Aguilera
354
asked Nov 9 at 11:14
Alberto Aguilera
354
354
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Nov 9 at 11:16
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1 Answer
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Archive with chain.from_iterable
from itertools import chain
print(list(chain.from_iterable(lst)).count('a'))
First make your list flatten and get the count.
answered Nov 9 at 11:24
Vikas Damodar
1,9391520
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
Archive with chain.from_iterable
from itertools import chain
print(list(chain.from_iterable(lst)).count('a'))
First make your list flatten and get the count.
answered Nov 9 at 11:24
Vikas Damodar
1,9391520
add a comment |
up vote
0
down vote
accepted
Archive with chain.from_iterable
from itertools import chain
print(list(chain.from_iterable(lst)).count('a'))
First make your list flatten and get the count.
answered Nov 9 at 11:24
Vikas Damodar
1,9391520
add a comment |
up vote
0
down vote
accepted
up vote
0
down vote
accepted
Archive with chain.from_iterable
from itertools import chain
print(list(chain.from_iterable(lst)).count('a'))
First make your list flatten and get the count.
answered Nov 9 at 11:24
Vikas Damodar
1,9391520
Archive with chain.from_iterable
from itertools import chain
print(list(chain.from_iterable(lst)).count('a'))
First make your list flatten and get the count.
answered Nov 9 at 11:24
Vikas Damodar
1,9391520
answered Nov 9 at 11:24
Vikas Damodar
1,9391520
answered Nov 9 at 11:24
Vikas Damodar
1,9391520
answered Nov 9 at 11:24
Vikas Damodar
1,9391520
1,9391520
add a comment |
add a comment |
