Django ORM : How to use Counter with annotate












1















tltr



Considering a list of emails:



list = ['a@a.com', 'b@a.com', 'b@a.com', 'a@a.com', 'c@a.com', 'a@a.com']


Considering a queryset of Users using these emails, how can I use annotate to count the occurrences of the Users emails in this list?



If I try this: 



users = User.objects.all()

users.values('email').annotate(email_in_list=Count('email))


the result is 1 for every users.
I expect these results for each user:



a@a.com - 3



b@a.com - 2



c@a.com - 1



Initial Question



I want to see how many refered users does have a user:



refered_user = Profile.objects.filter(user__groups__name="Refered")

list = refered_user.values_list('referer_email')



# Getting all the referers who  actually had refered users

referer_users = Profile.objects.filter(user__groups__name="Referer", user__email__in=list)


Now how can I see how many refered users has a referer?



I have tried this without success:



counter = Counter(refered_user)

referer_users.values('user__email').annotate(refered_num=counter['user__email'])


As requested, here are the models :



class Profile(models.Model):

    user = models.OneToOneField(User, on_delete=models.CASCADE)

    referer_email = models.CharField(verbose_name='Email Referer', max_length=99, blank=True)


EDIT : Considering Count()



I have tried this:



referer_users.values('user__email').annotate(refered_num=count('user__email'))


But the value of refered_num is always equal to 1, which is logical, because in the refered_num query, we have only User objects with one email for each.



How can I count the occurrences of the referer email in the refered_user list and annotate it in my referer_users query?






python django django-orm







share|improve this question

























  • can you please share your models?

    – ruddra
    Nov 15 '18 at 19:47











  • I have edited my question including the model

    – Aurélien
    Nov 15 '18 at 19:58
















1















tltr



Considering a list of emails:



list = ['a@a.com', 'b@a.com', 'b@a.com', 'a@a.com', 'c@a.com', 'a@a.com']


Considering a queryset of Users using these emails, how can I use annotate to count the occurrences of the Users emails in this list?



If I try this: 



users = User.objects.all()

users.values('email').annotate(email_in_list=Count('email))


the result is 1 for every users.
I expect these results for each user:



a@a.com - 3



b@a.com - 2



c@a.com - 1



Initial Question



I want to see how many refered users does have a user:



refered_user = Profile.objects.filter(user__groups__name="Refered")

list = refered_user.values_list('referer_email')



# Getting all the referers who  actually had refered users

referer_users = Profile.objects.filter(user__groups__name="Referer", user__email__in=list)


Now how can I see how many refered users has a referer?



I have tried this without success:



counter = Counter(refered_user)

referer_users.values('user__email').annotate(refered_num=counter['user__email'])


As requested, here are the models :



class Profile(models.Model):

    user = models.OneToOneField(User, on_delete=models.CASCADE)

    referer_email = models.CharField(verbose_name='Email Referer', max_length=99, blank=True)


EDIT : Considering Count()



I have tried this:



referer_users.values('user__email').annotate(refered_num=count('user__email'))


But the value of refered_num is always equal to 1, which is logical, because in the refered_num query, we have only User objects with one email for each.



How can I count the occurrences of the referer email in the refered_user list and annotate it in my referer_users query?






python django django-orm







share|improve this question

























  • can you please share your models?

    – ruddra
    Nov 15 '18 at 19:47











  • I have edited my question including the model

    – Aurélien
    Nov 15 '18 at 19:58














1












1








1


1






tltr



Considering a list of emails:



list = ['a@a.com', 'b@a.com', 'b@a.com', 'a@a.com', 'c@a.com', 'a@a.com']


Considering a queryset of Users using these emails, how can I use annotate to count the occurrences of the Users emails in this list?



If I try this: 



users = User.objects.all()

users.values('email').annotate(email_in_list=Count('email))


the result is 1 for every users.
I expect these results for each user:



a@a.com - 3



b@a.com - 2



c@a.com - 1



Initial Question



I want to see how many refered users does have a user:



refered_user = Profile.objects.filter(user__groups__name="Refered")

list = refered_user.values_list('referer_email')



# Getting all the referers who  actually had refered users

referer_users = Profile.objects.filter(user__groups__name="Referer", user__email__in=list)


Now how can I see how many refered users has a referer?



I have tried this without success:



counter = Counter(refered_user)

referer_users.values('user__email').annotate(refered_num=counter['user__email'])


As requested, here are the models :



class Profile(models.Model):

    user = models.OneToOneField(User, on_delete=models.CASCADE)

    referer_email = models.CharField(verbose_name='Email Referer', max_length=99, blank=True)


EDIT : Considering Count()



I have tried this:



referer_users.values('user__email').annotate(refered_num=count('user__email'))


But the value of refered_num is always equal to 1, which is logical, because in the refered_num query, we have only User objects with one email for each.



How can I count the occurrences of the referer email in the refered_user list and annotate it in my referer_users query?






python django django-orm







share|improve this question
















tltr



Considering a list of emails:



list = ['a@a.com', 'b@a.com', 'b@a.com', 'a@a.com', 'c@a.com', 'a@a.com']


Considering a queryset of Users using these emails, how can I use annotate to count the occurrences of the Users emails in this list?



If I try this: 



users = User.objects.all()

users.values('email').annotate(email_in_list=Count('email))


the result is 1 for every users.
I expect these results for each user:



a@a.com - 3



b@a.com - 2



c@a.com - 1



Initial Question



I want to see how many refered users does have a user:



refered_user = Profile.objects.filter(user__groups__name="Refered")

list = refered_user.values_list('referer_email')



# Getting all the referers who  actually had refered users

referer_users = Profile.objects.filter(user__groups__name="Referer", user__email__in=list)


Now how can I see how many refered users has a referer?



I have tried this without success:



counter = Counter(refered_user)

referer_users.values('user__email').annotate(refered_num=counter['user__email'])


As requested, here are the models :



class Profile(models.Model):

    user = models.OneToOneField(User, on_delete=models.CASCADE)

    referer_email = models.CharField(verbose_name='Email Referer', max_length=99, blank=True)


EDIT : Considering Count()



I have tried this:



referer_users.values('user__email').annotate(refered_num=count('user__email'))


But the value of refered_num is always equal to 1, which is logical, because in the refered_num query, we have only User objects with one email for each.



How can I count the occurrences of the referer email in the refered_user list and annotate it in my referer_users query?






python django django-orm




python django django-orm






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 16 '18 at 16:19







Aurélien

















asked Nov 15 '18 at 19:45









AurélienAurélien

19713




19713













  • can you please share your models?

    – ruddra
    Nov 15 '18 at 19:47











  • I have edited my question including the model

    – Aurélien
    Nov 15 '18 at 19:58



















  • can you please share your models?

    – ruddra
    Nov 15 '18 at 19:47











  • I have edited my question including the model

    – Aurélien
    Nov 15 '18 at 19:58

















can you please share your models?

– ruddra
Nov 15 '18 at 19:47





can you please share your models?

– ruddra
Nov 15 '18 at 19:47













I have edited my question including the model

– Aurélien
Nov 15 '18 at 19:58





I have edited my question including the model

– Aurélien
Nov 15 '18 at 19:58












2 Answers
2






active

oldest

votes


















2














Well, you wouldn't do it with Counter, that's a Python class for counting distinct items in an existing Python collection. You need to use the Django Count function:



from django.db.models import Count

referer_users.values('email').annotate(refered_num=Count('email'))





share|improve this answer
























  • Thanks for your answer. I have tried this on the first place, but refered_num was equal to 1 for every referer_users. Maybe should try this one more time.

    – Aurélien
    Nov 15 '18 at 20:01











  • Unfortunatly, it does not work. I have edited my question accordingly.

    – Aurélien
    Nov 16 '18 at 8:30











  • Hello Daniel, I tried to reformulate my problem. I think I was not clear enough.

    – Aurélien
    Nov 16 '18 at 16:20



















0














from django.db.models import Count

referer_users = referer_users.order_by()

referer_users = referer_users.values('email')

referer_users = referer_users.annotate(refered_num=Count('email'))


I think you are adding order_by('id'), and that's why it is giving 1. When order is added it also added to group by fields.






share|improve this answer
























  • I am not using order_by()

    – Aurélien
    Nov 16 '18 at 9:42











  • you may add default ordering in meta class

    – Tolqinbek Isoqov
    Nov 16 '18 at 9:47











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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









2














Well, you wouldn't do it with Counter, that's a Python class for counting distinct items in an existing Python collection. You need to use the Django Count function:



from django.db.models import Count

referer_users.values('email').annotate(refered_num=Count('email'))





share|improve this answer
























  • Thanks for your answer. I have tried this on the first place, but refered_num was equal to 1 for every referer_users. Maybe should try this one more time.

    – Aurélien
    Nov 15 '18 at 20:01











  • Unfortunatly, it does not work. I have edited my question accordingly.

    – Aurélien
    Nov 16 '18 at 8:30











  • Hello Daniel, I tried to reformulate my problem. I think I was not clear enough.

    – Aurélien
    Nov 16 '18 at 16:20
















2














Well, you wouldn't do it with Counter, that's a Python class for counting distinct items in an existing Python collection. You need to use the Django Count function:



from django.db.models import Count

referer_users.values('email').annotate(refered_num=Count('email'))





share|improve this answer
























  • Thanks for your answer. I have tried this on the first place, but refered_num was equal to 1 for every referer_users. Maybe should try this one more time.

    – Aurélien
    Nov 15 '18 at 20:01











  • Unfortunatly, it does not work. I have edited my question accordingly.

    – Aurélien
    Nov 16 '18 at 8:30











  • Hello Daniel, I tried to reformulate my problem. I think I was not clear enough.

    – Aurélien
    Nov 16 '18 at 16:20














2












2








2







Well, you wouldn't do it with Counter, that's a Python class for counting distinct items in an existing Python collection. You need to use the Django Count function:



from django.db.models import Count

referer_users.values('email').annotate(refered_num=Count('email'))





share|improve this answer













Well, you wouldn't do it with Counter, that's a Python class for counting distinct items in an existing Python collection. You need to use the Django Count function:



from django.db.models import Count

referer_users.values('email').annotate(refered_num=Count('email'))






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 15 '18 at 19:52









Daniel RosemanDaniel Roseman

448k41581636




448k41581636













  • Thanks for your answer. I have tried this on the first place, but refered_num was equal to 1 for every referer_users. Maybe should try this one more time.

    – Aurélien
    Nov 15 '18 at 20:01











  • Unfortunatly, it does not work. I have edited my question accordingly.

    – Aurélien
    Nov 16 '18 at 8:30











  • Hello Daniel, I tried to reformulate my problem. I think I was not clear enough.

    – Aurélien
    Nov 16 '18 at 16:20



















  • Thanks for your answer. I have tried this on the first place, but refered_num was equal to 1 for every referer_users. Maybe should try this one more time.

    – Aurélien
    Nov 15 '18 at 20:01











  • Unfortunatly, it does not work. I have edited my question accordingly.

    – Aurélien
    Nov 16 '18 at 8:30











  • Hello Daniel, I tried to reformulate my problem. I think I was not clear enough.

    – Aurélien
    Nov 16 '18 at 16:20

















Thanks for your answer. I have tried this on the first place, but refered_num was equal to 1 for every referer_users. Maybe should try this one more time.

– Aurélien
Nov 15 '18 at 20:01





Thanks for your answer. I have tried this on the first place, but refered_num was equal to 1 for every referer_users. Maybe should try this one more time.

– Aurélien
Nov 15 '18 at 20:01













Unfortunatly, it does not work. I have edited my question accordingly.

– Aurélien
Nov 16 '18 at 8:30





Unfortunatly, it does not work. I have edited my question accordingly.

– Aurélien
Nov 16 '18 at 8:30













Hello Daniel, I tried to reformulate my problem. I think I was not clear enough.

– Aurélien
Nov 16 '18 at 16:20





Hello Daniel, I tried to reformulate my problem. I think I was not clear enough.

– Aurélien
Nov 16 '18 at 16:20













0














from django.db.models import Count

referer_users = referer_users.order_by()

referer_users = referer_users.values('email')

referer_users = referer_users.annotate(refered_num=Count('email'))


I think you are adding order_by('id'), and that's why it is giving 1. When order is added it also added to group by fields.






share|improve this answer
























  • I am not using order_by()

    – Aurélien
    Nov 16 '18 at 9:42











  • you may add default ordering in meta class

    – Tolqinbek Isoqov
    Nov 16 '18 at 9:47
















0














from django.db.models import Count

referer_users = referer_users.order_by()

referer_users = referer_users.values('email')

referer_users = referer_users.annotate(refered_num=Count('email'))


I think you are adding order_by('id'), and that's why it is giving 1. When order is added it also added to group by fields.






share|improve this answer
























  • I am not using order_by()

    – Aurélien
    Nov 16 '18 at 9:42











  • you may add default ordering in meta class

    – Tolqinbek Isoqov
    Nov 16 '18 at 9:47














0












0








0







from django.db.models import Count

referer_users = referer_users.order_by()

referer_users = referer_users.values('email')

referer_users = referer_users.annotate(refered_num=Count('email'))


I think you are adding order_by('id'), and that's why it is giving 1. When order is added it also added to group by fields.






share|improve this answer













from django.db.models import Count

referer_users = referer_users.order_by()

referer_users = referer_users.values('email')

referer_users = referer_users.annotate(refered_num=Count('email'))


I think you are adding order_by('id'), and that's why it is giving 1. When order is added it also added to group by fields.







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 16 '18 at 9:33









Tolqinbek IsoqovTolqinbek Isoqov

696




696













  • I am not using order_by()

    – Aurélien
    Nov 16 '18 at 9:42











  • you may add default ordering in meta class

    – Tolqinbek Isoqov
    Nov 16 '18 at 9:47



















  • I am not using order_by()

    – Aurélien
    Nov 16 '18 at 9:42











  • you may add default ordering in meta class

    – Tolqinbek Isoqov
    Nov 16 '18 at 9:47

















I am not using order_by()

– Aurélien
Nov 16 '18 at 9:42





I am not using order_by()

– Aurélien
Nov 16 '18 at 9:42













you may add default ordering in meta class

– Tolqinbek Isoqov
Nov 16 '18 at 9:47





you may add default ordering in meta class

– Tolqinbek Isoqov
Nov 16 '18 at 9:47


















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