JS Global variable not recognized












1















I set my variable as a global variable so google will be able to read the name the user enter in actions on google. in "agent.add", I added in what I want google to read out.



However, It just keeps reading as your name is [object Oject] instead of the given name. This is my code in my index.js.



var myName = {}; 

exports.dialogflowFirebaseFulfillment = functions.https.onRequest((request, response) => {
const agent = new WebhookClient({ request, response });

function naming(agent){
myName = agent.parameters.givenName;
agent.add(`your name is ${myName}`);
}









share|improve this question

























  • What do you receive when you do a console.dir(myName) before your agent.add(.... statement?

    – David R
    Nov 16 '18 at 8:04











  • Hi, @DavidR, it still prints out your name is [object Oject]

    – ALABADAMA
    Nov 16 '18 at 8:09











  • No, you need to open up your DevTools (Press F12 to open up) in your chrome and navigate to console and post what you see there.

    – David R
    Nov 16 '18 at 8:14













  • It prints [Object Object] , this means it's accessible, Have you tried to stringify it? Try to use agent.add(your name is ${JSON.stringify(myName)});.

    – cнŝdk
    Nov 16 '18 at 8:15













  • And what's your agent data structure?

    – cнŝdk
    Nov 16 '18 at 8:24
















1















I set my variable as a global variable so google will be able to read the name the user enter in actions on google. in "agent.add", I added in what I want google to read out.



However, It just keeps reading as your name is [object Oject] instead of the given name. This is my code in my index.js.



var myName = {}; 

exports.dialogflowFirebaseFulfillment = functions.https.onRequest((request, response) => {
const agent = new WebhookClient({ request, response });

function naming(agent){
myName = agent.parameters.givenName;
agent.add(`your name is ${myName}`);
}









share|improve this question

























  • What do you receive when you do a console.dir(myName) before your agent.add(.... statement?

    – David R
    Nov 16 '18 at 8:04











  • Hi, @DavidR, it still prints out your name is [object Oject]

    – ALABADAMA
    Nov 16 '18 at 8:09











  • No, you need to open up your DevTools (Press F12 to open up) in your chrome and navigate to console and post what you see there.

    – David R
    Nov 16 '18 at 8:14













  • It prints [Object Object] , this means it's accessible, Have you tried to stringify it? Try to use agent.add(your name is ${JSON.stringify(myName)});.

    – cнŝdk
    Nov 16 '18 at 8:15













  • And what's your agent data structure?

    – cнŝdk
    Nov 16 '18 at 8:24














1












1








1








I set my variable as a global variable so google will be able to read the name the user enter in actions on google. in "agent.add", I added in what I want google to read out.



However, It just keeps reading as your name is [object Oject] instead of the given name. This is my code in my index.js.



var myName = {}; 

exports.dialogflowFirebaseFulfillment = functions.https.onRequest((request, response) => {
const agent = new WebhookClient({ request, response });

function naming(agent){
myName = agent.parameters.givenName;
agent.add(`your name is ${myName}`);
}









share|improve this question
















I set my variable as a global variable so google will be able to read the name the user enter in actions on google. in "agent.add", I added in what I want google to read out.



However, It just keeps reading as your name is [object Oject] instead of the given name. This is my code in my index.js.



var myName = {}; 

exports.dialogflowFirebaseFulfillment = functions.https.onRequest((request, response) => {
const agent = new WebhookClient({ request, response });

function naming(agent){
myName = agent.parameters.givenName;
agent.add(`your name is ${myName}`);
}






node.js json actions-on-google






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 16 '18 at 8:06







ALABADAMA

















asked Nov 16 '18 at 7:53









ALABADAMAALABADAMA

436




436













  • What do you receive when you do a console.dir(myName) before your agent.add(.... statement?

    – David R
    Nov 16 '18 at 8:04











  • Hi, @DavidR, it still prints out your name is [object Oject]

    – ALABADAMA
    Nov 16 '18 at 8:09











  • No, you need to open up your DevTools (Press F12 to open up) in your chrome and navigate to console and post what you see there.

    – David R
    Nov 16 '18 at 8:14













  • It prints [Object Object] , this means it's accessible, Have you tried to stringify it? Try to use agent.add(your name is ${JSON.stringify(myName)});.

    – cнŝdk
    Nov 16 '18 at 8:15













  • And what's your agent data structure?

    – cнŝdk
    Nov 16 '18 at 8:24



















  • What do you receive when you do a console.dir(myName) before your agent.add(.... statement?

    – David R
    Nov 16 '18 at 8:04











  • Hi, @DavidR, it still prints out your name is [object Oject]

    – ALABADAMA
    Nov 16 '18 at 8:09











  • No, you need to open up your DevTools (Press F12 to open up) in your chrome and navigate to console and post what you see there.

    – David R
    Nov 16 '18 at 8:14













  • It prints [Object Object] , this means it's accessible, Have you tried to stringify it? Try to use agent.add(your name is ${JSON.stringify(myName)});.

    – cнŝdk
    Nov 16 '18 at 8:15













  • And what's your agent data structure?

    – cнŝdk
    Nov 16 '18 at 8:24

















What do you receive when you do a console.dir(myName) before your agent.add(.... statement?

– David R
Nov 16 '18 at 8:04





What do you receive when you do a console.dir(myName) before your agent.add(.... statement?

– David R
Nov 16 '18 at 8:04













Hi, @DavidR, it still prints out your name is [object Oject]

– ALABADAMA
Nov 16 '18 at 8:09





Hi, @DavidR, it still prints out your name is [object Oject]

– ALABADAMA
Nov 16 '18 at 8:09













No, you need to open up your DevTools (Press F12 to open up) in your chrome and navigate to console and post what you see there.

– David R
Nov 16 '18 at 8:14







No, you need to open up your DevTools (Press F12 to open up) in your chrome and navigate to console and post what you see there.

– David R
Nov 16 '18 at 8:14















It prints [Object Object] , this means it's accessible, Have you tried to stringify it? Try to use agent.add(your name is ${JSON.stringify(myName)});.

– cнŝdk
Nov 16 '18 at 8:15







It prints [Object Object] , this means it's accessible, Have you tried to stringify it? Try to use agent.add(your name is ${JSON.stringify(myName)});.

– cнŝdk
Nov 16 '18 at 8:15















And what's your agent data structure?

– cнŝdk
Nov 16 '18 at 8:24





And what's your agent data structure?

– cнŝdk
Nov 16 '18 at 8:24












1 Answer
1






active

oldest

votes


















0














You probably shouldn't make that a global variable, particularly since you're just using it locally.



Something like this should work:



function naming(agent){
let myName = agent.parameters.givenName;
agent.add(`your name is ${myName}`);
}





share|improve this answer























    Your Answer






    StackExchange.ifUsing("editor", function () {
    StackExchange.using("externalEditor", function () {
    StackExchange.using("snippets", function () {
    StackExchange.snippets.init();
    });
    });
    }, "code-snippets");

    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "1"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });














    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53333569%2fjs-global-variable-not-recognized%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    You probably shouldn't make that a global variable, particularly since you're just using it locally.



    Something like this should work:



    function naming(agent){
    let myName = agent.parameters.givenName;
    agent.add(`your name is ${myName}`);
    }





    share|improve this answer




























      0














      You probably shouldn't make that a global variable, particularly since you're just using it locally.



      Something like this should work:



      function naming(agent){
      let myName = agent.parameters.givenName;
      agent.add(`your name is ${myName}`);
      }





      share|improve this answer


























        0












        0








        0







        You probably shouldn't make that a global variable, particularly since you're just using it locally.



        Something like this should work:



        function naming(agent){
        let myName = agent.parameters.givenName;
        agent.add(`your name is ${myName}`);
        }





        share|improve this answer













        You probably shouldn't make that a global variable, particularly since you're just using it locally.



        Something like this should work:



        function naming(agent){
        let myName = agent.parameters.givenName;
        agent.add(`your name is ${myName}`);
        }






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 16 '18 at 20:49









        PrisonerPrisoner

        33.5k23058




        33.5k23058






























            draft saved

            draft discarded




















































            Thanks for contributing an answer to Stack Overflow!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53333569%2fjs-global-variable-not-recognized%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            這個網誌中的熱門文章

            Tangent Lines Diagram Along Smooth Curve

            Yusuf al-Mu'taman ibn Hud

            Zucchini