How can I add new sections to an existing card on Gmail Addon?

I'm actually trying to create a Chat interface in Gmail using Add-ons with App Script. All the interactions are working. But it keeps navigating to different cards rather than have it all in one card. Like in Google Tasks.

Is there a way in which I can just keep adding sections to the same card dynamically to create a chat like interface.

I assume if it is possible on Google Tasks Add-on it should be possible in this case too. Please help me out as it is a necessary requirement.

edited Dec 11 '18 at 23:06

Kara

3,936104152

asked Nov 12 '18 at 7:52

Akhil

add a comment |

Is there a way in which I can just keep adding sections to the same card dynamically to create a chat like interface.

I assume if it is possible on Google Tasks Add-on it should be possible in this case too. Please help me out as it is a necessary requirement.

edited Dec 11 '18 at 23:06

Kara

3,936104152

asked Nov 12 '18 at 7:52

Akhil

add a comment |

Is there a way in which I can just keep adding sections to the same card dynamically to create a chat like interface.

I assume if it is possible on Google Tasks Add-on it should be possible in this case too. Please help me out as it is a necessary requirement.

edited Dec 11 '18 at 23:06

Kara

3,936104152

asked Nov 12 '18 at 7:52

Akhil

Is there a way in which I can just keep adding sections to the same card dynamically to create a chat like interface.

I assume if it is possible on Google Tasks Add-on it should be possible in this case too. Please help me out as it is a necessary requirement.

google-apps-script gmail-addons

edited Dec 11 '18 at 23:06

Kara

3,936104152

asked Nov 12 '18 at 7:52

Akhil

edited Dec 11 '18 at 23:06

Kara

3,936104152

asked Nov 12 '18 at 7:52

Akhil

edited Dec 11 '18 at 23:06

Kara

3,936104152

edited Dec 11 '18 at 23:06

Kara

3,936104152

edited Dec 11 '18 at 23:06

Kara

3,936104152

asked Nov 12 '18 at 7:52

Akhil

asked Nov 12 '18 at 7:52

Akhil

asked Nov 12 '18 at 7:52

Akhil

add a comment |

1 Answer
1

active

oldest

votes

Update :
Try this

    function renderRootCard(){

        var card = CardService.newCardBuilder();

        var section = CardService.newCardSection();

        var btnSet = CardService.newButtonSet();

        section.addWidget(CardService.newTextParagraph().setText("old widget"));

        section.addWidget(btnSet.addButton(addTaskBtn));

        card.addSection(section);



        var addTask = CardService.newAction().setFunctionName("addTask");

        var addTaskBtn = CardService.newTextButton()

            .setText("Add Task")

            .setOnClickAction(addTask); 





        return card.build();

    }



    function addTask(e) {

        var card = CardService.newCardBuilder();

        var section = CardService.newCardSection();

        var btnSet = CardService.newButtonSet();

        section.addWidget(CardService.newTextParagraph().setText("old widget"));

        section.addWidget(btnSet.addButton(addTaskBtn));

        section.addWidget(CardService.newTextParagraph().setText("new widget"));

var addTask = CardService.newAction().setFunctionName("addTask");

        var addTaskBtn = CardService.newTextButton()

            .setText("Add Task")

            .setOnClickAction(addTask); 

        return CardService.newNavigation().updateCard(card.build());

    }

Original answer:

In short: Possible

I understand what you are trying to do. This involves replacing the current card by updating it with a new card that has the same widgets as that of current card and additional widgets that are required.

Let's say, you are building a to-do app. When you click add task(say), you just create the same card, add some widgets and replace the current card with a new one.

edited Nov 13 '18 at 13:37

answered Nov 12 '18 at 12:22

Hari Balaji

28815

Yes! Exactly what I'm trying to achieve. But I haven't come across a code sample or a skeleton. Is it possible for you to share a sample?
– Akhil
Nov 13 '18 at 6:44

I've added based on your request.
– Hari Balaji
Nov 13 '18 at 13:40

Doesn't this code work also without the updateCard method? Also the main bit for me is how do I store or pass content of an existing card.
– Akhil
Nov 14 '18 at 7:13

Akhil, the code has updateCard method . Moreover, I could not find any straight forward way to do this, rather than redrawing the old card again, while doing an update. In order to persist the state of the old card , pass the state of the card to the new card through setParameters method. If CardService allows us the pass the Card as a parameter, we would not have to do this.
– Hari Balaji
Nov 14 '18 at 7:16

If I have to redraw the whole conversation then first I need to store them separately and recreate the card each time. setParameters doesn't work as well. Have tried that too.
– Akhil
Nov 14 '18 at 7:32

|
show 2 more comments

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

Update :
Try this

    function renderRootCard(){

        var card = CardService.newCardBuilder();

        var section = CardService.newCardSection();

        var btnSet = CardService.newButtonSet();

        section.addWidget(CardService.newTextParagraph().setText("old widget"));

        section.addWidget(btnSet.addButton(addTaskBtn));

        card.addSection(section);



        var addTask = CardService.newAction().setFunctionName("addTask");

        var addTaskBtn = CardService.newTextButton()

            .setText("Add Task")

            .setOnClickAction(addTask); 





        return card.build();

    }



    function addTask(e) {

        var card = CardService.newCardBuilder();

        var section = CardService.newCardSection();

        var btnSet = CardService.newButtonSet();

        section.addWidget(CardService.newTextParagraph().setText("old widget"));

        section.addWidget(btnSet.addButton(addTaskBtn));

        section.addWidget(CardService.newTextParagraph().setText("new widget"));

var addTask = CardService.newAction().setFunctionName("addTask");

        var addTaskBtn = CardService.newTextButton()

            .setText("Add Task")

            .setOnClickAction(addTask); 

        return CardService.newNavigation().updateCard(card.build());

    }

Original answer:

In short: Possible

Let's say, you are building a to-do app. When you click add task(say), you just create the same card, add some widgets and replace the current card with a new one.

edited Nov 13 '18 at 13:37

answered Nov 12 '18 at 12:22

Hari Balaji

28815

Yes! Exactly what I'm trying to achieve. But I haven't come across a code sample or a skeleton. Is it possible for you to share a sample?
– Akhil
Nov 13 '18 at 6:44

I've added based on your request.
– Hari Balaji
Nov 13 '18 at 13:40

Doesn't this code work also without the updateCard method? Also the main bit for me is how do I store or pass content of an existing card.
– Akhil
Nov 14 '18 at 7:13

Akhil, the code has updateCard method . Moreover, I could not find any straight forward way to do this, rather than redrawing the old card again, while doing an update. In order to persist the state of the old card , pass the state of the card to the new card through setParameters method. If CardService allows us the pass the Card as a parameter, we would not have to do this.
– Hari Balaji
Nov 14 '18 at 7:16

If I have to redraw the whole conversation then first I need to store them separately and recreate the card each time. setParameters doesn't work as well. Have tried that too.
– Akhil
Nov 14 '18 at 7:32

|
show 2 more comments

Update :
Try this

    function renderRootCard(){

        var card = CardService.newCardBuilder();

        var section = CardService.newCardSection();

        var btnSet = CardService.newButtonSet();

        section.addWidget(CardService.newTextParagraph().setText("old widget"));

        section.addWidget(btnSet.addButton(addTaskBtn));

        card.addSection(section);



        var addTask = CardService.newAction().setFunctionName("addTask");

        var addTaskBtn = CardService.newTextButton()

            .setText("Add Task")

            .setOnClickAction(addTask); 





        return card.build();

    }



    function addTask(e) {

        var card = CardService.newCardBuilder();

        var section = CardService.newCardSection();

        var btnSet = CardService.newButtonSet();

        section.addWidget(CardService.newTextParagraph().setText("old widget"));

        section.addWidget(btnSet.addButton(addTaskBtn));

        section.addWidget(CardService.newTextParagraph().setText("new widget"));

var addTask = CardService.newAction().setFunctionName("addTask");

        var addTaskBtn = CardService.newTextButton()

            .setText("Add Task")

            .setOnClickAction(addTask); 

        return CardService.newNavigation().updateCard(card.build());

    }

Original answer:

In short: Possible

Let's say, you are building a to-do app. When you click add task(say), you just create the same card, add some widgets and replace the current card with a new one.

edited Nov 13 '18 at 13:37

answered Nov 12 '18 at 12:22

Hari Balaji

28815

Yes! Exactly what I'm trying to achieve. But I haven't come across a code sample or a skeleton. Is it possible for you to share a sample?
– Akhil
Nov 13 '18 at 6:44

I've added based on your request.
– Hari Balaji
Nov 13 '18 at 13:40

Doesn't this code work also without the updateCard method? Also the main bit for me is how do I store or pass content of an existing card.
– Akhil
Nov 14 '18 at 7:13

Akhil, the code has updateCard method . Moreover, I could not find any straight forward way to do this, rather than redrawing the old card again, while doing an update. In order to persist the state of the old card , pass the state of the card to the new card through setParameters method. If CardService allows us the pass the Card as a parameter, we would not have to do this.
– Hari Balaji
Nov 14 '18 at 7:16

If I have to redraw the whole conversation then first I need to store them separately and recreate the card each time. setParameters doesn't work as well. Have tried that too.
– Akhil
Nov 14 '18 at 7:32

|
show 2 more comments

Update :
Try this

    function renderRootCard(){

        var card = CardService.newCardBuilder();

        var section = CardService.newCardSection();

        var btnSet = CardService.newButtonSet();

        section.addWidget(CardService.newTextParagraph().setText("old widget"));

        section.addWidget(btnSet.addButton(addTaskBtn));

        card.addSection(section);



        var addTask = CardService.newAction().setFunctionName("addTask");

        var addTaskBtn = CardService.newTextButton()

            .setText("Add Task")

            .setOnClickAction(addTask); 





        return card.build();

    }



    function addTask(e) {

        var card = CardService.newCardBuilder();

        var section = CardService.newCardSection();

        var btnSet = CardService.newButtonSet();

        section.addWidget(CardService.newTextParagraph().setText("old widget"));

        section.addWidget(btnSet.addButton(addTaskBtn));

        section.addWidget(CardService.newTextParagraph().setText("new widget"));

var addTask = CardService.newAction().setFunctionName("addTask");

        var addTaskBtn = CardService.newTextButton()

            .setText("Add Task")

            .setOnClickAction(addTask); 

        return CardService.newNavigation().updateCard(card.build());

    }

Original answer:

In short: Possible

Let's say, you are building a to-do app. When you click add task(say), you just create the same card, add some widgets and replace the current card with a new one.

edited Nov 13 '18 at 13:37

answered Nov 12 '18 at 12:22

Hari Balaji

28815

Update :
Try this

    function renderRootCard(){

        var card = CardService.newCardBuilder();

        var section = CardService.newCardSection();

        var btnSet = CardService.newButtonSet();

        section.addWidget(CardService.newTextParagraph().setText("old widget"));

        section.addWidget(btnSet.addButton(addTaskBtn));

        card.addSection(section);



        var addTask = CardService.newAction().setFunctionName("addTask");

        var addTaskBtn = CardService.newTextButton()

            .setText("Add Task")

            .setOnClickAction(addTask); 





        return card.build();

    }



    function addTask(e) {

        var card = CardService.newCardBuilder();

        var section = CardService.newCardSection();

        var btnSet = CardService.newButtonSet();

        section.addWidget(CardService.newTextParagraph().setText("old widget"));

        section.addWidget(btnSet.addButton(addTaskBtn));

        section.addWidget(CardService.newTextParagraph().setText("new widget"));

var addTask = CardService.newAction().setFunctionName("addTask");

        var addTaskBtn = CardService.newTextButton()

            .setText("Add Task")

            .setOnClickAction(addTask); 

        return CardService.newNavigation().updateCard(card.build());

    }

Original answer:

In short: Possible

Let's say, you are building a to-do app. When you click add task(say), you just create the same card, add some widgets and replace the current card with a new one.

edited Nov 13 '18 at 13:37

answered Nov 12 '18 at 12:22

Hari Balaji

28815

edited Nov 13 '18 at 13:37

answered Nov 12 '18 at 12:22

Hari Balaji

28815

answered Nov 12 '18 at 12:22

Hari Balaji

28815

answered Nov 12 '18 at 12:22

Hari Balaji

28815

Yes! Exactly what I'm trying to achieve. But I haven't come across a code sample or a skeleton. Is it possible for you to share a sample?
– Akhil
Nov 13 '18 at 6:44

I've added based on your request.
– Hari Balaji
Nov 13 '18 at 13:40

Doesn't this code work also without the updateCard method? Also the main bit for me is how do I store or pass content of an existing card.
– Akhil
Nov 14 '18 at 7:13

Akhil, the code has updateCard method . Moreover, I could not find any straight forward way to do this, rather than redrawing the old card again, while doing an update. In order to persist the state of the old card , pass the state of the card to the new card through setParameters method. If CardService allows us the pass the Card as a parameter, we would not have to do this.
– Hari Balaji
Nov 14 '18 at 7:16

If I have to redraw the whole conversation then first I need to store them separately and recreate the card each time. setParameters doesn't work as well. Have tried that too.
– Akhil
Nov 14 '18 at 7:32

|
show 2 more comments

Yes! Exactly what I'm trying to achieve. But I haven't come across a code sample or a skeleton. Is it possible for you to share a sample?
– Akhil
Nov 13 '18 at 6:44

I've added based on your request.
– Hari Balaji
Nov 13 '18 at 13:40

Doesn't this code work also without the updateCard method? Also the main bit for me is how do I store or pass content of an existing card.
– Akhil
Nov 14 '18 at 7:13

Akhil, the code has updateCard method . Moreover, I could not find any straight forward way to do this, rather than redrawing the old card again, while doing an update. In order to persist the state of the old card , pass the state of the card to the new card through setParameters method. If CardService allows us the pass the Card as a parameter, we would not have to do this.
– Hari Balaji
Nov 14 '18 at 7:16

If I have to redraw the whole conversation then first I need to store them separately and recreate the card each time. setParameters doesn't work as well. Have tried that too.
– Akhil
Nov 14 '18 at 7:32

Yes! Exactly what I'm trying to achieve. But I haven't come across a code sample or a skeleton. Is it possible for you to share a sample?
– Akhil
Nov 13 '18 at 6:44

I've added based on your request.
– Hari Balaji
Nov 13 '18 at 13:40

Doesn't this code work also without the updateCard method? Also the main bit for me is how do I store or pass content of an existing card.
– Akhil
Nov 14 '18 at 7:13

Akhil, the code has updateCard method . Moreover, I could not find any straight forward way to do this, rather than redrawing the old card again, while doing an update. In order to persist the state of the old card , pass the state of the card to the new card through setParameters method. If CardService allows us the pass the Card as a parameter, we would not have to do this.
– Hari Balaji
Nov 14 '18 at 7:16

If I have to redraw the whole conversation then first I need to store them separately and recreate the card each time. setParameters doesn't work as well. Have tried that too.
– Akhil
Nov 14 '18 at 7:32

|
show 2 more comments

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