Replace array of objects

-1

I have below array of objects

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

]

I have four dayOfWeek (1,2,5,7). Now I need to push the remaining three (3,4,6) with the dummy object ({ home1: "05:30", dayOfWeek: 7, away: "09:30"})

Now the logical part is I don't know which dayOfWeek are present in the array. There may be only one, two, three or blank. I need to push 7 days in that array every time.

How this can be done? Please suggest me the best way

Thank you!!!

asked Nov 12 '18 at 7:45

Dark Knight

84115

Does it need to be in order?
– CertainPerformance
Nov 12 '18 at 7:49

@CertainPerformance No order can be anything.
– Dark Knight
Nov 12 '18 at 7:51

you can loop through current array and store daysOfWeek in an array then loop the other 7 days dummy array and check if its in the previous array then do not need to insert that days. hopes you get that
– Tuhin
Nov 12 '18 at 7:53

add a comment |

-1

I have below array of objects

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

]

I have four dayOfWeek (1,2,5,7). Now I need to push the remaining three (3,4,6) with the dummy object ({ home1: "05:30", dayOfWeek: 7, away: "09:30"})

Now the logical part is I don't know which dayOfWeek are present in the array. There may be only one, two, three or blank. I need to push 7 days in that array every time.

How this can be done? Please suggest me the best way

Thank you!!!

asked Nov 12 '18 at 7:45

Dark Knight

84115

Does it need to be in order?
– CertainPerformance
Nov 12 '18 at 7:49

@CertainPerformance No order can be anything.
– Dark Knight
Nov 12 '18 at 7:51

you can loop through current array and store daysOfWeek in an array then loop the other 7 days dummy array and check if its in the previous array then do not need to insert that days. hopes you get that
– Tuhin
Nov 12 '18 at 7:53

add a comment |

-1

I have below array of objects

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

]

I have four dayOfWeek (1,2,5,7). Now I need to push the remaining three (3,4,6) with the dummy object ({ home1: "05:30", dayOfWeek: 7, away: "09:30"})

Now the logical part is I don't know which dayOfWeek are present in the array. There may be only one, two, three or blank. I need to push 7 days in that array every time.

How this can be done? Please suggest me the best way

Thank you!!!

asked Nov 12 '18 at 7:45

Dark Knight

84115

I have below array of objects

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

]

I have four dayOfWeek (1,2,5,7). Now I need to push the remaining three (3,4,6) with the dummy object ({ home1: "05:30", dayOfWeek: 7, away: "09:30"})

Now the logical part is I don't know which dayOfWeek are present in the array. There may be only one, two, three or blank. I need to push 7 days in that array every time.

How this can be done? Please suggest me the best way

Thank you!!!

javascript arrays lodash

asked Nov 12 '18 at 7:45

Dark Knight

84115

asked Nov 12 '18 at 7:45

Dark Knight

84115

asked Nov 12 '18 at 7:45

Dark Knight

84115

asked Nov 12 '18 at 7:45

Dark Knight

84115

asked Nov 12 '18 at 7:45

Dark Knight

84115

Does it need to be in order?
– CertainPerformance
Nov 12 '18 at 7:49

@CertainPerformance No order can be anything.
– Dark Knight
Nov 12 '18 at 7:51

you can loop through current array and store daysOfWeek in an array then loop the other 7 days dummy array and check if its in the previous array then do not need to insert that days. hopes you get that
– Tuhin
Nov 12 '18 at 7:53

add a comment |

Does it need to be in order?
– CertainPerformance
Nov 12 '18 at 7:49

@CertainPerformance No order can be anything.
– Dark Knight
Nov 12 '18 at 7:51

you can loop through current array and store daysOfWeek in an array then loop the other 7 days dummy array and check if its in the previous array then do not need to insert that days. hopes you get that
– Tuhin
Nov 12 '18 at 7:53

Does it need to be in order?
– CertainPerformance
Nov 12 '18 at 7:49

@CertainPerformance No order can be anything.
– Dark Knight
Nov 12 '18 at 7:51

you can loop through current array and store daysOfWeek in an array then loop the other 7 days dummy array and check if its in the previous array then do not need to insert that days. hopes you get that
– Tuhin
Nov 12 '18 at 7:53

add a comment |

4 Answers
4

active

oldest

votes

One option would be to make a Set of the days contained in the array so far, then iterate from 1 to 7, pushing a new object to the array with that day if it's not contained in the set:

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

];

const dummy = { home1: "05:30", away: "09:30" };

const days = new Set(array.map(({ dayOfWeek }) => dayOfWeek));

for (let i = 1; i <= 7; i++) {

  if (!days.has(i)) array.push({ ...dummy, dayOfWeek: i });

}

console.log(array);

I used a Set to reduce complexity, but I suppose if you only ever need 7 objects, it doesn't matter much, you could use find instead without creating a collection beforehand

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

];

const dummy = { home1: "05:30", away: "09:30" };

for (let i = 1; i <= 7; i++) {

  if (!array.find(({ dayOfWeek }) => dayOfWeek === i)) {

    array.push({ ...dummy, dayOfWeek: i });

  }

}

console.log(array);

answered Nov 12 '18 at 7:52

CertainPerformance

76k143761

add a comment |

Use Array.reduce to create a set of existing days. Now iterate and check whether there is an entry in set, if not push the object in array.

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

];

let daysSet = array.reduce((a,c) => a.add(c.dayOfWeek), new Set());

let obj = { home1: "16:30", dayOfWeek: 7, away: "09:30"};

for(let i = 1; i <=7; i++) {

  if(!daysSet.has(i)) array.push(Object.assign({}, obj, {dayOfWeek:i}));

}

console.log(array);

answered Nov 12 '18 at 7:56

Nikhil Aggarwal

23.7k32647

Thank you I didn't test it but I made an upvote because the first answer is worked for me
– Dark Knight
Nov 12 '18 at 8:06

Could you please upvote my question. Else I will be blocked by asking
– Dark Knight
Nov 12 '18 at 9:09

add a comment |

You can use "Array.from" and loop 7 times like below.

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

]



// sort array by day of week. Ignore this step if you are sure it will be sorted always

array.sort((a,b) => a.dayOfWeek - b.dayOfWeek)



var result = Array.from({ length: 7}

    , (_,i) => array[0].dayOfWeek == i + 1

                ? array.shift()

                : { home1: "05:30", dayOfWeek: i + 1, away: "09:30"})

                

console.log(result)

edited Nov 12 '18 at 8:02

answered Nov 12 '18 at 7:54

Nitish Narang

2,948815

add a comment |

You can first get all the dayOfWeek present in a array with map(). Then use for loop to insert the dayOfWeek by checking whether that is present in the array or not.

You can try the following way:

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

]

let exist = array.map(d => d.dayOfWeek);



for(let i = 1; i<=7; i++){

  let dummy = { home1: "05:30", dayOfWeek: 7, away: "09:30"};

  dummy.dayOfWeek = i;

  if(!exist.includes(i))

   array.splice(i-1, 0, dummy);

}

console.log(array);

edited Nov 12 '18 at 8:12

answered Nov 12 '18 at 8:04

Mamun

25k71428

Thank you I didn't test it but I made an upvote
– Dark Knight
Nov 12 '18 at 8:06

@DarkKnight, you are most welcome....you can test whenever you can:)
– Mamun
Nov 12 '18 at 8:09

Could you please upvote my question. Else I will be blocked by asking
– Dark Knight
Nov 12 '18 at 9:09

add a comment |

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4 Answers
4

active

oldest

votes

4 Answers
4

active

oldest

votes

One option would be to make a Set of the days contained in the array so far, then iterate from 1 to 7, pushing a new object to the array with that day if it's not contained in the set:

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

];

const dummy = { home1: "05:30", away: "09:30" };

const days = new Set(array.map(({ dayOfWeek }) => dayOfWeek));

for (let i = 1; i <= 7; i++) {

  if (!days.has(i)) array.push({ ...dummy, dayOfWeek: i });

}

console.log(array);

I used a Set to reduce complexity, but I suppose if you only ever need 7 objects, it doesn't matter much, you could use find instead without creating a collection beforehand

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

];

const dummy = { home1: "05:30", away: "09:30" };

for (let i = 1; i <= 7; i++) {

  if (!array.find(({ dayOfWeek }) => dayOfWeek === i)) {

    array.push({ ...dummy, dayOfWeek: i });

  }

}

console.log(array);

answered Nov 12 '18 at 7:52

CertainPerformance

76k143761

add a comment |

One option would be to make a Set of the days contained in the array so far, then iterate from 1 to 7, pushing a new object to the array with that day if it's not contained in the set:

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

];

const dummy = { home1: "05:30", away: "09:30" };

const days = new Set(array.map(({ dayOfWeek }) => dayOfWeek));

for (let i = 1; i <= 7; i++) {

  if (!days.has(i)) array.push({ ...dummy, dayOfWeek: i });

}

console.log(array);

I used a Set to reduce complexity, but I suppose if you only ever need 7 objects, it doesn't matter much, you could use find instead without creating a collection beforehand

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

];

const dummy = { home1: "05:30", away: "09:30" };

for (let i = 1; i <= 7; i++) {

  if (!array.find(({ dayOfWeek }) => dayOfWeek === i)) {

    array.push({ ...dummy, dayOfWeek: i });

  }

}

console.log(array);

answered Nov 12 '18 at 7:52

CertainPerformance

76k143761

add a comment |

One option would be to make a Set of the days contained in the array so far, then iterate from 1 to 7, pushing a new object to the array with that day if it's not contained in the set:

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

];

const dummy = { home1: "05:30", away: "09:30" };

const days = new Set(array.map(({ dayOfWeek }) => dayOfWeek));

for (let i = 1; i <= 7; i++) {

  if (!days.has(i)) array.push({ ...dummy, dayOfWeek: i });

}

console.log(array);

I used a Set to reduce complexity, but I suppose if you only ever need 7 objects, it doesn't matter much, you could use find instead without creating a collection beforehand

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

];

const dummy = { home1: "05:30", away: "09:30" };

for (let i = 1; i <= 7; i++) {

  if (!array.find(({ dayOfWeek }) => dayOfWeek === i)) {

    array.push({ ...dummy, dayOfWeek: i });

  }

}

console.log(array);

answered Nov 12 '18 at 7:52

CertainPerformance

76k143761

One option would be to make a Set of the days contained in the array so far, then iterate from 1 to 7, pushing a new object to the array with that day if it's not contained in the set:

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

];

const dummy = { home1: "05:30", away: "09:30" };

const days = new Set(array.map(({ dayOfWeek }) => dayOfWeek));

for (let i = 1; i <= 7; i++) {

  if (!days.has(i)) array.push({ ...dummy, dayOfWeek: i });

}

console.log(array);

I used a Set to reduce complexity, but I suppose if you only ever need 7 objects, it doesn't matter much, you could use find instead without creating a collection beforehand

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

];

const dummy = { home1: "05:30", away: "09:30" };

for (let i = 1; i <= 7; i++) {

  if (!array.find(({ dayOfWeek }) => dayOfWeek === i)) {

    array.push({ ...dummy, dayOfWeek: i });

  }

}

console.log(array);

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

];

const dummy = { home1: "05:30", away: "09:30" };

const days = new Set(array.map(({ dayOfWeek }) => dayOfWeek));

for (let i = 1; i <= 7; i++) {

  if (!days.has(i)) array.push({ ...dummy, dayOfWeek: i });

}

console.log(array);

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

];

const dummy = { home1: "05:30", away: "09:30" };

const days = new Set(array.map(({ dayOfWeek }) => dayOfWeek));

for (let i = 1; i <= 7; i++) {

  if (!days.has(i)) array.push({ ...dummy, dayOfWeek: i });

}

console.log(array);

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

];

const dummy = { home1: "05:30", away: "09:30" };

for (let i = 1; i <= 7; i++) {

  if (!array.find(({ dayOfWeek }) => dayOfWeek === i)) {

    array.push({ ...dummy, dayOfWeek: i });

  }

}

console.log(array);

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

];

const dummy = { home1: "05:30", away: "09:30" };

for (let i = 1; i <= 7; i++) {

  if (!array.find(({ dayOfWeek }) => dayOfWeek === i)) {

    array.push({ ...dummy, dayOfWeek: i });

  }

}

console.log(array);

answered Nov 12 '18 at 7:52

CertainPerformance

76k143761

answered Nov 12 '18 at 7:52

CertainPerformance

76k143761

answered Nov 12 '18 at 7:52

CertainPerformance

76k143761

answered Nov 12 '18 at 7:52

CertainPerformance

76k143761

add a comment |

Use Array.reduce to create a set of existing days. Now iterate and check whether there is an entry in set, if not push the object in array.

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

];

let daysSet = array.reduce((a,c) => a.add(c.dayOfWeek), new Set());

let obj = { home1: "16:30", dayOfWeek: 7, away: "09:30"};

for(let i = 1; i <=7; i++) {

  if(!daysSet.has(i)) array.push(Object.assign({}, obj, {dayOfWeek:i}));

}

console.log(array);

answered Nov 12 '18 at 7:56

Nikhil Aggarwal

23.7k32647

Thank you I didn't test it but I made an upvote because the first answer is worked for me
– Dark Knight
Nov 12 '18 at 8:06

Could you please upvote my question. Else I will be blocked by asking
– Dark Knight
Nov 12 '18 at 9:09

add a comment |

Use Array.reduce to create a set of existing days. Now iterate and check whether there is an entry in set, if not push the object in array.

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

];

let daysSet = array.reduce((a,c) => a.add(c.dayOfWeek), new Set());

let obj = { home1: "16:30", dayOfWeek: 7, away: "09:30"};

for(let i = 1; i <=7; i++) {

  if(!daysSet.has(i)) array.push(Object.assign({}, obj, {dayOfWeek:i}));

}

console.log(array);

answered Nov 12 '18 at 7:56

Nikhil Aggarwal

23.7k32647

Thank you I didn't test it but I made an upvote because the first answer is worked for me
– Dark Knight
Nov 12 '18 at 8:06

Could you please upvote my question. Else I will be blocked by asking
– Dark Knight
Nov 12 '18 at 9:09

add a comment |

Use Array.reduce to create a set of existing days. Now iterate and check whether there is an entry in set, if not push the object in array.

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

];

let daysSet = array.reduce((a,c) => a.add(c.dayOfWeek), new Set());

let obj = { home1: "16:30", dayOfWeek: 7, away: "09:30"};

for(let i = 1; i <=7; i++) {

  if(!daysSet.has(i)) array.push(Object.assign({}, obj, {dayOfWeek:i}));

}

console.log(array);

answered Nov 12 '18 at 7:56

Nikhil Aggarwal

23.7k32647

Use Array.reduce to create a set of existing days. Now iterate and check whether there is an entry in set, if not push the object in array.

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

];

let daysSet = array.reduce((a,c) => a.add(c.dayOfWeek), new Set());

let obj = { home1: "16:30", dayOfWeek: 7, away: "09:30"};

for(let i = 1; i <=7; i++) {

  if(!daysSet.has(i)) array.push(Object.assign({}, obj, {dayOfWeek:i}));

}

console.log(array);

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

];

let daysSet = array.reduce((a,c) => a.add(c.dayOfWeek), new Set());

let obj = { home1: "16:30", dayOfWeek: 7, away: "09:30"};

for(let i = 1; i <=7; i++) {

  if(!daysSet.has(i)) array.push(Object.assign({}, obj, {dayOfWeek:i}));

}

console.log(array);

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

];

let daysSet = array.reduce((a,c) => a.add(c.dayOfWeek), new Set());

let obj = { home1: "16:30", dayOfWeek: 7, away: "09:30"};

for(let i = 1; i <=7; i++) {

  if(!daysSet.has(i)) array.push(Object.assign({}, obj, {dayOfWeek:i}));

}

console.log(array);

answered Nov 12 '18 at 7:56

Nikhil Aggarwal

23.7k32647

answered Nov 12 '18 at 7:56

Nikhil Aggarwal

23.7k32647

answered Nov 12 '18 at 7:56

Nikhil Aggarwal

23.7k32647

answered Nov 12 '18 at 7:56

Nikhil Aggarwal

23.7k32647

Thank you I didn't test it but I made an upvote because the first answer is worked for me
– Dark Knight
Nov 12 '18 at 8:06

Could you please upvote my question. Else I will be blocked by asking
– Dark Knight
Nov 12 '18 at 9:09

add a comment |

Thank you I didn't test it but I made an upvote because the first answer is worked for me
– Dark Knight
Nov 12 '18 at 8:06

Could you please upvote my question. Else I will be blocked by asking
– Dark Knight
Nov 12 '18 at 9:09

Thank you I didn't test it but I made an upvote because the first answer is worked for me
– Dark Knight
Nov 12 '18 at 8:06

Could you please upvote my question. Else I will be blocked by asking
– Dark Knight
Nov 12 '18 at 9:09

add a comment |

You can use "Array.from" and loop 7 times like below.

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

]



// sort array by day of week. Ignore this step if you are sure it will be sorted always

array.sort((a,b) => a.dayOfWeek - b.dayOfWeek)



var result = Array.from({ length: 7}

    , (_,i) => array[0].dayOfWeek == i + 1

                ? array.shift()

                : { home1: "05:30", dayOfWeek: i + 1, away: "09:30"})

                

console.log(result)

edited Nov 12 '18 at 8:02

answered Nov 12 '18 at 7:54

Nitish Narang

2,948815

add a comment |

You can use "Array.from" and loop 7 times like below.

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

]



// sort array by day of week. Ignore this step if you are sure it will be sorted always

array.sort((a,b) => a.dayOfWeek - b.dayOfWeek)



var result = Array.from({ length: 7}

    , (_,i) => array[0].dayOfWeek == i + 1

                ? array.shift()

                : { home1: "05:30", dayOfWeek: i + 1, away: "09:30"})

                

console.log(result)

edited Nov 12 '18 at 8:02

answered Nov 12 '18 at 7:54

Nitish Narang

2,948815

add a comment |

You can use "Array.from" and loop 7 times like below.

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

]



// sort array by day of week. Ignore this step if you are sure it will be sorted always

array.sort((a,b) => a.dayOfWeek - b.dayOfWeek)



var result = Array.from({ length: 7}

    , (_,i) => array[0].dayOfWeek == i + 1

                ? array.shift()

                : { home1: "05:30", dayOfWeek: i + 1, away: "09:30"})

                

console.log(result)

edited Nov 12 '18 at 8:02

answered Nov 12 '18 at 7:54

Nitish Narang

2,948815

You can use "Array.from" and loop 7 times like below.

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

]



// sort array by day of week. Ignore this step if you are sure it will be sorted always

array.sort((a,b) => a.dayOfWeek - b.dayOfWeek)



var result = Array.from({ length: 7}

    , (_,i) => array[0].dayOfWeek == i + 1

                ? array.shift()

                : { home1: "05:30", dayOfWeek: i + 1, away: "09:30"})

                

console.log(result)

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

]



// sort array by day of week. Ignore this step if you are sure it will be sorted always

array.sort((a,b) => a.dayOfWeek - b.dayOfWeek)



var result = Array.from({ length: 7}

    , (_,i) => array[0].dayOfWeek == i + 1

                ? array.shift()

                : { home1: "05:30", dayOfWeek: i + 1, away: "09:30"})

                

console.log(result)

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

]



// sort array by day of week. Ignore this step if you are sure it will be sorted always

array.sort((a,b) => a.dayOfWeek - b.dayOfWeek)



var result = Array.from({ length: 7}

    , (_,i) => array[0].dayOfWeek == i + 1

                ? array.shift()

                : { home1: "05:30", dayOfWeek: i + 1, away: "09:30"})

                

console.log(result)

edited Nov 12 '18 at 8:02

answered Nov 12 '18 at 7:54

Nitish Narang

2,948815

edited Nov 12 '18 at 8:02

answered Nov 12 '18 at 7:54

Nitish Narang

2,948815

answered Nov 12 '18 at 7:54

Nitish Narang

2,948815

answered Nov 12 '18 at 7:54

Nitish Narang

2,948815

add a comment |

You can first get all the dayOfWeek present in a array with map(). Then use for loop to insert the dayOfWeek by checking whether that is present in the array or not.

You can try the following way:

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

]

let exist = array.map(d => d.dayOfWeek);



for(let i = 1; i<=7; i++){

  let dummy = { home1: "05:30", dayOfWeek: 7, away: "09:30"};

  dummy.dayOfWeek = i;

  if(!exist.includes(i))

   array.splice(i-1, 0, dummy);

}

console.log(array);

edited Nov 12 '18 at 8:12

answered Nov 12 '18 at 8:04

Mamun

25k71428

Thank you I didn't test it but I made an upvote
– Dark Knight
Nov 12 '18 at 8:06

@DarkKnight, you are most welcome....you can test whenever you can:)
– Mamun
Nov 12 '18 at 8:09

Could you please upvote my question. Else I will be blocked by asking
– Dark Knight
Nov 12 '18 at 9:09

add a comment |

You can first get all the dayOfWeek present in a array with map(). Then use for loop to insert the dayOfWeek by checking whether that is present in the array or not.

You can try the following way:

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

]

let exist = array.map(d => d.dayOfWeek);



for(let i = 1; i<=7; i++){

  let dummy = { home1: "05:30", dayOfWeek: 7, away: "09:30"};

  dummy.dayOfWeek = i;

  if(!exist.includes(i))

   array.splice(i-1, 0, dummy);

}

console.log(array);

edited Nov 12 '18 at 8:12

answered Nov 12 '18 at 8:04

Mamun

25k71428

Thank you I didn't test it but I made an upvote
– Dark Knight
Nov 12 '18 at 8:06

@DarkKnight, you are most welcome....you can test whenever you can:)
– Mamun
Nov 12 '18 at 8:09

Could you please upvote my question. Else I will be blocked by asking
– Dark Knight
Nov 12 '18 at 9:09

add a comment |

You can first get all the dayOfWeek present in a array with map(). Then use for loop to insert the dayOfWeek by checking whether that is present in the array or not.

You can try the following way:

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

]

let exist = array.map(d => d.dayOfWeek);



for(let i = 1; i<=7; i++){

  let dummy = { home1: "05:30", dayOfWeek: 7, away: "09:30"};

  dummy.dayOfWeek = i;

  if(!exist.includes(i))

   array.splice(i-1, 0, dummy);

}

console.log(array);

edited Nov 12 '18 at 8:12

answered Nov 12 '18 at 8:04

Mamun

25k71428

You can first get all the dayOfWeek present in a array with map(). Then use for loop to insert the dayOfWeek by checking whether that is present in the array or not.

You can try the following way:

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

]

let exist = array.map(d => d.dayOfWeek);



for(let i = 1; i<=7; i++){

  let dummy = { home1: "05:30", dayOfWeek: 7, away: "09:30"};

  dummy.dayOfWeek = i;

  if(!exist.includes(i))

   array.splice(i-1, 0, dummy);

}

console.log(array);

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

]

let exist = array.map(d => d.dayOfWeek);



for(let i = 1; i<=7; i++){

  let dummy = { home1: "05:30", dayOfWeek: 7, away: "09:30"};

  dummy.dayOfWeek = i;

  if(!exist.includes(i))

   array.splice(i-1, 0, dummy);

}

console.log(array);

const array = [

   { home1: "05:45", dayOfWeek: 1, away: "09:30"},

   { home1: "05:15", dayOfWeek: 2, away: "09:30"},

   { home1: "17:30", dayOfWeek: 5, away: "09:30"},

   { home1: "16:30", dayOfWeek: 7, away: "09:30"}

]

let exist = array.map(d => d.dayOfWeek);



for(let i = 1; i<=7; i++){

  let dummy = { home1: "05:30", dayOfWeek: 7, away: "09:30"};

  dummy.dayOfWeek = i;

  if(!exist.includes(i))

   array.splice(i-1, 0, dummy);

}

console.log(array);

edited Nov 12 '18 at 8:12

answered Nov 12 '18 at 8:04

Mamun

25k71428

edited Nov 12 '18 at 8:12

answered Nov 12 '18 at 8:04

Mamun

25k71428

answered Nov 12 '18 at 8:04

Mamun

25k71428

answered Nov 12 '18 at 8:04

Mamun

25k71428

Thank you I didn't test it but I made an upvote
– Dark Knight
Nov 12 '18 at 8:06

@DarkKnight, you are most welcome....you can test whenever you can:)
– Mamun
Nov 12 '18 at 8:09

Could you please upvote my question. Else I will be blocked by asking
– Dark Knight
Nov 12 '18 at 9:09

add a comment |

Thank you I didn't test it but I made an upvote
– Dark Knight
Nov 12 '18 at 8:06

@DarkKnight, you are most welcome....you can test whenever you can:)
– Mamun
Nov 12 '18 at 8:09

Could you please upvote my question. Else I will be blocked by asking
– Dark Knight
Nov 12 '18 at 9:09

Thank you I didn't test it but I made an upvote
– Dark Knight
Nov 12 '18 at 8:06

@DarkKnight, you are most welcome....you can test whenever you can:)
– Mamun
Nov 12 '18 at 8:09

Could you please upvote my question. Else I will be blocked by asking
– Dark Knight
Nov 12 '18 at 9:09

add a comment |

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