How to render a component only for one Route?












0














I am trying to remove Header component from route page only . How can i do this in React router 4 ?



this is my Routes



const AppRouter: any = () => (
<BrowserRouter>
<React.Fragment>
<Header />
<Switch>
<Route path={LOOP_MAIN_ROUTE} component={LandingPage} exact/>
<Route path={LOOP_LOGIN_ROUTE} component={LoginPage} exact/>
<ProtectedRoute path={LOOP_SEARCH_ROUTE} component={SearchPage} />
<ProtectedRoute path={LOOP_OFFER_ROUTE} component={Offer} exact />
<ProtectedRoute path={LOOP_OFFER_APPROVAL} component={OfferApproval} exact />
<ProtectedRoute path={LOOP_OFFER_CONFIRMATION} component={OfferConfirmation} exact />
</Switch>
</React.Fragment>
</BrowserRouter>
);

export default AppRouter;









share|improve this question






















  • for what path Header should render?
    – Sagiv b.g
    Nov 12 '18 at 15:15










  • there is no path ... First i have tried to render it for all routes , but now i need to NOT render for LOOP_MAIN_ROUTE
    – Norayr Ghukasyan
    Nov 12 '18 at 15:17










  • you can pass a regex, see this answer it may help
    – Sagiv b.g
    Nov 12 '18 at 15:20










  • @NorayrGhukasyan Consider updating the question with this information because the question says the opposite.
    – estus
    Nov 12 '18 at 15:32
















0














I am trying to remove Header component from route page only . How can i do this in React router 4 ?



this is my Routes



const AppRouter: any = () => (
<BrowserRouter>
<React.Fragment>
<Header />
<Switch>
<Route path={LOOP_MAIN_ROUTE} component={LandingPage} exact/>
<Route path={LOOP_LOGIN_ROUTE} component={LoginPage} exact/>
<ProtectedRoute path={LOOP_SEARCH_ROUTE} component={SearchPage} />
<ProtectedRoute path={LOOP_OFFER_ROUTE} component={Offer} exact />
<ProtectedRoute path={LOOP_OFFER_APPROVAL} component={OfferApproval} exact />
<ProtectedRoute path={LOOP_OFFER_CONFIRMATION} component={OfferConfirmation} exact />
</Switch>
</React.Fragment>
</BrowserRouter>
);

export default AppRouter;









share|improve this question






















  • for what path Header should render?
    – Sagiv b.g
    Nov 12 '18 at 15:15










  • there is no path ... First i have tried to render it for all routes , but now i need to NOT render for LOOP_MAIN_ROUTE
    – Norayr Ghukasyan
    Nov 12 '18 at 15:17










  • you can pass a regex, see this answer it may help
    – Sagiv b.g
    Nov 12 '18 at 15:20










  • @NorayrGhukasyan Consider updating the question with this information because the question says the opposite.
    – estus
    Nov 12 '18 at 15:32














0












0








0







I am trying to remove Header component from route page only . How can i do this in React router 4 ?



this is my Routes



const AppRouter: any = () => (
<BrowserRouter>
<React.Fragment>
<Header />
<Switch>
<Route path={LOOP_MAIN_ROUTE} component={LandingPage} exact/>
<Route path={LOOP_LOGIN_ROUTE} component={LoginPage} exact/>
<ProtectedRoute path={LOOP_SEARCH_ROUTE} component={SearchPage} />
<ProtectedRoute path={LOOP_OFFER_ROUTE} component={Offer} exact />
<ProtectedRoute path={LOOP_OFFER_APPROVAL} component={OfferApproval} exact />
<ProtectedRoute path={LOOP_OFFER_CONFIRMATION} component={OfferConfirmation} exact />
</Switch>
</React.Fragment>
</BrowserRouter>
);

export default AppRouter;









share|improve this question













I am trying to remove Header component from route page only . How can i do this in React router 4 ?



this is my Routes



const AppRouter: any = () => (
<BrowserRouter>
<React.Fragment>
<Header />
<Switch>
<Route path={LOOP_MAIN_ROUTE} component={LandingPage} exact/>
<Route path={LOOP_LOGIN_ROUTE} component={LoginPage} exact/>
<ProtectedRoute path={LOOP_SEARCH_ROUTE} component={SearchPage} />
<ProtectedRoute path={LOOP_OFFER_ROUTE} component={Offer} exact />
<ProtectedRoute path={LOOP_OFFER_APPROVAL} component={OfferApproval} exact />
<ProtectedRoute path={LOOP_OFFER_CONFIRMATION} component={OfferConfirmation} exact />
</Switch>
</React.Fragment>
</BrowserRouter>
);

export default AppRouter;






reactjs routing react-router






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 12 '18 at 15:10









Norayr Ghukasyan

1099




1099












  • for what path Header should render?
    – Sagiv b.g
    Nov 12 '18 at 15:15










  • there is no path ... First i have tried to render it for all routes , but now i need to NOT render for LOOP_MAIN_ROUTE
    – Norayr Ghukasyan
    Nov 12 '18 at 15:17










  • you can pass a regex, see this answer it may help
    – Sagiv b.g
    Nov 12 '18 at 15:20










  • @NorayrGhukasyan Consider updating the question with this information because the question says the opposite.
    – estus
    Nov 12 '18 at 15:32


















  • for what path Header should render?
    – Sagiv b.g
    Nov 12 '18 at 15:15










  • there is no path ... First i have tried to render it for all routes , but now i need to NOT render for LOOP_MAIN_ROUTE
    – Norayr Ghukasyan
    Nov 12 '18 at 15:17










  • you can pass a regex, see this answer it may help
    – Sagiv b.g
    Nov 12 '18 at 15:20










  • @NorayrGhukasyan Consider updating the question with this information because the question says the opposite.
    – estus
    Nov 12 '18 at 15:32
















for what path Header should render?
– Sagiv b.g
Nov 12 '18 at 15:15




for what path Header should render?
– Sagiv b.g
Nov 12 '18 at 15:15












there is no path ... First i have tried to render it for all routes , but now i need to NOT render for LOOP_MAIN_ROUTE
– Norayr Ghukasyan
Nov 12 '18 at 15:17




there is no path ... First i have tried to render it for all routes , but now i need to NOT render for LOOP_MAIN_ROUTE
– Norayr Ghukasyan
Nov 12 '18 at 15:17












you can pass a regex, see this answer it may help
– Sagiv b.g
Nov 12 '18 at 15:20




you can pass a regex, see this answer it may help
– Sagiv b.g
Nov 12 '18 at 15:20












@NorayrGhukasyan Consider updating the question with this information because the question says the opposite.
– estus
Nov 12 '18 at 15:32




@NorayrGhukasyan Consider updating the question with this information because the question says the opposite.
– estus
Nov 12 '18 at 15:32












2 Answers
2






active

oldest

votes


















1














One way to do this is using matchPath. For instance in your Header component:



import React from "react";
import {LOOP_MAIN_ROUTE} from "whereverYouHaveThisConstant";
import { withRouter, matchPath } from 'react-router-dom';
const Header = (props) => {
const suppressHeader = matchPath(props.location.pathname, {path: LOOP_MAIN_ROUTE});
if (suppressHeader ) {
return null;
}
return <>your header stuff</>;
};
export default withRouter(Header);





share|improve this answer





















  • This works fine , only i change the suppressHeader whit suppressHeader.isExact
    – Norayr Ghukasyan
    Nov 12 '18 at 15:38



















2














Header can be conditionally rendered as a route:



<Route render={
({ location: { pathname } }) => pathname !== LOOP_MAIN_ROUTE && <Header/>
}/>





share|improve this answer





















  • I think this is more elegant solution
    – Norayr Ghukasyan
    Nov 13 '18 at 6:22











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2 Answers
2






active

oldest

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2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














One way to do this is using matchPath. For instance in your Header component:



import React from "react";
import {LOOP_MAIN_ROUTE} from "whereverYouHaveThisConstant";
import { withRouter, matchPath } from 'react-router-dom';
const Header = (props) => {
const suppressHeader = matchPath(props.location.pathname, {path: LOOP_MAIN_ROUTE});
if (suppressHeader ) {
return null;
}
return <>your header stuff</>;
};
export default withRouter(Header);





share|improve this answer





















  • This works fine , only i change the suppressHeader whit suppressHeader.isExact
    – Norayr Ghukasyan
    Nov 12 '18 at 15:38
















1














One way to do this is using matchPath. For instance in your Header component:



import React from "react";
import {LOOP_MAIN_ROUTE} from "whereverYouHaveThisConstant";
import { withRouter, matchPath } from 'react-router-dom';
const Header = (props) => {
const suppressHeader = matchPath(props.location.pathname, {path: LOOP_MAIN_ROUTE});
if (suppressHeader ) {
return null;
}
return <>your header stuff</>;
};
export default withRouter(Header);





share|improve this answer





















  • This works fine , only i change the suppressHeader whit suppressHeader.isExact
    – Norayr Ghukasyan
    Nov 12 '18 at 15:38














1












1








1






One way to do this is using matchPath. For instance in your Header component:



import React from "react";
import {LOOP_MAIN_ROUTE} from "whereverYouHaveThisConstant";
import { withRouter, matchPath } from 'react-router-dom';
const Header = (props) => {
const suppressHeader = matchPath(props.location.pathname, {path: LOOP_MAIN_ROUTE});
if (suppressHeader ) {
return null;
}
return <>your header stuff</>;
};
export default withRouter(Header);





share|improve this answer












One way to do this is using matchPath. For instance in your Header component:



import React from "react";
import {LOOP_MAIN_ROUTE} from "whereverYouHaveThisConstant";
import { withRouter, matchPath } from 'react-router-dom';
const Header = (props) => {
const suppressHeader = matchPath(props.location.pathname, {path: LOOP_MAIN_ROUTE});
if (suppressHeader ) {
return null;
}
return <>your header stuff</>;
};
export default withRouter(Header);






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 12 '18 at 15:25









Ryan Cogswell

1,550211




1,550211












  • This works fine , only i change the suppressHeader whit suppressHeader.isExact
    – Norayr Ghukasyan
    Nov 12 '18 at 15:38


















  • This works fine , only i change the suppressHeader whit suppressHeader.isExact
    – Norayr Ghukasyan
    Nov 12 '18 at 15:38
















This works fine , only i change the suppressHeader whit suppressHeader.isExact
– Norayr Ghukasyan
Nov 12 '18 at 15:38




This works fine , only i change the suppressHeader whit suppressHeader.isExact
– Norayr Ghukasyan
Nov 12 '18 at 15:38













2














Header can be conditionally rendered as a route:



<Route render={
({ location: { pathname } }) => pathname !== LOOP_MAIN_ROUTE && <Header/>
}/>





share|improve this answer





















  • I think this is more elegant solution
    – Norayr Ghukasyan
    Nov 13 '18 at 6:22
















2














Header can be conditionally rendered as a route:



<Route render={
({ location: { pathname } }) => pathname !== LOOP_MAIN_ROUTE && <Header/>
}/>





share|improve this answer





















  • I think this is more elegant solution
    – Norayr Ghukasyan
    Nov 13 '18 at 6:22














2












2








2






Header can be conditionally rendered as a route:



<Route render={
({ location: { pathname } }) => pathname !== LOOP_MAIN_ROUTE && <Header/>
}/>





share|improve this answer












Header can be conditionally rendered as a route:



<Route render={
({ location: { pathname } }) => pathname !== LOOP_MAIN_ROUTE && <Header/>
}/>






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 12 '18 at 15:33









estus

67.3k2199215




67.3k2199215












  • I think this is more elegant solution
    – Norayr Ghukasyan
    Nov 13 '18 at 6:22


















  • I think this is more elegant solution
    – Norayr Ghukasyan
    Nov 13 '18 at 6:22
















I think this is more elegant solution
– Norayr Ghukasyan
Nov 13 '18 at 6:22




I think this is more elegant solution
– Norayr Ghukasyan
Nov 13 '18 at 6:22


















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