How to render a component only for one Route?
I am trying to remove Header component from route page only . How can i do this in React router 4 ?
this is my Routes
const AppRouter: any = () => (
<BrowserRouter>
<React.Fragment>
<Header />
<Switch>
<Route path={LOOP_MAIN_ROUTE} component={LandingPage} exact/>
<Route path={LOOP_LOGIN_ROUTE} component={LoginPage} exact/>
<ProtectedRoute path={LOOP_SEARCH_ROUTE} component={SearchPage} />
<ProtectedRoute path={LOOP_OFFER_ROUTE} component={Offer} exact />
<ProtectedRoute path={LOOP_OFFER_APPROVAL} component={OfferApproval} exact />
<ProtectedRoute path={LOOP_OFFER_CONFIRMATION} component={OfferConfirmation} exact />
</Switch>
</React.Fragment>
</BrowserRouter>
);
export default AppRouter;
reactjs routing react-router
add a comment |
I am trying to remove Header component from route page only . How can i do this in React router 4 ?
this is my Routes
const AppRouter: any = () => (
<BrowserRouter>
<React.Fragment>
<Header />
<Switch>
<Route path={LOOP_MAIN_ROUTE} component={LandingPage} exact/>
<Route path={LOOP_LOGIN_ROUTE} component={LoginPage} exact/>
<ProtectedRoute path={LOOP_SEARCH_ROUTE} component={SearchPage} />
<ProtectedRoute path={LOOP_OFFER_ROUTE} component={Offer} exact />
<ProtectedRoute path={LOOP_OFFER_APPROVAL} component={OfferApproval} exact />
<ProtectedRoute path={LOOP_OFFER_CONFIRMATION} component={OfferConfirmation} exact />
</Switch>
</React.Fragment>
</BrowserRouter>
);
export default AppRouter;
reactjs routing react-router
for what pathHeader
should render?
– Sagiv b.g
Nov 12 '18 at 15:15
there is no path ... First i have tried to render it for all routes , but now i need to NOT render for LOOP_MAIN_ROUTE
– Norayr Ghukasyan
Nov 12 '18 at 15:17
you can pass a regex, see this answer it may help
– Sagiv b.g
Nov 12 '18 at 15:20
@NorayrGhukasyan Consider updating the question with this information because the question says the opposite.
– estus
Nov 12 '18 at 15:32
add a comment |
I am trying to remove Header component from route page only . How can i do this in React router 4 ?
this is my Routes
const AppRouter: any = () => (
<BrowserRouter>
<React.Fragment>
<Header />
<Switch>
<Route path={LOOP_MAIN_ROUTE} component={LandingPage} exact/>
<Route path={LOOP_LOGIN_ROUTE} component={LoginPage} exact/>
<ProtectedRoute path={LOOP_SEARCH_ROUTE} component={SearchPage} />
<ProtectedRoute path={LOOP_OFFER_ROUTE} component={Offer} exact />
<ProtectedRoute path={LOOP_OFFER_APPROVAL} component={OfferApproval} exact />
<ProtectedRoute path={LOOP_OFFER_CONFIRMATION} component={OfferConfirmation} exact />
</Switch>
</React.Fragment>
</BrowserRouter>
);
export default AppRouter;
reactjs routing react-router
I am trying to remove Header component from route page only . How can i do this in React router 4 ?
this is my Routes
const AppRouter: any = () => (
<BrowserRouter>
<React.Fragment>
<Header />
<Switch>
<Route path={LOOP_MAIN_ROUTE} component={LandingPage} exact/>
<Route path={LOOP_LOGIN_ROUTE} component={LoginPage} exact/>
<ProtectedRoute path={LOOP_SEARCH_ROUTE} component={SearchPage} />
<ProtectedRoute path={LOOP_OFFER_ROUTE} component={Offer} exact />
<ProtectedRoute path={LOOP_OFFER_APPROVAL} component={OfferApproval} exact />
<ProtectedRoute path={LOOP_OFFER_CONFIRMATION} component={OfferConfirmation} exact />
</Switch>
</React.Fragment>
</BrowserRouter>
);
export default AppRouter;
reactjs routing react-router
reactjs routing react-router
asked Nov 12 '18 at 15:10
Norayr Ghukasyan
1099
1099
for what pathHeader
should render?
– Sagiv b.g
Nov 12 '18 at 15:15
there is no path ... First i have tried to render it for all routes , but now i need to NOT render for LOOP_MAIN_ROUTE
– Norayr Ghukasyan
Nov 12 '18 at 15:17
you can pass a regex, see this answer it may help
– Sagiv b.g
Nov 12 '18 at 15:20
@NorayrGhukasyan Consider updating the question with this information because the question says the opposite.
– estus
Nov 12 '18 at 15:32
add a comment |
for what pathHeader
should render?
– Sagiv b.g
Nov 12 '18 at 15:15
there is no path ... First i have tried to render it for all routes , but now i need to NOT render for LOOP_MAIN_ROUTE
– Norayr Ghukasyan
Nov 12 '18 at 15:17
you can pass a regex, see this answer it may help
– Sagiv b.g
Nov 12 '18 at 15:20
@NorayrGhukasyan Consider updating the question with this information because the question says the opposite.
– estus
Nov 12 '18 at 15:32
for what path
Header
should render?– Sagiv b.g
Nov 12 '18 at 15:15
for what path
Header
should render?– Sagiv b.g
Nov 12 '18 at 15:15
there is no path ... First i have tried to render it for all routes , but now i need to NOT render for LOOP_MAIN_ROUTE
– Norayr Ghukasyan
Nov 12 '18 at 15:17
there is no path ... First i have tried to render it for all routes , but now i need to NOT render for LOOP_MAIN_ROUTE
– Norayr Ghukasyan
Nov 12 '18 at 15:17
you can pass a regex, see this answer it may help
– Sagiv b.g
Nov 12 '18 at 15:20
you can pass a regex, see this answer it may help
– Sagiv b.g
Nov 12 '18 at 15:20
@NorayrGhukasyan Consider updating the question with this information because the question says the opposite.
– estus
Nov 12 '18 at 15:32
@NorayrGhukasyan Consider updating the question with this information because the question says the opposite.
– estus
Nov 12 '18 at 15:32
add a comment |
2 Answers
2
active
oldest
votes
One way to do this is using matchPath. For instance in your Header component:
import React from "react";
import {LOOP_MAIN_ROUTE} from "whereverYouHaveThisConstant";
import { withRouter, matchPath } from 'react-router-dom';
const Header = (props) => {
const suppressHeader = matchPath(props.location.pathname, {path: LOOP_MAIN_ROUTE});
if (suppressHeader ) {
return null;
}
return <>your header stuff</>;
};
export default withRouter(Header);
This works fine , only i change the suppressHeader whit suppressHeader.isExact
– Norayr Ghukasyan
Nov 12 '18 at 15:38
add a comment |
Header
can be conditionally rendered as a route:
<Route render={
({ location: { pathname } }) => pathname !== LOOP_MAIN_ROUTE && <Header/>
}/>
I think this is more elegant solution
– Norayr Ghukasyan
Nov 13 '18 at 6:22
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
One way to do this is using matchPath. For instance in your Header component:
import React from "react";
import {LOOP_MAIN_ROUTE} from "whereverYouHaveThisConstant";
import { withRouter, matchPath } from 'react-router-dom';
const Header = (props) => {
const suppressHeader = matchPath(props.location.pathname, {path: LOOP_MAIN_ROUTE});
if (suppressHeader ) {
return null;
}
return <>your header stuff</>;
};
export default withRouter(Header);
This works fine , only i change the suppressHeader whit suppressHeader.isExact
– Norayr Ghukasyan
Nov 12 '18 at 15:38
add a comment |
One way to do this is using matchPath. For instance in your Header component:
import React from "react";
import {LOOP_MAIN_ROUTE} from "whereverYouHaveThisConstant";
import { withRouter, matchPath } from 'react-router-dom';
const Header = (props) => {
const suppressHeader = matchPath(props.location.pathname, {path: LOOP_MAIN_ROUTE});
if (suppressHeader ) {
return null;
}
return <>your header stuff</>;
};
export default withRouter(Header);
This works fine , only i change the suppressHeader whit suppressHeader.isExact
– Norayr Ghukasyan
Nov 12 '18 at 15:38
add a comment |
One way to do this is using matchPath. For instance in your Header component:
import React from "react";
import {LOOP_MAIN_ROUTE} from "whereverYouHaveThisConstant";
import { withRouter, matchPath } from 'react-router-dom';
const Header = (props) => {
const suppressHeader = matchPath(props.location.pathname, {path: LOOP_MAIN_ROUTE});
if (suppressHeader ) {
return null;
}
return <>your header stuff</>;
};
export default withRouter(Header);
One way to do this is using matchPath. For instance in your Header component:
import React from "react";
import {LOOP_MAIN_ROUTE} from "whereverYouHaveThisConstant";
import { withRouter, matchPath } from 'react-router-dom';
const Header = (props) => {
const suppressHeader = matchPath(props.location.pathname, {path: LOOP_MAIN_ROUTE});
if (suppressHeader ) {
return null;
}
return <>your header stuff</>;
};
export default withRouter(Header);
answered Nov 12 '18 at 15:25
Ryan Cogswell
1,550211
1,550211
This works fine , only i change the suppressHeader whit suppressHeader.isExact
– Norayr Ghukasyan
Nov 12 '18 at 15:38
add a comment |
This works fine , only i change the suppressHeader whit suppressHeader.isExact
– Norayr Ghukasyan
Nov 12 '18 at 15:38
This works fine , only i change the suppressHeader whit suppressHeader.isExact
– Norayr Ghukasyan
Nov 12 '18 at 15:38
This works fine , only i change the suppressHeader whit suppressHeader.isExact
– Norayr Ghukasyan
Nov 12 '18 at 15:38
add a comment |
Header
can be conditionally rendered as a route:
<Route render={
({ location: { pathname } }) => pathname !== LOOP_MAIN_ROUTE && <Header/>
}/>
I think this is more elegant solution
– Norayr Ghukasyan
Nov 13 '18 at 6:22
add a comment |
Header
can be conditionally rendered as a route:
<Route render={
({ location: { pathname } }) => pathname !== LOOP_MAIN_ROUTE && <Header/>
}/>
I think this is more elegant solution
– Norayr Ghukasyan
Nov 13 '18 at 6:22
add a comment |
Header
can be conditionally rendered as a route:
<Route render={
({ location: { pathname } }) => pathname !== LOOP_MAIN_ROUTE && <Header/>
}/>
Header
can be conditionally rendered as a route:
<Route render={
({ location: { pathname } }) => pathname !== LOOP_MAIN_ROUTE && <Header/>
}/>
answered Nov 12 '18 at 15:33
estus
67.3k2199215
67.3k2199215
I think this is more elegant solution
– Norayr Ghukasyan
Nov 13 '18 at 6:22
add a comment |
I think this is more elegant solution
– Norayr Ghukasyan
Nov 13 '18 at 6:22
I think this is more elegant solution
– Norayr Ghukasyan
Nov 13 '18 at 6:22
I think this is more elegant solution
– Norayr Ghukasyan
Nov 13 '18 at 6:22
add a comment |
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for what path
Header
should render?– Sagiv b.g
Nov 12 '18 at 15:15
there is no path ... First i have tried to render it for all routes , but now i need to NOT render for LOOP_MAIN_ROUTE
– Norayr Ghukasyan
Nov 12 '18 at 15:17
you can pass a regex, see this answer it may help
– Sagiv b.g
Nov 12 '18 at 15:20
@NorayrGhukasyan Consider updating the question with this information because the question says the opposite.
– estus
Nov 12 '18 at 15:32