RegEx: Finding semicolon between double quotes












0














I am just starting with regular expressions. I need to find all the cases in the text, where there is semicolon in the string between double quotes. So I am searching for the cases like



"something;something"
"something ; something"
"something; something"
"something ;something"


I found code to find strings between double quotes:



(["'])(?:(?=(\?))2.)*?1


Can you help me modify it so I will find cases like I mentioned above?










share|improve this question



























    0














    I am just starting with regular expressions. I need to find all the cases in the text, where there is semicolon in the string between double quotes. So I am searching for the cases like



    "something;something"
    "something ; something"
    "something; something"
    "something ;something"


    I found code to find strings between double quotes:



    (["'])(?:(?=(\?))2.)*?1


    Can you help me modify it so I will find cases like I mentioned above?










    share|improve this question

























      0












      0








      0







      I am just starting with regular expressions. I need to find all the cases in the text, where there is semicolon in the string between double quotes. So I am searching for the cases like



      "something;something"
      "something ; something"
      "something; something"
      "something ;something"


      I found code to find strings between double quotes:



      (["'])(?:(?=(\?))2.)*?1


      Can you help me modify it so I will find cases like I mentioned above?










      share|improve this question













      I am just starting with regular expressions. I need to find all the cases in the text, where there is semicolon in the string between double quotes. So I am searching for the cases like



      "something;something"
      "something ; something"
      "something; something"
      "something ;something"


      I found code to find strings between double quotes:



      (["'])(?:(?=(\?))2.)*?1


      Can you help me modify it so I will find cases like I mentioned above?







      regex






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 12 '18 at 14:43









      JanFi86

      24111




      24111
























          2 Answers
          2






          active

          oldest

          votes


















          1














          You could use a negated character class where you can add what you don't want to match. If there can be only 1 semicolon in the string, then you can also add that to the character class, else you could use [^"rn]* where there can be multiple occurrences of ;



          "([^"rn;]*;[^";rn]*)"



          That would match





          • " Match literally


          • ( Capturing group



            • [^"rn;]* Match 0+ times not a ", newline or semicolon


            • ; Match literally


            • [^"rn;]* Match 0+ times not a ", newline or semicolon




          • ) Close capturing group


          • " Match literally


          Your value is in the first capturing group.



          Regex demo



          If you don't want to match just a semicolon between double quotes you could prepend a negative lookahead:



          (?!";")"([^"rn;]*;[^";rn]*)"






          share|improve this answer























          • Thank you for your solution. Can you modify it so it ommits cases like ";" ? That means it ommits cases where there is just semicolon between double quotes, without any characters or spaces. Thank you in advance.
            – JanFi86
            Nov 12 '18 at 15:01








          • 1




            @JanFi86 Do you mean like this? regex101.com/r/EMqrjV/3
            – The fourth bird
            Nov 12 '18 at 15:03








          • 1




            Exactly! Thank you so much!
            – JanFi86
            Nov 12 '18 at 15:06



















          0














          <?php
          $input = <<<INPUT
          a
          "something;something"
          b
          "something ; something"
          c
          "something; something"
          d
          "something ;something"
          e
          INPUT;

          preg_match_all("/"([^"]+;[^"]+)"/im", $input, $m);

          print_r($m);

          /*
          Array
          (
          [0] => Array
          (
          [0] => "something;something"
          [1] => "something ; something"
          [2] => "something; something"
          [3] => "something ;something"
          )

          [1] => Array
          (
          [0] => something;something
          [1] => something ; something
          [2] => something; something
          [3] => something ;something
          )

          )
          */





          share|improve this answer





















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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            1














            You could use a negated character class where you can add what you don't want to match. If there can be only 1 semicolon in the string, then you can also add that to the character class, else you could use [^"rn]* where there can be multiple occurrences of ;



            "([^"rn;]*;[^";rn]*)"



            That would match





            • " Match literally


            • ( Capturing group



              • [^"rn;]* Match 0+ times not a ", newline or semicolon


              • ; Match literally


              • [^"rn;]* Match 0+ times not a ", newline or semicolon




            • ) Close capturing group


            • " Match literally


            Your value is in the first capturing group.



            Regex demo



            If you don't want to match just a semicolon between double quotes you could prepend a negative lookahead:



            (?!";")"([^"rn;]*;[^";rn]*)"






            share|improve this answer























            • Thank you for your solution. Can you modify it so it ommits cases like ";" ? That means it ommits cases where there is just semicolon between double quotes, without any characters or spaces. Thank you in advance.
              – JanFi86
              Nov 12 '18 at 15:01








            • 1




              @JanFi86 Do you mean like this? regex101.com/r/EMqrjV/3
              – The fourth bird
              Nov 12 '18 at 15:03








            • 1




              Exactly! Thank you so much!
              – JanFi86
              Nov 12 '18 at 15:06
















            1














            You could use a negated character class where you can add what you don't want to match. If there can be only 1 semicolon in the string, then you can also add that to the character class, else you could use [^"rn]* where there can be multiple occurrences of ;



            "([^"rn;]*;[^";rn]*)"



            That would match





            • " Match literally


            • ( Capturing group



              • [^"rn;]* Match 0+ times not a ", newline or semicolon


              • ; Match literally


              • [^"rn;]* Match 0+ times not a ", newline or semicolon




            • ) Close capturing group


            • " Match literally


            Your value is in the first capturing group.



            Regex demo



            If you don't want to match just a semicolon between double quotes you could prepend a negative lookahead:



            (?!";")"([^"rn;]*;[^";rn]*)"






            share|improve this answer























            • Thank you for your solution. Can you modify it so it ommits cases like ";" ? That means it ommits cases where there is just semicolon between double quotes, without any characters or spaces. Thank you in advance.
              – JanFi86
              Nov 12 '18 at 15:01








            • 1




              @JanFi86 Do you mean like this? regex101.com/r/EMqrjV/3
              – The fourth bird
              Nov 12 '18 at 15:03








            • 1




              Exactly! Thank you so much!
              – JanFi86
              Nov 12 '18 at 15:06














            1












            1








            1






            You could use a negated character class where you can add what you don't want to match. If there can be only 1 semicolon in the string, then you can also add that to the character class, else you could use [^"rn]* where there can be multiple occurrences of ;



            "([^"rn;]*;[^";rn]*)"



            That would match





            • " Match literally


            • ( Capturing group



              • [^"rn;]* Match 0+ times not a ", newline or semicolon


              • ; Match literally


              • [^"rn;]* Match 0+ times not a ", newline or semicolon




            • ) Close capturing group


            • " Match literally


            Your value is in the first capturing group.



            Regex demo



            If you don't want to match just a semicolon between double quotes you could prepend a negative lookahead:



            (?!";")"([^"rn;]*;[^";rn]*)"






            share|improve this answer














            You could use a negated character class where you can add what you don't want to match. If there can be only 1 semicolon in the string, then you can also add that to the character class, else you could use [^"rn]* where there can be multiple occurrences of ;



            "([^"rn;]*;[^";rn]*)"



            That would match





            • " Match literally


            • ( Capturing group



              • [^"rn;]* Match 0+ times not a ", newline or semicolon


              • ; Match literally


              • [^"rn;]* Match 0+ times not a ", newline or semicolon




            • ) Close capturing group


            • " Match literally


            Your value is in the first capturing group.



            Regex demo



            If you don't want to match just a semicolon between double quotes you could prepend a negative lookahead:



            (?!";")"([^"rn;]*;[^";rn]*)"







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Nov 12 '18 at 15:09

























            answered Nov 12 '18 at 14:48









            The fourth bird

            20.7k71326




            20.7k71326












            • Thank you for your solution. Can you modify it so it ommits cases like ";" ? That means it ommits cases where there is just semicolon between double quotes, without any characters or spaces. Thank you in advance.
              – JanFi86
              Nov 12 '18 at 15:01








            • 1




              @JanFi86 Do you mean like this? regex101.com/r/EMqrjV/3
              – The fourth bird
              Nov 12 '18 at 15:03








            • 1




              Exactly! Thank you so much!
              – JanFi86
              Nov 12 '18 at 15:06


















            • Thank you for your solution. Can you modify it so it ommits cases like ";" ? That means it ommits cases where there is just semicolon between double quotes, without any characters or spaces. Thank you in advance.
              – JanFi86
              Nov 12 '18 at 15:01








            • 1




              @JanFi86 Do you mean like this? regex101.com/r/EMqrjV/3
              – The fourth bird
              Nov 12 '18 at 15:03








            • 1




              Exactly! Thank you so much!
              – JanFi86
              Nov 12 '18 at 15:06
















            Thank you for your solution. Can you modify it so it ommits cases like ";" ? That means it ommits cases where there is just semicolon between double quotes, without any characters or spaces. Thank you in advance.
            – JanFi86
            Nov 12 '18 at 15:01






            Thank you for your solution. Can you modify it so it ommits cases like ";" ? That means it ommits cases where there is just semicolon between double quotes, without any characters or spaces. Thank you in advance.
            – JanFi86
            Nov 12 '18 at 15:01






            1




            1




            @JanFi86 Do you mean like this? regex101.com/r/EMqrjV/3
            – The fourth bird
            Nov 12 '18 at 15:03






            @JanFi86 Do you mean like this? regex101.com/r/EMqrjV/3
            – The fourth bird
            Nov 12 '18 at 15:03






            1




            1




            Exactly! Thank you so much!
            – JanFi86
            Nov 12 '18 at 15:06




            Exactly! Thank you so much!
            – JanFi86
            Nov 12 '18 at 15:06













            0














            <?php
            $input = <<<INPUT
            a
            "something;something"
            b
            "something ; something"
            c
            "something; something"
            d
            "something ;something"
            e
            INPUT;

            preg_match_all("/"([^"]+;[^"]+)"/im", $input, $m);

            print_r($m);

            /*
            Array
            (
            [0] => Array
            (
            [0] => "something;something"
            [1] => "something ; something"
            [2] => "something; something"
            [3] => "something ;something"
            )

            [1] => Array
            (
            [0] => something;something
            [1] => something ; something
            [2] => something; something
            [3] => something ;something
            )

            )
            */





            share|improve this answer


























              0














              <?php
              $input = <<<INPUT
              a
              "something;something"
              b
              "something ; something"
              c
              "something; something"
              d
              "something ;something"
              e
              INPUT;

              preg_match_all("/"([^"]+;[^"]+)"/im", $input, $m);

              print_r($m);

              /*
              Array
              (
              [0] => Array
              (
              [0] => "something;something"
              [1] => "something ; something"
              [2] => "something; something"
              [3] => "something ;something"
              )

              [1] => Array
              (
              [0] => something;something
              [1] => something ; something
              [2] => something; something
              [3] => something ;something
              )

              )
              */





              share|improve this answer
























                0












                0








                0






                <?php
                $input = <<<INPUT
                a
                "something;something"
                b
                "something ; something"
                c
                "something; something"
                d
                "something ;something"
                e
                INPUT;

                preg_match_all("/"([^"]+;[^"]+)"/im", $input, $m);

                print_r($m);

                /*
                Array
                (
                [0] => Array
                (
                [0] => "something;something"
                [1] => "something ; something"
                [2] => "something; something"
                [3] => "something ;something"
                )

                [1] => Array
                (
                [0] => something;something
                [1] => something ; something
                [2] => something; something
                [3] => something ;something
                )

                )
                */





                share|improve this answer












                <?php
                $input = <<<INPUT
                a
                "something;something"
                b
                "something ; something"
                c
                "something; something"
                d
                "something ;something"
                e
                INPUT;

                preg_match_all("/"([^"]+;[^"]+)"/im", $input, $m);

                print_r($m);

                /*
                Array
                (
                [0] => Array
                (
                [0] => "something;something"
                [1] => "something ; something"
                [2] => "something; something"
                [3] => "something ;something"
                )

                [1] => Array
                (
                [0] => something;something
                [1] => something ; something
                [2] => something; something
                [3] => something ;something
                )

                )
                */






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 12 '18 at 14:48









                ZiTAL

                1,88232340




                1,88232340






























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