Python equivalent of R's c()?
This question has already been asked here: Python equivalent of R c() function, but unfortunately the solution given doesn't exactly apply to me.
For instance, if I combine values, into a vector or list, in R like so:
x = c(2,3,6,8)
I can preform calculations on that list, for example:
x*2
Output:
4 6 12 16
However, I'm not sure how to achieve the same thing in Python. The previously asked question (in the link above) deals with a list of numbers in a particular range. for example,
x = list(range(1:10))
I am wondering, how do I define a list of numbers (not in a range) in Python?
python
asked Nov 12 '18 at 16:43
Electrino
591312
add a comment |
This question has already been asked here: Python equivalent of R c() function, but unfortunately the solution given doesn't exactly apply to me.
For instance, if I combine values, into a vector or list, in R like so:
x = c(2,3,6,8)
I can preform calculations on that list, for example:
x*2
Output:
4 6 12 16
However, I'm not sure how to achieve the same thing in Python. The previously asked question (in the link above) deals with a list of numbers in a particular range. for example,
x = list(range(1:10))
I am wondering, how do I define a list of numbers (not in a range) in Python?
python
asked Nov 12 '18 at 16:43
Electrino
591312
2
If you're usingnumpy, then you just dox = np.array([2, 3, 6, 8])thenx * 2? eg - you actually give it alistof numbers...
– Jon Clements♦
Nov 12 '18 at 16:44
(1) That does define a list -- it just creates it from a range; (2) if you want elementwise operations on vectors/matrices/n-dim arrays, usenumpy.
– Linuxios
Nov 12 '18 at 16:45
np.arraydid the job for me. Thanks for your help
– Electrino
Nov 12 '18 at 16:52
duplicate of stackoverflow.com/questions/32443778/…
– Jean-François Fabre
Nov 12 '18 at 19:47
add a comment |
This question has already been asked here: Python equivalent of R c() function, but unfortunately the solution given doesn't exactly apply to me.
For instance, if I combine values, into a vector or list, in R like so:
x = c(2,3,6,8)
I can preform calculations on that list, for example:
x*2
Output:
4 6 12 16
However, I'm not sure how to achieve the same thing in Python. The previously asked question (in the link above) deals with a list of numbers in a particular range. for example,
x = list(range(1:10))
I am wondering, how do I define a list of numbers (not in a range) in Python?
python
asked Nov 12 '18 at 16:43
Electrino
591312
This question has already been asked here: Python equivalent of R c() function, but unfortunately the solution given doesn't exactly apply to me.
For instance, if I combine values, into a vector or list, in R like so:
x = c(2,3,6,8)
I can preform calculations on that list, for example:
x*2
Output:
4 6 12 16
However, I'm not sure how to achieve the same thing in Python. The previously asked question (in the link above) deals with a list of numbers in a particular range. for example,
x = list(range(1:10))
I am wondering, how do I define a list of numbers (not in a range) in Python?
python
python
asked Nov 12 '18 at 16:43
Electrino
591312
asked Nov 12 '18 at 16:43
Electrino
591312
asked Nov 12 '18 at 16:43
Electrino
591312
asked Nov 12 '18 at 16:43
Electrino
591312
asked Nov 12 '18 at 16:43
Electrino
591312
591312
2
If you're usingnumpy, then you just dox = np.array([2, 3, 6, 8])thenx * 2? eg - you actually give it alistof numbers...
– Jon Clements♦
Nov 12 '18 at 16:44
(1) That does define a list -- it just creates it from a range; (2) if you want elementwise operations on vectors/matrices/n-dim arrays, usenumpy.
– Linuxios
Nov 12 '18 at 16:45
np.arraydid the job for me. Thanks for your help
– Electrino
Nov 12 '18 at 16:52
duplicate of stackoverflow.com/questions/32443778/…
– Jean-François Fabre
Nov 12 '18 at 19:47
add a comment |
2
If you're usingnumpy, then you just dox = np.array([2, 3, 6, 8])thenx * 2? eg - you actually give it alistof numbers...
– Jon Clements♦
Nov 12 '18 at 16:44
(1) That does define a list -- it just creates it from a range; (2) if you want elementwise operations on vectors/matrices/n-dim arrays, usenumpy.
– Linuxios
Nov 12 '18 at 16:45
np.arraydid the job for me. Thanks for your help
– Electrino
Nov 12 '18 at 16:52
duplicate of stackoverflow.com/questions/32443778/…
– Jean-François Fabre
Nov 12 '18 at 19:47
2
2
If you're using
numpy, then you just do x = np.array([2, 3, 6, 8]) then x * 2 ? eg - you actually give it a list of numbers...– Jon Clements♦
Nov 12 '18 at 16:44
If you're using
numpy, then you just do x = np.array([2, 3, 6, 8]) then x * 2 ? eg - you actually give it a list of numbers...– Jon Clements♦
Nov 12 '18 at 16:44
(1) That does define a list -- it just creates it from a range; (2) if you want elementwise operations on vectors/matrices/n-dim arrays, use
numpy.– Linuxios
Nov 12 '18 at 16:45
(1) That does define a list -- it just creates it from a range; (2) if you want elementwise operations on vectors/matrices/n-dim arrays, use
numpy.– Linuxios
Nov 12 '18 at 16:45
np.array did the job for me. Thanks for your help– Electrino
Nov 12 '18 at 16:52
np.array did the job for me. Thanks for your help– Electrino
Nov 12 '18 at 16:52
duplicate of stackoverflow.com/questions/32443778/…
– Jean-François Fabre
Nov 12 '18 at 19:47
duplicate of stackoverflow.com/questions/32443778/…
– Jean-François Fabre
Nov 12 '18 at 19:47
add a comment |
1 Answer
1
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in python, you could use numpy arrays to do such things
import numpy
x = numpy.array([2, 3, 7])
y = x*2
and y will be equal to numpy.array([4, 6, 14])
answered Nov 12 '18 at 16:46
evinoshea
224
I'm afraid not, that would produce:[2, 3, 7, 2, 3, 7]
– LeKhan9
Nov 12 '18 at 16:47
Python does that for a different purpose.
– Austin
Nov 12 '18 at 16:49
Thats my bad, I was thinking of numpy arrays, which should have just been my original answer...
– evinoshea
Nov 12 '18 at 17:31
add a comment |
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1 Answer
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in python, you could use numpy arrays to do such things
import numpy
x = numpy.array([2, 3, 7])
y = x*2
and y will be equal to numpy.array([4, 6, 14])
answered Nov 12 '18 at 16:46
evinoshea
224
I'm afraid not, that would produce:[2, 3, 7, 2, 3, 7]
– LeKhan9
Nov 12 '18 at 16:47
Python does that for a different purpose.
– Austin
Nov 12 '18 at 16:49
Thats my bad, I was thinking of numpy arrays, which should have just been my original answer...
– evinoshea
Nov 12 '18 at 17:31
add a comment |
in python, you could use numpy arrays to do such things
import numpy
x = numpy.array([2, 3, 7])
y = x*2
and y will be equal to numpy.array([4, 6, 14])
answered Nov 12 '18 at 16:46
evinoshea
224
I'm afraid not, that would produce:[2, 3, 7, 2, 3, 7]
– LeKhan9
Nov 12 '18 at 16:47
Python does that for a different purpose.
– Austin
Nov 12 '18 at 16:49
Thats my bad, I was thinking of numpy arrays, which should have just been my original answer...
– evinoshea
Nov 12 '18 at 17:31
add a comment |
in python, you could use numpy arrays to do such things
import numpy
x = numpy.array([2, 3, 7])
y = x*2
and y will be equal to numpy.array([4, 6, 14])
answered Nov 12 '18 at 16:46
evinoshea
224
in python, you could use numpy arrays to do such things
import numpy
x = numpy.array([2, 3, 7])
y = x*2
and y will be equal to numpy.array([4, 6, 14])
answered Nov 12 '18 at 16:46
evinoshea
224
edited Nov 12 '18 at 17:30
answered Nov 12 '18 at 16:46
evinoshea
224
answered Nov 12 '18 at 16:46
evinoshea
224
answered Nov 12 '18 at 16:46
evinoshea
224
224
I'm afraid not, that would produce:[2, 3, 7, 2, 3, 7]
– LeKhan9
Nov 12 '18 at 16:47
Python does that for a different purpose.
– Austin
Nov 12 '18 at 16:49
Thats my bad, I was thinking of numpy arrays, which should have just been my original answer...
– evinoshea
Nov 12 '18 at 17:31
add a comment |
I'm afraid not, that would produce:[2, 3, 7, 2, 3, 7]
– LeKhan9
Nov 12 '18 at 16:47
Python does that for a different purpose.
– Austin
Nov 12 '18 at 16:49
Thats my bad, I was thinking of numpy arrays, which should have just been my original answer...
– evinoshea
Nov 12 '18 at 17:31
I'm afraid not, that would produce:
[2, 3, 7, 2, 3, 7]– LeKhan9
Nov 12 '18 at 16:47
I'm afraid not, that would produce:
[2, 3, 7, 2, 3, 7]– LeKhan9
Nov 12 '18 at 16:47
Python does that for a different purpose.
– Austin
Nov 12 '18 at 16:49
Python does that for a different purpose.
– Austin
Nov 12 '18 at 16:49
Thats my bad, I was thinking of numpy arrays, which should have just been my original answer...
– evinoshea
Nov 12 '18 at 17:31
Thats my bad, I was thinking of numpy arrays, which should have just been my original answer...
– evinoshea
Nov 12 '18 at 17:31
add a comment |
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2
If you're using
numpy, then you just dox = np.array([2, 3, 6, 8])thenx * 2? eg - you actually give it alistof numbers...– Jon Clements♦
Nov 12 '18 at 16:44
(1) That does define a list -- it just creates it from a range; (2) if you want elementwise operations on vectors/matrices/n-dim arrays, use
numpy.– Linuxios
Nov 12 '18 at 16:45
np.arraydid the job for me. Thanks for your help– Electrino
Nov 12 '18 at 16:52
duplicate of stackoverflow.com/questions/32443778/…
– Jean-François Fabre
Nov 12 '18 at 19:47