Accessing a class name that is stored in the Jquery variable

There are three pictures on the site.

<img src="images/kep1.jpg" class="kep1">

<img src="images/kep2.jpg" class="kep2">

<img src="images/kep4.jpg" class="kep4">

Click function to magnify one page at a time in the middle of the page page, but I'll store the necessary data in a variable.

var pos;

    var t;

    var h;

    var pic;

$("img").click(function(){

            pos = $(this).css("position");

            pic = $(this).attr("class");

            t = $(this).css("top");

            h = $(this).css("height");

            $(".szurkeDiv").show();

            $(this).animate(

                {

                    "position" : "fixed",

                    "top" : "50%",

                    "left" : "50%",

                    "margin-top" : "-300px",

                    "margin-left" : "-400px",

                    "width" : "800px",

                    "height" : "600px"

                }, 1000, function(){}

            );

        });

Then I want you to click on the image in the middle of the page to animate it back to its original location. I would like to access the PIC variable but not succeed.

$(pic).animate(

                {

                    "position" : pos,

                    "width" : "150px",

                    "margin-top" : "0px",

                    "margin-left" : "0px",

                    "left" : "5px",

                    "height" : h,

                    "top" : t

                }, 1000, function(){}

            );

How can I do this well, refer to the PIC variable?

Thanks for the help!!

edited Nov 12 '18 at 16:58

asked Nov 12 '18 at 16:52

PengeDroid

135

Possible duplicate of jquery select elements by class using name from variable
– Heretic Monkey
Nov 12 '18 at 17:11

jQuery is not a language, it's a library for JavaScript. It doesn't do any magic, it's written in JavaScript code. You should learn the basics of JavaScript before trying to learn how to use any third-party library. I'm not trying to sound judgmental here, just save yourself some trouble and sit through a proper lesson.
– Jacque Goupil
Nov 12 '18 at 17:13

I'm just learning this. This was the home lesson! :-)
– PengeDroid
Nov 12 '18 at 17:40

add a comment |

There are three pictures on the site.

<img src="images/kep1.jpg" class="kep1">

<img src="images/kep2.jpg" class="kep2">

<img src="images/kep4.jpg" class="kep4">

Click function to magnify one page at a time in the middle of the page page, but I'll store the necessary data in a variable.

var pos;

    var t;

    var h;

    var pic;

$("img").click(function(){

            pos = $(this).css("position");

            pic = $(this).attr("class");

            t = $(this).css("top");

            h = $(this).css("height");

            $(".szurkeDiv").show();

            $(this).animate(

                {

                    "position" : "fixed",

                    "top" : "50%",

                    "left" : "50%",

                    "margin-top" : "-300px",

                    "margin-left" : "-400px",

                    "width" : "800px",

                    "height" : "600px"

                }, 1000, function(){}

            );

        });

Then I want you to click on the image in the middle of the page to animate it back to its original location. I would like to access the PIC variable but not succeed.

$(pic).animate(

                {

                    "position" : pos,

                    "width" : "150px",

                    "margin-top" : "0px",

                    "margin-left" : "0px",

                    "left" : "5px",

                    "height" : h,

                    "top" : t

                }, 1000, function(){}

            );

How can I do this well, refer to the PIC variable?

Thanks for the help!!

edited Nov 12 '18 at 16:58

asked Nov 12 '18 at 16:52

PengeDroid

135

Possible duplicate of jquery select elements by class using name from variable
– Heretic Monkey
Nov 12 '18 at 17:11

jQuery is not a language, it's a library for JavaScript. It doesn't do any magic, it's written in JavaScript code. You should learn the basics of JavaScript before trying to learn how to use any third-party library. I'm not trying to sound judgmental here, just save yourself some trouble and sit through a proper lesson.
– Jacque Goupil
Nov 12 '18 at 17:13

I'm just learning this. This was the home lesson! :-)
– PengeDroid
Nov 12 '18 at 17:40

add a comment |

There are three pictures on the site.

<img src="images/kep1.jpg" class="kep1">

<img src="images/kep2.jpg" class="kep2">

<img src="images/kep4.jpg" class="kep4">

Click function to magnify one page at a time in the middle of the page page, but I'll store the necessary data in a variable.

var pos;

    var t;

    var h;

    var pic;

$("img").click(function(){

            pos = $(this).css("position");

            pic = $(this).attr("class");

            t = $(this).css("top");

            h = $(this).css("height");

            $(".szurkeDiv").show();

            $(this).animate(

                {

                    "position" : "fixed",

                    "top" : "50%",

                    "left" : "50%",

                    "margin-top" : "-300px",

                    "margin-left" : "-400px",

                    "width" : "800px",

                    "height" : "600px"

                }, 1000, function(){}

            );

        });

Then I want you to click on the image in the middle of the page to animate it back to its original location. I would like to access the PIC variable but not succeed.

$(pic).animate(

                {

                    "position" : pos,

                    "width" : "150px",

                    "margin-top" : "0px",

                    "margin-left" : "0px",

                    "left" : "5px",

                    "height" : h,

                    "top" : t

                }, 1000, function(){}

            );

How can I do this well, refer to the PIC variable?

Thanks for the help!!

edited Nov 12 '18 at 16:58

asked Nov 12 '18 at 16:52

PengeDroid

135

There are three pictures on the site.

<img src="images/kep1.jpg" class="kep1">

<img src="images/kep2.jpg" class="kep2">

<img src="images/kep4.jpg" class="kep4">

Click function to magnify one page at a time in the middle of the page page, but I'll store the necessary data in a variable.

var pos;

    var t;

    var h;

    var pic;

$("img").click(function(){

            pos = $(this).css("position");

            pic = $(this).attr("class");

            t = $(this).css("top");

            h = $(this).css("height");

            $(".szurkeDiv").show();

            $(this).animate(

                {

                    "position" : "fixed",

                    "top" : "50%",

                    "left" : "50%",

                    "margin-top" : "-300px",

                    "margin-left" : "-400px",

                    "width" : "800px",

                    "height" : "600px"

                }, 1000, function(){}

            );

        });

Then I want you to click on the image in the middle of the page to animate it back to its original location. I would like to access the PIC variable but not succeed.

$(pic).animate(

                {

                    "position" : pos,

                    "width" : "150px",

                    "margin-top" : "0px",

                    "margin-left" : "0px",

                    "left" : "5px",

                    "height" : h,

                    "top" : t

                }, 1000, function(){}

            );

How can I do this well, refer to the PIC variable?

Thanks for the help!!

jquery html css

edited Nov 12 '18 at 16:58

asked Nov 12 '18 at 16:52

PengeDroid

135

edited Nov 12 '18 at 16:58

asked Nov 12 '18 at 16:52

PengeDroid

135

edited Nov 12 '18 at 16:58

asked Nov 12 '18 at 16:52

PengeDroid

135

asked Nov 12 '18 at 16:52

PengeDroid

135

asked Nov 12 '18 at 16:52

PengeDroid

135

Possible duplicate of jquery select elements by class using name from variable
– Heretic Monkey
Nov 12 '18 at 17:11

jQuery is not a language, it's a library for JavaScript. It doesn't do any magic, it's written in JavaScript code. You should learn the basics of JavaScript before trying to learn how to use any third-party library. I'm not trying to sound judgmental here, just save yourself some trouble and sit through a proper lesson.
– Jacque Goupil
Nov 12 '18 at 17:13

I'm just learning this. This was the home lesson! :-)
– PengeDroid
Nov 12 '18 at 17:40

add a comment |

Possible duplicate of jquery select elements by class using name from variable
– Heretic Monkey
Nov 12 '18 at 17:11

jQuery is not a language, it's a library for JavaScript. It doesn't do any magic, it's written in JavaScript code. You should learn the basics of JavaScript before trying to learn how to use any third-party library. I'm not trying to sound judgmental here, just save yourself some trouble and sit through a proper lesson.
– Jacque Goupil
Nov 12 '18 at 17:13

I'm just learning this. This was the home lesson! :-)
– PengeDroid
Nov 12 '18 at 17:40

Possible duplicate of jquery select elements by class using name from variable
– Heretic Monkey
Nov 12 '18 at 17:11

jQuery is not a language, it's a library for JavaScript. It doesn't do any magic, it's written in JavaScript code. You should learn the basics of JavaScript before trying to learn how to use any third-party library. I'm not trying to sound judgmental here, just save yourself some trouble and sit through a proper lesson.
– Jacque Goupil
Nov 12 '18 at 17:13

I'm just learning this. This was the home lesson! :-)
– PengeDroid
Nov 12 '18 at 17:40

add a comment |

2 Answers
2

active

oldest

votes

try it with $('.' + pic) instead of $(pic).

See https://jsfiddle.net/g15v3c4z/

var pic = $('p').attr("class");



$('.' + pic).html('world!');

answered Nov 12 '18 at 17:02

Andreas

443

Thanks!!! :-)))
– PengeDroid
Nov 12 '18 at 17:44

add a comment |

Use plain CSS for the animation:

var img = $("img")



img.on("click", function(){

  $(this).toggleClass("zoom");

})

img {

    transition: all 0.5s ease;



}



.zoom {

  transform:scale(2);

  transform-origin: 0 0;

}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="container">

  <img src="https://via.placeholder.com/350" alt="">

    <img src="https://via.placeholder.com/350" alt="">



  <img src="https://via.placeholder.com/350" alt="">



</div>

answered Nov 12 '18 at 17:24

Ihsan S

324

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

try it with $('.' + pic) instead of $(pic).

See https://jsfiddle.net/g15v3c4z/

var pic = $('p').attr("class");



$('.' + pic).html('world!');

answered Nov 12 '18 at 17:02

Andreas

443

Thanks!!! :-)))
– PengeDroid
Nov 12 '18 at 17:44

add a comment |

try it with $('.' + pic) instead of $(pic).

See https://jsfiddle.net/g15v3c4z/

var pic = $('p').attr("class");



$('.' + pic).html('world!');

answered Nov 12 '18 at 17:02

Andreas

443

Thanks!!! :-)))
– PengeDroid
Nov 12 '18 at 17:44

add a comment |

try it with $('.' + pic) instead of $(pic).

See https://jsfiddle.net/g15v3c4z/

var pic = $('p').attr("class");



$('.' + pic).html('world!');

answered Nov 12 '18 at 17:02

Andreas

443

try it with $('.' + pic) instead of $(pic).

See https://jsfiddle.net/g15v3c4z/

var pic = $('p').attr("class");



$('.' + pic).html('world!');

answered Nov 12 '18 at 17:02

Andreas

443

answered Nov 12 '18 at 17:02

Andreas

443

answered Nov 12 '18 at 17:02

Andreas

443

answered Nov 12 '18 at 17:02

Andreas

443

Thanks!!! :-)))
– PengeDroid
Nov 12 '18 at 17:44

add a comment |

Thanks!!! :-)))
– PengeDroid
Nov 12 '18 at 17:44

Thanks!!! :-)))
– PengeDroid
Nov 12 '18 at 17:44

add a comment |

Use plain CSS for the animation:

var img = $("img")



img.on("click", function(){

  $(this).toggleClass("zoom");

})

img {

    transition: all 0.5s ease;



}



.zoom {

  transform:scale(2);

  transform-origin: 0 0;

}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="container">

  <img src="https://via.placeholder.com/350" alt="">

    <img src="https://via.placeholder.com/350" alt="">



  <img src="https://via.placeholder.com/350" alt="">



</div>

answered Nov 12 '18 at 17:24

Ihsan S

324

add a comment |

Use plain CSS for the animation:

var img = $("img")



img.on("click", function(){

  $(this).toggleClass("zoom");

})

img {

    transition: all 0.5s ease;



}



.zoom {

  transform:scale(2);

  transform-origin: 0 0;

}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="container">

  <img src="https://via.placeholder.com/350" alt="">

    <img src="https://via.placeholder.com/350" alt="">



  <img src="https://via.placeholder.com/350" alt="">



</div>

answered Nov 12 '18 at 17:24

Ihsan S

324

add a comment |

Use plain CSS for the animation:

var img = $("img")



img.on("click", function(){

  $(this).toggleClass("zoom");

})

img {

    transition: all 0.5s ease;



}



.zoom {

  transform:scale(2);

  transform-origin: 0 0;

}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="container">

  <img src="https://via.placeholder.com/350" alt="">

    <img src="https://via.placeholder.com/350" alt="">



  <img src="https://via.placeholder.com/350" alt="">



</div>

answered Nov 12 '18 at 17:24

Ihsan S

324

Use plain CSS for the animation:

var img = $("img")



img.on("click", function(){

  $(this).toggleClass("zoom");

})

img {

    transition: all 0.5s ease;



}



.zoom {

  transform:scale(2);

  transform-origin: 0 0;

}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="container">

  <img src="https://via.placeholder.com/350" alt="">

    <img src="https://via.placeholder.com/350" alt="">



  <img src="https://via.placeholder.com/350" alt="">



</div>

var img = $("img")



img.on("click", function(){

  $(this).toggleClass("zoom");

})

img {

    transition: all 0.5s ease;



}



.zoom {

  transform:scale(2);

  transform-origin: 0 0;

}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="container">

  <img src="https://via.placeholder.com/350" alt="">

    <img src="https://via.placeholder.com/350" alt="">



  <img src="https://via.placeholder.com/350" alt="">



</div>

var img = $("img")



img.on("click", function(){

  $(this).toggleClass("zoom");

})

img {

    transition: all 0.5s ease;



}



.zoom {

  transform:scale(2);

  transform-origin: 0 0;

}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="container">

  <img src="https://via.placeholder.com/350" alt="">

    <img src="https://via.placeholder.com/350" alt="">



  <img src="https://via.placeholder.com/350" alt="">



</div>

answered Nov 12 '18 at 17:24

Ihsan S

324

answered Nov 12 '18 at 17:24

Ihsan S

324

answered Nov 12 '18 at 17:24

Ihsan S

324

answered Nov 12 '18 at 17:24

Ihsan S

324

add a comment |

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