Adding a counter to a DataTemplate
I have a DataTemplate for an ItemsControl that outputs a Grid with some binded controls, and this works as expected.
However, I want the first column of the Grid to output a counter of each Grid made.
For example...
<DataTemplate x:Key="myDataTemplate">
<Grid>
<Grid.ColumnDefinitions>
<ColumnDefinition Width="75" />
<ColumnDefinition Width="150" />
</Grid.ColumnDefinitions>
<TextBlock Text="X" /> <!-- I want a counter to go here -->
<TextBox Grid.Column="1" Text="{Binding Path=Name}" />
</Grid>
</DataTemplate>
I want that first TextBlock to display 1, 2, 3, 4, etc... as the DataTemplate outputs new Grids.
Any ideas on the best way to do that?
Thanks!
xaml datatemplate
add a comment |
I have a DataTemplate for an ItemsControl that outputs a Grid with some binded controls, and this works as expected.
However, I want the first column of the Grid to output a counter of each Grid made.
For example...
<DataTemplate x:Key="myDataTemplate">
<Grid>
<Grid.ColumnDefinitions>
<ColumnDefinition Width="75" />
<ColumnDefinition Width="150" />
</Grid.ColumnDefinitions>
<TextBlock Text="X" /> <!-- I want a counter to go here -->
<TextBox Grid.Column="1" Text="{Binding Path=Name}" />
</Grid>
</DataTemplate>
I want that first TextBlock to display 1, 2, 3, 4, etc... as the DataTemplate outputs new Grids.
Any ideas on the best way to do that?
Thanks!
xaml datatemplate
add a comment |
I have a DataTemplate for an ItemsControl that outputs a Grid with some binded controls, and this works as expected.
However, I want the first column of the Grid to output a counter of each Grid made.
For example...
<DataTemplate x:Key="myDataTemplate">
<Grid>
<Grid.ColumnDefinitions>
<ColumnDefinition Width="75" />
<ColumnDefinition Width="150" />
</Grid.ColumnDefinitions>
<TextBlock Text="X" /> <!-- I want a counter to go here -->
<TextBox Grid.Column="1" Text="{Binding Path=Name}" />
</Grid>
</DataTemplate>
I want that first TextBlock to display 1, 2, 3, 4, etc... as the DataTemplate outputs new Grids.
Any ideas on the best way to do that?
Thanks!
xaml datatemplate
I have a DataTemplate for an ItemsControl that outputs a Grid with some binded controls, and this works as expected.
However, I want the first column of the Grid to output a counter of each Grid made.
For example...
<DataTemplate x:Key="myDataTemplate">
<Grid>
<Grid.ColumnDefinitions>
<ColumnDefinition Width="75" />
<ColumnDefinition Width="150" />
</Grid.ColumnDefinitions>
<TextBlock Text="X" /> <!-- I want a counter to go here -->
<TextBox Grid.Column="1" Text="{Binding Path=Name}" />
</Grid>
</DataTemplate>
I want that first TextBlock to display 1, 2, 3, 4, etc... as the DataTemplate outputs new Grids.
Any ideas on the best way to do that?
Thanks!
xaml datatemplate
xaml datatemplate
asked Nov 19 '18 at 19:16
user642153
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You can achieve this using AlternationCount and AlternationIndex of ItemsControl. Like,
<ItemsControl ItemsSource="{Binding Items}" AlternationCount="{Binding Items.Count}">
<ItemsControl.ItemTemplate>
<DataTemplate x:Key="myDataTemplate">
<Grid>
<Grid.ColumnDefinitions>
<ColumnDefinition Width="75" />
<ColumnDefinition Width="150" />
</Grid.ColumnDefinitions>
<TextBlock Text="{Binding Path=(ItemsControl.AlternationIndex), RelativeSource={RelativeSource TemplatedParent}}" />
<TextBox Grid.Column="1" Text="{Binding Path=Name}" />
</Grid>
</DataTemplate>
</ItemsControl.ItemTemplate>
</ItemsControl>
This will give you 0 based index; you can use IValueConverter if any changes needed.
answered Nov 20 '18 at 15:02
dhilmathydhilmathy
1,6341917
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53381221%2fadding-a-counter-to-a-datatemplate%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can achieve this using AlternationCount and AlternationIndex of ItemsControl. Like,
<ItemsControl ItemsSource="{Binding Items}" AlternationCount="{Binding Items.Count}">
<ItemsControl.ItemTemplate>
<DataTemplate x:Key="myDataTemplate">
<Grid>
<Grid.ColumnDefinitions>
<ColumnDefinition Width="75" />
<ColumnDefinition Width="150" />
</Grid.ColumnDefinitions>
<TextBlock Text="{Binding Path=(ItemsControl.AlternationIndex), RelativeSource={RelativeSource TemplatedParent}}" />
<TextBox Grid.Column="1" Text="{Binding Path=Name}" />
</Grid>
</DataTemplate>
</ItemsControl.ItemTemplate>
</ItemsControl>
This will give you 0 based index; you can use IValueConverter if any changes needed.
answered Nov 20 '18 at 15:02
dhilmathydhilmathy
1,6341917
add a comment |
You can achieve this using AlternationCount and AlternationIndex of ItemsControl. Like,
<ItemsControl ItemsSource="{Binding Items}" AlternationCount="{Binding Items.Count}">
<ItemsControl.ItemTemplate>
<DataTemplate x:Key="myDataTemplate">
<Grid>
<Grid.ColumnDefinitions>
<ColumnDefinition Width="75" />
<ColumnDefinition Width="150" />
</Grid.ColumnDefinitions>
<TextBlock Text="{Binding Path=(ItemsControl.AlternationIndex), RelativeSource={RelativeSource TemplatedParent}}" />
<TextBox Grid.Column="1" Text="{Binding Path=Name}" />
</Grid>
</DataTemplate>
</ItemsControl.ItemTemplate>
</ItemsControl>
This will give you 0 based index; you can use IValueConverter if any changes needed.
answered Nov 20 '18 at 15:02
dhilmathydhilmathy
1,6341917
add a comment |
You can achieve this using AlternationCount and AlternationIndex of ItemsControl. Like,
<ItemsControl ItemsSource="{Binding Items}" AlternationCount="{Binding Items.Count}">
<ItemsControl.ItemTemplate>
<DataTemplate x:Key="myDataTemplate">
<Grid>
<Grid.ColumnDefinitions>
<ColumnDefinition Width="75" />
<ColumnDefinition Width="150" />
</Grid.ColumnDefinitions>
<TextBlock Text="{Binding Path=(ItemsControl.AlternationIndex), RelativeSource={RelativeSource TemplatedParent}}" />
<TextBox Grid.Column="1" Text="{Binding Path=Name}" />
</Grid>
</DataTemplate>
</ItemsControl.ItemTemplate>
</ItemsControl>
This will give you 0 based index; you can use IValueConverter if any changes needed.
answered Nov 20 '18 at 15:02
dhilmathydhilmathy
1,6341917
You can achieve this using AlternationCount and AlternationIndex of ItemsControl. Like,
<ItemsControl ItemsSource="{Binding Items}" AlternationCount="{Binding Items.Count}">
<ItemsControl.ItemTemplate>
<DataTemplate x:Key="myDataTemplate">
<Grid>
<Grid.ColumnDefinitions>
<ColumnDefinition Width="75" />
<ColumnDefinition Width="150" />
</Grid.ColumnDefinitions>
<TextBlock Text="{Binding Path=(ItemsControl.AlternationIndex), RelativeSource={RelativeSource TemplatedParent}}" />
<TextBox Grid.Column="1" Text="{Binding Path=Name}" />
</Grid>
</DataTemplate>
</ItemsControl.ItemTemplate>
</ItemsControl>
This will give you 0 based index; you can use IValueConverter if any changes needed.
answered Nov 20 '18 at 15:02
dhilmathydhilmathy
1,6341917
answered Nov 20 '18 at 15:02
dhilmathydhilmathy
1,6341917
answered Nov 20 '18 at 15:02
dhilmathydhilmathy
1,6341917
answered Nov 20 '18 at 15:02
dhilmathydhilmathy
1,6341917
1,6341917
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53381221%2fadding-a-counter-to-a-datatemplate%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
