postgres: Combining filter() with a percentile_cont()
Trying to use a filter()
clause within a call to percentile_const
and I am not sure I can do this. Is there a way? Here's the example query:
select
count(*) as n1,
count(*) filter(where ha >= 0) as n2,
percentile_cont(.9) within group (order by es asc) as p1,
percentile_cont(.9) filter (where ha >= 0) within group (order by es asc) as p2
from mytable where mypid = 123;
The query works fine without the p2
call of course, but you can see what I want to do.
postgresql
add a comment |
Trying to use a filter()
clause within a call to percentile_const
and I am not sure I can do this. Is there a way? Here's the example query:
select
count(*) as n1,
count(*) filter(where ha >= 0) as n2,
percentile_cont(.9) within group (order by es asc) as p1,
percentile_cont(.9) filter (where ha >= 0) within group (order by es asc) as p2
from mytable where mypid = 123;
The query works fine without the p2
call of course, but you can see what I want to do.
postgresql
add a comment |
Trying to use a filter()
clause within a call to percentile_const
and I am not sure I can do this. Is there a way? Here's the example query:
select
count(*) as n1,
count(*) filter(where ha >= 0) as n2,
percentile_cont(.9) within group (order by es asc) as p1,
percentile_cont(.9) filter (where ha >= 0) within group (order by es asc) as p2
from mytable where mypid = 123;
The query works fine without the p2
call of course, but you can see what I want to do.
postgresql
Trying to use a filter()
clause within a call to percentile_const
and I am not sure I can do this. Is there a way? Here's the example query:
select
count(*) as n1,
count(*) filter(where ha >= 0) as n2,
percentile_cont(.9) within group (order by es asc) as p1,
percentile_cont(.9) filter (where ha >= 0) within group (order by es asc) as p2
from mytable where mypid = 123;
The query works fine without the p2
call of course, but you can see what I want to do.
postgresql
postgresql
asked Nov 19 '18 at 19:25
WellsWells
3,59083763
3,59083763
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
The filter
needs to go after the within group
part:
select
count(*) as n1,
count(*) filter(where ha >= 0) as n2,
percentile_cont(.9) within group (order by es asc) as p1,
percentile_cont(.9) within group (order by es asc) filter (where ha >= 0) as p2
from mytable
where mypid = 123;
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53381325%2fpostgres-combining-filter-with-a-percentile-cont%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The filter
needs to go after the within group
part:
select
count(*) as n1,
count(*) filter(where ha >= 0) as n2,
percentile_cont(.9) within group (order by es asc) as p1,
percentile_cont(.9) within group (order by es asc) filter (where ha >= 0) as p2
from mytable
where mypid = 123;
add a comment |
The filter
needs to go after the within group
part:
select
count(*) as n1,
count(*) filter(where ha >= 0) as n2,
percentile_cont(.9) within group (order by es asc) as p1,
percentile_cont(.9) within group (order by es asc) filter (where ha >= 0) as p2
from mytable
where mypid = 123;
add a comment |
The filter
needs to go after the within group
part:
select
count(*) as n1,
count(*) filter(where ha >= 0) as n2,
percentile_cont(.9) within group (order by es asc) as p1,
percentile_cont(.9) within group (order by es asc) filter (where ha >= 0) as p2
from mytable
where mypid = 123;
The filter
needs to go after the within group
part:
select
count(*) as n1,
count(*) filter(where ha >= 0) as n2,
percentile_cont(.9) within group (order by es asc) as p1,
percentile_cont(.9) within group (order by es asc) filter (where ha >= 0) as p2
from mytable
where mypid = 123;
answered Nov 19 '18 at 21:31
a_horse_with_no_namea_horse_with_no_name
298k46456548
298k46456548
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53381325%2fpostgres-combining-filter-with-a-percentile-cont%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown