Getting different String from snapshot.getKey(); and mAuth.getUid(); Without .push();
String I am getting from snapshot.getKey(); is different from any other String, although I am not doing push() if i virtually compare the values of my mAuth.getUid(); string and snapshot.getKey(); they both are same, but programmatically it is not showing.
I tried concatinating my snapshot.getKey(); string in textView.setText(snapshot.getKey();); also but nothing is shown in the screen.
Please note I am not posting my whole Fragment code.
In the code below the if statement is not getting true value.
FirebaseUser mAuth = FirebaseAuth.getInstance().getCurrentUser();
FirebaseDatabase database = FirebaseDatabase.getInstance();
DatabaseReference databaseReference = database.getReference();
DatabaseReference userref = databaseReference.child("Votes").child("Chat");
final HashMap<String, String> hash = new HashMap<>();
likeButton = (ImageView) view.findViewById(R.id.heartImage);
likeButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
hash.put("chatVoteLike", "Yes, I would like it");
userref.child(mAuth.getUid()).setValue(hash);
likeButton.setImageResource(R.drawable.red_heart);
}
});
userref.orderByKey().addValueEventListener(new ValueEventListener() {
@Override
public void onDataChange(DataSnapshot dataSnapshot) {
for (DataSnapshot snapshot : dataSnapshot.getChildren()){
String uID = snapshot.getKey();
Log.i("uId from", "firebase ---" + uID);
if (uID == mAuth.getUid()){
likeButton.setImageResource(R.drawable.red_heart);
}
}
}
@Override
public void onCancelled(DatabaseError databaseError) {
}
});
java
android 
android-studio firebase-realtime-database asked Nov 19 '18 at 19:25
kvadityaazkvadityaaz
13416
|
show 6 more comments
String I am getting from snapshot.getKey(); is different from any other String, although I am not doing push() if i virtually compare the values of my mAuth.getUid(); string and snapshot.getKey(); they both are same, but programmatically it is not showing.
I tried concatinating my snapshot.getKey(); string in textView.setText(snapshot.getKey();); also but nothing is shown in the screen.
Please note I am not posting my whole Fragment code.
In the code below the if statement is not getting true value.
FirebaseUser mAuth = FirebaseAuth.getInstance().getCurrentUser();
FirebaseDatabase database = FirebaseDatabase.getInstance();
DatabaseReference databaseReference = database.getReference();
DatabaseReference userref = databaseReference.child("Votes").child("Chat");
final HashMap<String, String> hash = new HashMap<>();
likeButton = (ImageView) view.findViewById(R.id.heartImage);
likeButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
hash.put("chatVoteLike", "Yes, I would like it");
userref.child(mAuth.getUid()).setValue(hash);
likeButton.setImageResource(R.drawable.red_heart);
}
});
userref.orderByKey().addValueEventListener(new ValueEventListener() {
@Override
public void onDataChange(DataSnapshot dataSnapshot) {
for (DataSnapshot snapshot : dataSnapshot.getChildren()){
String uID = snapshot.getKey();
Log.i("uId from", "firebase ---" + uID);
if (uID == mAuth.getUid()){
likeButton.setImageResource(R.drawable.red_heart);
}
}
}
@Override
public void onCancelled(DatabaseError databaseError) {
}
});
java
android android-studio firebase-realtime-database asked Nov 19 '18 at 19:25
kvadityaazkvadityaaz
13416
Please add your database structure.
– Alex Mamo
Nov 19 '18 at 19:30
added the screenshot
– kvadityaaz
Nov 19 '18 at 19:48
So you basically say thatmAuth.getUid()andsnapshot.getKey()return different result, right?
– Alex Mamo
Nov 19 '18 at 19:50
Yes, virtually the results are same but Programmatically they are different, although both are String .
– kvadityaaz
Nov 19 '18 at 19:56
1
Try usinguID.equals(mAuth.getUid())instead ofuID == mAuth.getUid()
– Jantzilla
Nov 20 '18 at 0:27
|
show 6 more comments
String I am getting from snapshot.getKey(); is different from any other String, although I am not doing push() if i virtually compare the values of my mAuth.getUid(); string and snapshot.getKey(); they both are same, but programmatically it is not showing.
I tried concatinating my snapshot.getKey(); string in textView.setText(snapshot.getKey();); also but nothing is shown in the screen.
Please note I am not posting my whole Fragment code.
In the code below the if statement is not getting true value.
FirebaseUser mAuth = FirebaseAuth.getInstance().getCurrentUser();
FirebaseDatabase database = FirebaseDatabase.getInstance();
DatabaseReference databaseReference = database.getReference();
DatabaseReference userref = databaseReference.child("Votes").child("Chat");
final HashMap<String, String> hash = new HashMap<>();
likeButton = (ImageView) view.findViewById(R.id.heartImage);
likeButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
hash.put("chatVoteLike", "Yes, I would like it");
userref.child(mAuth.getUid()).setValue(hash);
likeButton.setImageResource(R.drawable.red_heart);
}
});
userref.orderByKey().addValueEventListener(new ValueEventListener() {
@Override
public void onDataChange(DataSnapshot dataSnapshot) {
for (DataSnapshot snapshot : dataSnapshot.getChildren()){
String uID = snapshot.getKey();
Log.i("uId from", "firebase ---" + uID);
if (uID == mAuth.getUid()){
likeButton.setImageResource(R.drawable.red_heart);
}
}
}
@Override
public void onCancelled(DatabaseError databaseError) {
}
});
java
android android-studio firebase-realtime-database asked Nov 19 '18 at 19:25
kvadityaazkvadityaaz
13416
String I am getting from snapshot.getKey(); is different from any other String, although I am not doing push() if i virtually compare the values of my mAuth.getUid(); string and snapshot.getKey(); they both are same, but programmatically it is not showing.
I tried concatinating my snapshot.getKey(); string in textView.setText(snapshot.getKey();); also but nothing is shown in the screen.
Please note I am not posting my whole Fragment code.
In the code below the if statement is not getting true value.
FirebaseUser mAuth = FirebaseAuth.getInstance().getCurrentUser();
FirebaseDatabase database = FirebaseDatabase.getInstance();
DatabaseReference databaseReference = database.getReference();
DatabaseReference userref = databaseReference.child("Votes").child("Chat");
final HashMap<String, String> hash = new HashMap<>();
likeButton = (ImageView) view.findViewById(R.id.heartImage);
likeButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
hash.put("chatVoteLike", "Yes, I would like it");
userref.child(mAuth.getUid()).setValue(hash);
likeButton.setImageResource(R.drawable.red_heart);
}
});
userref.orderByKey().addValueEventListener(new ValueEventListener() {
@Override
public void onDataChange(DataSnapshot dataSnapshot) {
for (DataSnapshot snapshot : dataSnapshot.getChildren()){
String uID = snapshot.getKey();
Log.i("uId from", "firebase ---" + uID);
if (uID == mAuth.getUid()){
likeButton.setImageResource(R.drawable.red_heart);
}
}
}
@Override
public void onCancelled(DatabaseError databaseError) {
}
});
java
android android-studio firebase-realtime-database java
android android-studio firebase-realtime-database asked Nov 19 '18 at 19:25
kvadityaazkvadityaaz
13416
asked Nov 19 '18 at 19:25
kvadityaazkvadityaaz
13416
edited Nov 19 '18 at 19:47
kvadityaaz
asked Nov 19 '18 at 19:25
kvadityaazkvadityaaz
13416
asked Nov 19 '18 at 19:25
kvadityaazkvadityaaz
13416
asked Nov 19 '18 at 19:25
kvadityaazkvadityaaz
13416
13416
Please add your database structure.
– Alex Mamo
Nov 19 '18 at 19:30
added the screenshot
– kvadityaaz
Nov 19 '18 at 19:48
So you basically say thatmAuth.getUid()andsnapshot.getKey()return different result, right?
– Alex Mamo
Nov 19 '18 at 19:50
Yes, virtually the results are same but Programmatically they are different, although both are String .
– kvadityaaz
Nov 19 '18 at 19:56
1
Try usinguID.equals(mAuth.getUid())instead ofuID == mAuth.getUid()
– Jantzilla
Nov 20 '18 at 0:27
|
show 6 more comments
Please add your database structure.
– Alex Mamo
Nov 19 '18 at 19:30
added the screenshot
– kvadityaaz
Nov 19 '18 at 19:48
So you basically say thatmAuth.getUid()andsnapshot.getKey()return different result, right?
– Alex Mamo
Nov 19 '18 at 19:50
Yes, virtually the results are same but Programmatically they are different, although both are String .
– kvadityaaz
Nov 19 '18 at 19:56
1
Try usinguID.equals(mAuth.getUid())instead ofuID == mAuth.getUid()
– Jantzilla
Nov 20 '18 at 0:27
Please add your database structure.
– Alex Mamo
Nov 19 '18 at 19:30
Please add your database structure.
– Alex Mamo
Nov 19 '18 at 19:30
added the screenshot
– kvadityaaz
Nov 19 '18 at 19:48
added the screenshot
– kvadityaaz
Nov 19 '18 at 19:48
So you basically say that
mAuth.getUid() and snapshot.getKey() return different result, right?– Alex Mamo
Nov 19 '18 at 19:50
So you basically say that
mAuth.getUid() and snapshot.getKey() return different result, right?– Alex Mamo
Nov 19 '18 at 19:50
Yes, virtually the results are same but Programmatically they are different, although both are String .
– kvadityaaz
Nov 19 '18 at 19:56
Yes, virtually the results are same but Programmatically they are different, although both are String .
– kvadityaaz
Nov 19 '18 at 19:56
1
1
Try using
uID.equals(mAuth.getUid()) instead of uID == mAuth.getUid()– Jantzilla
Nov 20 '18 at 0:27
Try using
uID.equals(mAuth.getUid()) instead of uID == mAuth.getUid()– Jantzilla
Nov 20 '18 at 0:27
|
show 6 more comments
1 Answer
1
active
oldest
votes
The problem is Solved using using uID.equals(mAuth.getUid()) instead of uID == mAuth.getUid()
answered Nov 20 '18 at 4:36
kvadityaazkvadityaaz
13416
add a comment |
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The problem is Solved using using uID.equals(mAuth.getUid()) instead of uID == mAuth.getUid()
answered Nov 20 '18 at 4:36
kvadityaazkvadityaaz
13416
add a comment |
The problem is Solved using using uID.equals(mAuth.getUid()) instead of uID == mAuth.getUid()
answered Nov 20 '18 at 4:36
kvadityaazkvadityaaz
13416
add a comment |
The problem is Solved using using uID.equals(mAuth.getUid()) instead of uID == mAuth.getUid()
answered Nov 20 '18 at 4:36
kvadityaazkvadityaaz
13416
The problem is Solved using using uID.equals(mAuth.getUid()) instead of uID == mAuth.getUid()
answered Nov 20 '18 at 4:36
kvadityaazkvadityaaz
13416
answered Nov 20 '18 at 4:36
kvadityaazkvadityaaz
13416
answered Nov 20 '18 at 4:36
kvadityaazkvadityaaz
13416
answered Nov 20 '18 at 4:36
kvadityaazkvadityaaz
13416
13416
add a comment |
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Please add your database structure.
– Alex Mamo
Nov 19 '18 at 19:30
added the screenshot
– kvadityaaz
Nov 19 '18 at 19:48
So you basically say that
mAuth.getUid()andsnapshot.getKey()return different result, right?– Alex Mamo
Nov 19 '18 at 19:50
Yes, virtually the results are same but Programmatically they are different, although both are String .
– kvadityaaz
Nov 19 '18 at 19:56
1
Try using
uID.equals(mAuth.getUid())instead ofuID == mAuth.getUid()– Jantzilla
Nov 20 '18 at 0:27