If statement ignoring condition












-1















#include <stdio.h>
#include<math.h>

int binary_to_decimal(int n){
int ostatok, i=0, pom, decimal=0;
pom=n;
while(pom)
{
ostatok=pom%10;
decimal+=ostatok*pow(2,i);
pom/=10;
i++;
}
return decimal;
}

int main()
{
int m, n, i, max=0, number;
scanf(" %d %d", &n, &m);
int array[n];

for(i=0; i<n ;i++){
scanf(" %d", &number);
binary_to_decimal(number);
if(number>m) // this if statement doesn't seem to be doing it's job
array[i]=number;
if(array[i]>max)
max=array[i];
}

for(i=0; i<n ;i++)
{
printf(" %d %dn", array[i], binary_to_decimal(array[i]));
}
printf("Max %d %d", max, binary_to_decimal(max));
return 0;
}


The program is: you enter two int values, m and n. m is used as a value for comparison, while n is the number of binary number the user is inputting in the loop. If the inputted number is greater than the number m print out the values of the inputted number in binary then in decimal. At the end, print out the number with the biggest value in binary and decimal.
My problem is the if where i am comparing m and the inputted number and i can't seem to find the problem.










share|improve this question




















  • 2





    binary_to_decimal(number); this has no effect at all.

    – Osiris
    Nov 20 '18 at 16:37











  • Add printf("%d > %d?n", number, m); above if(number>m)?

    – Fiddling Bits
    Nov 20 '18 at 16:37








  • 1





    My guess is that you need to write number = binary_to_decimal(number); otherwise you compare the binary representation to the decimal one.

    – Osiris
    Nov 20 '18 at 16:39






  • 1





    array[i] only gets a value if number>m. That's conditional. But it is used unconditionally. Results are undefined. It's not an answer to your question, but is an additional problem.

    – donjuedo
    Nov 20 '18 at 16:45








  • 3





    @Spyware If you get some random number then maybe your binary_to_decimal function is broken.

    – Osiris
    Nov 20 '18 at 16:51
















-1















#include <stdio.h>
#include<math.h>

int binary_to_decimal(int n){
int ostatok, i=0, pom, decimal=0;
pom=n;
while(pom)
{
ostatok=pom%10;
decimal+=ostatok*pow(2,i);
pom/=10;
i++;
}
return decimal;
}

int main()
{
int m, n, i, max=0, number;
scanf(" %d %d", &n, &m);
int array[n];

for(i=0; i<n ;i++){
scanf(" %d", &number);
binary_to_decimal(number);
if(number>m) // this if statement doesn't seem to be doing it's job
array[i]=number;
if(array[i]>max)
max=array[i];
}

for(i=0; i<n ;i++)
{
printf(" %d %dn", array[i], binary_to_decimal(array[i]));
}
printf("Max %d %d", max, binary_to_decimal(max));
return 0;
}


The program is: you enter two int values, m and n. m is used as a value for comparison, while n is the number of binary number the user is inputting in the loop. If the inputted number is greater than the number m print out the values of the inputted number in binary then in decimal. At the end, print out the number with the biggest value in binary and decimal.
My problem is the if where i am comparing m and the inputted number and i can't seem to find the problem.










share|improve this question




















  • 2





    binary_to_decimal(number); this has no effect at all.

    – Osiris
    Nov 20 '18 at 16:37











  • Add printf("%d > %d?n", number, m); above if(number>m)?

    – Fiddling Bits
    Nov 20 '18 at 16:37








  • 1





    My guess is that you need to write number = binary_to_decimal(number); otherwise you compare the binary representation to the decimal one.

    – Osiris
    Nov 20 '18 at 16:39






  • 1





    array[i] only gets a value if number>m. That's conditional. But it is used unconditionally. Results are undefined. It's not an answer to your question, but is an additional problem.

    – donjuedo
    Nov 20 '18 at 16:45








  • 3





    @Spyware If you get some random number then maybe your binary_to_decimal function is broken.

    – Osiris
    Nov 20 '18 at 16:51














-1












-1








-1








#include <stdio.h>
#include<math.h>

int binary_to_decimal(int n){
int ostatok, i=0, pom, decimal=0;
pom=n;
while(pom)
{
ostatok=pom%10;
decimal+=ostatok*pow(2,i);
pom/=10;
i++;
}
return decimal;
}

int main()
{
int m, n, i, max=0, number;
scanf(" %d %d", &n, &m);
int array[n];

for(i=0; i<n ;i++){
scanf(" %d", &number);
binary_to_decimal(number);
if(number>m) // this if statement doesn't seem to be doing it's job
array[i]=number;
if(array[i]>max)
max=array[i];
}

for(i=0; i<n ;i++)
{
printf(" %d %dn", array[i], binary_to_decimal(array[i]));
}
printf("Max %d %d", max, binary_to_decimal(max));
return 0;
}


The program is: you enter two int values, m and n. m is used as a value for comparison, while n is the number of binary number the user is inputting in the loop. If the inputted number is greater than the number m print out the values of the inputted number in binary then in decimal. At the end, print out the number with the biggest value in binary and decimal.
My problem is the if where i am comparing m and the inputted number and i can't seem to find the problem.










share|improve this question
















#include <stdio.h>
#include<math.h>

int binary_to_decimal(int n){
int ostatok, i=0, pom, decimal=0;
pom=n;
while(pom)
{
ostatok=pom%10;
decimal+=ostatok*pow(2,i);
pom/=10;
i++;
}
return decimal;
}

int main()
{
int m, n, i, max=0, number;
scanf(" %d %d", &n, &m);
int array[n];

for(i=0; i<n ;i++){
scanf(" %d", &number);
binary_to_decimal(number);
if(number>m) // this if statement doesn't seem to be doing it's job
array[i]=number;
if(array[i]>max)
max=array[i];
}

for(i=0; i<n ;i++)
{
printf(" %d %dn", array[i], binary_to_decimal(array[i]));
}
printf("Max %d %d", max, binary_to_decimal(max));
return 0;
}


The program is: you enter two int values, m and n. m is used as a value for comparison, while n is the number of binary number the user is inputting in the loop. If the inputted number is greater than the number m print out the values of the inputted number in binary then in decimal. At the end, print out the number with the biggest value in binary and decimal.
My problem is the if where i am comparing m and the inputted number and i can't seem to find the problem.







c if-statement






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share|improve this question













share|improve this question




share|improve this question








edited Nov 20 '18 at 17:01









dbush

99.8k13104138




99.8k13104138










asked Nov 20 '18 at 16:35









PauseUnpausePauseUnpause

6418




6418








  • 2





    binary_to_decimal(number); this has no effect at all.

    – Osiris
    Nov 20 '18 at 16:37











  • Add printf("%d > %d?n", number, m); above if(number>m)?

    – Fiddling Bits
    Nov 20 '18 at 16:37








  • 1





    My guess is that you need to write number = binary_to_decimal(number); otherwise you compare the binary representation to the decimal one.

    – Osiris
    Nov 20 '18 at 16:39






  • 1





    array[i] only gets a value if number>m. That's conditional. But it is used unconditionally. Results are undefined. It's not an answer to your question, but is an additional problem.

    – donjuedo
    Nov 20 '18 at 16:45








  • 3





    @Spyware If you get some random number then maybe your binary_to_decimal function is broken.

    – Osiris
    Nov 20 '18 at 16:51














  • 2





    binary_to_decimal(number); this has no effect at all.

    – Osiris
    Nov 20 '18 at 16:37











  • Add printf("%d > %d?n", number, m); above if(number>m)?

    – Fiddling Bits
    Nov 20 '18 at 16:37








  • 1





    My guess is that you need to write number = binary_to_decimal(number); otherwise you compare the binary representation to the decimal one.

    – Osiris
    Nov 20 '18 at 16:39






  • 1





    array[i] only gets a value if number>m. That's conditional. But it is used unconditionally. Results are undefined. It's not an answer to your question, but is an additional problem.

    – donjuedo
    Nov 20 '18 at 16:45








  • 3





    @Spyware If you get some random number then maybe your binary_to_decimal function is broken.

    – Osiris
    Nov 20 '18 at 16:51








2




2





binary_to_decimal(number); this has no effect at all.

– Osiris
Nov 20 '18 at 16:37





binary_to_decimal(number); this has no effect at all.

– Osiris
Nov 20 '18 at 16:37













Add printf("%d > %d?n", number, m); above if(number>m)?

– Fiddling Bits
Nov 20 '18 at 16:37







Add printf("%d > %d?n", number, m); above if(number>m)?

– Fiddling Bits
Nov 20 '18 at 16:37






1




1





My guess is that you need to write number = binary_to_decimal(number); otherwise you compare the binary representation to the decimal one.

– Osiris
Nov 20 '18 at 16:39





My guess is that you need to write number = binary_to_decimal(number); otherwise you compare the binary representation to the decimal one.

– Osiris
Nov 20 '18 at 16:39




1




1





array[i] only gets a value if number>m. That's conditional. But it is used unconditionally. Results are undefined. It's not an answer to your question, but is an additional problem.

– donjuedo
Nov 20 '18 at 16:45







array[i] only gets a value if number>m. That's conditional. But it is used unconditionally. Results are undefined. It's not an answer to your question, but is an additional problem.

– donjuedo
Nov 20 '18 at 16:45






3




3





@Spyware If you get some random number then maybe your binary_to_decimal function is broken.

– Osiris
Nov 20 '18 at 16:51





@Spyware If you get some random number then maybe your binary_to_decimal function is broken.

– Osiris
Nov 20 '18 at 16:51












1 Answer
1






active

oldest

votes


















3














The call binary_to_decimal(number) does not change your number.
Try something like:



number = binary_to_decimal(number);





share|improve this answer





















  • 3





    C does not have references

    – Gerhardh
    Nov 20 '18 at 16:52






  • 1





    int &n is C++, not C.

    – Barmar
    Nov 20 '18 at 16:53













  • And your function never changes n.

    – Barmar
    Nov 20 '18 at 16:54











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









3














The call binary_to_decimal(number) does not change your number.
Try something like:



number = binary_to_decimal(number);





share|improve this answer





















  • 3





    C does not have references

    – Gerhardh
    Nov 20 '18 at 16:52






  • 1





    int &n is C++, not C.

    – Barmar
    Nov 20 '18 at 16:53













  • And your function never changes n.

    – Barmar
    Nov 20 '18 at 16:54
















3














The call binary_to_decimal(number) does not change your number.
Try something like:



number = binary_to_decimal(number);





share|improve this answer





















  • 3





    C does not have references

    – Gerhardh
    Nov 20 '18 at 16:52






  • 1





    int &n is C++, not C.

    – Barmar
    Nov 20 '18 at 16:53













  • And your function never changes n.

    – Barmar
    Nov 20 '18 at 16:54














3












3








3







The call binary_to_decimal(number) does not change your number.
Try something like:



number = binary_to_decimal(number);





share|improve this answer















The call binary_to_decimal(number) does not change your number.
Try something like:



number = binary_to_decimal(number);






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 20 '18 at 16:54

























answered Nov 20 '18 at 16:45









D. DianaD. Diana

314




314








  • 3





    C does not have references

    – Gerhardh
    Nov 20 '18 at 16:52






  • 1





    int &n is C++, not C.

    – Barmar
    Nov 20 '18 at 16:53













  • And your function never changes n.

    – Barmar
    Nov 20 '18 at 16:54














  • 3





    C does not have references

    – Gerhardh
    Nov 20 '18 at 16:52






  • 1





    int &n is C++, not C.

    – Barmar
    Nov 20 '18 at 16:53













  • And your function never changes n.

    – Barmar
    Nov 20 '18 at 16:54








3




3





C does not have references

– Gerhardh
Nov 20 '18 at 16:52





C does not have references

– Gerhardh
Nov 20 '18 at 16:52




1




1





int &n is C++, not C.

– Barmar
Nov 20 '18 at 16:53







int &n is C++, not C.

– Barmar
Nov 20 '18 at 16:53















And your function never changes n.

– Barmar
Nov 20 '18 at 16:54





And your function never changes n.

– Barmar
Nov 20 '18 at 16:54




















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