Owlready2 dynamic class generation
I am trying to dynamically create a class for an owlready2 ontology. The documentation suggests the following line of code:
NewClass = types.new_class("NewClassName", (SuperClass,), kwds = { "namespace" : my_ontology })
In my case this equals
types.new_class("NewClassName", (onto["ParentClass"],), kwds={'namespace' : onto})
However, when I run the above code, I get the following exception:
Traceback (most recent call last):
(onto[object.get('owl_dataProperty_parent')],), kwds={'namespace' : onto})
File "/usr/lib/python3.6/types.py", line 62, in new_class
return meta(name, bases, ns, **kwds)
TypeError: __new__() got an unexpected keyword argument 'namespace
I have no idea what went wrong there and after hours of debugging I am still clueless.
I am using Python 3.6.6 and version 0.11 of owlready2
python-3.x owlready
asked Nov 20 '18 at 16:41
enigmaenigma
3532416
add a comment |
I am trying to dynamically create a class for an owlready2 ontology. The documentation suggests the following line of code:
NewClass = types.new_class("NewClassName", (SuperClass,), kwds = { "namespace" : my_ontology })
In my case this equals
types.new_class("NewClassName", (onto["ParentClass"],), kwds={'namespace' : onto})
However, when I run the above code, I get the following exception:
Traceback (most recent call last):
(onto[object.get('owl_dataProperty_parent')],), kwds={'namespace' : onto})
File "/usr/lib/python3.6/types.py", line 62, in new_class
return meta(name, bases, ns, **kwds)
TypeError: __new__() got an unexpected keyword argument 'namespace
I have no idea what went wrong there and after hours of debugging I am still clueless.
I am using Python 3.6.6 and version 0.11 of owlready2
python-3.x owlready
asked Nov 20 '18 at 16:41
enigmaenigma
3532416
add a comment |
I am trying to dynamically create a class for an owlready2 ontology. The documentation suggests the following line of code:
NewClass = types.new_class("NewClassName", (SuperClass,), kwds = { "namespace" : my_ontology })
In my case this equals
types.new_class("NewClassName", (onto["ParentClass"],), kwds={'namespace' : onto})
However, when I run the above code, I get the following exception:
Traceback (most recent call last):
(onto[object.get('owl_dataProperty_parent')],), kwds={'namespace' : onto})
File "/usr/lib/python3.6/types.py", line 62, in new_class
return meta(name, bases, ns, **kwds)
TypeError: __new__() got an unexpected keyword argument 'namespace
I have no idea what went wrong there and after hours of debugging I am still clueless.
I am using Python 3.6.6 and version 0.11 of owlready2
python-3.x owlready
asked Nov 20 '18 at 16:41
enigmaenigma
3532416
I am trying to dynamically create a class for an owlready2 ontology. The documentation suggests the following line of code:
NewClass = types.new_class("NewClassName", (SuperClass,), kwds = { "namespace" : my_ontology })
In my case this equals
types.new_class("NewClassName", (onto["ParentClass"],), kwds={'namespace' : onto})
However, when I run the above code, I get the following exception:
Traceback (most recent call last):
(onto[object.get('owl_dataProperty_parent')],), kwds={'namespace' : onto})
File "/usr/lib/python3.6/types.py", line 62, in new_class
return meta(name, bases, ns, **kwds)
TypeError: __new__() got an unexpected keyword argument 'namespace
I have no idea what went wrong there and after hours of debugging I am still clueless.
I am using Python 3.6.6 and version 0.11 of owlready2
python-3.x owlready
python-3.x owlready
asked Nov 20 '18 at 16:41
enigmaenigma
3532416
asked Nov 20 '18 at 16:41
enigmaenigma
3532416
asked Nov 20 '18 at 16:41
enigmaenigma
3532416
asked Nov 20 '18 at 16:41
enigmaenigma
3532416
asked Nov 20 '18 at 16:41
enigmaenigma
3532416
3532416
add a comment |
add a comment |
1 Answer
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I figured out that the "namespace" attribute is not needed at all. So the following works just fine:
types.new_class("NewClassName", (onto["ParentClass"],))
Even though this does not solve the overall issue, it answered my question.
Additionally, it seams like this is the way to do it in general, cf.owlready forum. So maybe it is time to update the documentation.
answered Nov 21 '18 at 13:49
enigmaenigma
3532416
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I figured out that the "namespace" attribute is not needed at all. So the following works just fine:
types.new_class("NewClassName", (onto["ParentClass"],))
Even though this does not solve the overall issue, it answered my question.
Additionally, it seams like this is the way to do it in general, cf.owlready forum. So maybe it is time to update the documentation.
answered Nov 21 '18 at 13:49
enigmaenigma
3532416
add a comment |
I figured out that the "namespace" attribute is not needed at all. So the following works just fine:
types.new_class("NewClassName", (onto["ParentClass"],))
Even though this does not solve the overall issue, it answered my question.
Additionally, it seams like this is the way to do it in general, cf.owlready forum. So maybe it is time to update the documentation.
answered Nov 21 '18 at 13:49
enigmaenigma
3532416
add a comment |
I figured out that the "namespace" attribute is not needed at all. So the following works just fine:
types.new_class("NewClassName", (onto["ParentClass"],))
Even though this does not solve the overall issue, it answered my question.
Additionally, it seams like this is the way to do it in general, cf.owlready forum. So maybe it is time to update the documentation.
answered Nov 21 '18 at 13:49
enigmaenigma
3532416
I figured out that the "namespace" attribute is not needed at all. So the following works just fine:
types.new_class("NewClassName", (onto["ParentClass"],))
Even though this does not solve the overall issue, it answered my question.
Additionally, it seams like this is the way to do it in general, cf.owlready forum. So maybe it is time to update the documentation.
answered Nov 21 '18 at 13:49
enigmaenigma
3532416
answered Nov 21 '18 at 13:49
enigmaenigma
3532416
answered Nov 21 '18 at 13:49
enigmaenigma
3532416
answered Nov 21 '18 at 13:49
enigmaenigma
3532416
3532416
add a comment |
add a comment |
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