Making click event in TS in Angular 2+
1
Normally when adding a click event in Angular you would write this
<div (click)="myfunc()">click me </div>
but I want to do something like this in TS instead
`<div (click)="${this.myfunc()}">click me</div>`
It works a bit, but the click is made on load.
Then I tried this
`<div (click)="() => ${this.myfunc}">click me</div>`
But that did not work at all. Any help ?
Here is how I call the modal, where I want to use the code
openModalWithComponent(img) {
const initialState = {
title: 'Modal with component',
content: `
<img src="${img}" />
<div (click)="${this.onImageRemoveHandler()}">delete</div>`,
header: false,
footer: false
};
this.bsModalRef = this._modalService.show(
ModalContentComponent, {initialState});
}
angular typescript
edited Nov 19 '18 at 16:24
JJJ
29.1k147591
asked Nov 19 '18 at 12:55
JohansrkJohansrk
3,59122425
|
show 13 more comments
1
Normally when adding a click event in Angular you would write this
<div (click)="myfunc()">click me </div>
but I want to do something like this in TS instead
`<div (click)="${this.myfunc()}">click me</div>`
It works a bit, but the click is made on load.
Then I tried this
`<div (click)="() => ${this.myfunc}">click me</div>`
But that did not work at all. Any help ?
Here is how I call the modal, where I want to use the code
openModalWithComponent(img) {
const initialState = {
title: 'Modal with component',
content: `
<img src="${img}" />
<div (click)="${this.onImageRemoveHandler()}">delete</div>`,
header: false,
footer: false
};
this.bsModalRef = this._modalService.show(
ModalContentComponent, {initialState});
}
angular typescript
edited Nov 19 '18 at 16:24
JJJ
29.1k147591
asked Nov 19 '18 at 12:55
JohansrkJohansrk
3,59122425
Why would you do that in the first place ? Seems like an XY problem
– trichetriche
Nov 19 '18 at 13:03
because I am calling a modal component, where I want to inject some code
– Johansrk
Nov 19 '18 at 14:03
And how is changing the syntax going to change how you call your modal ? We would need the framework used for the modal and the code of the function to help you. Otherwise, only the first solution would work.
– trichetriche
Nov 19 '18 at 14:05
I updated my description, so you can see the modal
– Johansrk
Nov 19 '18 at 14:12
1
I mean you have to explain why you would use this syntax, this is a template litteral syntax and it's used for strings. So again, explain the issue, not what you think is the solution.
– trichetriche
Nov 19 '18 at 14:47
|
show 13 more comments
1
1
1
Normally when adding a click event in Angular you would write this
<div (click)="myfunc()">click me </div>
but I want to do something like this in TS instead
`<div (click)="${this.myfunc()}">click me</div>`
It works a bit, but the click is made on load.
Then I tried this
`<div (click)="() => ${this.myfunc}">click me</div>`
But that did not work at all. Any help ?
Here is how I call the modal, where I want to use the code
openModalWithComponent(img) {
const initialState = {
title: 'Modal with component',
content: `
<img src="${img}" />
<div (click)="${this.onImageRemoveHandler()}">delete</div>`,
header: false,
footer: false
};
this.bsModalRef = this._modalService.show(
ModalContentComponent, {initialState});
}
angular typescript
edited Nov 19 '18 at 16:24
JJJ
29.1k147591
asked Nov 19 '18 at 12:55
JohansrkJohansrk
3,59122425
Normally when adding a click event in Angular you would write this
<div (click)="myfunc()">click me </div>
but I want to do something like this in TS instead
`<div (click)="${this.myfunc()}">click me</div>`
It works a bit, but the click is made on load.
Then I tried this
`<div (click)="() => ${this.myfunc}">click me</div>`
But that did not work at all. Any help ?
Here is how I call the modal, where I want to use the code
openModalWithComponent(img) {
const initialState = {
title: 'Modal with component',
content: `
<img src="${img}" />
<div (click)="${this.onImageRemoveHandler()}">delete</div>`,
header: false,
footer: false
};
this.bsModalRef = this._modalService.show(
ModalContentComponent, {initialState});
}
angular typescript
angular typescript
edited Nov 19 '18 at 16:24
JJJ
29.1k147591
asked Nov 19 '18 at 12:55
JohansrkJohansrk
3,59122425
edited Nov 19 '18 at 16:24
JJJ
29.1k147591
asked Nov 19 '18 at 12:55
JohansrkJohansrk
3,59122425
edited Nov 19 '18 at 16:24
JJJ
29.1k147591
edited Nov 19 '18 at 16:24
JJJ
29.1k147591
edited Nov 19 '18 at 16:24
JJJ
29.1k147591
29.1k147591
asked Nov 19 '18 at 12:55
JohansrkJohansrk
3,59122425
asked Nov 19 '18 at 12:55
JohansrkJohansrk
3,59122425
asked Nov 19 '18 at 12:55
JohansrkJohansrk
3,59122425
3,59122425
Why would you do that in the first place ? Seems like an XY problem
– trichetriche
Nov 19 '18 at 13:03
because I am calling a modal component, where I want to inject some code
– Johansrk
Nov 19 '18 at 14:03
And how is changing the syntax going to change how you call your modal ? We would need the framework used for the modal and the code of the function to help you. Otherwise, only the first solution would work.
– trichetriche
Nov 19 '18 at 14:05
I updated my description, so you can see the modal
– Johansrk
Nov 19 '18 at 14:12
1
I mean you have to explain why you would use this syntax, this is a template litteral syntax and it's used for strings. So again, explain the issue, not what you think is the solution.
– trichetriche
Nov 19 '18 at 14:47
|
show 13 more comments
Why would you do that in the first place ? Seems like an XY problem
– trichetriche
Nov 19 '18 at 13:03
because I am calling a modal component, where I want to inject some code
– Johansrk
Nov 19 '18 at 14:03
And how is changing the syntax going to change how you call your modal ? We would need the framework used for the modal and the code of the function to help you. Otherwise, only the first solution would work.
– trichetriche
Nov 19 '18 at 14:05
I updated my description, so you can see the modal
– Johansrk
Nov 19 '18 at 14:12
1
I mean you have to explain why you would use this syntax, this is a template litteral syntax and it's used for strings. So again, explain the issue, not what you think is the solution.
– trichetriche
Nov 19 '18 at 14:47
Why would you do that in the first place ? Seems like an XY problem
– trichetriche
Nov 19 '18 at 13:03
Why would you do that in the first place ? Seems like an XY problem
– trichetriche
Nov 19 '18 at 13:03
because I am calling a modal component, where I want to inject some code
– Johansrk
Nov 19 '18 at 14:03
because I am calling a modal component, where I want to inject some code
– Johansrk
Nov 19 '18 at 14:03
And how is changing the syntax going to change how you call your modal ? We would need the framework used for the modal and the code of the function to help you. Otherwise, only the first solution would work.
– trichetriche
Nov 19 '18 at 14:05
And how is changing the syntax going to change how you call your modal ? We would need the framework used for the modal and the code of the function to help you. Otherwise, only the first solution would work.
– trichetriche
Nov 19 '18 at 14:05
I updated my description, so you can see the modal
– Johansrk
Nov 19 '18 at 14:12
I updated my description, so you can see the modal
– Johansrk
Nov 19 '18 at 14:12
1
1
I mean you have to explain why you would use this syntax, this is a template litteral syntax and it's used for strings. So again, explain the issue, not what you think is the solution.
– trichetriche
Nov 19 '18 at 14:47
I mean you have to explain why you would use this syntax, this is a template litteral syntax and it's used for strings. So again, explain the issue, not what you think is the solution.
– trichetriche
Nov 19 '18 at 14:47
|
show 13 more comments
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Why would you do that in the first place ? Seems like an XY problem
– trichetriche
Nov 19 '18 at 13:03
because I am calling a modal component, where I want to inject some code
– Johansrk
Nov 19 '18 at 14:03
And how is changing the syntax going to change how you call your modal ? We would need the framework used for the modal and the code of the function to help you. Otherwise, only the first solution would work.
– trichetriche
Nov 19 '18 at 14:05
I updated my description, so you can see the modal
– Johansrk
Nov 19 '18 at 14:12
1
I mean you have to explain why you would use this syntax, this is a template litteral syntax and it's used for strings. So again, explain the issue, not what you think is the solution.
– trichetriche
Nov 19 '18 at 14:47